ext4: speed-up releasing blocks on commit
Improve mb_free_blocks speed by clearing entire range at once instead
of iterating over each bit. Freeing block-by-block also makes buddy
bitmap subtree flip twice making most of the work a no-op. Very few
bits in buddy bitmap require change, e.g. freeing entire group is a 1
bit flip only. As a result, releasing blocks of 60G file now takes
5ms instead of 2.7s. This is especially good for non-preemptive
kernels as there is no rescheduling during release.
Signed-off-by: Andrey Sidorov <qrxd43@motorola.com>
Signed-off-by: "Theodore Ts'o" <tytso@mit.edu>
diff --git a/fs/ext4/mballoc.c b/fs/ext4/mballoc.c
index 8c8d052..6a87f72 100644
--- a/fs/ext4/mballoc.c
+++ b/fs/ext4/mballoc.c
@@ -405,6 +405,12 @@
ext4_clear_bit(bit, addr);
}
+static inline int mb_test_and_clear_bit(int bit, void *addr)
+{
+ addr = mb_correct_addr_and_bit(&bit, addr);
+ return ext4_test_and_clear_bit(bit, addr);
+}
+
static inline int mb_find_next_zero_bit(void *addr, int max, int start)
{
int fix = 0, ret, tmpmax;
@@ -764,6 +770,24 @@
spin_unlock(&EXT4_SB(sb)->s_bal_lock);
}
+static void mb_regenerate_buddy(struct ext4_buddy *e4b)
+{
+ int count;
+ int order = 1;
+ void *buddy;
+
+ while ((buddy = mb_find_buddy(e4b, order++, &count))) {
+ ext4_set_bits(buddy, 0, count);
+ }
+ e4b->bd_info->bb_fragments = 0;
+ memset(e4b->bd_info->bb_counters, 0,
+ sizeof(*e4b->bd_info->bb_counters) *
+ (e4b->bd_sb->s_blocksize_bits + 2));
+
+ ext4_mb_generate_buddy(e4b->bd_sb, e4b->bd_buddy,
+ e4b->bd_bitmap, e4b->bd_group);
+}
+
/* The buddy information is attached the buddy cache inode
* for convenience. The information regarding each group
* is loaded via ext4_mb_load_buddy. The information involve
@@ -1246,6 +1270,33 @@
}
}
+/* clear bits in given range
+ * will return first found zero bit if any, -1 otherwise
+ */
+static int mb_test_and_clear_bits(void *bm, int cur, int len)
+{
+ __u32 *addr;
+ int zero_bit = -1;
+
+ len = cur + len;
+ while (cur < len) {
+ if ((cur & 31) == 0 && (len - cur) >= 32) {
+ /* fast path: clear whole word at once */
+ addr = bm + (cur >> 3);
+ if (*addr != (__u32)(-1) && zero_bit == -1)
+ zero_bit = cur + mb_find_next_zero_bit(addr, 32, 0);
+ *addr = 0;
+ cur += 32;
+ continue;
+ }
+ if (!mb_test_and_clear_bit(cur, bm) && zero_bit == -1)
+ zero_bit = cur;
+ cur++;
+ }
+
+ return zero_bit;
+}
+
void ext4_set_bits(void *bm, int cur, int len)
{
__u32 *addr;
@@ -1264,17 +1315,90 @@
}
}
-static void mb_free_blocks(struct inode *inode, struct ext4_buddy *e4b,
- int first, int count)
+/*
+ * _________________________________________________________________ */
+
+static inline int mb_buddy_adjust_border(int* bit, void* bitmap, int side)
{
- int block = 0;
- int max = 0;
- int order;
- void *buddy;
- void *buddy2;
+ if (mb_test_bit(*bit + side, bitmap)) {
+ mb_clear_bit(*bit, bitmap);
+ (*bit) -= side;
+ return 1;
+ }
+ else {
+ (*bit) += side;
+ mb_set_bit(*bit, bitmap);
+ return -1;
+ }
+}
+
+static void mb_buddy_mark_free(struct ext4_buddy *e4b, int first, int last)
+{
+ int max;
+ int order = 1;
+ void *buddy = mb_find_buddy(e4b, order, &max);
+
+ while (buddy) {
+ void *buddy2;
+
+ /* Bits in range [first; last] are known to be set since
+ * corresponding blocks were allocated. Bits in range
+ * (first; last) will stay set because they form buddies on
+ * upper layer. We just deal with borders if they don't
+ * align with upper layer and then go up.
+ * Releasing entire group is all about clearing
+ * single bit of highest order buddy.
+ */
+
+ /* Example:
+ * ---------------------------------
+ * | 1 | 1 | 1 | 1 |
+ * ---------------------------------
+ * | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
+ * ---------------------------------
+ * 0 1 2 3 4 5 6 7
+ * \_____________________/
+ *
+ * Neither [1] nor [6] is aligned to above layer.
+ * Left neighbour [0] is free, so mark it busy,
+ * decrease bb_counters and extend range to
+ * [0; 6]
+ * Right neighbour [7] is busy. It can't be coaleasced with [6], so
+ * mark [6] free, increase bb_counters and shrink range to
+ * [0; 5].
+ * Then shift range to [0; 2], go up and do the same.
