Simplify the signature for itertools.accumulate() to match numpy. Handle one item iterable the same way as min()/max().
diff --git a/Doc/library/itertools.rst b/Doc/library/itertools.rst
index 56eb452..befc6be 100644
--- a/Doc/library/itertools.rst
+++ b/Doc/library/itertools.rst
@@ -90,13 +90,15 @@
parameter (which defaults to :const:`0`). Elements may be any addable type
including :class:`Decimal` or :class:`Fraction`. Equivalent to::
- def accumulate(iterable, start=0):
+ def accumulate(iterable):
'Return running totals'
- # accumulate([1,2,3,4,5]) --> 1 3 6 10 15
- total = start
- for element in iterable:
- total += element
- yield total
+ # accumulate([1,2,3,4,5]) --> 1 3 6 10 15
+ it = iter(iterable)
+ total = next(it)
+ yield total
+ for element in it:
+ total += element
+ yield total
.. versionadded:: 3.2