more robust assignment of lineno for keyword args
get the lineno from the name of the keyword arg
example of case that didn't work--
def foo(x, y, a = None,
b = None):
diff --git a/Lib/compiler/transformer.py b/Lib/compiler/transformer.py
index 9c8b32e..18ec815 100644
--- a/Lib/compiler/transformer.py
+++ b/Lib/compiler/transformer.py
@@ -993,9 +993,9 @@
n = n[1]
if n[0] != token.NAME:
raise SyntaxError, "keyword can't be an expression (%s)"%n[0]
- n = Node('keyword', n[1], result)
- n.lineno = result.lineno
- return 1, n
+ node = Node('keyword', n[1], result)
+ node.lineno = n[2]
+ return 1, node
def com_subscriptlist(self, primary, nodelist, assigning):
# slicing: simple_slicing | extended_slicing