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David Howells108b42b2006-03-31 16:00:29 +01001 ============================
2 LINUX KERNEL MEMORY BARRIERS
3 ============================
4
5By: David Howells <dhowells@redhat.com>
David Howells90fddab2010-03-24 09:43:00 +00006 Paul E. McKenney <paulmck@linux.vnet.ibm.com>
David Howells108b42b2006-03-31 16:00:29 +01007
8Contents:
9
10 (*) Abstract memory access model.
11
12 - Device operations.
13 - Guarantees.
14
15 (*) What are memory barriers?
16
17 - Varieties of memory barrier.
18 - What may not be assumed about memory barriers?
19 - Data dependency barriers.
20 - Control dependencies.
21 - SMP barrier pairing.
22 - Examples of memory barrier sequences.
David Howells670bd952006-06-10 09:54:12 -070023 - Read memory barriers vs load speculation.
Paul E. McKenney241e6662011-02-10 16:54:50 -080024 - Transitivity
David Howells108b42b2006-03-31 16:00:29 +010025
26 (*) Explicit kernel barriers.
27
28 - Compiler barrier.
Jarek Poplawski81fc6322007-05-23 13:58:20 -070029 - CPU memory barriers.
David Howells108b42b2006-03-31 16:00:29 +010030 - MMIO write barrier.
31
32 (*) Implicit kernel memory barriers.
33
34 - Locking functions.
35 - Interrupt disabling functions.
David Howells50fa6102009-04-28 15:01:38 +010036 - Sleep and wake-up functions.
David Howells108b42b2006-03-31 16:00:29 +010037 - Miscellaneous functions.
38
39 (*) Inter-CPU locking barrier effects.
40
41 - Locks vs memory accesses.
42 - Locks vs I/O accesses.
43
44 (*) Where are memory barriers needed?
45
46 - Interprocessor interaction.
47 - Atomic operations.
48 - Accessing devices.
49 - Interrupts.
50
51 (*) Kernel I/O barrier effects.
52
53 (*) Assumed minimum execution ordering model.
54
55 (*) The effects of the cpu cache.
56
57 - Cache coherency.
58 - Cache coherency vs DMA.
59 - Cache coherency vs MMIO.
60
61 (*) The things CPUs get up to.
62
63 - And then there's the Alpha.
64
David Howells90fddab2010-03-24 09:43:00 +000065 (*) Example uses.
66
67 - Circular buffers.
68
David Howells108b42b2006-03-31 16:00:29 +010069 (*) References.
70
71
72============================
73ABSTRACT MEMORY ACCESS MODEL
74============================
75
76Consider the following abstract model of the system:
77
78 : :
79 : :
80 : :
81 +-------+ : +--------+ : +-------+
82 | | : | | : | |
83 | | : | | : | |
84 | CPU 1 |<----->| Memory |<----->| CPU 2 |
85 | | : | | : | |
86 | | : | | : | |
87 +-------+ : +--------+ : +-------+
88 ^ : ^ : ^
89 | : | : |
90 | : | : |
91 | : v : |
92 | : +--------+ : |
93 | : | | : |
94 | : | | : |
95 +---------->| Device |<----------+
96 : | | :
97 : | | :
98 : +--------+ :
99 : :
100
101Each CPU executes a program that generates memory access operations. In the
102abstract CPU, memory operation ordering is very relaxed, and a CPU may actually
103perform the memory operations in any order it likes, provided program causality
104appears to be maintained. Similarly, the compiler may also arrange the
105instructions it emits in any order it likes, provided it doesn't affect the
106apparent operation of the program.
107
108So in the above diagram, the effects of the memory operations performed by a
109CPU are perceived by the rest of the system as the operations cross the
110interface between the CPU and rest of the system (the dotted lines).
111
112
113For example, consider the following sequence of events:
114
115 CPU 1 CPU 2
116 =============== ===============
117 { A == 1; B == 2 }
118 A = 3; x = A;
119 B = 4; y = B;
120
121The set of accesses as seen by the memory system in the middle can be arranged
122in 24 different combinations:
123
124 STORE A=3, STORE B=4, x=LOAD A->3, y=LOAD B->4
125 STORE A=3, STORE B=4, y=LOAD B->4, x=LOAD A->3
126 STORE A=3, x=LOAD A->3, STORE B=4, y=LOAD B->4
127 STORE A=3, x=LOAD A->3, y=LOAD B->2, STORE B=4
128 STORE A=3, y=LOAD B->2, STORE B=4, x=LOAD A->3
129 STORE A=3, y=LOAD B->2, x=LOAD A->3, STORE B=4
130 STORE B=4, STORE A=3, x=LOAD A->3, y=LOAD B->4
131 STORE B=4, ...
132 ...
133
134and can thus result in four different combinations of values:
135
136 x == 1, y == 2
137 x == 1, y == 4
138 x == 3, y == 2
139 x == 3, y == 4
140
141
142Furthermore, the stores committed by a CPU to the memory system may not be
143perceived by the loads made by another CPU in the same order as the stores were
144committed.
145
146
147As a further example, consider this sequence of events:
148
149 CPU 1 CPU 2
150 =============== ===============
151 { A == 1, B == 2, C = 3, P == &A, Q == &C }
152 B = 4; Q = P;
153 P = &B D = *Q;
154
155There is an obvious data dependency here, as the value loaded into D depends on
156the address retrieved from P by CPU 2. At the end of the sequence, any of the
157following results are possible:
158
159 (Q == &A) and (D == 1)
160 (Q == &B) and (D == 2)
161 (Q == &B) and (D == 4)
162
163Note that CPU 2 will never try and load C into D because the CPU will load P
164into Q before issuing the load of *Q.
165
166
167DEVICE OPERATIONS
168-----------------
169
170Some devices present their control interfaces as collections of memory
171locations, but the order in which the control registers are accessed is very
172important. For instance, imagine an ethernet card with a set of internal
173registers that are accessed through an address port register (A) and a data
174port register (D). To read internal register 5, the following code might then
175be used:
176
177 *A = 5;
178 x = *D;
179
180but this might show up as either of the following two sequences:
181
182 STORE *A = 5, x = LOAD *D
183 x = LOAD *D, STORE *A = 5
184
185the second of which will almost certainly result in a malfunction, since it set
186the address _after_ attempting to read the register.
187
188
189GUARANTEES
190----------
191
192There are some minimal guarantees that may be expected of a CPU:
193
194 (*) On any given CPU, dependent memory accesses will be issued in order, with
195 respect to itself. This means that for:
196
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800197 ACCESS_ONCE(Q) = P; smp_read_barrier_depends(); D = ACCESS_ONCE(*Q);
David Howells108b42b2006-03-31 16:00:29 +0100198
199 the CPU will issue the following memory operations:
200
201 Q = LOAD P, D = LOAD *Q
202
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800203 and always in that order. On most systems, smp_read_barrier_depends()
204 does nothing, but it is required for DEC Alpha. The ACCESS_ONCE()
205 is required to prevent compiler mischief. Please note that you
206 should normally use something like rcu_dereference() instead of
207 open-coding smp_read_barrier_depends().
David Howells108b42b2006-03-31 16:00:29 +0100208
209 (*) Overlapping loads and stores within a particular CPU will appear to be
210 ordered within that CPU. This means that for:
211
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800212 a = ACCESS_ONCE(*X); ACCESS_ONCE(*X) = b;
David Howells108b42b2006-03-31 16:00:29 +0100213
214 the CPU will only issue the following sequence of memory operations:
215
216 a = LOAD *X, STORE *X = b
217
218 And for:
219
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800220 ACCESS_ONCE(*X) = c; d = ACCESS_ONCE(*X);
David Howells108b42b2006-03-31 16:00:29 +0100221
222 the CPU will only issue:
223
224 STORE *X = c, d = LOAD *X
225
Matt LaPlantefa00e7e2006-11-30 04:55:36 +0100226 (Loads and stores overlap if they are targeted at overlapping pieces of
David Howells108b42b2006-03-31 16:00:29 +0100227 memory).
228
229And there are a number of things that _must_ or _must_not_ be assumed:
230
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800231 (*) It _must_not_ be assumed that the compiler will do what you want with
232 memory references that are not protected by ACCESS_ONCE(). Without
233 ACCESS_ONCE(), the compiler is within its rights to do all sorts
Paul E. McKenney692118d2013-12-11 13:59:07 -0800234 of "creative" transformations, which are covered in the Compiler
235 Barrier section.
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800236
David Howells108b42b2006-03-31 16:00:29 +0100237 (*) It _must_not_ be assumed that independent loads and stores will be issued
238 in the order given. This means that for:
239
240 X = *A; Y = *B; *D = Z;
241
242 we may get any of the following sequences:
243
244 X = LOAD *A, Y = LOAD *B, STORE *D = Z
245 X = LOAD *A, STORE *D = Z, Y = LOAD *B
246 Y = LOAD *B, X = LOAD *A, STORE *D = Z
247 Y = LOAD *B, STORE *D = Z, X = LOAD *A
248 STORE *D = Z, X = LOAD *A, Y = LOAD *B
249 STORE *D = Z, Y = LOAD *B, X = LOAD *A
250
251 (*) It _must_ be assumed that overlapping memory accesses may be merged or
252 discarded. This means that for:
253
254 X = *A; Y = *(A + 4);
255
256 we may get any one of the following sequences:
257
258 X = LOAD *A; Y = LOAD *(A + 4);
259 Y = LOAD *(A + 4); X = LOAD *A;
260 {X, Y} = LOAD {*A, *(A + 4) };
261
262 And for:
263
Paul E. McKenneyf191eec2012-10-03 10:28:30 -0700264 *A = X; *(A + 4) = Y;
David Howells108b42b2006-03-31 16:00:29 +0100265
Paul E. McKenneyf191eec2012-10-03 10:28:30 -0700266 we may get any of:
David Howells108b42b2006-03-31 16:00:29 +0100267
Paul E. McKenneyf191eec2012-10-03 10:28:30 -0700268 STORE *A = X; STORE *(A + 4) = Y;
269 STORE *(A + 4) = Y; STORE *A = X;
270 STORE {*A, *(A + 4) } = {X, Y};
David Howells108b42b2006-03-31 16:00:29 +0100271
272
273=========================
274WHAT ARE MEMORY BARRIERS?
275=========================
276
277As can be seen above, independent memory operations are effectively performed
278in random order, but this can be a problem for CPU-CPU interaction and for I/O.
279What is required is some way of intervening to instruct the compiler and the
280CPU to restrict the order.
281
282Memory barriers are such interventions. They impose a perceived partial
David Howells2b948952006-06-25 05:48:49 -0700283ordering over the memory operations on either side of the barrier.
284
285Such enforcement is important because the CPUs and other devices in a system
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700286can use a variety of tricks to improve performance, including reordering,
David Howells2b948952006-06-25 05:48:49 -0700287deferral and combination of memory operations; speculative loads; speculative
288branch prediction and various types of caching. Memory barriers are used to
289override or suppress these tricks, allowing the code to sanely control the
290interaction of multiple CPUs and/or devices.
David Howells108b42b2006-03-31 16:00:29 +0100291
292
293VARIETIES OF MEMORY BARRIER
294---------------------------
295
296Memory barriers come in four basic varieties:
297
298 (1) Write (or store) memory barriers.
299
300 A write memory barrier gives a guarantee that all the STORE operations
301 specified before the barrier will appear to happen before all the STORE
302 operations specified after the barrier with respect to the other
303 components of the system.
304
305 A write barrier is a partial ordering on stores only; it is not required
306 to have any effect on loads.
307
David Howells6bc39272006-06-25 05:49:22 -0700308 A CPU can be viewed as committing a sequence of store operations to the
David Howells108b42b2006-03-31 16:00:29 +0100309 memory system as time progresses. All stores before a write barrier will
310 occur in the sequence _before_ all the stores after the write barrier.
311
312 [!] Note that write barriers should normally be paired with read or data
313 dependency barriers; see the "SMP barrier pairing" subsection.
314
315
316 (2) Data dependency barriers.
317
318 A data dependency barrier is a weaker form of read barrier. In the case
319 where two loads are performed such that the second depends on the result
320 of the first (eg: the first load retrieves the address to which the second
321 load will be directed), a data dependency barrier would be required to
322 make sure that the target of the second load is updated before the address
323 obtained by the first load is accessed.
324
325 A data dependency barrier is a partial ordering on interdependent loads
326 only; it is not required to have any effect on stores, independent loads
327 or overlapping loads.
328
329 As mentioned in (1), the other CPUs in the system can be viewed as
330 committing sequences of stores to the memory system that the CPU being
331 considered can then perceive. A data dependency barrier issued by the CPU
332 under consideration guarantees that for any load preceding it, if that
333 load touches one of a sequence of stores from another CPU, then by the
334 time the barrier completes, the effects of all the stores prior to that
335 touched by the load will be perceptible to any loads issued after the data
336 dependency barrier.
337
338 See the "Examples of memory barrier sequences" subsection for diagrams
339 showing the ordering constraints.
340
341 [!] Note that the first load really has to have a _data_ dependency and
342 not a control dependency. If the address for the second load is dependent
343 on the first load, but the dependency is through a conditional rather than
344 actually loading the address itself, then it's a _control_ dependency and
345 a full read barrier or better is required. See the "Control dependencies"
346 subsection for more information.
347
348 [!] Note that data dependency barriers should normally be paired with
349 write barriers; see the "SMP barrier pairing" subsection.
350
351
352 (3) Read (or load) memory barriers.
353
354 A read barrier is a data dependency barrier plus a guarantee that all the
355 LOAD operations specified before the barrier will appear to happen before
356 all the LOAD operations specified after the barrier with respect to the
357 other components of the system.
358
359 A read barrier is a partial ordering on loads only; it is not required to
360 have any effect on stores.
361
362 Read memory barriers imply data dependency barriers, and so can substitute
363 for them.
364
365 [!] Note that read barriers should normally be paired with write barriers;
366 see the "SMP barrier pairing" subsection.
367
368
369 (4) General memory barriers.
370
David Howells670bd952006-06-10 09:54:12 -0700371 A general memory barrier gives a guarantee that all the LOAD and STORE
372 operations specified before the barrier will appear to happen before all
373 the LOAD and STORE operations specified after the barrier with respect to
374 the other components of the system.
