| ; This testcase failed due to a bad assertion in SymbolTable.cpp, removed in the 1.20 revision | |
| ; Basically the symbol table assumed that if there was an abstract type in the symbol table, | |
| ; [in this case for the entry %foo of type void(opaque)* ], that there should have also been | |
| ; named types by now. This was obviously not the case here, and this is valid. Assertion | |
| ; disabled. | |
| declare void "foo"(%bb) | |
| %bb = type int | |
| implementation | |