InstCombine: Improvement to check if signed addition overflows.

This patch implements two things:

1. If we know one number is positive and another is negative, we return true as
    signed addition of two opposite signed numbers will never overflow.

2. Implemented TODO : If one of the operands only has one non-zero bit, and if
    the other operand has a known-zero bit in a more significant place than it
    (not including the sign bit) the ripple may go up to and fill the zero, but
    won't change the sign. e.x -  (x & ~4) + 1

We make sure that we are ignoring 0 at MSB.

Patch by Suyog Sarda.

llvm-svn: 210186
diff --git a/llvm/test/Transforms/InstCombine/AddOverFlow.ll b/llvm/test/Transforms/InstCombine/AddOverFlow.ll
new file mode 100644
index 0000000..590c65a
--- /dev/null
+++ b/llvm/test/Transforms/InstCombine/AddOverFlow.ll
@@ -0,0 +1,58 @@
+; RUN: opt < %s -instcombine -S | FileCheck %s
+
+target datalayout = "e-m:e-i64:64-f80:128-n8:16:32:64-S128"
+
+; CHECK-LABEL: @oppositesign
+; CHECK: add nsw i16 %a, %b
+define i16 @oppositesign(i16 %x, i16 %y) {
+; %a is negative, %b is positive
+  %a = or i16 %x, 32768
+  %b = and i16 %y, 32767
+  %c = add i16 %a, %b
+  ret i16 %c
+}
+
+; CHECK-LABEL: @ripple_nsw1
+; CHECK: add nsw i16 %a, %b
+define i16 @ripple_nsw1(i16 %x, i16 %y) {
+; %a has at most one bit set
+  %a = and i16 %y, 1
+
+; %b has a 0 bit other than the sign bit
+  %b = and i16 %x, 49151
+
+  %c = add i16 %a, %b
+  ret i16 %c
+}
+
+; Like the previous test, but flip %a and %b
+; CHECK-LABEL: @ripple_nsw2
+; CHECK: add nsw i16 %b, %a
+define i16 @ripple_nsw2(i16 %x, i16 %y) {
+  %a = and i16 %y, 1
+  %b = and i16 %x, 49151
+  %c = add i16 %b, %a
+  ret i16 %c
+}
+
+; CHECK-LABEL: @ripple_no_nsw1
+; CHECK: add i32 %a, %x
+define i32 @ripple_no_nsw1(i32 %x, i32 %y) {
+; We know nothing about %x
+  %a = and i32 %y, 1
+  %b = add i32 %a, %x
+  ret i32 %b
+}
+
+; CHECK-LABEL: @ripple_no_nsw2
+; CHECK: add i16 %a, %b
+define i16 @ripple_no_nsw2(i16 %x, i16 %y) {
+; %a has at most one bit set
+  %a = and i16 %y, 1
+
+; %b has a 0 bit, but it is the sign bit
+  %b = and i16 %x, 32767
+
+  %c = add i16 %a, %b
+  ret i16 %c
+}