UBIFS: use nicer 64-bit math
Instead of using do_div(), use better primitives from
linux/math64.h.
Signed-off-by: Artem Bityutskiy <Artem.Bityutskiy@nokia.com>
diff --git a/fs/ubifs/budget.c b/fs/ubifs/budget.c
index e423425..0bcb803 100644
--- a/fs/ubifs/budget.c
+++ b/fs/ubifs/budget.c
@@ -32,7 +32,7 @@
#include "ubifs.h"
#include <linux/writeback.h>
-#include <asm/div64.h>
+#include <linux/math64.h>
/*
* When pessimistic budget calculations say that there is no enough space,
@@ -258,8 +258,8 @@
*/
int ubifs_calc_min_idx_lebs(struct ubifs_info *c)
{
- int ret;
- uint64_t idx_size;
+ int idx_lebs, eff_leb_size = c->leb_size - c->max_idx_node_sz;
+ long long idx_size;
idx_size = c->old_idx_sz + c->budg_idx_growth + c->budg_uncommitted_idx;
@@ -271,18 +271,16 @@
* pair, nor similarly the two variables for the new index size, so we
* have to do this costly 64-bit division on fast-path.
*/
- if (do_div(idx_size, c->leb_size - c->max_idx_node_sz))
- ret = idx_size + 1;
- else
- ret = idx_size;
+ idx_size += eff_leb_size - 1;
+ idx_lebs = div_u64(idx_size, eff_leb_size);
/*
* The index head is not available for the in-the-gaps method, so add an
* extra LEB to compensate.
*/
- ret += 1;
- if (ret < MIN_INDEX_LEBS)
- ret = MIN_INDEX_LEBS;
- return ret;
+ idx_lebs += 1;
+ if (idx_lebs < MIN_INDEX_LEBS)
+ idx_lebs = MIN_INDEX_LEBS;
+ return idx_lebs;
}
/**
@@ -718,7 +716,7 @@
* Note, the calculation is pessimistic, which means that most of the time
* UBIFS reports less space than it actually has.
*/
-long long ubifs_reported_space(const struct ubifs_info *c, uint64_t free)
+long long ubifs_reported_space(const struct ubifs_info *c, long long free)
{
int divisor, factor, f;
@@ -740,8 +738,7 @@
divisor = UBIFS_MAX_DATA_NODE_SZ;
divisor += (c->max_idx_node_sz * 3) / (f - 1);
free *= factor;
- do_div(free, divisor);
- return free;
+ return div_u64(free, divisor);
}
/**