Issue #19005: Fix documentation for PyIter_Next().
diff --git a/Doc/c-api/iter.rst b/Doc/c-api/iter.rst
index 88ac0c1..8d1567c 100644
--- a/Doc/c-api/iter.rst
+++ b/Doc/c-api/iter.rst
@@ -7,7 +7,7 @@
.. versionadded:: 2.2
-There are only a couple of functions specifically for working with iterators.
+There are two functions specifically for working with iterators.
.. c:function:: int PyIter_Check(PyObject *o)
@@ -17,11 +17,10 @@
.. c:function:: PyObject* PyIter_Next(PyObject *o)
- Return the next value from the iteration *o*. If the object is an iterator,
- this retrieves the next value from the iteration, and returns *NULL* with no
- exception set if there are no remaining items. If the object is not an
- iterator, :exc:`TypeError` is raised, or if there is an error in retrieving the
- item, returns *NULL* and passes along the exception.
+ Return the next value from the iteration *o*. The object must be an iterator
+ (it is up to the caller to check this). If there are no remaining values,
+ returns *NULL* with no exception set. If an error occurs while retrieving
+ the item, returns *NULL* and passes along the exception.
To write a loop which iterates over an iterator, the C code should look
something like this::