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Dan Gohmanf17a25c2007-07-18 16:29:46 +00001//===- Interval.cpp - Interval class code ---------------------------------===//
2//
3// The LLVM Compiler Infrastructure
4//
Chris Lattner081ce942007-12-29 20:36:04 +00005// This file is distributed under the University of Illinois Open Source
6// License. See LICENSE.TXT for details.
Dan Gohmanf17a25c2007-07-18 16:29:46 +00007//
8//===----------------------------------------------------------------------===//
9//
10// This file contains the definition of the Interval class, which represents a
11// partition of a control flow graph of some kind.
12//
13//===----------------------------------------------------------------------===//
14
15#include "llvm/Analysis/Interval.h"
16#include "llvm/BasicBlock.h"
17#include "llvm/Support/CFG.h"
18#include <algorithm>
19
20using namespace llvm;
21
22//===----------------------------------------------------------------------===//
23// Interval Implementation
24//===----------------------------------------------------------------------===//
25
26// isLoop - Find out if there is a back edge in this interval...
27//
28bool Interval::isLoop() const {
29 // There is a loop in this interval iff one of the predecessors of the header
30 // node lives in the interval.
31 for (::pred_iterator I = ::pred_begin(HeaderNode), E = ::pred_end(HeaderNode);
32 I != E; ++I) {
33 if (contains(*I)) return true;
34 }
35 return false;
36}
37
38
39void Interval::print(std::ostream &o) const {
40 o << "-------------------------------------------------------------\n"
41 << "Interval Contents:\n";
42
43 // Print out all of the basic blocks in the interval...
44 for (std::vector<BasicBlock*>::const_iterator I = Nodes.begin(),
45 E = Nodes.end(); I != E; ++I)
46 o << **I << "\n";
47
48 o << "Interval Predecessors:\n";
49 for (std::vector<BasicBlock*>::const_iterator I = Predecessors.begin(),
50 E = Predecessors.end(); I != E; ++I)
51 o << **I << "\n";
52
53 o << "Interval Successors:\n";
54 for (std::vector<BasicBlock*>::const_iterator I = Successors.begin(),
55 E = Successors.end(); I != E; ++I)
56 o << **I << "\n";
57}