third_party/fdlibm/fdlibm.js

// The following is adapted from fdlibm (http://www.netlib.org/fdlibm),
//
// ====================================================
// Copyright (C) 1993-2004 by Sun Microsystems, Inc. All rights reserved.
//
// Developed at SunSoft, a Sun Microsystems, Inc. business.
// Permission to use, copy, modify, and distribute this
// software is freely granted, provided that this notice
// is preserved.
// ====================================================
//
// The original source code covered by the above license above has been
// modified significantly by Google Inc.
// Copyright 2014 the V8 project authors. All rights reserved.
//
// The following is a straightforward translation of fdlibm routines
// by Raymond Toy (rtoy@google.com).

// Double constants that do not have empty lower 32 bits are found in fdlibm.cc
// and exposed through kMath as typed array. We assume the compiler to convert
// from decimal to binary accurately enough to produce the intended values.
// kMath is initialized to a Float64Array during genesis and not writable.
var kMath;

const INVPIO2 = kMath[0];
const PIO2_1  = kMath[1];
const PIO2_1T = kMath[2];
const PIO2_2  = kMath[3];
const PIO2_2T = kMath[4];
const PIO2_3  = kMath[5];
const PIO2_3T = kMath[6];
const PIO4    = kMath[32];
const PIO4LO  = kMath[33];

// Compute k and r such that x - k*pi/2 = r where |r| < pi/4. For
// precision, r is returned as two values y0 and y1 such that r = y0 + y1
// to more than double precision.
macro REMPIO2(X)
  var n, y0, y1;
  var hx = %_DoubleHi(X);
  var ix = hx & 0x7fffffff;

  if (ix < 0x4002d97c) {
    // |X| ~< 3*pi/4, special case with n = +/- 1
    if (hx > 0) {
      var z = X - PIO2_1;
      if (ix != 0x3ff921fb) {
        // 33+53 bit pi is good enough
        y0 = z - PIO2_1T;
        y1 = (z - y0) - PIO2_1T;
      } else {
        // near pi/2, use 33+33+53 bit pi
        z -= PIO2_2;
        y0 = z - PIO2_2T;
        y1 = (z - y0) - PIO2_2T;
      }
      n = 1;
    } else {
      // Negative X
      var z = X + PIO2_1;
      if (ix != 0x3ff921fb) {
        // 33+53 bit pi is good enough
        y0 = z + PIO2_1T;
        y1 = (z - y0) + PIO2_1T;
      } else {
        // near pi/2, use 33+33+53 bit pi
        z += PIO2_2;
        y0 = z + PIO2_2T;
        y1 = (z - y0) + PIO2_2T;
      }
      n = -1;
    }
  } else if (ix <= 0x413921fb) {
    // |X| ~<= 2^19*(pi/2), medium size
    var t = MathAbs(X);
    n = (t * INVPIO2 + 0.5) | 0;
    var r = t - n * PIO2_1;
    var w = n * PIO2_1T;
    // First round good to 85 bit
    y0 = r - w;
    if (ix - (%_DoubleHi(y0) & 0x7ff00000) > 0x1000000) {
      // 2nd iteration needed, good to 118
      t = r;
      w = n * PIO2_2;
      r = t - w;
      w = n * PIO2_2T - ((t - r) - w);
      y0 = r - w;
      if (ix - (%_DoubleHi(y0) & 0x7ff00000) > 0x3100000) {
        // 3rd iteration needed. 151 bits accuracy
        t = r;
        w = n * PIO2_3;
        r = t - w;
        w = n * PIO2_3T - ((t - r) - w);
        y0 = r - w;
      }
    }
    y1 = (r - y0) - w;
    if (hx < 0) {
      n = -n;
      y0 = -y0;
      y1 = -y1;
    }
  } else {
    // Need to do full Payne-Hanek reduction here.
    var r = %RemPiO2(X);
    n = r[0];
    y0 = r[1];
    y1 = r[2];
  }
endmacro


