reduce(): Clarified what is returned in the case of a sequence 1 item long and
initial/default value.
diff --git a/Doc/lib/libfuncs.tex b/Doc/lib/libfuncs.tex
index 5526dc5..1aa59dc 100644
--- a/Doc/lib/libfuncs.tex
+++ b/Doc/lib/libfuncs.tex
@@ -717,12 +717,12 @@
\begin{funcdesc}{reduce}{function, sequence\optional{, initializer}}
Apply \var{function} of two arguments cumulatively to the items of
\var{sequence}, from left to right, so as to reduce the sequence to
- a single value. For example,
- \code{reduce(lambda x, y: x+y, [1, 2, 3, 4, 5])} calculates
- \code{((((1+2)+3)+4)+5)}.
- If the optional \var{initializer} is present, it is placed before
- the items of the sequence in the calculation, and serves as a
- default when the sequence is empty.
+ a single value. For example, \code{reduce(lambda x, y: x+y, [1, 2,
+ 3, 4, 5])} calculates \code{((((1+2)+3)+4)+5)}. If the optional
+ \var{initializer} is present, it is placed before the items of the
+ sequence in the calculation, and serves as a default when the
+ sequence is empty. If \var{initializer} is not given and
+ \var{sequence} contains only one item, the first item is returned.
\end{funcdesc}
\begin{funcdesc}{reload}{module}