375
376 A general memory barrier is a partial ordering over both loads and stores.
David Howells108b42b2006-03-31 16:00:29 +0100377
378 General memory barriers imply both read and write memory barriers, and so
379 can substitute for either.
380
381
382And a couple of implicit varieties:
383
384 (5) LOCK operations.
385
386 This acts as a one-way permeable barrier. It guarantees that all memory
387 operations after the LOCK operation will appear to happen after the LOCK
388 operation with respect to the other components of the system.
389
390 Memory operations that occur before a LOCK operation may appear to happen
391 after it completes.
392
393 A LOCK operation should almost always be paired with an UNLOCK operation.
394
395
396 (6) UNLOCK operations.
397
398 This also acts as a one-way permeable barrier. It guarantees that all
399 memory operations before the UNLOCK operation will appear to happen before
400 the UNLOCK operation with respect to the other components of the system.
401
402 Memory operations that occur after an UNLOCK operation may appear to
403 happen before it completes.
404
405 LOCK and UNLOCK operations are guaranteed to appear with respect to each
406 other strictly in the order specified.
407
408 The use of LOCK and UNLOCK operations generally precludes the need for
409 other sorts of memory barrier (but note the exceptions mentioned in the
410 subsection "MMIO write barrier").
411
412
413Memory barriers are only required where there's a possibility of interaction
414between two CPUs or between a CPU and a device. If it can be guaranteed that
415there won't be any such interaction in any particular piece of code, then
416memory barriers are unnecessary in that piece of code.
417
418
419Note that these are the _minimum_ guarantees. Different architectures may give
420more substantial guarantees, but they may _not_ be relied upon outside of arch
421specific code.
422
423
424WHAT MAY NOT BE ASSUMED ABOUT MEMORY BARRIERS?
425----------------------------------------------
426
427There are certain things that the Linux kernel memory barriers do not guarantee:
428
429 (*) There is no guarantee that any of the memory accesses specified before a
430 memory barrier will be _complete_ by the completion of a memory barrier
431 instruction; the barrier can be considered to draw a line in that CPU's
432 access queue that accesses of the appropriate type may not cross.
433
434 (*) There is no guarantee that issuing a memory barrier on one CPU will have
435 any direct effect on another CPU or any other hardware in the system. The
436 indirect effect will be the order in which the second CPU sees the effects
437 of the first CPU's accesses occur, but see the next point:
438
David Howells6bc39272006-06-25 05:49:22 -0700439 (*) There is no guarantee that a CPU will see the correct order of effects
David Howells108b42b2006-03-31 16:00:29 +0100440 from a second CPU's accesses, even _if_ the second CPU uses a memory
441 barrier, unless the first CPU _also_ uses a matching memory barrier (see
442 the subsection on "SMP Barrier Pairing").
443
444 (*) There is no guarantee that some intervening piece of off-the-CPU
445 hardware[*] will not reorder the memory accesses. CPU cache coherency
446 mechanisms should propagate the indirect effects of a memory barrier
447 between CPUs, but might not do so in order.
448
449 [*] For information on bus mastering DMA and coherency please read:
450
Randy Dunlap4b5ff462008-03-10 17:16:32 -0700451 Documentation/PCI/pci.txt
Paul Bolle395cf962011-08-15 02:02:26 +0200452 Documentation/DMA-API-HOWTO.txt
David Howells108b42b2006-03-31 16:00:29 +0100453 Documentation/DMA-API.txt
454
455
456DATA DEPENDENCY BARRIERS
457------------------------
458
459The usage requirements of data dependency barriers are a little subtle, and
460it's not always obvious that they're needed. To illustrate, consider the
461following sequence of events:
462
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800463 CPU 1 CPU 2
464 =============== ===============
David Howells108b42b2006-03-31 16:00:29 +0100465 { A == 1, B == 2, C = 3, P == &A, Q == &C }
466 B = 4;
467 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800468 ACCESS_ONCE(P) = &B
469 Q = ACCESS_ONCE(P);
470 D = *Q;
David Howells108b42b2006-03-31 16:00:29 +0100471
472There's a clear data dependency here, and it would seem that by the end of the
473sequence, Q must be either &A or &B, and that:
474
475 (Q == &A) implies (D == 1)
476 (Q == &B) implies (D == 4)
477
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700478But! CPU 2's perception of P may be updated _before_ its perception of B, thus
David Howells108b42b2006-03-31 16:00:29 +0100479leading to the following situation:
480
481 (Q == &B) and (D == 2) ????
482
483Whilst this may seem like a failure of coherency or causality maintenance, it
484isn't, and this behaviour can be observed on certain real CPUs (such as the DEC
485Alpha).
486
David Howells2b948952006-06-25 05:48:49 -0700487To deal with this, a data dependency barrier or better must be inserted
488between the address load and the data load:
David Howells108b42b2006-03-31 16:00:29 +0100489
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800490 CPU 1 CPU 2
491 =============== ===============
David Howells108b42b2006-03-31 16:00:29 +0100492 { A == 1, B == 2, C = 3, P == &A, Q == &C }
493 B = 4;
494 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800495 ACCESS_ONCE(P) = &B
496 Q = ACCESS_ONCE(P);
497 <data dependency barrier>
498 D = *Q;
David Howells108b42b2006-03-31 16:00:29 +0100499
500This enforces the occurrence of one of the two implications, and prevents the
501third possibility from arising.
502
503[!] Note that this extremely counterintuitive situation arises most easily on
504machines with split caches, so that, for example, one cache bank processes
505even-numbered cache lines and the other bank processes odd-numbered cache
506lines. The pointer P might be stored in an odd-numbered cache line, and the
507variable B might be stored in an even-numbered cache line. Then, if the
508even-numbered bank of the reading CPU's cache is extremely busy while the
509odd-numbered bank is idle, one can see the new value of the pointer P (&B),
David Howells6bc39272006-06-25 05:49:22 -0700510but the old value of the variable B (2).
David Howells108b42b2006-03-31 16:00:29 +0100511
512
Ingo Molnare0edc782013-11-22 11:24:53 +0100513Another example of where data dependency barriers might be required is where a
David Howells108b42b2006-03-31 16:00:29 +0100514number is read from memory and then used to calculate the index for an array
515access:
516
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800517 CPU 1 CPU 2
518 =============== ===============
David Howells108b42b2006-03-31 16:00:29 +0100519 { M[0] == 1, M[1] == 2, M[3] = 3, P == 0, Q == 3 }
520 M[1] = 4;
521 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800522 ACCESS_ONCE(P) = 1
523 Q = ACCESS_ONCE(P);
524 <data dependency barrier>
525 D = M[Q];
David Howells108b42b2006-03-31 16:00:29 +0100526
527
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800528The data dependency barrier is very important to the RCU system,
529for example. See rcu_assign_pointer() and rcu_dereference() in
530include/linux/rcupdate.h. This permits the current target of an RCU'd
531pointer to be replaced with a new modified target, without the replacement
532target appearing to be incompletely initialised.
David Howells108b42b2006-03-31 16:00:29 +0100533
534See also the subsection on "Cache Coherency" for a more thorough example.
535
536
537CONTROL DEPENDENCIES
538--------------------
539
540A control dependency requires a full read memory barrier, not simply a data
541dependency barrier to make it work correctly. Consider the following bit of
542code:
543
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800544 q = ACCESS_ONCE(a);
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800545 if (q) {
546 <data dependency barrier> /* BUG: No data dependency!!! */
547 p = ACCESS_ONCE(b);
Paul E. McKenney45c8a362013-07-02 15:24:09 -0700548 }
David Howells108b42b2006-03-31 16:00:29 +0100549
550This will not have the desired effect because there is no actual data
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800551dependency, but rather a control dependency that the CPU may short-circuit
552by attempting to predict the outcome in advance, so that other CPUs see
553the load from b as having happened before the load from a. In such a
554case what's actually required is:
David Howells108b42b2006-03-31 16:00:29 +0100555
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800556 q = ACCESS_ONCE(a);
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800557 if (q) {
Paul E. McKenney45c8a362013-07-02 15:24:09 -0700558 <read barrier>
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800559 p = ACCESS_ONCE(b);
Paul E. McKenney45c8a362013-07-02 15:24:09 -0700560 }
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800561
562However, stores are not speculated. This means that ordering -is- provided
563in the following example:
564
565 q = ACCESS_ONCE(a);
566 if (ACCESS_ONCE(q)) {
567 ACCESS_ONCE(b) = p;
568 }
569
570Please note that ACCESS_ONCE() is not optional! Without the ACCESS_ONCE(),
571the compiler is within its rights to transform this example:
572
573 q = a;
574 if (q) {
575 b = p; /* BUG: Compiler can reorder!!! */
576 do_something();
577 } else {
578 b = p; /* BUG: Compiler can reorder!!! */
579 do_something_else();
580 }
581
582into this, which of course defeats the ordering:
583
584 b = p;
585 q = a;
586 if (q)
587 do_something();
588 else
589 do_something_else();
590
591Worse yet, if the compiler is able to prove (say) that the value of
592variable 'a' is always non-zero, it would be well within its rights
593to optimize the original example by eliminating the "if" statement
594as follows:
595
596 q = a;
597 b = p; /* BUG: Compiler can reorder!!! */
598 do_something();
599
600The solution is again ACCESS_ONCE(), which preserves the ordering between
601the load from variable 'a' and the store to variable 'b':
602
603 q = ACCESS_ONCE(a);
604 if (q) {
605 ACCESS_ONCE(b) = p;
606 do_something();
607 } else {
608 ACCESS_ONCE(b) = p;
609 do_something_else();
610 }
611
612You could also use barrier() to prevent the compiler from moving
613the stores to variable 'b', but barrier() would not prevent the
614compiler from proving to itself that a==1 always, so ACCESS_ONCE()
615is also needed.
616
617It is important to note that control dependencies absolutely require a
618a conditional. For example, the following "optimized" version of
619the above example breaks ordering:
620
621 q = ACCESS_ONCE(a);
622 ACCESS_ONCE(b) = p; /* BUG: No ordering vs. load from a!!! */
623 if (q) {
624 /* ACCESS_ONCE(b) = p; -- moved up, BUG!!! */
625 do_something();
626 } else {
627 /* ACCESS_ONCE(b) = p; -- moved up, BUG!!! */
628 do_something_else();
629 }
630
631It is of course legal for the prior load to be part of the conditional,
632for example, as follows:
633
634 if (ACCESS_ONCE(a) > 0) {
635 ACCESS_ONCE(b) = q / 2;
636 do_something();
637 } else {
638 ACCESS_ONCE(b) = q / 3;
639 do_something_else();
640 }
641
642This will again ensure that the load from variable 'a' is ordered before the
643stores to variable 'b'.
644
645In addition, you need to be careful what you do with the local variable 'q',
646otherwise the compiler might be able to guess the value and again remove
647the needed conditional. For example:
648
649 q = ACCESS_ONCE(a);
650 if (q % MAX) {
651 ACCESS_ONCE(b) = p;
652 do_something();
653 } else {
654 ACCESS_ONCE(b) = p;
655 do_something_else();
656 }
657
658If MAX is defined to be 1, then the compiler knows that (q % MAX) is
659equal to zero, in which case the compiler is within its rights to
660transform the above code into the following:
661
662 q = ACCESS_ONCE(a);
663 ACCESS_ONCE(b) = p;
664 do_something_else();
665
666This transformation loses the ordering between the load from variable 'a'
667and the store to variable 'b'. If you are relying on this ordering, you
668should do something like the following:
669
670 q = ACCESS_ONCE(a);
671 BUILD_BUG_ON(MAX <= 1); /* Order load from a with store to b. */
672 if (q % MAX) {
673 ACCESS_ONCE(b) = p;
674 do_something();
675 } else {
676 ACCESS_ONCE(b) = p;
677 do_something_else();
678 }
679
680Finally, control dependencies do -not- provide transitivity. This is
681demonstrated by two related examples:
682
683 CPU 0 CPU 1
684 ===================== =====================
685 r1 = ACCESS_ONCE(x); r2 = ACCESS_ONCE(y);
686 if (r1 >= 0) if (r2 >= 0)
687 ACCESS_ONCE(y) = 1; ACCESS_ONCE(x) = 1;
688
689 assert(!(r1 == 1 && r2 == 1));
690
691The above two-CPU example will never trigger the assert(). However,
692if control dependencies guaranteed transitivity (which they do not),
693then adding the following two CPUs would guarantee a related assertion:
694
695 CPU 2 CPU 3
696 ===================== =====================
697 ACCESS_ONCE(x) = 2; ACCESS_ONCE(y) = 2;
698
699 assert(!(r1 == 2 && r2 == 2 && x == 1 && y == 1)); /* FAILS!!! */
700
701But because control dependencies do -not- provide transitivity, the
702above assertion can fail after the combined four-CPU example completes.
703If you need the four-CPU example to provide ordering, you will need
704smp_mb() between the loads and stores in the CPU 0 and CPU 1 code fragments.
705
706In summary:
707
708 (*) Control dependencies can order prior loads against later stores.
709 However, they do -not- guarantee any other sort of ordering:
710 Not prior loads against later loads, nor prior stores against
711 later anything. If you need these other forms of ordering,
712 use smb_rmb(), smp_wmb(), or, in the case of prior stores and
713 later loads, smp_mb().
714
715 (*) Control dependencies require at least one run-time conditional
716 between the prior load and the subsequent store. If the compiler
717 is able to optimize the conditional away, it will have also
718 optimized away the ordering. Careful use of ACCESS_ONCE() can
719 help to preserve the needed conditional.
720
721 (*) Control dependencies require that the compiler avoid reordering the
722 dependency into nonexistence. Careful use of ACCESS_ONCE() or
Paul E. McKenney692118d2013-12-11 13:59:07 -0800723 barrier() can help to preserve your control dependency. Please
724 see the Compiler Barrier section for more information.
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800725
726 (*) Control dependencies do -not- provide transitivity. If you
727 need transitivity, use smp_mb().
David Howells108b42b2006-03-31 16:00:29 +0100728
729
730SMP BARRIER PAIRING
731-------------------
732
733When dealing with CPU-CPU interactions, certain types of memory barrier should
734always be paired. A lack of appropriate pairing is almost certainly an error.
