PyUnicode_IS_ASCII() macro ensures that the string is ready
It has no sense to check if a not ready string is ASCII or not.
diff --git a/Include/unicodeobject.h b/Include/unicodeobject.h
index 836bafb..ecf8386 100644
--- a/Include/unicodeobject.h
+++ b/Include/unicodeobject.h
@@ -424,10 +424,12 @@
#define SSTATE_INTERNED_IMMORTAL 2
/* Return true if the string contains only ASCII characters, or 0 if not. The
- string may be compact (PyUnicode_IS_COMPACT_ASCII) or not. No type checks
- or Ready calls are performed. */
-#define PyUnicode_IS_ASCII(op) \
- (((PyASCIIObject*)op)->state.ascii)
+ string may be compact (PyUnicode_IS_COMPACT_ASCII) or not, but must be
+ ready. */
+#define PyUnicode_IS_ASCII(op) \
+ (assert(PyUnicode_Check(op)), \
+ assert(PyUnicode_IS_READY(op)), \
+ ((PyASCIIObject*)op)->state.ascii)
/* Return true if the string is compact or 0 if not.
No type checks or Ready calls are performed. */
@@ -437,7 +439,7 @@
/* Return true if the string is a compact ASCII string (use PyASCIIObject
structure), or 0 if not. No type checks or Ready calls are performed. */
#define PyUnicode_IS_COMPACT_ASCII(op) \
- (PyUnicode_IS_ASCII(op) && PyUnicode_IS_COMPACT(op))
+ (((PyASCIIObject*)op)->state.ascii && PyUnicode_IS_COMPACT(op))
enum PyUnicode_Kind {
/* String contains only wstr byte characters. This is only possible