commit | 363af8821162f2429f316e505b931365fae0b9f6 | [log] [tgz] |
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author | Jon Dufresne <jon.dufresne@gmail.com> | Sun Sep 16 11:48:54 2018 -0700 |
committer | Jon Dufresne <jon.dufresne@gmail.com> | Sun Sep 16 11:48:54 2018 -0700 |
tree | b5f411971a214a1d5be4fa3780e4a58a2b4cedcd | |
parent | 242b347ba0e155b45909ecbca73da53f67be4030 [diff] |
Correct capitalization of PyPI As spelled on https://pypi.org/.
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
Note that as in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?