735
736A write barrier should always be paired with a data dependency barrier or read
737barrier, though a general barrier would also be viable. Similarly a read
738barrier or a data dependency barrier should always be paired with at least an
739write barrier, though, again, a general barrier is viable:
740
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800741 CPU 1 CPU 2
742 =============== ===============
743 ACCESS_ONCE(a) = 1;
David Howells108b42b2006-03-31 16:00:29 +0100744 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800745 ACCESS_ONCE(b) = 2; x = ACCESS_ONCE(b);
746 <read barrier>
747 y = ACCESS_ONCE(a);
David Howells108b42b2006-03-31 16:00:29 +0100748
749Or:
750
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800751 CPU 1 CPU 2
752 =============== ===============================
David Howells108b42b2006-03-31 16:00:29 +0100753 a = 1;
754 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800755 ACCESS_ONCE(b) = &a; x = ACCESS_ONCE(b);
756 <data dependency barrier>
757 y = *x;
David Howells108b42b2006-03-31 16:00:29 +0100758
759Basically, the read barrier always has to be there, even though it can be of
760the "weaker" type.
761
David Howells670bd952006-06-10 09:54:12 -0700762[!] Note that the stores before the write barrier would normally be expected to
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700763match the loads after the read barrier or the data dependency barrier, and vice
David Howells670bd952006-06-10 09:54:12 -0700764versa:
765
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800766 CPU 1 CPU 2
767 =================== ===================
768 ACCESS_ONCE(a) = 1; }---- --->{ v = ACCESS_ONCE(c);
769 ACCESS_ONCE(b) = 2; } \ / { w = ACCESS_ONCE(d);
770 <write barrier> \ <read barrier>
771 ACCESS_ONCE(c) = 3; } / \ { x = ACCESS_ONCE(a);
772 ACCESS_ONCE(d) = 4; }---- --->{ y = ACCESS_ONCE(b);
David Howells670bd952006-06-10 09:54:12 -0700773
David Howells108b42b2006-03-31 16:00:29 +0100774
775EXAMPLES OF MEMORY BARRIER SEQUENCES
776------------------------------------
777
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700778Firstly, write barriers act as partial orderings on store operations.
David Howells108b42b2006-03-31 16:00:29 +0100779Consider the following sequence of events:
780
781 CPU 1
782 =======================
783 STORE A = 1
784 STORE B = 2
785 STORE C = 3
786 <write barrier>
787 STORE D = 4
788 STORE E = 5
789
790This sequence of events is committed to the memory coherence system in an order
791that the rest of the system might perceive as the unordered set of { STORE A,
Adrian Bunk80f72282006-06-30 18:27:16 +0200792STORE B, STORE C } all occurring before the unordered set of { STORE D, STORE E
David Howells108b42b2006-03-31 16:00:29 +0100793}:
794
795 +-------+ : :
796 | | +------+
797 | |------>| C=3 | } /\
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700798 | | : +------+ }----- \ -----> Events perceptible to
799 | | : | A=1 | } \/ the rest of the system
David Howells108b42b2006-03-31 16:00:29 +0100800 | | : +------+ }
801 | CPU 1 | : | B=2 | }
802 | | +------+ }
803 | | wwwwwwwwwwwwwwww } <--- At this point the write barrier
804 | | +------+ } requires all stores prior to the
805 | | : | E=5 | } barrier to be committed before
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700806 | | : +------+ } further stores may take place
David Howells108b42b2006-03-31 16:00:29 +0100807 | |------>| D=4 | }
808 | | +------+
809 +-------+ : :
810 |
David Howells670bd952006-06-10 09:54:12 -0700811 | Sequence in which stores are committed to the
812 | memory system by CPU 1
David Howells108b42b2006-03-31 16:00:29 +0100813 V
814
815
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700816Secondly, data dependency barriers act as partial orderings on data-dependent
David Howells108b42b2006-03-31 16:00:29 +0100817loads. Consider the following sequence of events:
818
819 CPU 1 CPU 2
820 ======================= =======================
David Howellsc14038c2006-04-10 22:54:24 -0700821 { B = 7; X = 9; Y = 8; C = &Y }
David Howells108b42b2006-03-31 16:00:29 +0100822 STORE A = 1
823 STORE B = 2
824 <write barrier>
825 STORE C = &B LOAD X
826 STORE D = 4 LOAD C (gets &B)
827 LOAD *C (reads B)
828
829Without intervention, CPU 2 may perceive the events on CPU 1 in some
830effectively random order, despite the write barrier issued by CPU 1:
831
832 +-------+ : : : :
833 | | +------+ +-------+ | Sequence of update
834 | |------>| B=2 |----- --->| Y->8 | | of perception on
835 | | : +------+ \ +-------+ | CPU 2
836 | CPU 1 | : | A=1 | \ --->| C->&Y | V
837 | | +------+ | +-------+
838 | | wwwwwwwwwwwwwwww | : :
839 | | +------+ | : :
840 | | : | C=&B |--- | : : +-------+
841 | | : +------+ \ | +-------+ | |
842 | |------>| D=4 | ----------->| C->&B |------>| |
843 | | +------+ | +-------+ | |
844 +-------+ : : | : : | |
845 | : : | |
846 | : : | CPU 2 |
847 | +-------+ | |
848 Apparently incorrect ---> | | B->7 |------>| |
849 perception of B (!) | +-------+ | |
850 | : : | |
851 | +-------+ | |
852 The load of X holds ---> \ | X->9 |------>| |
853 up the maintenance \ +-------+ | |
854 of coherence of B ----->| B->2 | +-------+
855 +-------+
856 : :
857
858
859In the above example, CPU 2 perceives that B is 7, despite the load of *C
Paolo Ornati670e9f32006-10-03 22:57:56 +0200860(which would be B) coming after the LOAD of C.
David Howells108b42b2006-03-31 16:00:29 +0100861
862If, however, a data dependency barrier were to be placed between the load of C
David Howellsc14038c2006-04-10 22:54:24 -0700863and the load of *C (ie: B) on CPU 2:
864
865 CPU 1 CPU 2
866 ======================= =======================
867 { B = 7; X = 9; Y = 8; C = &Y }
868 STORE A = 1
869 STORE B = 2
870 <write barrier>
871 STORE C = &B LOAD X
872 STORE D = 4 LOAD C (gets &B)
873 <data dependency barrier>
874 LOAD *C (reads B)
875
876then the following will occur:
David Howells108b42b2006-03-31 16:00:29 +0100877
878 +-------+ : : : :
879 | | +------+ +-------+
880 | |------>| B=2 |----- --->| Y->8 |
881 | | : +------+ \ +-------+
882 | CPU 1 | : | A=1 | \ --->| C->&Y |
883 | | +------+ | +-------+
884 | | wwwwwwwwwwwwwwww | : :
885 | | +------+ | : :
886 | | : | C=&B |--- | : : +-------+
887 | | : +------+ \ | +-------+ | |
888 | |------>| D=4 | ----------->| C->&B |------>| |
889 | | +------+ | +-------+ | |
890 +-------+ : : | : : | |
891 | : : | |
892 | : : | CPU 2 |
893 | +-------+ | |
David Howells670bd952006-06-10 09:54:12 -0700894 | | X->9 |------>| |
895 | +-------+ | |
896 Makes sure all effects ---> \ ddddddddddddddddd | |
897 prior to the store of C \ +-------+ | |
898 are perceptible to ----->| B->2 |------>| |
899 subsequent loads +-------+ | |
David Howells108b42b2006-03-31 16:00:29 +0100900 : : +-------+
901
902
903And thirdly, a read barrier acts as a partial order on loads. Consider the
904following sequence of events:
905
906 CPU 1 CPU 2
907 ======================= =======================
David Howells670bd952006-06-10 09:54:12 -0700908 { A = 0, B = 9 }
David Howells108b42b2006-03-31 16:00:29 +0100909 STORE A=1
David Howells108b42b2006-03-31 16:00:29 +0100910 <write barrier>
David Howells670bd952006-06-10 09:54:12 -0700911 STORE B=2
David Howells108b42b2006-03-31 16:00:29 +0100912 LOAD B
David Howells670bd952006-06-10 09:54:12 -0700913 LOAD A
David Howells108b42b2006-03-31 16:00:29 +0100914
915Without intervention, CPU 2 may then choose to perceive the events on CPU 1 in
916some effectively random order, despite the write barrier issued by CPU 1:
917
David Howells670bd952006-06-10 09:54:12 -0700918 +-------+ : : : :
919 | | +------+ +-------+
920 | |------>| A=1 |------ --->| A->0 |
921 | | +------+ \ +-------+
922 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 |
923 | | +------+ | +-------+
924 | |------>| B=2 |--- | : :
925 | | +------+ \ | : : +-------+
926 +-------+ : : \ | +-------+ | |
927 ---------->| B->2 |------>| |
928 | +-------+ | CPU 2 |
929 | | A->0 |------>| |
930 | +-------+ | |
931 | : : +-------+
932 \ : :
933 \ +-------+
934 ---->| A->1 |
935 +-------+
936 : :
David Howells108b42b2006-03-31 16:00:29 +0100937
938
David Howells6bc39272006-06-25 05:49:22 -0700939If, however, a read barrier were to be placed between the load of B and the
David Howells670bd952006-06-10 09:54:12 -0700940load of A on CPU 2:
David Howells108b42b2006-03-31 16:00:29 +0100941
David Howells670bd952006-06-10 09:54:12 -0700942 CPU 1 CPU 2
943 ======================= =======================
944 { A = 0, B = 9 }
945 STORE A=1
946 <write barrier>
947 STORE B=2
948 LOAD B
949 <read barrier>
950 LOAD A
951
952then the partial ordering imposed by CPU 1 will be perceived correctly by CPU
9532:
954
955 +-------+ : : : :
956 | | +------+ +-------+
957 | |------>| A=1 |------ --->| A->0 |
958 | | +------+ \ +-------+
959 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 |
960 | | +------+ | +-------+
961 | |------>| B=2 |--- | : :
962 | | +------+ \ | : : +-------+
963 +-------+ : : \ | +-------+ | |
964 ---------->| B->2 |------>| |
965 | +-------+ | CPU 2 |
966 | : : | |
967 | : : | |
968 At this point the read ----> \ rrrrrrrrrrrrrrrrr | |
969 barrier causes all effects \ +-------+ | |
970 prior to the storage of B ---->| A->1 |------>| |
971 to be perceptible to CPU 2 +-------+ | |
972 : : +-------+
973
974
975To illustrate this more completely, consider what could happen if the code
976contained a load of A either side of the read barrier:
977
978 CPU 1 CPU 2
979 ======================= =======================
980 { A = 0, B = 9 }
981 STORE A=1
982 <write barrier>
983 STORE B=2
984 LOAD B
985 LOAD A [first load of A]
986 <read barrier>
987 LOAD A [second load of A]
988
989Even though the two loads of A both occur after the load of B, they may both
990come up with different values:
991
992 +-------+ : : : :
993 | | +------+ +-------+
994 | |------>| A=1 |------ --->| A->0 |
995 | | +------+ \ +-------+
996 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 |
997 | | +------+ | +-------+
998 | |------>| B=2 |--- | : :
999 | | +------+ \ | : : +-------+
1000 +-------+ : : \ | +-------+ | |
1001 ---------->| B->2 |------>| |
1002 | +-------+ | CPU 2 |
1003 | : : | |
1004 | : : | |
1005 | +-------+ | |
1006 | | A->0 |------>| 1st |
1007 | +-------+ | |
1008 At this point the read ----> \ rrrrrrrrrrrrrrrrr | |
1009 barrier causes all effects \ +-------+ | |
1010 prior to the storage of B ---->| A->1 |------>| 2nd |
1011 to be perceptible to CPU 2 +-------+ | |
1012 : : +-------+
1013
1014
1015But it may be that the update to A from CPU 1 becomes perceptible to CPU 2
1016before the read barrier completes anyway:
1017
1018 +-------+ : : : :
1019 | | +------+ +-------+
1020 | |------>| A=1 |------ --->| A->0 |
1021 | | +------+ \ +-------+
1022 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 |
1023 | | +------+ | +-------+
1024 | |------>| B=2 |--- | : :
1025 | | +------+ \ | : : +-------+
1026 +-------+ : : \ | +-------+ | |
1027 ---------->| B->2 |------>| |
1028 | +-------+ | CPU 2 |
1029 | : : | |
1030 \ : : | |
1031 \ +-------+ | |
1032 ---->| A->1 |------>| 1st |
1033 +-------+ | |
1034 rrrrrrrrrrrrrrrrr | |
1035 +-------+ | |
1036 | A->1 |------>| 2nd |
1037 +-------+ | |
1038 : : +-------+
1039
1040
1041The guarantee is that the second load will always come up with A == 1 if the
1042load of B came up with B == 2. No such guarantee exists for the first load of
1043A; that may come up with either A == 0 or A == 1.
1044
1045
1046READ MEMORY BARRIERS VS LOAD SPECULATION
1047----------------------------------------
1048
1049Many CPUs speculate with loads: that is they see that they will need to load an
1050item from memory, and they find a time where they're not using the bus for any
1051other loads, and so do the load in advance - even though they haven't actually
1052got to that point in the instruction execution flow yet. This permits the
1053actual load instruction to potentially complete immediately because the CPU
1054already has the value to hand.
1055
1056It may turn out that the CPU didn't actually need the value - perhaps because a
1057branch circumvented the load - in which case it can discard the value or just
1058cache it for later use.
