btrfs: fixup error handling in fixup_inode_link_counts
commit 011b28acf940eb61c000059dd9e2cfcbf52ed96b upstream.
This function has the following pattern
while (1) {
ret = whatever();
if (ret)
goto out;
}
ret = 0
out:
return ret;
However several places in this while loop we simply break; when there's
a problem, thus clearing the return value, and in one case we do a
return -EIO, and leak the memory for the path.
Fix this by re-arranging the loop to deal with ret == 1 coming from
btrfs_search_slot, and then simply delete the
ret = 0;
out:
bit so everybody can break if there is an error, which will allow for
proper error handling to occur.
CC: stable@vger.kernel.org # 4.4+
Signed-off-by: Josef Bacik <josef@toxicpanda.com>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
diff --git a/fs/btrfs/tree-log.c b/fs/btrfs/tree-log.c
index 5c86fec..11ecd79 100644
--- a/fs/btrfs/tree-log.c
+++ b/fs/btrfs/tree-log.c
@@ -1529,6 +1529,7 @@
break;
if (ret == 1) {
+ ret = 0;
if (path->slots[0] == 0)
break;
path->slots[0]--;
@@ -1541,17 +1542,19 @@
ret = btrfs_del_item(trans, root, path);
if (ret)
- goto out;
+ break;
btrfs_release_path(path);
inode = read_one_inode(root, key.offset);
- if (!inode)
- return -EIO;
+ if (!inode) {
+ ret = -EIO;
+ break;
+ }
ret = fixup_inode_link_count(trans, root, inode);
iput(inode);
if (ret)
- goto out;
+ break;
/*
* fixup on a directory may create new entries,
@@ -1560,8 +1563,6 @@
*/
key.offset = (u64)-1;
}
- ret = 0;
-out:
btrfs_release_path(path);
return ret;
}