On path with known exact float, extract the double with the fast macro. (GH-21072)
(cherry picked from commit 930f4518aea7f3f0f914ce93c3fb92831a7e1d2a)
Co-authored-by: Raymond Hettinger <rhettinger@users.noreply.github.com>
diff --git a/Modules/mathmodule.c b/Modules/mathmodule.c
index f1d59c0..4aa7e65 100644
--- a/Modules/mathmodule.c
+++ b/Modules/mathmodule.c
@@ -1255,9 +1255,15 @@
math_floor(PyObject *module, PyObject *number)
/*[clinic end generated code: output=c6a65c4884884b8a input=63af6b5d7ebcc3d6]*/
{
+ double x;
+
_Py_IDENTIFIER(__floor__);
- if (!PyFloat_CheckExact(number)) {
+ if (PyFloat_CheckExact(number)) {
+ x = PyFloat_AS_DOUBLE(number);
+ }
+ else
+ {
PyObject *method = _PyObject_LookupSpecial(number, &PyId___floor__);
if (method != NULL) {
PyObject *result = _PyObject_CallNoArg(method);
@@ -1266,11 +1272,10 @@
}
if (PyErr_Occurred())
return NULL;
+ x = PyFloat_AsDouble(number);
+ if (x == -1.0 && PyErr_Occurred())
+ return NULL;
}
- double x = PyFloat_AsDouble(number);
- if (x == -1.0 && PyErr_Occurred())
- return NULL;
-
return PyLong_FromDouble(floor(x));
}