PCI: x86: use generic pci_swizzle_interrupt_pin()
Use the generic pci_swizzle_interrupt_pin() instead of arch-specific code.
Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: Ingo Molnar <mingo@redhat.com>
Cc: hpa@zytor.com
Signed-off-by: Bjorn Helgaas <bjorn.helgaas@hp.com>
Signed-off-by: Jesse Barnes <jbarnes@virtuousgeek.org>
diff --git a/arch/x86/pci/irq.c b/arch/x86/pci/irq.c
index e1d605b..4064345 100644
--- a/arch/x86/pci/irq.c
+++ b/arch/x86/pci/irq.c
@@ -1068,7 +1068,7 @@
struct pci_dev *bridge = dev->bus->self;
int bus;
- pin = (((pin - 1) + PCI_SLOT(dev->devfn)) % 4) + 1;
+ pin = pci_swizzle_interrupt_pin(dev, pin);
bus = bridge->bus->number;
irq = IO_APIC_get_PCI_irq_vector(bus,
PCI_SLOT(bridge->devfn), pin - 1);
@@ -1232,7 +1232,7 @@
while (irq < 0 && dev->bus->parent) { /* go back to the bridge */
struct pci_dev *bridge = dev->bus->self;
- pin = (((pin - 1) + PCI_SLOT(dev->devfn)) % 4) + 1;
+ pin = pci_swizzle_interrupt_pin(dev, pin);
irq = IO_APIC_get_PCI_irq_vector(bridge->bus->number,
PCI_SLOT(bridge->devfn), pin - 1);
if (irq >= 0)