// __kernel_sin(X, Y, IY)
// kernel sin function on [-pi/4, pi/4], pi/4 ~ 0.7854
// Input X is assumed to be bounded by ~pi/4 in magnitude.
// Input Y is the tail of X so that x = X + Y.
//
// Algorithm
//  1. Since ieee_sin(-x) = -ieee_sin(x), we need only to consider positive x.
//  2. ieee_sin(x) is approximated by a polynomial of degree 13 on
//     [0,pi/4]
//                           3            13
//          sin(x) ~ x + S1*x + ... + S6*x
//     where
//
//    |ieee_sin(x)    2     4     6     8     10     12  |     -58
//    |----- - (1+S1*x +S2*x +S3*x +S4*x +S5*x  +S6*x   )| <= 2
//    |  x                                               |
//
//  3. ieee_sin(X+Y) = ieee_sin(X) + sin'(X')*Y
//              ~ ieee_sin(X) + (1-X*X/2)*Y
//     For better accuracy, let
//               3      2      2      2      2
//          r = X *(S2+X *(S3+X *(S4+X *(S5+X *S6))))
//     then                   3    2
//          sin(x) = X + (S1*X + (X *(r-Y/2)+Y))
//
macro KSIN(x)
kMath[7+x]
endmacro

macro RETURN_KERNELSIN(X, Y, SIGN)
  var z = X * X;
  var v = z * X;
  var r = KSIN(1) + z * (KSIN(2) + z * (KSIN(3) +
                    z * (KSIN(4) + z * KSIN(5))));
  return (X - ((z * (0.5 * Y - v * r) - Y) - v * KSIN(0))) SIGN;
endmacro

// __kernel_cos(X, Y)
// kernel cos function on [-pi/4, pi/4], pi/4 ~ 0.785398164
// Input X is assumed to be bounded by ~pi/4 in magnitude.
// Input Y is the tail of X so that x = X + Y.
//
// Algorithm
//  1. Since ieee_cos(-x) = ieee_cos(x), we need only to consider positive x.
//  2. ieee_cos(x) is approximated by a polynomial of degree 14 on
//     [0,pi/4]
//                                   4            14
//          cos(x) ~ 1 - x*x/2 + C1*x + ... + C6*x
//     where the remez error is
//
//  |                   2     4     6     8     10    12     14 |     -58
//  |ieee_cos(x)-(1-.5*x +C1*x +C2*x +C3*x +C4*x +C5*x  +C6*x  )| <= 2
//  |                                                           |
//
//                 4     6     8     10    12     14
//  3. let r = C1*x +C2*x +C3*x +C4*x +C5*x  +C6*x  , then
//         ieee_cos(x) = 1 - x*x/2 + r
//     since ieee_cos(X+Y) ~ ieee_cos(X) - ieee_sin(X)*Y
//                    ~ ieee_cos(X) - X*Y,
//     a correction term is necessary in ieee_cos(x) and hence
//         cos(X+Y) = 1 - (X*X/2 - (r - X*Y))
//     For better accuracy when x > 0.3, let qx = |x|/4 with
//     the last 32 bits mask off, and if x > 0.78125, let qx = 0.28125.
//     Then
//         cos(X+Y) = (1-qx) - ((X*X/2-qx) - (r-X*Y)).
//     Note that 1-qx and (X*X/2-qx) is EXACT here, and the
//     magnitude of the latter is at least a quarter of X*X/2,
//     thus, reducing the rounding error in the subtraction.
//
macro KCOS(x)
kMath[13+x]
endmacro

macro RETURN_KERNELCOS(X, Y, SIGN)
  var ix = %_DoubleHi(X) & 0x7fffffff;
  var z = X * X;
  var r = z * (KCOS(0) + z * (KCOS(1) + z * (KCOS(2)+
          z * (KCOS(3) + z * (KCOS(4) + z * KCOS(5))))));
  if (ix < 0x3fd33333) {  // |x| ~< 0.3
    return (1 - (0.5 * z - (z * r - X * Y))) SIGN;
  } else {
    var qx;
    if (ix > 0x3fe90000) {  // |x| > 0.78125
      qx = 0.28125;
    } else {
      qx = %_ConstructDouble(%_DoubleHi(0.25 * X), 0);
    }
    var hz = 0.5 * z - qx;
    return (1 - qx - (hz - (z * r - X * Y))) SIGN;
  }
endmacro