1059
1060Consider:
1061
Ingo Molnare0edc782013-11-22 11:24:53 +01001062 CPU 1 CPU 2
David Howells670bd952006-06-10 09:54:12 -07001063 ======================= =======================
Ingo Molnare0edc782013-11-22 11:24:53 +01001064 LOAD B
1065 DIVIDE } Divide instructions generally
1066 DIVIDE } take a long time to perform
1067 LOAD A
David Howells670bd952006-06-10 09:54:12 -07001068
1069Which might appear as this:
1070
1071 : : +-------+
1072 +-------+ | |
1073 --->| B->2 |------>| |
1074 +-------+ | CPU 2 |
1075 : :DIVIDE | |
1076 +-------+ | |
1077 The CPU being busy doing a ---> --->| A->0 |~~~~ | |
1078 division speculates on the +-------+ ~ | |
1079 LOAD of A : : ~ | |
1080 : :DIVIDE | |
1081 : : ~ | |
1082 Once the divisions are complete --> : : ~-->| |
1083 the CPU can then perform the : : | |
1084 LOAD with immediate effect : : +-------+
1085
1086
1087Placing a read barrier or a data dependency barrier just before the second
1088load:
1089
Ingo Molnare0edc782013-11-22 11:24:53 +01001090 CPU 1 CPU 2
David Howells670bd952006-06-10 09:54:12 -07001091 ======================= =======================
Ingo Molnare0edc782013-11-22 11:24:53 +01001092 LOAD B
1093 DIVIDE
1094 DIVIDE
David Howells670bd952006-06-10 09:54:12 -07001095 <read barrier>
Ingo Molnare0edc782013-11-22 11:24:53 +01001096 LOAD A
David Howells670bd952006-06-10 09:54:12 -07001097
1098will force any value speculatively obtained to be reconsidered to an extent
1099dependent on the type of barrier used. If there was no change made to the
1100speculated memory location, then the speculated value will just be used:
1101
1102 : : +-------+
1103 +-------+ | |
1104 --->| B->2 |------>| |
1105 +-------+ | CPU 2 |
1106 : :DIVIDE | |
1107 +-------+ | |
1108 The CPU being busy doing a ---> --->| A->0 |~~~~ | |
1109 division speculates on the +-------+ ~ | |
1110 LOAD of A : : ~ | |
1111 : :DIVIDE | |
1112 : : ~ | |
1113 : : ~ | |
1114 rrrrrrrrrrrrrrrr~ | |
1115 : : ~ | |
1116 : : ~-->| |
1117 : : | |
1118 : : +-------+
1119
1120
1121but if there was an update or an invalidation from another CPU pending, then
1122the speculation will be cancelled and the value reloaded:
1123
1124 : : +-------+
1125 +-------+ | |
1126 --->| B->2 |------>| |
1127 +-------+ | CPU 2 |
1128 : :DIVIDE | |
1129 +-------+ | |
1130 The CPU being busy doing a ---> --->| A->0 |~~~~ | |
1131 division speculates on the +-------+ ~ | |
1132 LOAD of A : : ~ | |
1133 : :DIVIDE | |
1134 : : ~ | |
1135 : : ~ | |
1136 rrrrrrrrrrrrrrrrr | |
1137 +-------+ | |
1138 The speculation is discarded ---> --->| A->1 |------>| |
1139 and an updated value is +-------+ | |
1140 retrieved : : +-------+
David Howells108b42b2006-03-31 16:00:29 +01001141
1142
Paul E. McKenney241e6662011-02-10 16:54:50 -08001143TRANSITIVITY
1144------------
1145
1146Transitivity is a deeply intuitive notion about ordering that is not
1147always provided by real computer systems. The following example
1148demonstrates transitivity (also called "cumulativity"):
1149
1150 CPU 1 CPU 2 CPU 3
1151 ======================= ======================= =======================
1152 { X = 0, Y = 0 }
1153 STORE X=1 LOAD X STORE Y=1
1154 <general barrier> <general barrier>
1155 LOAD Y LOAD X
1156
1157Suppose that CPU 2's load from X returns 1 and its load from Y returns 0.
1158This indicates that CPU 2's load from X in some sense follows CPU 1's
1159store to X and that CPU 2's load from Y in some sense preceded CPU 3's
1160store to Y. The question is then "Can CPU 3's load from X return 0?"
1161
1162Because CPU 2's load from X in some sense came after CPU 1's store, it
1163is natural to expect that CPU 3's load from X must therefore return 1.
1164This expectation is an example of transitivity: if a load executing on
1165CPU A follows a load from the same variable executing on CPU B, then
1166CPU A's load must either return the same value that CPU B's load did,
1167or must return some later value.
1168
1169In the Linux kernel, use of general memory barriers guarantees
1170transitivity. Therefore, in the above example, if CPU 2's load from X
1171returns 1 and its load from Y returns 0, then CPU 3's load from X must
1172also return 1.
1173
1174However, transitivity is -not- guaranteed for read or write barriers.
1175For example, suppose that CPU 2's general barrier in the above example
1176is changed to a read barrier as shown below:
1177
1178 CPU 1 CPU 2 CPU 3
1179 ======================= ======================= =======================
1180 { X = 0, Y = 0 }
1181 STORE X=1 LOAD X STORE Y=1
1182 <read barrier> <general barrier>
1183 LOAD Y LOAD X
1184
1185This substitution destroys transitivity: in this example, it is perfectly
1186legal for CPU 2's load from X to return 1, its load from Y to return 0,
1187and CPU 3's load from X to return 0.
1188
1189The key point is that although CPU 2's read barrier orders its pair
1190of loads, it does not guarantee to order CPU 1's store. Therefore, if
1191this example runs on a system where CPUs 1 and 2 share a store buffer
1192or a level of cache, CPU 2 might have early access to CPU 1's writes.
1193General barriers are therefore required to ensure that all CPUs agree
1194on the combined order of CPU 1's and CPU 2's accesses.
1195
1196To reiterate, if your code requires transitivity, use general barriers
1197throughout.
1198
1199
David Howells108b42b2006-03-31 16:00:29 +01001200========================
1201EXPLICIT KERNEL BARRIERS
1202========================
1203
1204The Linux kernel has a variety of different barriers that act at different
1205levels:
1206
1207 (*) Compiler barrier.
1208
1209 (*) CPU memory barriers.
1210
1211 (*) MMIO write barrier.
1212
1213
1214COMPILER BARRIER
1215----------------
1216
1217The Linux kernel has an explicit compiler barrier function that prevents the
1218compiler from moving the memory accesses either side of it to the other side:
1219
1220 barrier();
1221
Peter Zijlstra18c03c62013-12-11 13:59:06 -08001222This is a general barrier -- there are no read-read or write-write variants
Paul E. McKenney692118d2013-12-11 13:59:07 -08001223of barrier(). However, ACCESS_ONCE() can be thought of as a weak form
Peter Zijlstra18c03c62013-12-11 13:59:06 -08001224for barrier() that affects only the specific accesses flagged by the
1225ACCESS_ONCE().
David Howells108b42b2006-03-31 16:00:29 +01001226
Paul E. McKenney692118d2013-12-11 13:59:07 -08001227The barrier() function has the following effects:
1228
1229 (*) Prevents the compiler from reordering accesses following the
1230 barrier() to precede any accesses preceding the barrier().
1231 One example use for this property is to ease communication between
1232 interrupt-handler code and the code that was interrupted.
1233
1234 (*) Within a loop, forces the compiler to load the variables used
1235 in that loop's conditional on each pass through that loop.
1236
1237The ACCESS_ONCE() function can prevent any number of optimizations that,
1238while perfectly safe in single-threaded code, can be fatal in concurrent
1239code. Here are some examples of these sorts of optimizations:
1240
1241 (*) The compiler is within its rights to merge successive loads from
1242 the same variable. Such merging can cause the compiler to "optimize"
1243 the following code:
1244
1245 while (tmp = a)
1246 do_something_with(tmp);
1247
1248 into the following code, which, although in some sense legitimate
1249 for single-threaded code, is almost certainly not what the developer
1250 intended:
1251
1252 if (tmp = a)
1253 for (;;)
1254 do_something_with(tmp);
1255
1256 Use ACCESS_ONCE() to prevent the compiler from doing this to you:
1257
1258 while (tmp = ACCESS_ONCE(a))
1259 do_something_with(tmp);
1260
1261 (*) The compiler is within its rights to reload a variable, for example,
1262 in cases where high register pressure prevents the compiler from
1263 keeping all data of interest in registers. The compiler might
1264 therefore optimize the variable 'tmp' out of our previous example:
1265
1266 while (tmp = a)
1267 do_something_with(tmp);
1268
1269 This could result in the following code, which is perfectly safe in
1270 single-threaded code, but can be fatal in concurrent code:
1271
1272 while (a)
1273 do_something_with(a);
1274
1275 For example, the optimized version of this code could result in
1276 passing a zero to do_something_with() in the case where the variable
1277 a was modified by some other CPU between the "while" statement and
1278 the call to do_something_with().
1279
1280 Again, use ACCESS_ONCE() to prevent the compiler from doing this:
1281
1282 while (tmp = ACCESS_ONCE(a))
1283 do_something_with(tmp);
1284
1285 Note that if the compiler runs short of registers, it might save
1286 tmp onto the stack. The overhead of this saving and later restoring
1287 is why compilers reload variables. Doing so is perfectly safe for
1288 single-threaded code, so you need to tell the compiler about cases
1289 where it is not safe.
1290
1291 (*) The compiler is within its rights to omit a load entirely if it knows
1292 what the value will be. For example, if the compiler can prove that
1293 the value of variable 'a' is always zero, it can optimize this code:
1294
1295 while (tmp = a)
1296 do_something_with(tmp);
1297
1298 Into this:
1299
1300 do { } while (0);
1301
1302 This transformation is a win for single-threaded code because it gets
1303 rid of a load and a branch. The problem is that the compiler will
1304 carry out its proof assuming that the current CPU is the only one
1305 updating variable 'a'. If variable 'a' is shared, then the compiler's
1306 proof will be erroneous. Use ACCESS_ONCE() to tell the compiler
1307 that it doesn't know as much as it thinks it does:
1308
1309 while (tmp = ACCESS_ONCE(a))
1310 do_something_with(tmp);
1311
1312 But please note that the compiler is also closely watching what you
1313 do with the value after the ACCESS_ONCE(). For example, suppose you
1314 do the following and MAX is a preprocessor macro with the value 1:
1315
1316 while ((tmp = ACCESS_ONCE(a)) % MAX)
1317 do_something_with(tmp);
1318
1319 Then the compiler knows that the result of the "%" operator applied
1320 to MAX will always be zero, again allowing the compiler to optimize
1321 the code into near-nonexistence. (It will still load from the
1322 variable 'a'.)
1323
1324 (*) Similarly, the compiler is within its rights to omit a store entirely
1325 if it knows that the variable already has the value being stored.
1326 Again, the compiler assumes that the current CPU is the only one
1327 storing into the variable, which can cause the compiler to do the
1328 wrong thing for shared variables. For example, suppose you have
1329 the following:
1330
1331 a = 0;
1332 /* Code that does not store to variable a. */
1333 a = 0;
1334
1335 The compiler sees that the value of variable 'a' is already zero, so
1336 it might well omit the second store. This would come as a fatal
1337 surprise if some other CPU might have stored to variable 'a' in the
1338 meantime.
1339
1340 Use ACCESS_ONCE() to prevent the compiler from making this sort of
1341 wrong guess:
1342
1343 ACCESS_ONCE(a) = 0;
1344 /* Code that does not store to variable a. */
1345 ACCESS_ONCE(a) = 0;
1346
1347 (*) The compiler is within its rights to reorder memory accesses unless
1348 you tell it not to. For example, consider the following interaction
1349 between process-level code and an interrupt handler:
1350
1351 void process_level(void)
1352 {
1353 msg = get_message();
1354 flag = true;
1355 }
1356
1357 void interrupt_handler(void)
1358 {
1359 if (flag)
1360 process_message(msg);
1361 }
1362
1363 There is nothing to prevent the the compiler from transforming
1364 process_level() to the following, in fact, this might well be a
1365 win for single-threaded code:
1366
1367 void process_level(void)
1368 {
1369 flag = true;
1370 msg = get_message();
1371 }
1372
1373 If the interrupt occurs between these two statement, then
1374 interrupt_handler() might be passed a garbled msg. Use ACCESS_ONCE()
1375 to prevent this as follows:
1376
1377 void process_level(void)
1378 {
1379 ACCESS_ONCE(msg) = get_message();
1380 ACCESS_ONCE(flag) = true;
1381 }
1382
1383 void interrupt_handler(void)
1384 {
1385 if (ACCESS_ONCE(flag))
1386 process_message(ACCESS_ONCE(msg));
1387 }
1388
1389 Note that the ACCESS_ONCE() wrappers in interrupt_handler()
1390 are needed if this interrupt handler can itself be interrupted
1391 by something that also accesses 'flag' and 'msg', for example,
1392 a nested interrupt or an NMI. Otherwise, ACCESS_ONCE() is not
1393 needed in interrupt_handler() other than for documentation purposes.
1394 (Note also that nested interrupts do not typically occur in modern
1395 Linux kernels, in fact, if an interrupt handler returns with
1396 interrupts enabled, you will get a WARN_ONCE() splat.)
1397
1398 You should assume that the compiler can move ACCESS_ONCE() past
1399 code not containing ACCESS_ONCE(), barrier(), or similar primitives.
1400
1401 This effect could also be achieved using barrier(), but ACCESS_ONCE()
1402 is more selective: With ACCESS_ONCE(), the compiler need only forget
1403 the contents of the indicated memory locations, while with barrier()
1404 the compiler must discard the value of all memory locations that
1405 it has currented cached in any machine registers. Of course,
1406 the compiler must also respect the order in which the ACCESS_ONCE()s
1407 occur, though the CPU of course need not do so.
1408
1409 (*) The compiler is within its rights to invent stores to a variable,
1410 as in the following example:
1411
1412 if (a)
1413 b = a;
1414 else
1415 b = 42;
1416
1417 The compiler might save a branch by optimizing this as follows:
1418
1419 b = 42;
1420 if (a)
1421 b = a;
1422
1423 In single-threaded code, this is not only safe, but also saves
1424 a branch. Unfortunately, in concurrent code, this optimization
1425 could cause some other CPU to see a spurious value of 42 -- even
1426 if variable 'a' was never zero -- when loading variable 'b'.
1427 Use ACCESS_ONCE() to prevent this as follows:
1428
1429 if (a)
1430 ACCESS_ONCE(b) = a;
1431 else
1432 ACCESS_ONCE(b) = 42;
1433
1434 The compiler can also invent loads. These are usually less
1435 damaging, but they can result in cache-line bouncing and thus in
1436 poor performance and scalability. Use ACCESS_ONCE() to prevent
1437 invented loads.
1438
1439 (*) For aligned memory locations whose size allows them to be accessed
1440 with a single memory-reference instruction, prevents "load tearing"
1441 and "store tearing," in which a single large access is replaced by
1442 multiple smaller accesses. For example, given an architecture having
1443 16-bit store instructions with 7-bit immediate fields, the compiler
1444 might be tempted to use two 16-bit store-immediate instructions to
1445 implement the following 32-bit store:
1446
1447 p = 0x00010002;
1448
1449 Please note that GCC really does use this sort of optimization,
1450 which is not surprising given that it would likely take more
1451 than two instructions to build the constant and then store it.
