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Greg Kroah-Hartmanb2441312017-11-01 15:07:57 +01001/* SPDX-License-Identifier: GPL-2.0 */
Linus Torvalds1da177e2005-04-16 15:20:36 -07002/*
3 * McKinley-optimized version of copy_page().
4 *
5 * Copyright (C) 2002 Hewlett-Packard Co
6 * David Mosberger <davidm@hpl.hp.com>
7 *
8 * Inputs:
9 * in0: address of target page
10 * in1: address of source page
11 * Output:
12 * no return value
13 *
14 * General idea:
15 * - use regular loads and stores to prefetch data to avoid consuming M-slot just for
16 * lfetches => good for in-cache performance
17 * - avoid l2 bank-conflicts by not storing into the same 16-byte bank within a single
18 * cycle
19 *
20 * Principle of operation:
21 * First, note that L1 has a line-size of 64 bytes and L2 a line-size of 128 bytes.
22 * To avoid secondary misses in L2, we prefetch both source and destination with a line-size
23 * of 128 bytes. When both of these lines are in the L2 and the first half of the
24 * source line is in L1, we start copying the remaining words. The second half of the
25 * source line is prefetched in an earlier iteration, so that by the time we start
26 * accessing it, it's also present in the L1.
27 *
28 * We use a software-pipelined loop to control the overall operation. The pipeline
29 * has 2*PREFETCH_DIST+K stages. The first PREFETCH_DIST stages are used for prefetching
30 * source cache-lines. The second PREFETCH_DIST stages are used for prefetching destination
31 * cache-lines, the last K stages are used to copy the cache-line words not copied by
32 * the prefetches. The four relevant points in the pipelined are called A, B, C, D:
33 * p[A] is TRUE if a source-line should be prefetched, p[B] is TRUE if a destination-line
34 * should be prefetched, p[C] is TRUE if the second half of an L2 line should be brought
35 * into L1D and p[D] is TRUE if a cacheline needs to be copied.
36 *
37 * This all sounds very complicated, but thanks to the modulo-scheduled loop support,
38 * the resulting code is very regular and quite easy to follow (once you get the idea).
39 *
40 * As a secondary optimization, the first 2*PREFETCH_DIST iterations are implemented
41 * as the separate .prefetch_loop. Logically, this loop performs exactly like the
42 * main-loop (.line_copy), but has all known-to-be-predicated-off instructions removed,
43 * so that each loop iteration is faster (again, good for cached case).
44 *
45 * When reading the code, it helps to keep the following picture in mind:
46 *
47 * word 0 word 1
48 * +------+------+---
49 * | v[x] | t1 | ^
50 * | t2 | t3 | |
51 * | t4 | t5 | |
52 * | t6 | t7 | | 128 bytes
53 * | n[y] | t9 | | (L2 cache line)
54 * | t10 | t11 | |
55 * | t12 | t13 | |
56 * | t14 | t15 | v
57 * +------+------+---
58 *
59 * Here, v[x] is copied by the (memory) prefetch. n[y] is loaded at p[C]
60 * to fetch the second-half of the L2 cache line into L1, and the tX words are copied in
61 * an order that avoids bank conflicts.
62 */
63#include <asm/asmmacro.h>
64#include <asm/page.h>
Al Viroe007c532016-01-17 01:13:41 -050065#include <asm/export.h>
Linus Torvalds1da177e2005-04-16 15:20:36 -070066
67#define PREFETCH_DIST 8 // McKinley sustains 16 outstanding L2 misses (8 ld, 8 st)
68
69#define src0 r2
70#define src1 r3
71#define dst0 r9
72#define dst1 r10
73#define src_pre_mem r11
74#define dst_pre_mem r14
75#define src_pre_l2 r15
76#define dst_pre_l2 r16
77#define t1 r17
78#define t2 r18
79#define t3 r19
80#define t4 r20
81#define t5 t1 // alias!
82#define t6 t2 // alias!
83#define t7 t3 // alias!
84#define t9 t5 // alias!
85#define t10 t4 // alias!
86#define t11 t7 // alias!
87#define t12 t6 // alias!
88#define t14 t10 // alias!