// kernel tan function on [-pi/4, pi/4], pi/4 ~ 0.7854
// Input x is assumed to be bounded by ~pi/4 in magnitude.
// Input y is the tail of x.
// Input k indicates whether ieee_tan (if k = 1) or -1/tan (if k = -1)
// is returned.
//
// Algorithm
//  1. Since ieee_tan(-x) = -ieee_tan(x), we need only to consider positive x.
//  2. if x < 2^-28 (hx<0x3e300000 0), return x with inexact if x!=0.
//  3. ieee_tan(x) is approximated by a odd polynomial of degree 27 on
//     [0,0.67434]
//                           3             27
//          tan(x) ~ x + T1*x + ... + T13*x
//     where
//
//     |ieee_tan(x)    2     4            26   |     -59.2
//     |----- - (1+T1*x +T2*x +.... +T13*x    )| <= 2
//     |  x                                    |
//
//     Note: ieee_tan(x+y) = ieee_tan(x) + tan'(x)*y
//                    ~ ieee_tan(x) + (1+x*x)*y
//     Therefore, for better accuracy in computing ieee_tan(x+y), let
//               3      2      2       2       2
//          r = x *(T2+x *(T3+x *(...+x *(T12+x *T13))))
//     then
//                              3    2
//          tan(x+y) = x + (T1*x + (x *(r+y)+y))
//
//  4. For x in [0.67434,pi/4],  let y = pi/4 - x, then
//          tan(x) = ieee_tan(pi/4-y) = (1-ieee_tan(y))/(1+ieee_tan(y))
//                 = 1 - 2*(ieee_tan(y) - (ieee_tan(y)^2)/(1+ieee_tan(y)))
//
// Set returnTan to 1 for tan; -1 for cot.  Anything else is illegal
// and will cause incorrect results.
//
macro KTAN(x)
kMath[19+x]
endmacro

function KernelTan(x, y, returnTan) {
  var z;
  var w;
  var hx = %_DoubleHi(x);
  var ix = hx & 0x7fffffff;

  if (ix < 0x3e300000) {  // |x| < 2^-28
    if (((ix | %_DoubleLo(x)) | (returnTan + 1)) == 0) {
      // x == 0 && returnTan = -1
      return 1 / MathAbs(x);
    } else {
      if (returnTan == 1) {
        return x;
      } else {
        // Compute -1/(x + y) carefully
        var w = x + y;
        var z = %_ConstructDouble(%_DoubleHi(w), 0);
        var v = y - (z - x);
        var a = -1 / w;
        var t = %_ConstructDouble(%_DoubleHi(a), 0);
        var s = 1 + t * z;
        return t + a * (s + t * v);
      }
    }
  }
  if (ix >= 0x3fe59428) {  // |x| > .6744
    if (x < 0) {
      x = -x;
      y = -y;
    }
    z = PIO4 - x;
    w = PIO4LO - y;
    x = z + w;
    y = 0;
  }
  z = x * x;
  w = z * z;

  // Break x^5 * (T1 + x^2*T2 + ...) into
  // x^5 * (T1 + x^4*T3 + ... + x^20*T11) +
  // x^5 * (x^2 * (T2 + x^4*T4 + ... + x^22*T12))
  var r = KTAN(1) + w * (KTAN(3) + w * (KTAN(5) +
                    w * (KTAN(7) + w * (KTAN(9) + w * KTAN(11)))));
  var v = z * (KTAN(2) + w * (KTAN(4) + w * (KTAN(6) +
                         w * (KTAN(8) + w * (KTAN(10) + w * KTAN(12))))));
  var s = z * x;
  r = y + z * (s * (r + v) + y);
  r = r + KTAN(0) * s;
  w = x + r;
  if (ix >= 0x3fe59428) {
    return (1 - ((hx >> 30) & 2)) *
      (returnTan - 2.0 * (x - (w * w / (w + returnTan) - r)));
  }
  if (returnTan == 1) {
    return w;
  } else {
    z = %_ConstructDouble(%_DoubleHi(w), 0);
    v = r - (z - x);
    var a = -1 / w;
    var t = %_ConstructDouble(%_DoubleHi(a), 0);
    s = 1 + t * z;
    return t + a * (s + t * v);
  }
}

