commit | 2d7a16070523666795d2e9b31230d05dbb1e91c1 | [log] [tgz] |
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author | Android Build Coastguard Worker <android-build-coastguard-worker@google.com> | Thu Oct 28 17:28:59 2021 +0000 |
committer | Android Build Coastguard Worker <android-build-coastguard-worker@google.com> | Thu Oct 28 17:28:59 2021 +0000 |
tree | 994f7da7a7f4f482fcf3528bbe7ba101c62806b8 | |
parent | dc697dc7e41b5ed89bca2b23629bdf4a9d940583 [diff] | |
parent | 47b0afeb8ac7ffe664258ad1c4e5d0c8fee73512 [diff] |
Snap for 7862349 from 47b0afeb8ac7ffe664258ad1c4e5d0c8fee73512 to t-keystone-qcom-release Change-Id: I5eeccee31ce2b48177b72b192faec29a95d046ea
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals >>> ipaddress.ip_address('1.2.3.4') IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4') IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4') Traceback (most recent call last): File "<stdin>", line 1, in <module> File "ipaddress.py", line 163, in ip_address ' a unicode object?' % address) ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?