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Dan Gohmanf17a25c2007-07-18 16:29:46 +00001; An integer truncation to i1 should be done with an and instruction to make
2; sure only the LSBit survives. Test that this is the case both for a returned
3; value and as the operand of a branch.
Dan Gohman0a063102009-09-08 23:54:48 +00004; RUN: llc < %s -march=x86 | grep {\\(and\\)\\|\\(test.*\\\$1\\)} | \
Duncan Sands0fc01e42008-11-10 17:28:30 +00005; RUN: count 5
Dan Gohmanf17a25c2007-07-18 16:29:46 +00006
Reid Spencerf234bed2007-07-19 23:13:04 +00007define i1 @test1(i32 %X) zeroext {
Dan Gohmanf17a25c2007-07-18 16:29:46 +00008 %Y = trunc i32 %X to i1
9 ret i1 %Y
10}
11
12define i1 @test2(i32 %val, i32 %mask) {
13entry:
14 %shifted = ashr i32 %val, %mask
15 %anded = and i32 %shifted, 1
16 %trunced = trunc i32 %anded to i1
17 br i1 %trunced, label %ret_true, label %ret_false
18ret_true:
19 ret i1 true
20ret_false:
21 ret i1 false
22}
23
24define i32 @test3(i8* %ptr) {
25 %val = load i8* %ptr
26 %tmp = trunc i8 %val to i1
27 br i1 %tmp, label %cond_true, label %cond_false
28cond_true:
29 ret i32 21
30cond_false:
31 ret i32 42
32}
33
34define i32 @test4(i8* %ptr) {
35 %tmp = ptrtoint i8* %ptr to i1
36 br i1 %tmp, label %cond_true, label %cond_false
37cond_true:
38 ret i32 21
39cond_false:
40 ret i32 42
41}
42
Dan Gohmanf17a25c2007-07-18 16:29:46 +000043define i32 @test6(double %d) {
44 %tmp = fptosi double %d to i1
45 br i1 %tmp, label %cond_true, label %cond_false
46cond_true:
47 ret i32 21
48cond_false:
49 ret i32 42
50}
51