cifs: fix handling of scopeid in cifs_convert_address
The code finds, the '%' sign in an ipv6 address and copies that to a
buffer allocated on the stack. It then ignores that buffer, and passes
'pct' to simple_strtoul(), which doesn't work right because we're
comparing 'endp' against a completely different string.
Fix it by passing the correct pointer. While we're at it, this is a
good candidate for conversion to strict_strtoul as well.
Cc: stable@kernel.org
Cc: David Howells <dhowells@redhat.com>
Reported-by: Björn JACKE <bj@sernet.de>
Signed-off-by: Jeff Layton <jlayton@redhat.com>
Signed-off-by: Steve French <sfrench@us.ibm.com>
diff --git a/fs/cifs/netmisc.c b/fs/cifs/netmisc.c
index 8d9189f..79f641e 100644
--- a/fs/cifs/netmisc.c
+++ b/fs/cifs/netmisc.c
@@ -170,7 +170,7 @@
{
int rc, alen, slen;
const char *pct;
- char *endp, scope_id[13];
+ char scope_id[13];
struct sockaddr_in *s4 = (struct sockaddr_in *) dst;
struct sockaddr_in6 *s6 = (struct sockaddr_in6 *) dst;
@@ -197,9 +197,9 @@
memcpy(scope_id, pct + 1, slen);
scope_id[slen] = '\0';
- s6->sin6_scope_id = (u32) simple_strtoul(pct, &endp, 0);
- if (endp != scope_id + slen)
- return 0;
+ rc = strict_strtoul(scope_id, 0,
+ (unsigned long *)&s6->sin6_scope_id);
+ rc = (rc == 0) ? 1 : 0;
}
return rc;