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Chris Lattner3e0d4b92006-04-26 18:32:59 +00001; The i induction variable looks like a wrap-around, but it really is just
2; a simple affine IV. Make sure that indvars eliminates it.
3
Dan Gohman28beeea2007-08-15 13:36:28 +00004; RUN: llvm-upgrade < %s | llvm-as | opt -indvars | llvm-dis | grep phi | count 1
Chris Lattner3e0d4b92006-04-26 18:32:59 +00005
6void %foo() {
7entry:
8 br label %bb6
9
10bb6: ; preds = %cond_true, %entry
11 %j.0 = phi int [ 1, %entry ], [ %tmp5, %cond_true ] ; <int> [#uses=3]
12 %i.0 = phi int [ 0, %entry ], [ %j.0, %cond_true ] ; <int> [#uses=1]
13 %tmp7 = call int (...)* %foo2( ) ; <int> [#uses=1]
14 %tmp = setne int %tmp7, 0 ; <bool> [#uses=1]
15 br bool %tmp, label %cond_true, label %return
16
17cond_true: ; preds = %bb6
18 %tmp2 = call int (...)* %bar( int %i.0, int %j.0 ) ; <int> [#uses=0]
19 %tmp5 = add int %j.0, 1 ; <int> [#uses=1]
20 br label %bb6
21
22return: ; preds = %bb6
23 ret void
24}
25
26declare int %bar(...)
27
28declare int %foo2(...)