function MathSinSlow(x) {
  REMPIO2(x);
  var sign = 1 - (n & 2);
  if (n & 1) {
    RETURN_KERNELCOS(y0, y1, * sign);
  } else {
    RETURN_KERNELSIN(y0, y1, * sign);
  }
}

function MathCosSlow(x) {
  REMPIO2(x);
  if (n & 1) {
    var sign = (n & 2) - 1;
    RETURN_KERNELSIN(y0, y1, * sign);
  } else {
    var sign = 1 - (n & 2);
    RETURN_KERNELCOS(y0, y1, * sign);
  }
}

// ECMA 262 - 15.8.2.16
function MathSin(x) {
  x = x * 1;  // Convert to number.
  if ((%_DoubleHi(x) & 0x7fffffff) <= 0x3fe921fb) {
    // |x| < pi/4, approximately.  No reduction needed.
    RETURN_KERNELSIN(x, 0, /* empty */);
  }
  return MathSinSlow(x);
}

// ECMA 262 - 15.8.2.7
function MathCos(x) {
  x = x * 1;  // Convert to number.
  if ((%_DoubleHi(x) & 0x7fffffff) <= 0x3fe921fb) {
    // |x| < pi/4, approximately.  No reduction needed.
    RETURN_KERNELCOS(x, 0, /* empty */);
  }
  return MathCosSlow(x);
}

// ECMA 262 - 15.8.2.18
function MathTan(x) {
  x = x * 1;  // Convert to number.
  if ((%_DoubleHi(x) & 0x7fffffff) <= 0x3fe921fb) {
    // |x| < pi/4, approximately.  No reduction needed.
    return KernelTan(x, 0, 1);
  }
  REMPIO2(x);
  return KernelTan(y0, y1, (n & 1) ? -1 : 1);
}

// ES6 draft 09-27-13, section 20.2.2.20.
// Math.log1p
//
// Method :
//   1. Argument Reduction: find k and f such that
//                      1+x = 2^k * (1+f),
//         where  sqrt(2)/2 < 1+f < sqrt(2) .
//
//      Note. If k=0, then f=x is exact. However, if k!=0, then f
//      may not be representable exactly. In that case, a correction
//      term is need. Let u=1+x rounded. Let c = (1+x)-u, then
//      log(1+x) - log(u) ~ c/u. Thus, we proceed to compute log(u),
//      and add back the correction term c/u.
//      (Note: when x > 2**53, one can simply return log(x))
//
//   2. Approximation of log1p(f).
//      Let s = f/(2+f) ; based on log(1+f) = log(1+s) - log(1-s)
//            = 2s + 2/3 s**3 + 2/5 s**5 + .....,
//            = 2s + s*R
//      We use a special Reme algorithm on [0,0.1716] to generate
//      a polynomial of degree 14 to approximate R The maximum error
//      of this polynomial approximation is bounded by 2**-58.45. In
//      other words,
//                      2      4      6      8      10      12      14
//          R(z) ~ Lp1*s +Lp2*s +Lp3*s +Lp4*s +Lp5*s  +Lp6*s  +Lp7*s
//      (the values of Lp1 to Lp7 are listed in the program)
//      and
//          |      2          14          |     -58.45
//          | Lp1*s +...+Lp7*s    -  R(z) | <= 2
//          |                             |
//      Note that 2s = f - s*f = f - hfsq + s*hfsq, where hfsq = f*f/2.
//      In order to guarantee error in log below 1ulp, we compute log
//      by
//              log1p(f) = f - (hfsq - s*(hfsq+R)).
//
//      3. Finally, log1p(x) = k*ln2 + log1p(f).
//                           = k*ln2_hi+(f-(hfsq-(s*(hfsq+R)+k*ln2_lo)))
//         Here ln2 is split into two floating point number:
//                      ln2_hi + ln2_lo,
//         where n*ln2_hi is always exact for |n| < 2000.
//
// Special cases:
//      log1p(x) is NaN with signal if x < -1 (including -INF) ;
//      log1p(+INF) is +INF; log1p(-1) is -INF with signal;
//      log1p(NaN) is that NaN with no signal.
//
// Accuracy:
//      according to an error analysis, the error is always less than
//      1 ulp (unit in the last place).
//
// Constants:
//      Constants are found in fdlibm.cc. We assume the C++ compiler to convert
//      from decimal to binary accurately enough to produce the intended values.
//
// Note: Assuming log() return accurate answer, the following
//       algorithm can be used to compute log1p(x) to within a few ULP:
//
//              u = 1+x;
//              if (u==1.0) return x ; else
//                          return log(u)*(x/(u-1.0));
//
//       See HP-15C Advanced Functions Handbook, p.193.
//
const LN2_HI    = kMath[34];
const LN2_LO    = kMath[35];
const TWO54     = kMath[36];
const TWO_THIRD = kMath[37];
macro KLOG1P(x)
(kMath[38+x])
endmacro

