allow the keyword else immediately after (no space) an integer (closes #21642)
diff --git a/Lib/test/test_grammar.py b/Lib/test/test_grammar.py
index 86cc084..5f77c1d 100644
--- a/Lib/test/test_grammar.py
+++ b/Lib/test/test_grammar.py
@@ -75,6 +75,12 @@
x = .3e14
x = 3.1e4
+ def test_float_exponent_tokenization(self):
+ # See issue 21642.
+ self.assertEqual(1 if 1else 0, 1)
+ self.assertEqual(1 if 0else 0, 0)
+ self.assertRaises(SyntaxError, eval, "0 if 1Else 0")
+
def testStringLiterals(self):
x = ''; y = ""; self.assertTrue(len(x) == 0 and x == y)
x = '\''; y = "'"; self.assertTrue(len(x) == 1 and x == y and ord(x) == 39)