drm/amdgpu: Fix use of interruptible waiting
1. The signal interrupt can affect the expected behaviour.
2. There is no good mechanism to handle the corresponding error.
When signal interrupt happens, unpin is not called.
As a result, inside AMDGPU, the statistic of pin size will be wrong.
Signed-off-by: Alex Xie <AlexBin.Xie@amd.com>
Reviewed-by: Christian König <christian.koenig@amd.com>
Signed-off-by: Alex Deucher <alexander.deucher@amd.com>
diff --git a/drivers/gpu/drm/amd/amdgpu/amdgpu_benchmark.c b/drivers/gpu/drm/amd/amdgpu/amdgpu_benchmark.c
index 726b3e0..1beae5b 100644
--- a/drivers/gpu/drm/amd/amdgpu/amdgpu_benchmark.c
+++ b/drivers/gpu/drm/amd/amdgpu/amdgpu_benchmark.c
@@ -123,7 +123,7 @@ static void amdgpu_benchmark_move(struct amdgpu_device *adev, unsigned size,
}
if (sobj) {
- r = amdgpu_bo_reserve(sobj, false);
+ r = amdgpu_bo_reserve(sobj, true);
if (likely(r == 0)) {
amdgpu_bo_unpin(sobj);
amdgpu_bo_unreserve(sobj);
@@ -131,7 +131,7 @@ static void amdgpu_benchmark_move(struct amdgpu_device *adev, unsigned size,
amdgpu_bo_unref(&sobj);
}
if (dobj) {
- r = amdgpu_bo_reserve(dobj, false);
+ r = amdgpu_bo_reserve(dobj, true);
if (likely(r == 0)) {
amdgpu_bo_unpin(dobj);
amdgpu_bo_unreserve(dobj);