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Ben Lindstromd1aed9c2001-06-10 00:41:18 +00001/*
2 * Copyright (c) 2001 Markus Friedl. All rights reserved.
3 *
4 * Redistribution and use in source and binary forms, with or without
5 * modification, are permitted provided that the following conditions
6 * are met:
7 * 1. Redistributions of source code must retain the above copyright
8 * notice, this list of conditions and the following disclaimer.
9 * 2. Redistributions in binary form must reproduce the above copyright
10 * notice, this list of conditions and the following disclaimer in the
11 * documentation and/or other materials provided with the distribution.
12 *
13 * THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
14 * IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
15 * OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
16 * IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
17 * INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
18 * NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
19 * DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
20 * THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
21 * (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
22 * THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
23 */
24#include "includes.h"
Damien Millera5ebe0c2002-01-22 23:24:33 +110025RCSID("$OpenBSD: auth-skey.c,v 1.14 2002/01/11 20:14:11 markus Exp $");
Ben Lindstromd1aed9c2001-06-10 00:41:18 +000026
27#ifdef SKEY
28
29#include <skey.h>
30
31#include "xmalloc.h"
32#include "auth.h"
33
34static void *
35skey_init_ctx(Authctxt *authctxt)
36{
37 return authctxt;
38}
39
40#define PROMPT "\nS/Key Password: "
41
42static int
Damien Miller9f0f5c62001-12-21 14:45:46 +110043skey_query(void *ctx, char **name, char **infotxt,
Ben Lindstromd1aed9c2001-06-10 00:41:18 +000044 u_int* numprompts, char ***prompts, u_int **echo_on)
45{
46 Authctxt *authctxt = ctx;
47 char challenge[1024], *p;
48 int len;
49 struct skey skey;
50
51 if (skeychallenge(&skey, authctxt->user, challenge) == -1)
52 return -1;
53
54 *name = xstrdup("");
55 *infotxt = xstrdup("");
56 *numprompts = 1;
57 *prompts = xmalloc(*numprompts * sizeof(char*));
58 *echo_on = xmalloc(*numprompts * sizeof(u_int));
59 (*echo_on)[0] = 0;
60
61 len = strlen(challenge) + strlen(PROMPT) + 1;
62 p = xmalloc(len);
Damien Millera5ebe0c2002-01-22 23:24:33 +110063 strlcpy(p, challenge, len);
Ben Lindstromd1aed9c2001-06-10 00:41:18 +000064 strlcat(p, PROMPT, len);
65 (*prompts)[0] = p;
66
67 return 0;
68}
69
70static int
71skey_respond(void *ctx, u_int numresponses, char **responses)
72{
73 Authctxt *authctxt = ctx;
Damien Miller9f0f5c62001-12-21 14:45:46 +110074
Ben Lindstromd1aed9c2001-06-10 00:41:18 +000075 if (authctxt->valid &&
Damien Miller9f0f5c62001-12-21 14:45:46 +110076 numresponses == 1 &&
Ben Lindstromd1aed9c2001-06-10 00:41:18 +000077 skey_haskey(authctxt->pw->pw_name) == 0 &&
78 skey_passcheck(authctxt->pw->pw_name, responses[0]) != -1)
79 return 0;
80 return -1;
81}
82
83static void
84skey_free_ctx(void *ctx)
85{
86 /* we don't have a special context */
87}
88
89KbdintDevice skey_device = {
90 "skey",
91 skey_init_ctx,
92 skey_query,
93 skey_respond,
94 skey_free_ctx
95};
96#endif /* SKEY */