| """Routine to "compile" a .py file to a .pyc (or .pyo) file. | 
 |  | 
 | This module has intimate knowledge of the format of .pyc files. | 
 | """ | 
 |  | 
 | import imp | 
 | MAGIC = imp.get_magic() | 
 |  | 
 | def wr_long(f, x): | 
 |     """Internal; write a 32-bit int to a file in little-endian order.""" | 
 |     f.write(chr( x        & 0xff)) | 
 |     f.write(chr((x >> 8)  & 0xff)) | 
 |     f.write(chr((x >> 16) & 0xff)) | 
 |     f.write(chr((x >> 24) & 0xff)) | 
 |  | 
 | def compile(file, cfile=None, dfile=None): | 
 |     """Byte-compile one Python source file to Python bytecode. | 
 |  | 
 |     Arguments: | 
 |  | 
 |     file:  source filename | 
 |     cfile: target filename; defaults to source with 'c' or 'o' appended | 
 |            ('c' normally, 'o' in optimizing mode, giving .pyc or .pyo) | 
 |     dfile: purported filename; defaults to source (this is the filename | 
 |            that will show up in error messages) | 
 |  | 
 |     Note that it isn't necessary to byte-compile Python modules for | 
 |     execution efficiency -- Python itself byte-compiles a module when | 
 |     it is loaded, and if it can, writes out the bytecode to the | 
 |     corresponding .pyc (or .pyo) file. | 
 |  | 
 |     However, if a Python installation is shared between users, it is a | 
 |     good idea to byte-compile all modules upon installation, since | 
 |     other users may not be able to write in the source directories, | 
 |     and thus they won't be able to write the .pyc/.pyo file, and then | 
 |     they would be byte-compiling every module each time it is loaded. | 
 |     This can slow down program start-up considerably. | 
 |  | 
 |     See compileall.py for a script/module that uses this module to | 
 |     byte-compile all installed files (or all files in selected | 
 |     directories). | 
 |  | 
 |     """ | 
 |     import os, marshal, __builtin__ | 
 |     f = open(file) | 
 |     try: | 
 |         timestamp = long(os.fstat(f.fileno())[8]) | 
 |     except AttributeError: | 
 |         timestamp = long(os.stat(file)[8]) | 
 |     codestring = f.read() | 
 |     # If parsing from a string, line breaks are \n (see parsetok.c:tok_nextc) | 
 |     # Replace will return original string if pattern is not found, so | 
 |     # we don't need to check whether it is found first. | 
 |     codestring = codestring.replace("\r\n","\n") | 
 |     codestring = codestring.replace("\r","\n") | 
 |     f.close() | 
 |     if codestring and codestring[-1] != '\n': | 
 |         codestring = codestring + '\n' | 
 |     try: | 
 |         codeobject = __builtin__.compile(codestring, dfile or file, 'exec') | 
 |     except SyntaxError, detail: | 
 |         import traceback, sys, string | 
 |         lines = traceback.format_exception_only(SyntaxError, detail) | 
 |         for line in lines: | 
 |             sys.stderr.write(string.replace(line, 'File "<string>"', | 
 |                                             'File "%s"' % (dfile or file))) | 
 |         return | 
 |     if not cfile: | 
 |         cfile = file + (__debug__ and 'c' or 'o') | 
 |     fc = open(cfile, 'wb') | 
 |     fc.write('\0\0\0\0') | 
 |     wr_long(fc, timestamp) | 
 |     marshal.dump(codeobject, fc) | 
 |     fc.flush() | 
 |     fc.seek(0, 0) | 
 |     fc.write(MAGIC) | 
 |     fc.close() | 
 |     if os.name == 'mac': | 
 |         import macfs | 
 |         macfs.FSSpec(cfile).SetCreatorType('Pyth', 'PYC ') |