blob: 6f6856534c44bc1866ac954c7d16b92879417787 [file] [log] [blame]
Deepa Dinamanieb9eefe2012-09-24 11:35:01 -07001/* Copyright (c) 2012, The Linux Foundation. All rights reserved.
2 *
3 * Redistribution and use in source and binary forms, with or without
4 * modification, are permitted provided that the following conditions are
5 * met:
6 * * Redistributions of source code must retain the above copyright
7 * notice, this list of conditions and the following disclaimer.
8 * * Redistributions in binary form must reproduce the above
9 * copyright notice, this list of conditions and the following
10 * disclaimer in the documentation and/or other materials provided
11 * with the distribution.
12 * * Neither the name of The Linux Foundation nor the names of its
13 * contributors may be used to endorse or promote products derived
14 * from this software without specific prior written permission.
15 *
16 * THIS SOFTWARE IS PROVIDED "AS IS" AND ANY EXPRESS OR IMPLIED
17 * WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF
18 * MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND NON-INFRINGEMENT
19 * ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR CONTRIBUTORS
20 * BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR
21 * CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF
22 * SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR
23 * BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY,
24 * WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE
25 * OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN
26 * IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
27*/
28
29#include <stdlib.h>
30#include <string.h>
31#include <ctype.h>
32
33int
34itoa(int num, unsigned char* str, int len, int base)
35{
36 int sum = num;
37 int i = 0;
38 int digit;
39
40 if (len == 0)
41 return -1;
42
43 do
44 {
45 digit = sum % base;
46
47 if (digit < 0xA)
48 str[i++] = '0' + digit;
49 else
50 str[i++] = 'A' + digit - 0xA;
51
52 sum /= base;
53
54 }while (sum && (i < (len - 1)));
55
56 if (i == (len - 1) && sum)
57 return -1;
58
59 str[i] = '\0';
60 strrev(str);
61
62 return 0;
63}