AMDGPU: test for uniformity of branch instruction, not its condition
Summary:
If a divergent branch instruction is marked as divergent by propagation
rule 2 in DivergencePropagator::exploreSyncDependency() and its condition
is uniform, that branch would incorrectly be assumed to be uniform.
Reviewers: arsenm, tstellar
Reviewed By: arsenm
Subscribers: kzhuravl, jvesely, wdng, nhaehnle, yaxunl, dstuttard, tpr, t-tye, llvm-commits
Differential Revision: https://reviews.llvm.org/D56331
llvm-svn: 350532
diff --git a/llvm/lib/Target/AMDGPU/AMDGPUAnnotateUniformValues.cpp b/llvm/lib/Target/AMDGPU/AMDGPUAnnotateUniformValues.cpp
index 4e0cc73..f88e3b0 100644
--- a/llvm/lib/Target/AMDGPU/AMDGPUAnnotateUniformValues.cpp
+++ b/llvm/lib/Target/AMDGPU/AMDGPUAnnotateUniformValues.cpp
@@ -117,14 +117,8 @@
}
void AMDGPUAnnotateUniformValues::visitBranchInst(BranchInst &I) {
- if (I.isUnconditional())
- return;
-
- Value *Cond = I.getCondition();
- if (!DA->isUniform(Cond))
- return;
-
- setUniformMetadata(I.getParent()->getTerminator());
+ if (DA->isUniform(&I))
+ setUniformMetadata(I.getParent()->getTerminator());
}
void AMDGPUAnnotateUniformValues::visitLoadInst(LoadInst &I) {