commit | b08ee5f7e4135d64b8edd769367f8964a725122e | [log] [tgz] |
---|---|---|
author | Borislav Petkov <bp@suse.de> | Fri Jul 11 12:43:38 2014 +0200 |
committer | H. Peter Anvin <hpa@linux.intel.com> | Fri Jul 11 17:28:51 2014 -0700 |
tree | c23c93542548c4ef5da24ed60d3c5dc038b3b607 | |
parent | 891715793f0451e5114d200be932ac14ce8521a3 [diff] |
x86: Simplify __HAVE_ARCH_CMPXCHG tests Both the 32-bit and 64-bit cmpxchg.h header define __HAVE_ARCH_CMPXCHG and there's ifdeffery which checks it. But since both bitness define it, we can just as well move it up to the main cmpxchg header and simpify a bit of code in doing that. Signed-off-by: Borislav Petkov <bp@suse.de> Link: http://lkml.kernel.org/r/20140711104338.GB17083@pd.tnic Signed-off-by: H. Peter Anvin <hpa@linux.intel.com>