tree: 60920c68544e043cb709d7ee2556068f93b97437 [path history] [tgz]
  1. build.generic.cmd
  2. build.VS2010.cmd
  3. build.VS2012.cmd
  4. build.VS2013.cmd
  5. build.VS2015.cmd
  6. README.md
build/VS_scripts/README.md

Command line scripts for Visual Studio compilation without IDE

Here are a few command lines for reference :

Build with Visual Studio 2013 for msvcr120.dll

Running the following command will build both the Release Win32 and Release x64 versions:

build\build.VS2013.cmd

The result of each build will be in the corresponding build\bin\Release\{ARCH}\ folder.

If you want to only need one architecture:

  • Win32: build\build.generic.cmd VS2013 Win32 Release v120
  • x64: build\build.generic.cmd VS2013 x64 Release v120

If you want a Debug build:

  • Win32: build\build.generic.cmd VS2013 Win32 Debug v120
  • x64: build\build.generic.cmd VS2013 x64 Debug v120

Build with Visual Studio 2015 for msvcr140.dll

Running the following command will build both the Release Win32 and Release x64 versions:

build\build.VS2015.cmd

The result of each build will be in the corresponding build\bin\Release\{ARCH}\ folder.

If you want to only need one architecture:

  • Win32: build\build.generic.cmd VS2015 Win32 Release v140
  • x64: build\build.generic.cmd VS2015 x64 Release v140

If you want a Debug build:

  • Win32: build\build.generic.cmd VS2015 Win32 Debug v140
  • x64: build\build.generic.cmd VS2015 x64 Debug v140

Build with Visual Studio 2015 for msvcr120.dll

You need to invoke build\build.generic.cmd with the proper arguments:

For Win32

build\build.generic.cmd VS2015 Win32 Release v120

The result of the build will be in the build\bin\Release\Win32\ folder.

For x64

build\build.generic.cmd VS2015 x64 Release v120

The result of the build will be in the build\bin\Release\x64\ folder.

If you want Debug builds, replace Release with Debug.