function MathLog1p(x) {
  x = x * 1;  // Convert to number.
  var hx = %_DoubleHi(x);
  var ax = hx & 0x7fffffff;
  var k = 1;
  var f = x;
  var hu = 1;
  var c = 0;
  var u = x;

  if (hx < 0x3fda827a) {
    // x < 0.41422
    if (ax >= 0x3ff00000) {  // |x| >= 1
      if (x === -1) {
        return -INFINITY;  // log1p(-1) = -inf
      } else {
        return NAN;  // log1p(x<-1) = NaN
      }
    } else if (ax < 0x3c900000)  {
      // For |x| < 2^-54 we can return x.
      return x;
    } else if (ax < 0x3e200000) {
      // For |x| < 2^-29 we can use a simple two-term Taylor series.
      return x - x * x * 0.5;
    }

    if ((hx > 0) || (hx <= -0x402D413D)) {  // (int) 0xbfd2bec3 = -0x402d413d
      // -.2929 < x < 0.41422
      k = 0;
    }
  }

  // Handle Infinity and NAN
  if (hx >= 0x7ff00000) return x;

  if (k !== 0) {
    if (hx < 0x43400000) {
      // x < 2^53
      u = 1 + x;
      hu = %_DoubleHi(u);
      k = (hu >> 20) - 1023;
      c = (k > 0) ? 1 - (u - x) : x - (u - 1);
      c = c / u;
    } else {
      hu = %_DoubleHi(u);
      k = (hu >> 20) - 1023;
    }
    hu = hu & 0xfffff;
    if (hu < 0x6a09e) {
      u = %_ConstructDouble(hu | 0x3ff00000, %_DoubleLo(u));  // Normalize u.
    } else {
      ++k;
      u = %_ConstructDouble(hu | 0x3fe00000, %_DoubleLo(u));  // Normalize u/2.
      hu = (0x00100000 - hu) >> 2;
    }
    f = u - 1;
  }

  var hfsq = 0.5 * f * f;
  if (hu === 0) {
    // |f| < 2^-20;
    if (f === 0) {
      if (k === 0) {
        return 0.0;
      } else {
        return k * LN2_HI + (c + k * LN2_LO);
      }
    }
    var R = hfsq * (1 - TWO_THIRD * f);
    if (k === 0) {
      return f - R;
    } else {
      return k * LN2_HI - ((R - (k * LN2_LO + c)) - f);
    }
  }

  var s = f / (2 + f);
  var z = s * s;
  var R = z * (KLOG1P(0) + z * (KLOG1P(1) + z *
              (KLOG1P(2) + z * (KLOG1P(3) + z *
              (KLOG1P(4) + z * (KLOG1P(5) + z * KLOG1P(6)))))));
  if (k === 0) {
    return f - (hfsq - s * (hfsq + R));
  } else {
    return k * LN2_HI - ((hfsq - (s * (hfsq + R) + (k * LN2_LO + c))) - f);
  }
}

