[POWERPC] Fix mdelay badness on shared processor partitions
On partitioned PPC64 systems where a partition is given 1/10 of a
processor, we have seen mdelay() delaying for 10 times longer than it
should. The reason is that the generic mdelay(n) does n delays of 1
millisecond each. However, with 1/10 of a processor, we only get a
one-millisecond timeslice every 10ms. Thus each 1 millisecond delay
loop ends up taking 10ms elapsed time.
The solution is just to use the PPC64 udelay function, which uses the
timebase to ensure that the delay is based on elapsed time rather than
how much processing time the partition has been given. (Yes, the
generic mdelay uses the PPC64 udelay, but the problem is that the
start time gets reset every millisecond, and each time it gets reset
we lose another 9ms.)
Signed-off-by: Anton Blanchard <anton@samba.org>
Signed-off-by: Paul Mackerras <paulus@samba.org>
Acked-by: Andrew Morton <akpm@osdl.org>
diff --git a/include/linux/delay.h b/include/linux/delay.h
index acb7486..17ddb55 100644
--- a/include/linux/delay.h
+++ b/include/linux/delay.h
@@ -25,10 +25,7 @@
#define MAX_UDELAY_MS 5
#endif
-#ifdef notdef
-#define mdelay(n) (\
- {unsigned long __ms=(n); while (__ms--) udelay(1000);})
-#else
+#ifndef mdelay
#define mdelay(n) (\
(__builtin_constant_p(n) && (n)<=MAX_UDELAY_MS) ? udelay((n)*1000) : \
({unsigned long __ms=(n); while (__ms--) udelay(1000);}))