The call to free_opts() in merge_options() is invalid C. The oldopts
argument always refers to the memory pointed to by the opts global,
which may be freed by the call to free_opts(), but oldopts is used
after the free_opts() call. This patch makes sure we don't use freed
memory. (Marcus Sundberg <marcus@ingate.com>)
ip6tables merge by myself.
diff --git a/ip6tables.c b/ip6tables.c
index 49dcbf0..3b32606 100644
--- a/ip6tables.c
+++ b/ip6tables.c
@@ -1029,9 +1029,6 @@
unsigned int num_old, num_new, i;
struct option *merge;
- /* Release previous options merged if any */
- free_opts(0);
-
for (num_old = 0; oldopts[num_old].name; num_old++);
for (num_new = 0; newopts[num_new].name; num_new++);
@@ -1040,6 +1037,7 @@
merge = malloc(sizeof(struct option) * (num_new + num_old + 1));
memcpy(merge, oldopts, num_old * sizeof(struct option));
+ free_opts(0); /* Release previous options merged if any */
for (i = 0; i < num_new; i++) {
merge[num_old + i] = newopts[i];
merge[num_old + i].val += *option_offset;