namei: make set_root_rcu() return void
The only caller that cares about its return value can just
as easily pick it from nd->root_seq itself. We used to just
calculate it and return to caller, but these days we are
storing it in nd->root_seq in all cases.
Signed-off-by: Al Viro <viro@zeniv.linux.org.uk>
diff --git a/fs/namei.c b/fs/namei.c
index 2dad0ea..ae4e4c1 100644
--- a/fs/namei.c
+++ b/fs/namei.c
@@ -792,7 +792,7 @@
get_fs_root(current->fs, &nd->root);
}
-static unsigned set_root_rcu(struct nameidata *nd)
+static void set_root_rcu(struct nameidata *nd)
{
struct fs_struct *fs = current->fs;
unsigned seq;
@@ -802,7 +802,6 @@
nd->root = fs->root;
nd->root_seq = __read_seqcount_begin(&nd->root.dentry->d_seq);
} while (read_seqcount_retry(&fs->seq, seq));
- return nd->root_seq;
}
static void path_put_conditional(struct path *path, struct nameidata *nd)
@@ -1998,7 +1997,8 @@
if (*s == '/') {
if (flags & LOOKUP_RCU) {
rcu_read_lock();
- nd->seq = set_root_rcu(nd);
+ set_root_rcu(nd);
+ nd->seq = nd->root_seq;
} else {
set_root(nd);
path_get(&nd->root);