89#define t13 r21
90#define t15 r22
91
92#define saved_lc r23
93#define saved_pr r24
94
95#define A 0
96#define B (PREFETCH_DIST)
97#define C (B + PREFETCH_DIST)
98#define D (C + 3)
99#define N (D + 1)
100#define Nrot ((N + 7) & ~7)
101
102GLOBAL_ENTRY(copy_page)
103 .prologue
104 alloc r8 = ar.pfs, 2, Nrot-2, 0, Nrot
105
106 .rotr v[2*PREFETCH_DIST], n[D-C+1]
107 .rotp p[N]
108
109 .save ar.lc, saved_lc
110 mov saved_lc = ar.lc
111 .save pr, saved_pr
112 mov saved_pr = pr
113 .body
114
115 mov src_pre_mem = in1
116 mov pr.rot = 0x10000
117 mov ar.ec = 1 // special unrolled loop
118
119 mov dst_pre_mem = in0
120 mov ar.lc = 2*PREFETCH_DIST - 1
121
122 add src_pre_l2 = 8*8, in1
123 add dst_pre_l2 = 8*8, in0
124 add src0 = 8, in1 // first t1 src
125 add src1 = 3*8, in1 // first t3 src
126 add dst0 = 8, in0 // first t1 dst
127 add dst1 = 3*8, in0 // first t3 dst
128 mov t1 = (PAGE_SIZE/128) - (2*PREFETCH_DIST) - 1
129 nop.m 0
130 nop.i 0
131 ;;
132 // same as .line_copy loop, but with all predicated-off instructions removed:
133.prefetch_loop:
134(p[A]) ld8 v[A] = [src_pre_mem], 128 // M0
135(p[B]) st8 [dst_pre_mem] = v[B], 128 // M2
136 br.ctop.sptk .prefetch_loop
137 ;;
138 cmp.eq p16, p0 = r0, r0 // reset p16 to 1 (br.ctop cleared it to zero)
139 mov ar.lc = t1 // with 64KB pages, t1 is too big to fit in 8 bits!
140 mov ar.ec = N // # of stages in pipeline
141 ;;
142.line_copy:
143(p[D]) ld8 t2 = [src0], 3*8 // M0
144(p[D]) ld8 t4 = [src1], 3*8 // M1
145(p[B]) st8 [dst_pre_mem] = v[B], 128 // M2 prefetch dst from memory
146(p[D]) st8 [dst_pre_l2] = n[D-C], 128 // M3 prefetch dst from L2
147 ;;
148(p[A]) ld8 v[A] = [src_pre_mem], 128 // M0 prefetch src from memory
149(p[C]) ld8 n[0] = [src_pre_l2], 128 // M1 prefetch src from L2
150(p[D]) st8 [dst0] = t1, 8 // M2
151(p[D]) st8 [dst1] = t3, 8 // M3
152 ;;
153(p[D]) ld8 t5 = [src0], 8
154(p[D]) ld8 t7 = [src1], 3*8
155(p[D]) st8 [dst0] = t2, 3*8
156(p[D]) st8 [dst1] = t4, 3*8
157 ;;
158(p[D]) ld8 t6 = [src0], 3*8
159(p[D]) ld8 t10 = [src1], 8
160(p[D]) st8 [dst0] = t5, 8
161(p[D]) st8 [dst1] = t7, 3*8
162 ;;
163(p[D]) ld8 t9 = [src0], 3*8
164(p[D]) ld8 t11 = [src1], 3*8
165(p[D]) st8 [dst0] = t6, 3*8
166(p[D]) st8 [dst1] = t10, 8
167 ;;
168(p[D]) ld8 t12 = [src0], 8
169(p[D]) ld8 t14 = [src1], 8
170(p[D]) st8 [dst0] = t9, 3*8
171(p[D]) st8 [dst1] = t11, 3*8
172 ;;
173(p[D]) ld8 t13 = [src0], 4*8
174(p[D]) ld8 t15 = [src1], 4*8
175(p[D]) st8 [dst0] = t12, 8
176(p[D]) st8 [dst1] = t14, 8
177 ;;
178(p[D-1])ld8 t1 = [src0], 8
179(p[D-1])ld8 t3 = [src1], 8
180(p[D]) st8 [dst0] = t13, 4*8
181(p[D]) st8 [dst1] = t15, 4*8
182 br.ctop.sptk .line_copy
183 ;;
184 mov ar.lc = saved_lc
185 mov pr = saved_pr, -1
186 br.ret.sptk.many rp
187END(copy_page)
Al Viroe007c532016-01-17 01:13:41 -0500188EXPORT_SYMBOL(copy_page)