Bryan Wu | 1394f03 | 2007-05-06 14:50:22 -0700 | [diff] [blame] | 1 | /* |
| 2 | * File: arch/blackfin/lib/divsi3.S |
| 3 | * Based on: |
| 4 | * Author: |
| 5 | * |
| 6 | * Created: |
| 7 | * Description: 16 / 32 bit signed division. |
| 8 | * Special cases : |
| 9 | * 1) If(numerator == 0) |
| 10 | * return 0 |
| 11 | * 2) If(denominator ==0) |
| 12 | * return positive max = 0x7fffffff |
| 13 | * 3) If(numerator == denominator) |
| 14 | * return 1 |
| 15 | * 4) If(denominator ==1) |
| 16 | * return numerator |
| 17 | * 5) If(denominator == -1) |
| 18 | * return -numerator |
| 19 | * |
| 20 | * Operand : R0 - Numerator (i) |
| 21 | * R1 - Denominator (i) |
| 22 | * R0 - Quotient (o) |
| 23 | * Registers Used : R2-R7,P0-P2 |
| 24 | * |
| 25 | * Modified: |
| 26 | * Copyright 2004-2006 Analog Devices Inc. |
| 27 | * |
| 28 | * Bugs: Enter bugs at http://blackfin.uclinux.org/ |
| 29 | * |
| 30 | * This program is free software; you can redistribute it and/or modify |
| 31 | * it under the terms of the GNU General Public License as published by |
| 32 | * the Free Software Foundation; either version 2 of the License, or |
| 33 | * (at your option) any later version. |
| 34 | * |
| 35 | * This program is distributed in the hope that it will be useful, |
| 36 | * but WITHOUT ANY WARRANTY; without even the implied warranty of |
| 37 | * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the |
| 38 | * GNU General Public License for more details. |
| 39 | * |
| 40 | * You should have received a copy of the GNU General Public License |
| 41 | * along with this program; if not, see the file COPYING, or write |
| 42 | * to the Free Software Foundation, Inc., |
| 43 | * 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA |
| 44 | */ |
| 45 | |
| 46 | .global ___divsi3; |
Mike Frysinger | 51be24c | 2007-06-11 15:31:30 +0800 | [diff] [blame] | 47 | .type ___divsi3, STT_FUNC; |
Bryan Wu | 1394f03 | 2007-05-06 14:50:22 -0700 | [diff] [blame] | 48 | |
| 49 | #ifdef CONFIG_ARITHMETIC_OPS_L1 |
| 50 | .section .l1.text |
| 51 | #else |
| 52 | .text |
| 53 | #endif |
| 54 | |
| 55 | .align 2; |
| 56 | ___divsi3 : |
| 57 | |
| 58 | |
| 59 | R3 = R0 ^ R1; |
| 60 | R0 = ABS R0; |
| 61 | |
| 62 | CC = V; |
| 63 | |
| 64 | r3 = rot r3 by -1; |
| 65 | r1 = abs r1; /* now both positive, r3.30 means "negate result", |
| 66 | ** r3.31 means overflow, add one to result |
| 67 | */ |
| 68 | cc = r0 < r1; |
| 69 | if cc jump .Lret_zero; |
| 70 | r2 = r1 >> 15; |
| 71 | cc = r2; |
| 72 | if cc jump .Lidents; |
| 73 | r2 = r1 << 16; |
| 74 | cc = r2 <= r0; |
| 75 | if cc jump .Lidents; |
| 76 | |
| 77 | DIVS(R0, R1); |
| 78 | DIVQ(R0, R1); |
| 79 | DIVQ(R0, R1); |
| 80 | DIVQ(R0, R1); |
| 81 | DIVQ(R0, R1); |
| 82 | DIVQ(R0, R1); |
| 83 | DIVQ(R0, R1); |
| 84 | DIVQ(R0, R1); |
| 85 | DIVQ(R0, R1); |
| 86 | DIVQ(R0, R1); |
| 87 | DIVQ(R0, R1); |
| 88 | DIVQ(R0, R1); |
| 89 | DIVQ(R0, R1); |
| 90 | DIVQ(R0, R1); |
| 91 | DIVQ(R0, R1); |
| 92 | DIVQ(R0, R1); |
| 93 | DIVQ(R0, R1); |
| 94 | |
| 95 | R0 = R0.L (Z); |
| 96 | r1 = r3 >> 31; /* add overflow issue back in */ |
| 97 | r0 = r0 + r1; |
| 98 | r1 = -r0; |
| 99 | cc = bittst(r3, 30); |
| 100 | if cc r0 = r1; |
| 101 | RTS; |
| 102 | |
| 103 | /* Can't use the primitives. Test common identities. |
| 104 | ** If the identity is true, return the value in R2. |
| 105 | */ |
| 106 | |
| 107 | .Lidents: |
| 108 | CC = R1 == 0; /* check for divide by zero */ |
| 109 | IF CC JUMP .Lident_return; |
| 110 | |
| 111 | CC = R0 == 0; /* check for division of zero */ |
| 112 | IF CC JUMP .Lzero_return; |
| 113 | |
| 114 | CC = R0 == R1; /* check for identical operands */ |
