[ALSA] Fix schedule_timeout usage
Use schedule_timeout_{,un}interruptible() instead of
set_current_state()/schedule_timeout() to reduce kernel size. Also use
human-time conversion functions instead of hard-coded division to avoid
rounding issues.
Signed-off-by: Nishanth Aravamudan <nacc@us.ibm.com>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Takashi Iwai <tiwai@suse.de>
diff --git a/sound/isa/wavefront/wavefront_synth.c b/sound/isa/wavefront/wavefront_synth.c
index 0c3c951..abd79b7 100644
--- a/sound/isa/wavefront/wavefront_synth.c
+++ b/sound/isa/wavefront/wavefront_synth.c
@@ -275,8 +275,7 @@
wavefront_sleep (int limit)
{
- set_current_state(TASK_INTERRUPTIBLE);
- schedule_timeout(limit);
+ schedule_timeout_interruptible(limit);
return signal_pending(current);
}
@@ -1788,8 +1787,7 @@
outb (val,port);
spin_unlock_irq(&dev->irq_lock);
while (1) {
- set_current_state(TASK_INTERRUPTIBLE);
- if ((timeout = schedule_timeout(timeout)) == 0)
+ if ((timeout = schedule_timeout_interruptible(timeout)) == 0)
return;
if (dev->irq_ok)
return;