1452 This optimization can therefore be a win in single-threaded code.
1453 In fact, a recent bug (since fixed) caused GCC to incorrectly use
1454 this optimization in a volatile store. In the absence of such bugs,
1455 use of ACCESS_ONCE() prevents store tearing in the following example:
1456
1457 ACCESS_ONCE(p) = 0x00010002;
1458
1459 Use of packed structures can also result in load and store tearing,
1460 as in this example:
1461
1462 struct __attribute__((__packed__)) foo {
1463 short a;
1464 int b;
1465 short c;
1466 };
1467 struct foo foo1, foo2;
1468 ...
1469
1470 foo2.a = foo1.a;
1471 foo2.b = foo1.b;
1472 foo2.c = foo1.c;
1473
1474 Because there are no ACCESS_ONCE() wrappers and no volatile markings,
1475 the compiler would be well within its rights to implement these three
1476 assignment statements as a pair of 32-bit loads followed by a pair
1477 of 32-bit stores. This would result in load tearing on 'foo1.b'
1478 and store tearing on 'foo2.b'. ACCESS_ONCE() again prevents tearing
1479 in this example:
1480
1481 foo2.a = foo1.a;
1482 ACCESS_ONCE(foo2.b) = ACCESS_ONCE(foo1.b);
1483 foo2.c = foo1.c;
1484
1485All that aside, it is never necessary to use ACCESS_ONCE() on a variable
1486that has been marked volatile. For example, because 'jiffies' is marked
1487volatile, it is never necessary to say ACCESS_ONCE(jiffies). The reason
1488for this is that ACCESS_ONCE() is implemented as a volatile cast, which
1489has no effect when its argument is already marked volatile.
1490
1491Please note that these compiler barriers have no direct effect on the CPU,
1492which may then reorder things however it wishes.
David Howells108b42b2006-03-31 16:00:29 +01001493
1494
1495CPU MEMORY BARRIERS
1496-------------------
1497
1498The Linux kernel has eight basic CPU memory barriers:
1499
1500 TYPE MANDATORY SMP CONDITIONAL
1501 =============== ======================= ===========================
1502 GENERAL mb() smp_mb()
1503 WRITE wmb() smp_wmb()
1504 READ rmb() smp_rmb()
1505 DATA DEPENDENCY read_barrier_depends() smp_read_barrier_depends()
1506
1507
Nick Piggin73f10282008-05-14 06:35:11 +02001508All memory barriers except the data dependency barriers imply a compiler
1509barrier. Data dependencies do not impose any additional compiler ordering.
1510
1511Aside: In the case of data dependencies, the compiler would be expected to
1512issue the loads in the correct order (eg. `a[b]` would have to load the value
1513of b before loading a[b]), however there is no guarantee in the C specification
1514that the compiler may not speculate the value of b (eg. is equal to 1) and load
1515a before b (eg. tmp = a[1]; if (b != 1) tmp = a[b]; ). There is also the
1516problem of a compiler reloading b after having loaded a[b], thus having a newer
1517copy of b than a[b]. A consensus has not yet been reached about these problems,
1518however the ACCESS_ONCE macro is a good place to start looking.
David Howells108b42b2006-03-31 16:00:29 +01001519
1520SMP memory barriers are reduced to compiler barriers on uniprocessor compiled
Jarek Poplawski81fc6322007-05-23 13:58:20 -07001521systems because it is assumed that a CPU will appear to be self-consistent,
David Howells108b42b2006-03-31 16:00:29 +01001522and will order overlapping accesses correctly with respect to itself.
1523
1524[!] Note that SMP memory barriers _must_ be used to control the ordering of
1525references to shared memory on SMP systems, though the use of locking instead
1526is sufficient.
1527
1528Mandatory barriers should not be used to control SMP effects, since mandatory
1529barriers unnecessarily impose overhead on UP systems. They may, however, be
1530used to control MMIO effects on accesses through relaxed memory I/O windows.
1531These are required even on non-SMP systems as they affect the order in which
1532memory operations appear to a device by prohibiting both the compiler and the
1533CPU from reordering them.
1534
1535
1536There are some more advanced barrier functions:
1537
1538 (*) set_mb(var, value)
David Howells108b42b2006-03-31 16:00:29 +01001539
Oleg Nesterov75b2bd52006-11-08 17:44:38 -08001540 This assigns the value to the variable and then inserts a full memory
Steven Rostedtf92213b2006-07-14 16:05:01 -04001541 barrier after it, depending on the function. It isn't guaranteed to
David Howells108b42b2006-03-31 16:00:29 +01001542 insert anything more than a compiler barrier in a UP compilation.
1543
1544
1545 (*) smp_mb__before_atomic_dec();
1546 (*) smp_mb__after_atomic_dec();
1547 (*) smp_mb__before_atomic_inc();
1548 (*) smp_mb__after_atomic_inc();
1549
1550 These are for use with atomic add, subtract, increment and decrement
David Howellsdbc87002006-04-10 22:54:23 -07001551 functions that don't return a value, especially when used for reference
1552 counting. These functions do not imply memory barriers.
David Howells108b42b2006-03-31 16:00:29 +01001553
1554 As an example, consider a piece of code that marks an object as being dead
1555 and then decrements the object's reference count:
1556
1557 obj->dead = 1;
1558 smp_mb__before_atomic_dec();
1559 atomic_dec(&obj->ref_count);
1560
1561 This makes sure that the death mark on the object is perceived to be set
1562 *before* the reference counter is decremented.
1563
1564 See Documentation/atomic_ops.txt for more information. See the "Atomic
1565 operations" subsection for information on where to use these.
1566
1567
1568 (*) smp_mb__before_clear_bit(void);
1569 (*) smp_mb__after_clear_bit(void);
1570
1571 These are for use similar to the atomic inc/dec barriers. These are
1572 typically used for bitwise unlocking operations, so care must be taken as
1573 there are no implicit memory barriers here either.
1574
1575 Consider implementing an unlock operation of some nature by clearing a
1576 locking bit. The clear_bit() would then need to be barriered like this:
1577
1578 smp_mb__before_clear_bit();
1579 clear_bit( ... );
1580
1581 This prevents memory operations before the clear leaking to after it. See
1582 the subsection on "Locking Functions" with reference to UNLOCK operation
1583 implications.
1584
1585 See Documentation/atomic_ops.txt for more information. See the "Atomic
1586 operations" subsection for information on where to use these.
1587
1588
1589MMIO WRITE BARRIER
1590------------------
1591
1592The Linux kernel also has a special barrier for use with memory-mapped I/O
1593writes:
1594
1595 mmiowb();
1596
1597This is a variation on the mandatory write barrier that causes writes to weakly
1598ordered I/O regions to be partially ordered. Its effects may go beyond the
1599CPU->Hardware interface and actually affect the hardware at some level.
1600
1601See the subsection "Locks vs I/O accesses" for more information.
1602
1603
1604===============================
1605IMPLICIT KERNEL MEMORY BARRIERS
1606===============================
1607
1608Some of the other functions in the linux kernel imply memory barriers, amongst
David Howells670bd952006-06-10 09:54:12 -07001609which are locking and scheduling functions.
David Howells108b42b2006-03-31 16:00:29 +01001610
1611This specification is a _minimum_ guarantee; any particular architecture may
1612provide more substantial guarantees, but these may not be relied upon outside
1613of arch specific code.
1614
1615
1616LOCKING FUNCTIONS
1617-----------------
1618
1619The Linux kernel has a number of locking constructs:
1620
1621 (*) spin locks
1622 (*) R/W spin locks
1623 (*) mutexes
1624 (*) semaphores
1625 (*) R/W semaphores
1626 (*) RCU
1627
1628In all cases there are variants on "LOCK" operations and "UNLOCK" operations
1629for each construct. These operations all imply certain barriers:
1630
1631 (1) LOCK operation implication:
1632
1633 Memory operations issued after the LOCK will be completed after the LOCK
1634 operation has completed.
1635
1636 Memory operations issued before the LOCK may be completed after the LOCK
1637 operation has completed.
1638
1639 (2) UNLOCK operation implication:
1640
1641 Memory operations issued before the UNLOCK will be completed before the
1642 UNLOCK operation has completed.
1643
1644 Memory operations issued after the UNLOCK may be completed before the
1645 UNLOCK operation has completed.
1646
1647 (3) LOCK vs LOCK implication:
1648
1649 All LOCK operations issued before another LOCK operation will be completed
1650 before that LOCK operation.
1651
1652 (4) LOCK vs UNLOCK implication:
1653
1654 All LOCK operations issued before an UNLOCK operation will be completed
1655 before the UNLOCK operation.
1656
1657 All UNLOCK operations issued before a LOCK operation will be completed
1658 before the LOCK operation.
1659
1660 (5) Failed conditional LOCK implication:
1661
1662 Certain variants of the LOCK operation may fail, either due to being
1663 unable to get the lock immediately, or due to receiving an unblocked
1664 signal whilst asleep waiting for the lock to become available. Failed
1665 locks do not imply any sort of barrier.
1666
1667Therefore, from (1), (2) and (4) an UNLOCK followed by an unconditional LOCK is
1668equivalent to a full barrier, but a LOCK followed by an UNLOCK is not.
1669
Jarek Poplawski81fc6322007-05-23 13:58:20 -07001670[!] Note: one of the consequences of LOCKs and UNLOCKs being only one-way
1671 barriers is that the effects of instructions outside of a critical section
1672 may seep into the inside of the critical section.
David Howells108b42b2006-03-31 16:00:29 +01001673
David Howells670bd952006-06-10 09:54:12 -07001674A LOCK followed by an UNLOCK may not be assumed to be full memory barrier
1675because it is possible for an access preceding the LOCK to happen after the
1676LOCK, and an access following the UNLOCK to happen before the UNLOCK, and the
1677two accesses can themselves then cross:
1678
1679 *A = a;
1680 LOCK
1681 UNLOCK
1682 *B = b;
1683
1684may occur as:
1685
1686 LOCK, STORE *B, STORE *A, UNLOCK
1687
David Howells108b42b2006-03-31 16:00:29 +01001688Locks and semaphores may not provide any guarantee of ordering on UP compiled
1689systems, and so cannot be counted on in such a situation to actually achieve
1690anything at all - especially with respect to I/O accesses - unless combined
1691with interrupt disabling operations.
1692
1693See also the section on "Inter-CPU locking barrier effects".
1694
1695
1696As an example, consider the following:
1697
1698 *A = a;
1699 *B = b;
1700 LOCK
1701 *C = c;
1702 *D = d;
1703 UNLOCK
1704 *E = e;
1705 *F = f;
1706
1707The following sequence of events is acceptable:
1708
1709 LOCK, {*F,*A}, *E, {*C,*D}, *B, UNLOCK
1710
1711 [+] Note that {*F,*A} indicates a combined access.
1712
1713But none of the following are:
1714
1715 {*F,*A}, *B, LOCK, *C, *D, UNLOCK, *E
1716 *A, *B, *C, LOCK, *D, UNLOCK, *E, *F
1717 *A, *B, LOCK, *C, UNLOCK, *D, *E, *F
1718 *B, LOCK, *C, *D, UNLOCK, {*F,*A}, *E
1719
1720
1721
1722INTERRUPT DISABLING FUNCTIONS
1723-----------------------------
1724
1725Functions that disable interrupts (LOCK equivalent) and enable interrupts
1726(UNLOCK equivalent) will act as compiler barriers only. So if memory or I/O
1727barriers are required in such a situation, they must be provided from some
1728other means.
1729
1730
David Howells50fa6102009-04-28 15:01:38 +01001731SLEEP AND WAKE-UP FUNCTIONS
1732---------------------------
1733
1734Sleeping and waking on an event flagged in global data can be viewed as an
1735interaction between two pieces of data: the task state of the task waiting for
1736the event and the global data used to indicate the event. To make sure that
1737these appear to happen in the right order, the primitives to begin the process
1738of going to sleep, and the primitives to initiate a wake up imply certain
1739barriers.
1740
1741Firstly, the sleeper normally follows something like this sequence of events:
1742
1743 for (;;) {
1744 set_current_state(TASK_UNINTERRUPTIBLE);
1745 if (event_indicated)
1746 break;
1747 schedule();
1748 }
1749
1750A general memory barrier is interpolated automatically by set_current_state()
1751after it has altered the task state:
1752
1753 CPU 1
1754 ===============================
1755 set_current_state();
1756 set_mb();
1757 STORE current->state
1758 <general barrier>
1759 LOAD event_indicated
1760
1761set_current_state() may be wrapped by:
1762
1763 prepare_to_wait();
1764 prepare_to_wait_exclusive();
1765
1766which therefore also imply a general memory barrier after setting the state.
