There are two ways of checking for a given type, for example isa<PointerType>(T)
and T->isPointerTy(). Convert most instances of the first form to the second form.
Requested by Chris.
git-svn-id: https://llvm.org/svn/llvm-project/llvm/trunk@96344 91177308-0d34-0410-b5e6-96231b3b80d8
diff --git a/lib/Target/MSIL/MSILWriter.cpp b/lib/Target/MSIL/MSILWriter.cpp
index 3330d09..6f94800 100644
--- a/lib/Target/MSIL/MSILWriter.cpp
+++ b/lib/Target/MSIL/MSILWriter.cpp
@@ -57,7 +57,7 @@
TypeSymbolTable& Table = M.getTypeSymbolTable();
std::set<const Type *> Types = getAnalysis<FindUsedTypes>().getTypes();
for (TypeSymbolTable::iterator I = Table.begin(), E = Table.end(); I!=E; ) {
- if (!isa<StructType>(I->second) && !isa<OpaqueType>(I->second))
+ if (!I->second->isStructTy() && !isa<OpaqueType>(I->second))
Table.remove(I++);
else {
std::set<const Type *>::iterator T = Types.find(I->second);
@@ -1459,7 +1459,7 @@
for (std::set<const Type*>::const_iterator
UI = UsedTypes->begin(), UE = UsedTypes->end(); UI!=UE; ++UI) {
const Type* Ty = *UI;
- if (isa<ArrayType>(Ty) || isa<VectorType>(Ty) || isa<StructType>(Ty))
+ if (Ty->isArrayTy() || Ty->isVectorTy() || Ty->isStructTy())
Name = getTypeName(Ty, false, true);
// Type with no need to declare.
else continue;