drivers/net/a2065.c: Convert release_resource to release_region/release_mem_region
Request_mem_region should be used with release_mem_region, not
release_resource.
The semantic match that finds this problem is as follows:
(http://coccinelle.lip6.fr/)
// <smpl>
@@
expression x,E;
@@
*x = request_mem_region(...)
... when != release_mem_region(x)
when != x = E
* release_resource(x);
// </smpl>
Signed-off-by: Julia Lawall <julia@diku.dk>
Signed-off-by: David S. Miller <davem@davemloft.net>
diff --git a/drivers/net/a2065.c b/drivers/net/a2065.c
index f142cc2..deaa8bc 100644
--- a/drivers/net/a2065.c
+++ b/drivers/net/a2065.c
@@ -711,14 +711,14 @@
return -EBUSY;
r2 = request_mem_region(mem_start, A2065_RAM_SIZE, "RAM");
if (!r2) {
- release_resource(r1);
+ release_mem_region(base_addr, sizeof(struct lance_regs));
return -EBUSY;
}
dev = alloc_etherdev(sizeof(struct lance_private));
if (dev == NULL) {
- release_resource(r1);
- release_resource(r2);
+ release_mem_region(base_addr, sizeof(struct lance_regs));
+ release_mem_region(mem_start, A2065_RAM_SIZE);
return -ENOMEM;
}
@@ -764,8 +764,8 @@
err = register_netdev(dev);
if (err) {
- release_resource(r1);
- release_resource(r2);
+ release_mem_region(base_addr, sizeof(struct lance_regs));
+ release_mem_region(mem_start, A2065_RAM_SIZE);
free_netdev(dev);
return err;
}