| 115 | IF CC JUMP .Lident_return; |
| 116 | |
| 117 | CC = R1 == 1; /* check for divide by 1 */ |
| 118 | IF CC JUMP .Lident_return; |
| 119 | |
| 120 | R2.L = ONES R1; |
| 121 | R2 = R2.L (Z); |
| 122 | CC = R2 == 1; |
| 123 | IF CC JUMP .Lpower_of_two; |
| 124 | |
| 125 | /* Identities haven't helped either. |
| 126 | ** Perform the full division process. |
| 127 | */ |
| 128 | |
| 129 | P1 = 31; /* Set loop counter */ |
| 130 | |
| 131 | [--SP] = (R7:5); /* Push registers R5-R7 */ |
| 132 | R2 = -R1; |
| 133 | [--SP] = R2; |
| 134 | R2 = R0 << 1; /* R2 lsw of dividend */ |
| 135 | R6 = R0 ^ R1; /* Get sign */ |
| 136 | R5 = R6 >> 31; /* Shift sign to LSB */ |
| 137 | |
| 138 | R0 = 0 ; /* Clear msw partial remainder */ |
| 139 | R2 = R2 | R5; /* Shift quotient bit */ |
| 140 | R6 = R0 ^ R1; /* Get new quotient bit */ |
| 141 | |
| 142 | LSETUP(.Llst,.Llend) LC0 = P1; /* Setup loop */ |
| 143 | .Llst: R7 = R2 >> 31; /* record copy of carry from R2 */ |
| 144 | R2 = R2 << 1; /* Shift 64 bit dividend up by 1 bit */ |
| 145 | R0 = R0 << 1 || R5 = [SP]; |
| 146 | R0 = R0 | R7; /* and add carry */ |
| 147 | CC = R6 < 0; /* Check quotient(AQ) */ |
| 148 | /* we might be subtracting divisor (AQ==0) */ |
| 149 | IF CC R5 = R1; /* or we might be adding divisor (AQ==1)*/ |
| 150 | R0 = R0 + R5; /* do add or subtract, as indicated by AQ */ |
| 151 | R6 = R0 ^ R1; /* Generate next quotient bit */ |
| 152 | R5 = R6 >> 31; |
| 153 | /* Assume AQ==1, shift in zero */ |
| 154 | BITTGL(R5,0); /* tweak AQ to be what we want to shift in */ |
| 155 | .Llend: R2 = R2 + R5; /* and then set shifted-in value to |
| 156 | ** tweaked AQ. |
| 157 | */ |
| 158 | r1 = r3 >> 31; |
| 159 | r2 = r2 + r1; |
| 160 | cc = bittst(r3,30); |
| 161 | r0 = -r2; |
| 162 | if !cc r0 = r2; |
| 163 | SP += 4; |
| 164 | (R7:5)= [SP++]; /* Pop registers R6-R7 */ |
| 165 | RTS; |
| 166 | |
| 167 | .Lident_return: |
| 168 | CC = R1 == 0; /* check for divide by zero => 0x7fffffff */ |
| 169 | R2 = -1 (X); |
| 170 | R2 >>= 1; |
| 171 | IF CC JUMP .Ltrue_ident_return; |
| 172 | |
| 173 | CC = R0 == R1; /* check for identical operands => 1 */ |
| 174 | R2 = 1 (Z); |
| 175 | IF CC JUMP .Ltrue_ident_return; |
| 176 | |
| 177 | R2 = R0; /* assume divide by 1 => numerator */ |
| 178 | /*FALLTHRU*/ |
| 179 | |
| 180 | .Ltrue_ident_return: |
| 181 | R0 = R2; /* Return an identity value */ |
| 182 | R2 = -R2; |
| 183 | CC = bittst(R3,30); |
| 184 | IF CC R0 = R2; |
| 185 | .Lzero_return: |
| 186 | RTS; /* ...including zero */ |
| 187 | |
| 188 | .Lpower_of_two: |
| 189 | /* Y has a single bit set, which means it's a power of two. |
| 190 | ** That means we can perform the division just by shifting |
| 191 | ** X to the right the appropriate number of bits |
| 192 | */ |
| 193 | |
| 194 | /* signbits returns the number of sign bits, minus one. |
| 195 | ** 1=>30, 2=>29, ..., 0x40000000=>0. Which means we need |
| 196 | ** to shift right n-signbits spaces. It also means 0x80000000 |
| 197 | ** is a special case, because that *also* gives a signbits of 0 |
| 198 | */ |
| 199 | |
| 200 | R2 = R0 >> 31; |
| 201 | CC = R1 < 0; |
| 202 | IF CC JUMP .Ltrue_ident_return; |
| 203 | |
| 204 | R1.l = SIGNBITS R1; |
| 205 | R1 = R1.L (Z); |
| 206 | R1 += -30; |
| 207 | R0 = LSHIFT R0 by R1.L; |
| 208 | r1 = r3 >> 31; |
| 209 | r0 = r0 + r1; |
| 210 | R2 = -R0; // negate result if necessary |
| 211 | CC = bittst(R3,30); |
| 212 | IF CC R0 = R2; |
| 213 | RTS; |
| 214 | |
| 215 | .Lret_zero: |
| 216 | R0 = 0; |
| 217 | RTS; |
Mike Frysinger | 51be24c | 2007-06-11 15:31:30 +0800 | [diff] [blame] | 218 | |
| 219 | .size ___divsi3, .-___divsi3 |