// ES6 draft 09-27-13, section 20.2.2.14.
// Math.expm1
// Returns exp(x)-1, the exponential of x minus 1.
//
// Method
//   1. Argument reduction:
//      Given x, find r and integer k such that
//
//               x = k*ln2 + r,  |r| <= 0.5*ln2 ~ 0.34658
//
//      Here a correction term c will be computed to compensate
//      the error in r when rounded to a floating-point number.
//
//   2. Approximating expm1(r) by a special rational function on
//      the interval [0,0.34658]:
//      Since
//          r*(exp(r)+1)/(exp(r)-1) = 2+ r^2/6 - r^4/360 + ...
//      we define R1(r*r) by
//          r*(exp(r)+1)/(exp(r)-1) = 2+ r^2/6 * R1(r*r)
//      That is,
//          R1(r**2) = 6/r *((exp(r)+1)/(exp(r)-1) - 2/r)
//                   = 6/r * ( 1 + 2.0*(1/(exp(r)-1) - 1/r))
//                   = 1 - r^2/60 + r^4/2520 - r^6/100800 + ...
//      We use a special Remes algorithm on [0,0.347] to generate
//      a polynomial of degree 5 in r*r to approximate R1. The
//      maximum error of this polynomial approximation is bounded
//      by 2**-61. In other words,
//          R1(z) ~ 1.0 + Q1*z + Q2*z**2 + Q3*z**3 + Q4*z**4 + Q5*z**5
//      where   Q1  =  -1.6666666666666567384E-2,
//              Q2  =   3.9682539681370365873E-4,
//              Q3  =  -9.9206344733435987357E-6,
//              Q4  =   2.5051361420808517002E-7,
//              Q5  =  -6.2843505682382617102E-9;
//      (where z=r*r, and the values of Q1 to Q5 are listed below)
//      with error bounded by
//          |                  5           |     -61
//          | 1.0+Q1*z+...+Q5*z   -  R1(z) | <= 2
//          |                              |
//
//      expm1(r) = exp(r)-1 is then computed by the following
//      specific way which minimize the accumulation rounding error:
//                             2     3
//                            r     r    [ 3 - (R1 + R1*r/2)  ]
//            expm1(r) = r + --- + --- * [--------------------]
//                            2     2    [ 6 - r*(3 - R1*r/2) ]
//
//      To compensate the error in the argument reduction, we use
//              expm1(r+c) = expm1(r) + c + expm1(r)*c
//                         ~ expm1(r) + c + r*c
//      Thus c+r*c will be added in as the correction terms for
//      expm1(r+c). Now rearrange the term to avoid optimization
//      screw up:
//                      (      2                                    2 )
//                      ({  ( r    [ R1 -  (3 - R1*r/2) ]  )  }    r  )
//       expm1(r+c)~r - ({r*(--- * [--------------------]-c)-c} - --- )
//                      ({  ( 2    [ 6 - r*(3 - R1*r/2) ]  )  }    2  )
//                      (                                             )
//
//                 = r - E
//   3. Scale back to obtain expm1(x):
//      From step 1, we have
//         expm1(x) = either 2^k*[expm1(r)+1] - 1
//                  = or     2^k*[expm1(r) + (1-2^-k)]
//   4. Implementation notes:
//      (A). To save one multiplication, we scale the coefficient Qi
//           to Qi*2^i, and replace z by (x^2)/2.
//      (B). To achieve maximum accuracy, we compute expm1(x) by
//        (i)   if x < -56*ln2, return -1.0, (raise inexact if x!=inf)
//        (ii)  if k=0, return r-E
//        (iii) if k=-1, return 0.5*(r-E)-0.5
//        (iv)  if k=1 if r < -0.25, return 2*((r+0.5)- E)
//                     else          return  1.0+2.0*(r-E);
//        (v)   if (k<-2||k>56) return 2^k(1-(E-r)) - 1 (or exp(x)-1)
//        (vi)  if k <= 20, return 2^k((1-2^-k)-(E-r)), else
//        (vii) return 2^k(1-((E+2^-k)-r))
//
// Special cases:
//      expm1(INF) is INF, expm1(NaN) is NaN;
//      expm1(-INF) is -1, and
//      for finite argument, only expm1(0)=0 is exact.
//
// Accuracy:
//      according to an error analysis, the error is always less than
//      1 ulp (unit in the last place).
//
// Misc. info.
//      For IEEE double
//          if x > 7.09782712893383973096e+02 then expm1(x) overflow
//
const KEXPM1_OVERFLOW = kMath[45];
const INVLN2          = kMath[46];
macro KEXPM1(x)
(kMath[47+x])
endmacro

function MathExpm1(x) {
  x = x * 1;  // Convert to number.
  var y;
  var hi;
  var lo;
  var k;
  var t;
  var c;

  var hx = %_DoubleHi(x);
  var xsb = hx & 0x80000000;     // Sign bit of x
  var y = (xsb === 0) ? x : -x;  // y = |x|
  hx &= 0x7fffffff;              // High word of |x|

