sh: correct definitions to access stack pointers
A definition like:
#define regs_return_value(regs) ((regs)->regs[0])
called with regs_return_value(foo) will be preprocessed to:
((foo)->foo[0])
^^^
So to fix this to ensure the preprocessor compiles such calls correctly.
Signed-off-by: Roel Kluin <roel.kluin@gmail.com>
Signed-off-by: Paul Mundt <lethal@linux-sh.org>
diff --git a/arch/sh/include/asm/ptrace.h b/arch/sh/include/asm/ptrace.h
index f6edc10..de167d3 100644
--- a/arch/sh/include/asm/ptrace.h
+++ b/arch/sh/include/asm/ptrace.h
@@ -40,8 +40,8 @@
#include <asm/system.h>
#define user_mode(regs) (((regs)->sr & 0x40000000)==0)
-#define user_stack_pointer(regs) ((unsigned long)(regs)->regs[15])
-#define kernel_stack_pointer(regs) ((unsigned long)(regs)->regs[15])
+#define user_stack_pointer(_regs) ((unsigned long)(_regs)->regs[15])
+#define kernel_stack_pointer(_regs) ((unsigned long)(_regs)->regs[15])
#define instruction_pointer(regs) ((unsigned long)(regs)->pc)
extern void show_regs(struct pt_regs *);