1767The whole sequence above is available in various canned forms, all of which
1768interpolate the memory barrier in the right place:
1769
1770 wait_event();
1771 wait_event_interruptible();
1772 wait_event_interruptible_exclusive();
1773 wait_event_interruptible_timeout();
1774 wait_event_killable();
1775 wait_event_timeout();
1776 wait_on_bit();
1777 wait_on_bit_lock();
1778
1779
1780Secondly, code that performs a wake up normally follows something like this:
1781
1782 event_indicated = 1;
1783 wake_up(&event_wait_queue);
1784
1785or:
1786
1787 event_indicated = 1;
1788 wake_up_process(event_daemon);
1789
1790A write memory barrier is implied by wake_up() and co. if and only if they wake
1791something up. The barrier occurs before the task state is cleared, and so sits
1792between the STORE to indicate the event and the STORE to set TASK_RUNNING:
1793
1794 CPU 1 CPU 2
1795 =============================== ===============================
1796 set_current_state(); STORE event_indicated
1797 set_mb(); wake_up();
1798 STORE current->state <write barrier>
1799 <general barrier> STORE current->state
1800 LOAD event_indicated
1801
1802The available waker functions include:
1803
1804 complete();
1805 wake_up();
1806 wake_up_all();
1807 wake_up_bit();
1808 wake_up_interruptible();
1809 wake_up_interruptible_all();
1810 wake_up_interruptible_nr();
1811 wake_up_interruptible_poll();
1812 wake_up_interruptible_sync();
1813 wake_up_interruptible_sync_poll();
1814 wake_up_locked();
1815 wake_up_locked_poll();
1816 wake_up_nr();
1817 wake_up_poll();
1818 wake_up_process();
1819
1820
1821[!] Note that the memory barriers implied by the sleeper and the waker do _not_
1822order multiple stores before the wake-up with respect to loads of those stored
1823values after the sleeper has called set_current_state(). For instance, if the
1824sleeper does:
1825
1826 set_current_state(TASK_INTERRUPTIBLE);
1827 if (event_indicated)
1828 break;
1829 __set_current_state(TASK_RUNNING);
1830 do_something(my_data);
1831
1832and the waker does:
1833
1834 my_data = value;
1835 event_indicated = 1;
1836 wake_up(&event_wait_queue);
1837
1838there's no guarantee that the change to event_indicated will be perceived by
1839the sleeper as coming after the change to my_data. In such a circumstance, the
1840code on both sides must interpolate its own memory barriers between the
1841separate data accesses. Thus the above sleeper ought to do:
1842
1843 set_current_state(TASK_INTERRUPTIBLE);
1844 if (event_indicated) {
1845 smp_rmb();
1846 do_something(my_data);
1847 }
1848
1849and the waker should do:
1850
1851 my_data = value;
1852 smp_wmb();
1853 event_indicated = 1;
1854 wake_up(&event_wait_queue);
1855
1856
David Howells108b42b2006-03-31 16:00:29 +01001857MISCELLANEOUS FUNCTIONS
1858-----------------------
1859
1860Other functions that imply barriers:
1861
1862 (*) schedule() and similar imply full memory barriers.
1863
David Howells108b42b2006-03-31 16:00:29 +01001864
1865=================================
1866INTER-CPU LOCKING BARRIER EFFECTS
1867=================================
1868
1869On SMP systems locking primitives give a more substantial form of barrier: one
1870that does affect memory access ordering on other CPUs, within the context of
1871conflict on any particular lock.
1872
1873
1874LOCKS VS MEMORY ACCESSES
1875------------------------
1876
Aneesh Kumar79afecf2006-05-15 09:44:36 -07001877Consider the following: the system has a pair of spinlocks (M) and (Q), and
David Howells108b42b2006-03-31 16:00:29 +01001878three CPUs; then should the following sequence of events occur:
1879
1880 CPU 1 CPU 2
1881 =============================== ===============================
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08001882 ACCESS_ONCE(*A) = a; ACCESS_ONCE(*E) = e;
David Howells108b42b2006-03-31 16:00:29 +01001883 LOCK M LOCK Q
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08001884 ACCESS_ONCE(*B) = b; ACCESS_ONCE(*F) = f;
1885 ACCESS_ONCE(*C) = c; ACCESS_ONCE(*G) = g;
David Howells108b42b2006-03-31 16:00:29 +01001886 UNLOCK M UNLOCK Q
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08001887 ACCESS_ONCE(*D) = d; ACCESS_ONCE(*H) = h;
David Howells108b42b2006-03-31 16:00:29 +01001888
Jarek Poplawski81fc6322007-05-23 13:58:20 -07001889Then there is no guarantee as to what order CPU 3 will see the accesses to *A
David Howells108b42b2006-03-31 16:00:29 +01001890through *H occur in, other than the constraints imposed by the separate locks
1891on the separate CPUs. It might, for example, see:
1892
1893 *E, LOCK M, LOCK Q, *G, *C, *F, *A, *B, UNLOCK Q, *D, *H, UNLOCK M
1894
1895But it won't see any of:
1896
1897 *B, *C or *D preceding LOCK M
1898 *A, *B or *C following UNLOCK M
1899 *F, *G or *H preceding LOCK Q
1900 *E, *F or *G following UNLOCK Q
1901
1902
1903However, if the following occurs:
1904
1905 CPU 1 CPU 2
1906 =============================== ===============================
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08001907 ACCESS_ONCE(*A) = a;
1908 LOCK M [1]
1909 ACCESS_ONCE(*B) = b;
1910 ACCESS_ONCE(*C) = c;
1911 UNLOCK M [1]
1912 ACCESS_ONCE(*D) = d; ACCESS_ONCE(*E) = e;
1913 LOCK M [2]
1914 ACCESS_ONCE(*F) = f;
1915 ACCESS_ONCE(*G) = g;
1916 UNLOCK M [2]
1917 ACCESS_ONCE(*H) = h;
David Howells108b42b2006-03-31 16:00:29 +01001918
Jarek Poplawski81fc6322007-05-23 13:58:20 -07001919CPU 3 might see:
David Howells108b42b2006-03-31 16:00:29 +01001920
1921 *E, LOCK M [1], *C, *B, *A, UNLOCK M [1],
1922 LOCK M [2], *H, *F, *G, UNLOCK M [2], *D
1923
Jarek Poplawski81fc6322007-05-23 13:58:20 -07001924But assuming CPU 1 gets the lock first, CPU 3 won't see any of:
David Howells108b42b2006-03-31 16:00:29 +01001925
1926 *B, *C, *D, *F, *G or *H preceding LOCK M [1]
1927 *A, *B or *C following UNLOCK M [1]
1928 *F, *G or *H preceding LOCK M [2]
1929 *A, *B, *C, *E, *F or *G following UNLOCK M [2]
1930
1931
1932LOCKS VS I/O ACCESSES
1933---------------------
1934
1935Under certain circumstances (especially involving NUMA), I/O accesses within
1936two spinlocked sections on two different CPUs may be seen as interleaved by the
1937PCI bridge, because the PCI bridge does not necessarily participate in the
1938cache-coherence protocol, and is therefore incapable of issuing the required
1939read memory barriers.
1940
1941For example:
1942
1943 CPU 1 CPU 2
1944 =============================== ===============================
1945 spin_lock(Q)
1946 writel(0, ADDR)
1947 writel(1, DATA);
1948 spin_unlock(Q);
1949 spin_lock(Q);
1950 writel(4, ADDR);
1951 writel(5, DATA);
1952 spin_unlock(Q);
1953
1954may be seen by the PCI bridge as follows:
1955
1956 STORE *ADDR = 0, STORE *ADDR = 4, STORE *DATA = 1, STORE *DATA = 5
1957
1958which would probably cause the hardware to malfunction.
1959
1960
1961What is necessary here is to intervene with an mmiowb() before dropping the
1962spinlock, for example:
1963
1964 CPU 1 CPU 2
1965 =============================== ===============================
1966 spin_lock(Q)
1967 writel(0, ADDR)
1968 writel(1, DATA);
1969 mmiowb();
1970 spin_unlock(Q);
1971 spin_lock(Q);
1972 writel(4, ADDR);
1973 writel(5, DATA);
1974 mmiowb();
1975 spin_unlock(Q);
1976
Jarek Poplawski81fc6322007-05-23 13:58:20 -07001977this will ensure that the two stores issued on CPU 1 appear at the PCI bridge
1978before either of the stores issued on CPU 2.
David Howells108b42b2006-03-31 16:00:29 +01001979
1980
Jarek Poplawski81fc6322007-05-23 13:58:20 -07001981Furthermore, following a store by a load from the same device obviates the need
1982for the mmiowb(), because the load forces the store to complete before the load
David Howells108b42b2006-03-31 16:00:29 +01001983is performed:
1984
1985 CPU 1 CPU 2
1986 =============================== ===============================
1987 spin_lock(Q)
1988 writel(0, ADDR)
1989 a = readl(DATA);
1990 spin_unlock(Q);
1991 spin_lock(Q);
1992 writel(4, ADDR);
1993 b = readl(DATA);
1994 spin_unlock(Q);
1995
1996
1997See Documentation/DocBook/deviceiobook.tmpl for more information.
1998
1999
2000=================================
2001WHERE ARE MEMORY BARRIERS NEEDED?
2002=================================
2003
2004Under normal operation, memory operation reordering is generally not going to
2005be a problem as a single-threaded linear piece of code will still appear to
David Howells50fa6102009-04-28 15:01:38 +01002006work correctly, even if it's in an SMP kernel. There are, however, four
David Howells108b42b2006-03-31 16:00:29 +01002007circumstances in which reordering definitely _could_ be a problem:
2008
2009 (*) Interprocessor interaction.
2010
2011 (*) Atomic operations.
2012
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002013 (*) Accessing devices.
David Howells108b42b2006-03-31 16:00:29 +01002014
2015 (*) Interrupts.
2016
2017
2018INTERPROCESSOR INTERACTION
2019--------------------------
2020
2021When there's a system with more than one processor, more than one CPU in the
2022system may be working on the same data set at the same time. This can cause
2023synchronisation problems, and the usual way of dealing with them is to use
2024locks. Locks, however, are quite expensive, and so it may be preferable to
2025operate without the use of a lock if at all possible. In such a case
2026operations that affect both CPUs may have to be carefully ordered to prevent
2027a malfunction.
2028
2029Consider, for example, the R/W semaphore slow path. Here a waiting process is
2030queued on the semaphore, by virtue of it having a piece of its stack linked to
2031the semaphore's list of waiting processes:
2032
2033 struct rw_semaphore {
2034 ...
2035 spinlock_t lock;
2036 struct list_head waiters;
2037 };
2038
2039 struct rwsem_waiter {
2040 struct list_head list;
2041 struct task_struct *task;
2042 };
2043
2044To wake up a particular waiter, the up_read() or up_write() functions have to:
2045
2046 (1) read the next pointer from this waiter's record to know as to where the
2047 next waiter record is;
2048
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002049 (2) read the pointer to the waiter's task structure;
David Howells108b42b2006-03-31 16:00:29 +01002050
2051 (3) clear the task pointer to tell the waiter it has been given the semaphore;
2052
2053 (4) call wake_up_process() on the task; and
2054
2055 (5) release the reference held on the waiter's task struct.
2056
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002057In other words, it has to perform this sequence of events:
David Howells108b42b2006-03-31 16:00:29 +01002058
2059 LOAD waiter->list.next;
2060 LOAD waiter->task;
2061 STORE waiter->task;
2062 CALL wakeup
2063 RELEASE task
2064
2065and if any of these steps occur out of order, then the whole thing may
2066malfunction.
2067
2068Once it has queued itself and dropped the semaphore lock, the waiter does not
2069get the lock again; it instead just waits for its task pointer to be cleared
2070before proceeding. Since the record is on the waiter's stack, this means that
2071if the task pointer is cleared _before_ the next pointer in the list is read,
2072another CPU might start processing the waiter and might clobber the waiter's
2073stack before the up*() function has a chance to read the next pointer.
2074
2075Consider then what might happen to the above sequence of events:
2076
2077 CPU 1 CPU 2
2078 =============================== ===============================
2079 down_xxx()
2080 Queue waiter
2081 Sleep
2082 up_yyy()
2083 LOAD waiter->task;
2084 STORE waiter->task;
2085 Woken up by other event
2086 <preempt>
2087 Resume processing
2088 down_xxx() returns
2089 call foo()
2090 foo() clobbers *waiter
2091 </preempt>
2092 LOAD waiter->list.next;
2093 --- OOPS ---
2094
2095This could be dealt with using the semaphore lock, but then the down_xxx()
2096function has to needlessly get the spinlock again after being woken up.
2097
2098The way to deal with this is to insert a general SMP memory barrier:
2099
2100 LOAD waiter->list.next;
2101 LOAD waiter->task;
2102 smp_mb();
2103 STORE waiter->task;
2104 CALL wakeup
2105 RELEASE task
2106
2107In this case, the barrier makes a guarantee that all memory accesses before the
2108barrier will appear to happen before all the memory accesses after the barrier
2109with respect to the other CPUs on the system. It does _not_ guarantee that all
2110the memory accesses before the barrier will be complete by the time the barrier
2111instruction itself is complete.
2112
2113On a UP system - where this wouldn't be a problem - the smp_mb() is just a
2114compiler barrier, thus making sure the compiler emits the instructions in the
David Howells6bc39272006-06-25 05:49:22 -07002115right order without actually intervening in the CPU. Since there's only one
2116CPU, that CPU's dependency ordering logic will take care of everything else.
David Howells108b42b2006-03-31 16:00:29 +01002117
2118
2119ATOMIC OPERATIONS
2120-----------------
2121
David Howellsdbc87002006-04-10 22:54:23 -07002122Whilst they are technically interprocessor interaction considerations, atomic
2123operations are noted specially as some of them imply full memory barriers and
2124some don't, but they're very heavily relied on as a group throughout the
2125kernel.
2126
2127Any atomic operation that modifies some state in memory and returns information
2128about the state (old or new) implies an SMP-conditional general memory barrier
Nick Piggin26333572007-10-18 03:06:39 -07002129(smp_mb()) on each side of the actual operation (with the exception of
2130explicit lock operations, described later). These include:
David Howells108b42b2006-03-31 16:00:29 +01002131
2132 xchg();
2133 cmpxchg();
Paul E. McKenneyfb2b5812013-12-11 13:59:05 -08002134 atomic_xchg(); atomic_long_xchg();
2135 atomic_cmpxchg(); atomic_long_cmpxchg();
2136 atomic_inc_return(); atomic_long_inc_return();
2137 atomic_dec_return(); atomic_long_dec_return();
2138 atomic_add_return(); atomic_long_add_return();
2139 atomic_sub_return(); atomic_long_sub_return();
2140 atomic_inc_and_test(); atomic_long_inc_and_test();
2141 atomic_dec_and_test(); atomic_long_dec_and_test();
2142 atomic_sub_and_test(); atomic_long_sub_and_test();
2143 atomic_add_negative(); atomic_long_add_negative();
David Howellsdbc87002006-04-10 22:54:23 -07002144 test_and_set_bit();
2145 test_and_clear_bit();
2146 test_and_change_bit();
David Howells108b42b2006-03-31 16:00:29 +01002147
Paul E. McKenneyfb2b5812013-12-11 13:59:05 -08002148 /* when succeeds (returns 1) */
2149 atomic_add_unless(); atomic_long_add_unless();
2150
David Howellsdbc87002006-04-10 22:54:23 -07002151These are used for such things as implementing LOCK-class and UNLOCK-class
2152operations and adjusting reference counters towards object destruction, and as
2153such the implicit memory barrier effects are necessary.