+ */
+
+
+ if (first & 1)
+ e4b->bd_info->bb_counters[order] += mb_buddy_adjust_border(&first, buddy, -1);
+ if (!(last & 1))
+ e4b->bd_info->bb_counters[order] += mb_buddy_adjust_border(&last, buddy, 1);
+ if (first > last)
+ break;
+ order++;
+
+ if (first == last || !(buddy2 = mb_find_buddy(e4b, order, &max))) {
+ mb_clear_bits(buddy, first, last - first + 1);
+ e4b->bd_info->bb_counters[order - 1] += last - first + 1;
+ break;
+ }
+ first >>= 1;
+ last >>= 1;
+ buddy = buddy2;
+ }
+}
+
+static void mb_free_blocks(struct inode *inode, struct ext4_buddy *e4b,
+ int first, int count)
+{
+ int left_is_free = 0;
+ int right_is_free = 0;
+ int block;
+ int last = first + count - 1;
struct super_block *sb = e4b->bd_sb;
- BUG_ON(first + count > (sb->s_blocksize << 3));
+ BUG_ON(last >= (sb->s_blocksize << 3));
assert_spin_locked(ext4_group_lock_ptr(sb, e4b->bd_group));
mb_check_buddy(e4b);
mb_free_blocks_double(inode, e4b, first, count);
@@ -1283,67 +1407,54 @@
if (first < e4b->bd_info->bb_first_free)
e4b->bd_info->bb_first_free = first;
- /* let's maintain fragments counter */
+ /* access memory sequentially: check left neighbour,
+ * clear range and then check right neighbour
+ */
if (first != 0)
- block = !mb_test_bit(first - 1, e4b->bd_bitmap);
- if (first + count < EXT4_SB(sb)->s_mb_maxs[0])
- max = !mb_test_bit(first + count, e4b->bd_bitmap);
- if (block && max)
+ left_is_free = !mb_test_bit(first - 1, e4b->bd_bitmap);
+ block = mb_test_and_clear_bits(e4b->bd_bitmap, first, count);
+ if (last + 1 < EXT4_SB(sb)->s_mb_maxs[0])
+ right_is_free = !mb_test_bit(last + 1, e4b->bd_bitmap);
+
+ if (unlikely(block != -1)) {
+ ext4_fsblk_t blocknr;
+
+ blocknr = ext4_group_first_block_no(sb, e4b->bd_group);
+ blocknr += EXT4_C2B(EXT4_SB(sb), block);
+ ext4_grp_locked_error(sb, e4b->bd_group,
+ inode ? inode->i_ino : 0,
+ blocknr,
+ "freeing already freed block "
+ "(bit %u)", block);
+ mb_regenerate_buddy(e4b);
+ goto done;
+ }
+
+ /* let's maintain fragments counter */
+ if (left_is_free && right_is_free)
e4b->bd_info->bb_fragments--;
- else if (!block && !max)
+ else if (!left_is_free && !right_is_free)
e4b->bd_info->bb_fragments++;
- /* let's maintain buddy itself */
- while (count-- > 0) {
- block = first++;
- order = 0;
-
- if (!mb_test_bit(block, e4b->bd_bitmap)) {
- ext4_fsblk_t blocknr;
-
- blocknr = ext4_group_first_block_no(sb, e4b->bd_group);
- blocknr += EXT4_C2B(EXT4_SB(sb), block);
- ext4_grp_locked_error(sb, e4b->bd_group,
- inode ? inode->i_ino : 0,
- blocknr,
- "freeing already freed block "
- "(bit %u)", block);
- }
- mb_clear_bit(block, e4b->bd_bitmap);
- e4b->bd_info->bb_counters[order]++;
-
- /* start of the buddy */
- buddy = mb_find_buddy(e4b, order, &max);
-
- do {
- block &= ~1UL;
- if (mb_test_bit(block, buddy) ||
- mb_test_bit(block + 1, buddy))
- break;
-
- /* both the buddies are free, try to coalesce them */
- buddy2 = mb_find_buddy(e4b, order + 1, &max);
-
- if (!buddy2)
- break;
-
- if (order > 0) {
- /* for special purposes, we don't set
- * free bits in bitmap */
- mb_set_bit(block, buddy);
- mb_set_bit(block + 1, buddy);
- }
- e4b->bd_info->bb_counters[order]--;
- e4b->bd_info->bb_counters[order]--;
-
- block = block >> 1;
- order++;
- e4b->bd_info->bb_counters[order]++;
-
- mb_clear_bit(block, buddy2);
- buddy = buddy2;
- } while (1);
+ /* buddy[0] == bd_bitmap is a special case, so handle
+ * it right away and let mb_buddy_mark_free stay free of
+ * zero order checks.
+ * Check if neighbours are to be coaleasced,
+ * adjust bitmap bb_counters and borders appropriately.
+ */
+ if (first & 1) {
+ first += !left_is_free;
+ e4b->bd_info->bb_counters[0] += left_is_free ? -1 : 1;
}
+ if (!(last & 1)) {
+ last -= !right_is_free;
+ e4b->bd_info->bb_counters[0] += right_is_free ? -1 : 1;
+ }
+
+ if (first <= last)
+ mb_buddy_mark_free(e4b, first >> 1, last >> 1);
+
+done:
mb_set_largest_free_order(sb, e4b->bd_info);
mb_check_buddy(e4b);
}