UBIFS: fix available blocks count
Take into account that 2 eraseblocks are never available because
they are reserved for the index. This gives more realistic count
of FS blocks.
To avoid future confusions like this, introduce a constant.
Signed-off-by: Artem Bityutskiy <Artem.Bityutskiy@nokia.com>
diff --git a/fs/ubifs/super.c b/fs/ubifs/super.c
index 2dbaa4f..a6a7798 100644
--- a/fs/ubifs/super.c
+++ b/fs/ubifs/super.c
@@ -695,9 +695,10 @@
* necessary to report something for the 'statfs()' call.
*
* Subtract the LEB reserved for GC, the LEB which is reserved for
- * deletions, and assume only one journal head is available.
+ * deletions, minimum LEBs for the index, and assume only one journal
+ * head is available.
*/
- tmp64 = c->main_lebs - 2 - c->jhead_cnt + 1;
+ tmp64 = c->main_lebs - 1 - 1 - MIN_INDEX_LEBS - c->jhead_cnt + 1;
tmp64 *= (uint64_t)c->leb_size - c->leb_overhead;
tmp64 = ubifs_reported_space(c, tmp64);
c->block_cnt = tmp64 >> UBIFS_BLOCK_SHIFT;