David Howells108b42b2006-03-31 16:00:29 +01002154
David Howells108b42b2006-03-31 16:00:29 +01002155
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002156The following operations are potential problems as they do _not_ imply memory
David Howellsdbc87002006-04-10 22:54:23 -07002157barriers, but might be used for implementing such things as UNLOCK-class
2158operations:
2159
2160 atomic_set();
David Howells108b42b2006-03-31 16:00:29 +01002161 set_bit();
2162 clear_bit();
2163 change_bit();
David Howellsdbc87002006-04-10 22:54:23 -07002164
2165With these the appropriate explicit memory barrier should be used if necessary
2166(smp_mb__before_clear_bit() for instance).
David Howells108b42b2006-03-31 16:00:29 +01002167
2168
David Howellsdbc87002006-04-10 22:54:23 -07002169The following also do _not_ imply memory barriers, and so may require explicit
2170memory barriers under some circumstances (smp_mb__before_atomic_dec() for
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002171instance):
David Howells108b42b2006-03-31 16:00:29 +01002172
2173 atomic_add();
2174 atomic_sub();
2175 atomic_inc();
2176 atomic_dec();
2177
2178If they're used for statistics generation, then they probably don't need memory
2179barriers, unless there's a coupling between statistical data.
2180
2181If they're used for reference counting on an object to control its lifetime,
2182they probably don't need memory barriers because either the reference count
2183will be adjusted inside a locked section, or the caller will already hold
2184sufficient references to make the lock, and thus a memory barrier unnecessary.
2185
2186If they're used for constructing a lock of some description, then they probably
2187do need memory barriers as a lock primitive generally has to do things in a
2188specific order.
2189
David Howells108b42b2006-03-31 16:00:29 +01002190Basically, each usage case has to be carefully considered as to whether memory
David Howellsdbc87002006-04-10 22:54:23 -07002191barriers are needed or not.
2192
Nick Piggin26333572007-10-18 03:06:39 -07002193The following operations are special locking primitives:
2194
2195 test_and_set_bit_lock();
2196 clear_bit_unlock();
2197 __clear_bit_unlock();
2198
2199These implement LOCK-class and UNLOCK-class operations. These should be used in
2200preference to other operations when implementing locking primitives, because
2201their implementations can be optimised on many architectures.
2202
David Howellsdbc87002006-04-10 22:54:23 -07002203[!] Note that special memory barrier primitives are available for these
2204situations because on some CPUs the atomic instructions used imply full memory
2205barriers, and so barrier instructions are superfluous in conjunction with them,
2206and in such cases the special barrier primitives will be no-ops.
David Howells108b42b2006-03-31 16:00:29 +01002207
2208See Documentation/atomic_ops.txt for more information.
2209
2210
2211ACCESSING DEVICES
2212-----------------
2213
2214Many devices can be memory mapped, and so appear to the CPU as if they're just
2215a set of memory locations. To control such a device, the driver usually has to
2216make the right memory accesses in exactly the right order.
2217
2218However, having a clever CPU or a clever compiler creates a potential problem
2219in that the carefully sequenced accesses in the driver code won't reach the
2220device in the requisite order if the CPU or the compiler thinks it is more
2221efficient to reorder, combine or merge accesses - something that would cause
2222the device to malfunction.
2223
2224Inside of the Linux kernel, I/O should be done through the appropriate accessor
2225routines - such as inb() or writel() - which know how to make such accesses
2226appropriately sequential. Whilst this, for the most part, renders the explicit
2227use of memory barriers unnecessary, there are a couple of situations where they
2228might be needed:
2229
2230 (1) On some systems, I/O stores are not strongly ordered across all CPUs, and
2231 so for _all_ general drivers locks should be used and mmiowb() must be
2232 issued prior to unlocking the critical section.
2233
2234 (2) If the accessor functions are used to refer to an I/O memory window with
2235 relaxed memory access properties, then _mandatory_ memory barriers are
2236 required to enforce ordering.
2237
2238See Documentation/DocBook/deviceiobook.tmpl for more information.
2239
2240
2241INTERRUPTS
2242----------
2243
2244A driver may be interrupted by its own interrupt service routine, and thus the
2245two parts of the driver may interfere with each other's attempts to control or
2246access the device.
2247
2248This may be alleviated - at least in part - by disabling local interrupts (a
2249form of locking), such that the critical operations are all contained within
2250the interrupt-disabled section in the driver. Whilst the driver's interrupt
2251routine is executing, the driver's core may not run on the same CPU, and its
2252interrupt is not permitted to happen again until the current interrupt has been
2253handled, thus the interrupt handler does not need to lock against that.
2254
2255However, consider a driver that was talking to an ethernet card that sports an
2256address register and a data register. If that driver's core talks to the card
2257under interrupt-disablement and then the driver's interrupt handler is invoked:
2258
2259 LOCAL IRQ DISABLE
2260 writew(ADDR, 3);
2261 writew(DATA, y);
2262 LOCAL IRQ ENABLE
2263 <interrupt>
2264 writew(ADDR, 4);
2265 q = readw(DATA);
2266 </interrupt>
2267
2268The store to the data register might happen after the second store to the
2269address register if ordering rules are sufficiently relaxed:
2270
2271 STORE *ADDR = 3, STORE *ADDR = 4, STORE *DATA = y, q = LOAD *DATA
2272
2273
2274If ordering rules are relaxed, it must be assumed that accesses done inside an
2275interrupt disabled section may leak outside of it and may interleave with
2276accesses performed in an interrupt - and vice versa - unless implicit or
2277explicit barriers are used.
2278
2279Normally this won't be a problem because the I/O accesses done inside such
2280sections will include synchronous load operations on strictly ordered I/O
2281registers that form implicit I/O barriers. If this isn't sufficient then an
2282mmiowb() may need to be used explicitly.
2283
2284
2285A similar situation may occur between an interrupt routine and two routines
2286running on separate CPUs that communicate with each other. If such a case is
2287likely, then interrupt-disabling locks should be used to guarantee ordering.
2288
2289
2290==========================
2291KERNEL I/O BARRIER EFFECTS
2292==========================
2293
2294When accessing I/O memory, drivers should use the appropriate accessor
2295functions:
2296
2297 (*) inX(), outX():
2298
2299 These are intended to talk to I/O space rather than memory space, but
2300 that's primarily a CPU-specific concept. The i386 and x86_64 processors do
2301 indeed have special I/O space access cycles and instructions, but many
2302 CPUs don't have such a concept.
2303
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002304 The PCI bus, amongst others, defines an I/O space concept which - on such
2305 CPUs as i386 and x86_64 - readily maps to the CPU's concept of I/O
David Howells6bc39272006-06-25 05:49:22 -07002306 space. However, it may also be mapped as a virtual I/O space in the CPU's
2307 memory map, particularly on those CPUs that don't support alternate I/O
2308 spaces.
David Howells108b42b2006-03-31 16:00:29 +01002309
2310 Accesses to this space may be fully synchronous (as on i386), but
2311 intermediary bridges (such as the PCI host bridge) may not fully honour
2312 that.
2313
2314 They are guaranteed to be fully ordered with respect to each other.
2315
2316 They are not guaranteed to be fully ordered with respect to other types of
2317 memory and I/O operation.
2318
2319 (*) readX(), writeX():
2320
2321 Whether these are guaranteed to be fully ordered and uncombined with
2322 respect to each other on the issuing CPU depends on the characteristics
2323 defined for the memory window through which they're accessing. On later
2324 i386 architecture machines, for example, this is controlled by way of the
2325 MTRR registers.
2326
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002327 Ordinarily, these will be guaranteed to be fully ordered and uncombined,
David Howells108b42b2006-03-31 16:00:29 +01002328 provided they're not accessing a prefetchable device.
2329
2330 However, intermediary hardware (such as a PCI bridge) may indulge in
2331 deferral if it so wishes; to flush a store, a load from the same location
2332 is preferred[*], but a load from the same device or from configuration
2333 space should suffice for PCI.
2334
2335 [*] NOTE! attempting to load from the same location as was written to may
Ingo Molnare0edc782013-11-22 11:24:53 +01002336 cause a malfunction - consider the 16550 Rx/Tx serial registers for
2337 example.
David Howells108b42b2006-03-31 16:00:29 +01002338
2339 Used with prefetchable I/O memory, an mmiowb() barrier may be required to
2340 force stores to be ordered.
2341
2342 Please refer to the PCI specification for more information on interactions
2343 between PCI transactions.
2344
2345 (*) readX_relaxed()
2346
2347 These are similar to readX(), but are not guaranteed to be ordered in any
2348 way. Be aware that there is no I/O read barrier available.
2349
2350 (*) ioreadX(), iowriteX()
2351
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002352 These will perform appropriately for the type of access they're actually
David Howells108b42b2006-03-31 16:00:29 +01002353 doing, be it inX()/outX() or readX()/writeX().
2354
2355
2356========================================
2357ASSUMED MINIMUM EXECUTION ORDERING MODEL
2358========================================
2359
2360It has to be assumed that the conceptual CPU is weakly-ordered but that it will
2361maintain the appearance of program causality with respect to itself. Some CPUs
2362(such as i386 or x86_64) are more constrained than others (such as powerpc or
2363frv), and so the most relaxed case (namely DEC Alpha) must be assumed outside
2364of arch-specific code.
2365
2366This means that it must be considered that the CPU will execute its instruction
2367stream in any order it feels like - or even in parallel - provided that if an
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002368instruction in the stream depends on an earlier instruction, then that
David Howells108b42b2006-03-31 16:00:29 +01002369earlier instruction must be sufficiently complete[*] before the later
2370instruction may proceed; in other words: provided that the appearance of
2371causality is maintained.
2372
2373 [*] Some instructions have more than one effect - such as changing the
2374 condition codes, changing registers or changing memory - and different
2375 instructions may depend on different effects.
2376
2377A CPU may also discard any instruction sequence that winds up having no
2378ultimate effect. For example, if two adjacent instructions both load an
2379immediate value into the same register, the first may be discarded.
2380
2381
2382Similarly, it has to be assumed that compiler might reorder the instruction
2383stream in any way it sees fit, again provided the appearance of causality is
2384maintained.
2385
2386
2387============================
2388THE EFFECTS OF THE CPU CACHE
2389============================
2390
2391The way cached memory operations are perceived across the system is affected to
2392a certain extent by the caches that lie between CPUs and memory, and by the
2393memory coherence system that maintains the consistency of state in the system.
2394
2395As far as the way a CPU interacts with another part of the system through the
2396caches goes, the memory system has to include the CPU's caches, and memory
2397barriers for the most part act at the interface between the CPU and its cache
2398(memory barriers logically act on the dotted line in the following diagram):
2399
2400 <--- CPU ---> : <----------- Memory ----------->
2401 :
2402 +--------+ +--------+ : +--------+ +-----------+
2403 | | | | : | | | | +--------+
Ingo Molnare0edc782013-11-22 11:24:53 +01002404 | CPU | | Memory | : | CPU | | | | |
2405 | Core |--->| Access |----->| Cache |<-->| | | |
David Howells108b42b2006-03-31 16:00:29 +01002406 | | | Queue | : | | | |--->| Memory |
Ingo Molnare0edc782013-11-22 11:24:53 +01002407 | | | | : | | | | | |
2408 +--------+ +--------+ : +--------+ | | | |
David Howells108b42b2006-03-31 16:00:29 +01002409 : | Cache | +--------+
2410 : | Coherency |
2411 : | Mechanism | +--------+
2412 +--------+ +--------+ : +--------+ | | | |
2413 | | | | : | | | | | |
2414 | CPU | | Memory | : | CPU | | |--->| Device |
Ingo Molnare0edc782013-11-22 11:24:53 +01002415 | Core |--->| Access |----->| Cache |<-->| | | |
2416 | | | Queue | : | | | | | |
David Howells108b42b2006-03-31 16:00:29 +01002417 | | | | : | | | | +--------+
2418 +--------+ +--------+ : +--------+ +-----------+
2419 :
2420 :
2421
2422Although any particular load or store may not actually appear outside of the
2423CPU that issued it since it may have been satisfied within the CPU's own cache,
2424it will still appear as if the full memory access had taken place as far as the
2425other CPUs are concerned since the cache coherency mechanisms will migrate the
2426cacheline over to the accessing CPU and propagate the effects upon conflict.
2427
2428The CPU core may execute instructions in any order it deems fit, provided the
2429expected program causality appears to be maintained. Some of the instructions
2430generate load and store operations which then go into the queue of memory
2431accesses to be performed. The core may place these in the queue in any order
2432it wishes, and continue execution until it is forced to wait for an instruction
2433to complete.
2434
2435What memory barriers are concerned with is controlling the order in which
2436accesses cross from the CPU side of things to the memory side of things, and
2437the order in which the effects are perceived to happen by the other observers
2438in the system.
2439
2440[!] Memory barriers are _not_ needed within a given CPU, as CPUs always see
2441their own loads and stores as if they had happened in program order.
2442
2443[!] MMIO or other device accesses may bypass the cache system. This depends on
2444the properties of the memory window through which devices are accessed and/or
2445the use of any special device communication instructions the CPU may have.
2446
2447
2448CACHE COHERENCY
2449---------------
2450
2451Life isn't quite as simple as it may appear above, however: for while the
2452caches are expected to be coherent, there's no guarantee that that coherency
2453will be ordered. This means that whilst changes made on one CPU will
2454eventually become visible on all CPUs, there's no guarantee that they will
2455become apparent in the same order on those other CPUs.
2456
2457
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002458Consider dealing with a system that has a pair of CPUs (1 & 2), each of which
2459has a pair of parallel data caches (CPU 1 has A/B, and CPU 2 has C/D):
David Howells108b42b2006-03-31 16:00:29 +01002460
2461 :
2462 : +--------+
2463 : +---------+ | |
2464 +--------+ : +--->| Cache A |<------->| |
2465 | | : | +---------+ | |
2466 | CPU 1 |<---+ | |
2467 | | : | +---------+ | |
2468 +--------+ : +--->| Cache B |<------->| |
2469 : +---------+ | |
2470 : | Memory |
2471 : +---------+ | System |
2472 +--------+ : +--->| Cache C |<------->| |
2473 | | : | +---------+ | |
2474 | CPU 2 |<---+ | |
2475 | | : | +---------+ | |
2476 +--------+ : +--->| Cache D |<------->| |
2477 : +---------+ | |
2478 : +--------+
2479 :
2480
2481Imagine the system has the following properties:
2482
2483 (*) an odd-numbered cache line may be in cache A, cache C or it may still be
2484 resident in memory;
2485
2486 (*) an even-numbered cache line may be in cache B, cache D or it may still be
2487 resident in memory;
2488
2489 (*) whilst the CPU core is interrogating one cache, the other cache may be
2490 making use of the bus to access the rest of the system - perhaps to
2491 displace a dirty cacheline or to do a speculative load;
2492
2493 (*) each cache has a queue of operations that need to be applied to that cache
2494 to maintain coherency with the rest of the system;
2495
2496 (*) the coherency queue is not flushed by normal loads to lines already
2497 present in the cache, even though the contents of the queue may
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002498 potentially affect those loads.