  // Filter out huge and non-finite argument
  if (hx >= 0x4043687a) {     // if |x| ~=> 56 * ln2
    if (hx >= 0x40862e42) {   // if |x| >= 709.78
      if (hx >= 0x7ff00000) {
        // expm1(inf) = inf; expm1(-inf) = -1; expm1(nan) = nan;
        return (x === -INFINITY) ? -1 : x;
      }
      if (x > KEXPM1_OVERFLOW) return INFINITY;  // Overflow
    }
    if (xsb != 0) return -1;  // x < -56 * ln2, return -1.
  }

  // Argument reduction
  if (hx > 0x3fd62e42) {    // if |x| > 0.5 * ln2
    if (hx < 0x3ff0a2b2) {  // and |x| < 1.5 * ln2
      if (xsb === 0) {
        hi = x - LN2_HI;
        lo = LN2_LO;
        k = 1;
      } else {
        hi = x + LN2_HI;
        lo = -LN2_LO;
        k = -1;
      }
    } else {
      k = (INVLN2 * x + ((xsb === 0) ? 0.5 : -0.5)) | 0;
      t = k;
      // t * ln2_hi is exact here.
      hi = x - t * LN2_HI;
      lo = t * LN2_LO;
    }
    x = hi - lo;
    c = (hi - x) - lo;
  } else if (hx < 0x3c900000)	{
    // When |x| < 2^-54, we can return x.
    return x;
  } else {
    // Fall through.
    k = 0;
  }

  // x is now in primary range
  var hfx = 0.5 * x;
  var hxs = x * hfx;
  var r1 = 1 + hxs * (KEXPM1(0) + hxs * (KEXPM1(1) + hxs *
                     (KEXPM1(2) + hxs * (KEXPM1(3) + hxs * KEXPM1(4)))));
  t = 3 - r1 * hfx;
  var e = hxs * ((r1 - t) / (6 - x * t));
  if (k === 0) {  // c is 0
    return x - (x*e - hxs);
  } else {
    e = (x * (e - c) - c);
    e -= hxs;
    if (k === -1) return 0.5 * (x - e) - 0.5;
    if (k === 1) {
      if (x < -0.25) return -2 * (e - (x + 0.5));
      return 1 + 2 * (x - e);
    }

    if (k <= -2 || k > 56) {
      // suffice to return exp(x) + 1
      y = 1 - (e - x);
      // Add k to y's exponent
      y = %_ConstructDouble(%_DoubleHi(y) + (k << 20), %_DoubleLo(y));
      return y - 1;
    }
    if (k < 20) {
      // t = 1 - 2^k
      t = %_ConstructDouble(0x3ff00000 - (0x200000 >> k), 0);
      y = t - (e - x);
      // Add k to y's exponent
      y = %_ConstructDouble(%_DoubleHi(y) + (k << 20), %_DoubleLo(y));
    } else {
      // t = 2^-k
      t = %_ConstructDouble((0x3ff - k) << 20, 0);
      y = x - (e + t);
      y += 1;
      // Add k to y's exponent
      y = %_ConstructDouble(%_DoubleHi(y) + (k << 20), %_DoubleLo(y));
    }
  }
  return y;
}


