ARM: LMB: Convert arm_memory_present() to use LMB memory information
Signed-off-by: Russell King <rmk+kernel@arm.linux.org.uk>
diff --git a/arch/arm/mm/init.c b/arch/arm/mm/init.c
index 99d6bc9..a453982 100644
--- a/arch/arm/mm/init.c
+++ b/arch/arm/mm/init.c
@@ -257,17 +257,16 @@
}
EXPORT_SYMBOL(pfn_valid);
-static void arm_memory_present(struct meminfo *mi)
+static void arm_memory_present(void)
{
}
#else
-static void arm_memory_present(struct meminfo *mi)
+static void arm_memory_present(void)
{
int i;
- for_each_bank(i, mi) {
- struct membank *bank = &mi->bank[i];
- memory_present(0, bank_pfn_start(bank), bank_pfn_end(bank));
- }
+ for (i = 0; i < memblock.memory.cnt; i++)
+ memory_present(0, memblock_start_pfn(&memblock.memory, i),
+ memblock_end_pfn(&memblock.memory, i));
}
#endif
@@ -320,7 +319,7 @@
* Sparsemem tries to allocate bootmem in memory_present(),
* so must be done after the fixed reservations
*/
- arm_memory_present(mi);
+ arm_memory_present();
/*
* sparse_init() needs the bootmem allocator up and running.