David Howells108b42b2006-03-31 16:00:29 +01002499
2500Imagine, then, that two writes are made on the first CPU, with a write barrier
2501between them to guarantee that they will appear to reach that CPU's caches in
2502the requisite order:
2503
2504 CPU 1 CPU 2 COMMENT
2505 =============== =============== =======================================
2506 u == 0, v == 1 and p == &u, q == &u
2507 v = 2;
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002508 smp_wmb(); Make sure change to v is visible before
David Howells108b42b2006-03-31 16:00:29 +01002509 change to p
2510 <A:modify v=2> v is now in cache A exclusively
2511 p = &v;
2512 <B:modify p=&v> p is now in cache B exclusively
2513
2514The write memory barrier forces the other CPUs in the system to perceive that
2515the local CPU's caches have apparently been updated in the correct order. But
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002516now imagine that the second CPU wants to read those values:
David Howells108b42b2006-03-31 16:00:29 +01002517
2518 CPU 1 CPU 2 COMMENT
2519 =============== =============== =======================================
2520 ...
2521 q = p;
2522 x = *q;
2523
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002524The above pair of reads may then fail to happen in the expected order, as the
David Howells108b42b2006-03-31 16:00:29 +01002525cacheline holding p may get updated in one of the second CPU's caches whilst
2526the update to the cacheline holding v is delayed in the other of the second
2527CPU's caches by some other cache event:
2528
2529 CPU 1 CPU 2 COMMENT
2530 =============== =============== =======================================
2531 u == 0, v == 1 and p == &u, q == &u
2532 v = 2;
2533 smp_wmb();
2534 <A:modify v=2> <C:busy>
2535 <C:queue v=2>
Aneesh Kumar79afecf2006-05-15 09:44:36 -07002536 p = &v; q = p;
David Howells108b42b2006-03-31 16:00:29 +01002537 <D:request p>
2538 <B:modify p=&v> <D:commit p=&v>
Ingo Molnare0edc782013-11-22 11:24:53 +01002539 <D:read p>
David Howells108b42b2006-03-31 16:00:29 +01002540 x = *q;
2541 <C:read *q> Reads from v before v updated in cache
2542 <C:unbusy>
2543 <C:commit v=2>
2544
2545Basically, whilst both cachelines will be updated on CPU 2 eventually, there's
2546no guarantee that, without intervention, the order of update will be the same
2547as that committed on CPU 1.
2548
2549
2550To intervene, we need to interpolate a data dependency barrier or a read
2551barrier between the loads. This will force the cache to commit its coherency
2552queue before processing any further requests:
2553
2554 CPU 1 CPU 2 COMMENT
2555 =============== =============== =======================================
2556 u == 0, v == 1 and p == &u, q == &u
2557 v = 2;
2558 smp_wmb();
2559 <A:modify v=2> <C:busy>
2560 <C:queue v=2>
Paolo 'Blaisorblade' Giarrusso3fda9822006-10-19 23:28:19 -07002561 p = &v; q = p;
David Howells108b42b2006-03-31 16:00:29 +01002562 <D:request p>
2563 <B:modify p=&v> <D:commit p=&v>
Ingo Molnare0edc782013-11-22 11:24:53 +01002564 <D:read p>
David Howells108b42b2006-03-31 16:00:29 +01002565 smp_read_barrier_depends()
2566 <C:unbusy>
2567 <C:commit v=2>
2568 x = *q;
2569 <C:read *q> Reads from v after v updated in cache
2570
2571
2572This sort of problem can be encountered on DEC Alpha processors as they have a
2573split cache that improves performance by making better use of the data bus.
2574Whilst most CPUs do imply a data dependency barrier on the read when a memory
2575access depends on a read, not all do, so it may not be relied on.
2576
2577Other CPUs may also have split caches, but must coordinate between the various
Matt LaPlante3f6dee92006-10-03 22:45:33 +02002578cachelets for normal memory accesses. The semantics of the Alpha removes the
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002579need for coordination in the absence of memory barriers.
David Howells108b42b2006-03-31 16:00:29 +01002580
2581
2582CACHE COHERENCY VS DMA
2583----------------------
2584
2585Not all systems maintain cache coherency with respect to devices doing DMA. In
2586such cases, a device attempting DMA may obtain stale data from RAM because
2587dirty cache lines may be resident in the caches of various CPUs, and may not
2588have been written back to RAM yet. To deal with this, the appropriate part of
2589the kernel must flush the overlapping bits of cache on each CPU (and maybe
2590invalidate them as well).
2591
2592In addition, the data DMA'd to RAM by a device may be overwritten by dirty
2593cache lines being written back to RAM from a CPU's cache after the device has
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002594installed its own data, or cache lines present in the CPU's cache may simply
2595obscure the fact that RAM has been updated, until at such time as the cacheline
2596is discarded from the CPU's cache and reloaded. To deal with this, the
2597appropriate part of the kernel must invalidate the overlapping bits of the
David Howells108b42b2006-03-31 16:00:29 +01002598cache on each CPU.
2599
2600See Documentation/cachetlb.txt for more information on cache management.
2601
2602
2603CACHE COHERENCY VS MMIO
2604-----------------------
2605
2606Memory mapped I/O usually takes place through memory locations that are part of
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002607a window in the CPU's memory space that has different properties assigned than
David Howells108b42b2006-03-31 16:00:29 +01002608the usual RAM directed window.
2609
2610Amongst these properties is usually the fact that such accesses bypass the
2611caching entirely and go directly to the device buses. This means MMIO accesses
2612may, in effect, overtake accesses to cached memory that were emitted earlier.
2613A memory barrier isn't sufficient in such a case, but rather the cache must be
2614flushed between the cached memory write and the MMIO access if the two are in
2615any way dependent.
2616
2617
2618=========================
2619THE THINGS CPUS GET UP TO
2620=========================
2621
2622A programmer might take it for granted that the CPU will perform memory
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002623operations in exactly the order specified, so that if the CPU is, for example,
David Howells108b42b2006-03-31 16:00:29 +01002624given the following piece of code to execute:
2625
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002626 a = ACCESS_ONCE(*A);
2627 ACCESS_ONCE(*B) = b;
2628 c = ACCESS_ONCE(*C);
2629 d = ACCESS_ONCE(*D);
2630 ACCESS_ONCE(*E) = e;
David Howells108b42b2006-03-31 16:00:29 +01002631
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002632they would then expect that the CPU will complete the memory operation for each
David Howells108b42b2006-03-31 16:00:29 +01002633instruction before moving on to the next one, leading to a definite sequence of
2634operations as seen by external observers in the system:
2635
2636 LOAD *A, STORE *B, LOAD *C, LOAD *D, STORE *E.
2637
2638
2639Reality is, of course, much messier. With many CPUs and compilers, the above
2640assumption doesn't hold because:
2641
2642 (*) loads are more likely to need to be completed immediately to permit
2643 execution progress, whereas stores can often be deferred without a
2644 problem;
2645
2646 (*) loads may be done speculatively, and the result discarded should it prove
2647 to have been unnecessary;
2648
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002649 (*) loads may be done speculatively, leading to the result having been fetched
2650 at the wrong time in the expected sequence of events;
David Howells108b42b2006-03-31 16:00:29 +01002651
2652 (*) the order of the memory accesses may be rearranged to promote better use
2653 of the CPU buses and caches;
2654
2655 (*) loads and stores may be combined to improve performance when talking to
2656 memory or I/O hardware that can do batched accesses of adjacent locations,
2657 thus cutting down on transaction setup costs (memory and PCI devices may
2658 both be able to do this); and
2659
2660 (*) the CPU's data cache may affect the ordering, and whilst cache-coherency
2661 mechanisms may alleviate this - once the store has actually hit the cache
2662 - there's no guarantee that the coherency management will be propagated in
2663 order to other CPUs.
2664
2665So what another CPU, say, might actually observe from the above piece of code
2666is:
2667
2668 LOAD *A, ..., LOAD {*C,*D}, STORE *E, STORE *B
2669
2670 (Where "LOAD {*C,*D}" is a combined load)
2671
2672
2673However, it is guaranteed that a CPU will be self-consistent: it will see its
2674_own_ accesses appear to be correctly ordered, without the need for a memory
2675barrier. For instance with the following code:
2676
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002677 U = ACCESS_ONCE(*A);
2678 ACCESS_ONCE(*A) = V;
2679 ACCESS_ONCE(*A) = W;
2680 X = ACCESS_ONCE(*A);
2681 ACCESS_ONCE(*A) = Y;
2682 Z = ACCESS_ONCE(*A);
David Howells108b42b2006-03-31 16:00:29 +01002683
2684and assuming no intervention by an external influence, it can be assumed that
2685the final result will appear to be:
2686
2687 U == the original value of *A
2688 X == W
2689 Z == Y
2690 *A == Y
2691
2692The code above may cause the CPU to generate the full sequence of memory
2693accesses:
2694
2695 U=LOAD *A, STORE *A=V, STORE *A=W, X=LOAD *A, STORE *A=Y, Z=LOAD *A
2696
2697in that order, but, without intervention, the sequence may have almost any
2698combination of elements combined or discarded, provided the program's view of
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002699the world remains consistent. Note that ACCESS_ONCE() is -not- optional
2700in the above example, as there are architectures where a given CPU might
2701interchange successive loads to the same location. On such architectures,
2702ACCESS_ONCE() does whatever is necessary to prevent this, for example, on
2703Itanium the volatile casts used by ACCESS_ONCE() cause GCC to emit the
2704special ld.acq and st.rel instructions that prevent such reordering.
David Howells108b42b2006-03-31 16:00:29 +01002705
2706The compiler may also combine, discard or defer elements of the sequence before
2707the CPU even sees them.
2708
2709For instance:
2710
2711 *A = V;
2712 *A = W;
2713
2714may be reduced to:
2715
2716 *A = W;
2717
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002718since, without either a write barrier or an ACCESS_ONCE(), it can be
2719assumed that the effect of the storage of V to *A is lost. Similarly:
David Howells108b42b2006-03-31 16:00:29 +01002720
2721 *A = Y;
2722 Z = *A;
2723
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002724may, without a memory barrier or an ACCESS_ONCE(), be reduced to:
David Howells108b42b2006-03-31 16:00:29 +01002725
2726 *A = Y;
2727 Z = Y;
2728
2729and the LOAD operation never appear outside of the CPU.
2730
2731
2732AND THEN THERE'S THE ALPHA
2733--------------------------
2734
2735The DEC Alpha CPU is one of the most relaxed CPUs there is. Not only that,
2736some versions of the Alpha CPU have a split data cache, permitting them to have
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002737two semantically-related cache lines updated at separate times. This is where
David Howells108b42b2006-03-31 16:00:29 +01002738the data dependency barrier really becomes necessary as this synchronises both
2739caches with the memory coherence system, thus making it seem like pointer
2740changes vs new data occur in the right order.
2741
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002742The Alpha defines the Linux kernel's memory barrier model.
David Howells108b42b2006-03-31 16:00:29 +01002743
2744See the subsection on "Cache Coherency" above.
2745
2746
David Howells90fddab2010-03-24 09:43:00 +00002747============
2748EXAMPLE USES
2749============
2750
2751CIRCULAR BUFFERS
2752----------------
2753
2754Memory barriers can be used to implement circular buffering without the need
2755of a lock to serialise the producer with the consumer. See:
2756
2757 Documentation/circular-buffers.txt
2758
2759for details.
2760
2761
David Howells108b42b2006-03-31 16:00:29 +01002762==========
2763REFERENCES
2764==========
2765
2766Alpha AXP Architecture Reference Manual, Second Edition (Sites & Witek,
2767Digital Press)
2768 Chapter 5.2: Physical Address Space Characteristics
2769 Chapter 5.4: Caches and Write Buffers
2770 Chapter 5.5: Data Sharing
2771 Chapter 5.6: Read/Write Ordering
2772
2773AMD64 Architecture Programmer's Manual Volume 2: System Programming
2774 Chapter 7.1: Memory-Access Ordering
2775 Chapter 7.4: Buffering and Combining Memory Writes
2776
2777IA-32 Intel Architecture Software Developer's Manual, Volume 3:
2778System Programming Guide
2779 Chapter 7.1: Locked Atomic Operations
2780 Chapter 7.2: Memory Ordering
2781 Chapter 7.4: Serializing Instructions
2782
2783The SPARC Architecture Manual, Version 9
2784 Chapter 8: Memory Models
2785 Appendix D: Formal Specification of the Memory Models
2786 Appendix J: Programming with the Memory Models
2787
2788UltraSPARC Programmer Reference Manual
2789 Chapter 5: Memory Accesses and Cacheability
2790 Chapter 15: Sparc-V9 Memory Models
2791
2792UltraSPARC III Cu User's Manual
2793 Chapter 9: Memory Models
2794
2795UltraSPARC IIIi Processor User's Manual
2796 Chapter 8: Memory Models
2797
2798UltraSPARC Architecture 2005
2799 Chapter 9: Memory
2800 Appendix D: Formal Specifications of the Memory Models
2801
2802UltraSPARC T1 Supplement to the UltraSPARC Architecture 2005
2803 Chapter 8: Memory Models
2804 Appendix F: Caches and Cache Coherency
2805
2806Solaris Internals, Core Kernel Architecture, p63-68:
2807 Chapter 3.3: Hardware Considerations for Locks and
2808 Synchronization
2809
2810Unix Systems for Modern Architectures, Symmetric Multiprocessing and Caching
2811for Kernel Programmers:
2812 Chapter 13: Other Memory Models
2813
2814Intel Itanium Architecture Software Developer's Manual: Volume 1:
2815 Section 2.6: Speculation
2816 Section 4.4: Memory Access