// ES6 draft 09-27-13, section 20.2.2.30.
// Math.sinh
// Method :
// mathematically sinh(x) if defined to be (exp(x)-exp(-x))/2
//      1. Replace x by |x| (sinh(-x) = -sinh(x)).
//      2.
//                                                  E + E/(E+1)
//          0        <= x <= 22     :  sinh(x) := --------------, E=expm1(x)
//                                                      2
//
//          22       <= x <= lnovft :  sinh(x) := exp(x)/2
//          lnovft   <= x <= ln2ovft:  sinh(x) := exp(x/2)/2 * exp(x/2)
//          ln2ovft  <  x           :  sinh(x) := x*shuge (overflow)
//
// Special cases:
//      sinh(x) is |x| if x is +Infinity, -Infinity, or NaN.
//      only sinh(0)=0 is exact for finite x.
//
const KSINH_OVERFLOW = kMath[52];
const TWO_M28 = 3.725290298461914e-9;  // 2^-28, empty lower half
const LOG_MAXD = 709.7822265625;  // 0x40862e42 00000000, empty lower half

function MathSinh(x) {
  x = x * 1;  // Convert to number.
  var h = (x < 0) ? -0.5 : 0.5;
  // |x| in [0, 22]. return sign(x)*0.5*(E+E/(E+1))
  var ax = MathAbs(x);
  if (ax < 22) {
    // For |x| < 2^-28, sinh(x) = x
    if (ax < TWO_M28) return x;
    var t = MathExpm1(ax);
    if (ax < 1) return h * (2 * t - t * t / (t + 1));
    return h * (t + t / (t + 1));
  }
  // |x| in [22, log(maxdouble)], return 0.5 * exp(|x|)
  if (ax < LOG_MAXD) return h * MathExp(ax);
  // |x| in [log(maxdouble), overflowthreshold]
  // overflowthreshold = 710.4758600739426
  if (ax <= KSINH_OVERFLOW) {
    var w = MathExp(0.5 * ax);
    var t = h * w;
    return t * w;
  }
  // |x| > overflowthreshold or is NaN.
  // Return Infinity of the appropriate sign or NaN.
  return x * INFINITY;
}


// ES6 draft 09-27-13, section 20.2.2.12.
// Math.cosh
// Method :
// mathematically cosh(x) if defined to be (exp(x)+exp(-x))/2
//      1. Replace x by |x| (cosh(x) = cosh(-x)).
//      2.
//                                                      [ exp(x) - 1 ]^2
//          0        <= x <= ln2/2  :  cosh(x) := 1 + -------------------
//                                                         2*exp(x)
//
//                                                 exp(x) + 1/exp(x)
//          ln2/2    <= x <= 22     :  cosh(x) := -------------------
//                                                        2
//          22       <= x <= lnovft :  cosh(x) := exp(x)/2
//          lnovft   <= x <= ln2ovft:  cosh(x) := exp(x/2)/2 * exp(x/2)
//          ln2ovft  <  x           :  cosh(x) := huge*huge (overflow)
//
// Special cases:
//      cosh(x) is |x| if x is +INF, -INF, or NaN.
//      only cosh(0)=1 is exact for finite x.
//
const KCOSH_OVERFLOW = kMath[52];

function MathCosh(x) {
  x = x * 1;  // Convert to number.
  var ix = %_DoubleHi(x) & 0x7fffffff;
  // |x| in [0,0.5*log2], return 1+expm1(|x|)^2/(2*exp(|x|))
  if (ix < 0x3fd62e43) {
    var t = MathExpm1(MathAbs(x));
    var w = 1 + t;
    // For |x| < 2^-55, cosh(x) = 1
    if (ix < 0x3c800000) return w;
    return 1 + (t * t) / (w + w);
  }
  // |x| in [0.5*log2, 22], return (exp(|x|)+1/exp(|x|)/2
  if (ix < 0x40360000) {
    var t = MathExp(MathAbs(x));
    return 0.5 * t + 0.5 / t;
  }
  // |x| in [22, log(maxdouble)], return half*exp(|x|)
  if (ix < 0x40862e42) return 0.5 * MathExp(MathAbs(x));
  // |x| in [log(maxdouble), overflowthreshold]
  if (MathAbs(x) <= KCOSH_OVERFLOW) {
    var w = MathExp(0.5 * MathAbs(x));
    var t = 0.5 * w;
    return t * w;
  }
  if (NUMBER_IS_NAN(x)) return x;
  // |x| > overflowthreshold.
  return INFINITY;
}