| /* |
| * percent.c - Take percentage of a number |
| * |
| * Copyright (C) 2006 Theodore Ts'o <tytso@mit.edu> |
| * |
| * This file can be redistributed under the terms of the GNU Library General |
| * Public License |
| */ |
| |
| #include "e2p.h" |
| |
| #include <stdlib.h> |
| |
| /* |
| * We work really hard to calculate this accurately, while avoiding |
| * an overflow. "Is there a hyphen in anal-retentive?" :-) |
| */ |
| unsigned int e2p_percent(int percent, unsigned int base) |
| { |
| unsigned int mask = ~((1 << (sizeof(unsigned int) - 1) * 8) - 1); |
| |
| if (!percent) |
| return 0; |
| if (100 % percent == 0) |
| return base / (100 / percent); |
| if (mask & base) |
| return (base / 100) * percent; |
| return base * percent / 100; |
| } |
| |
| #ifdef DEBUG |
| #include <unistd.h> |
| #include <stdio.h> |
| |
| main(int argc, char **argv) |
| { |
| unsigned int base; |
| int percent; |
| char *p; |
| int log_block_size = 0; |
| |
| if (argc != 3) { |
| fprintf(stderr, "Usage: %s percent base\n", argv[0]); |
| exit(1); |
| } |
| |
| percent = strtoul(argv[1], &p, 0); |
| if (p[0] && p[1]) { |
| fprintf(stderr, "Bad percent: %s\n", argv[1]); |
| exit(1); |
| } |
| |
| base = strtoul(argv[2], &p, 0); |
| if (p[0] && p[1]) { |
| fprintf(stderr, "Bad base: %s\n", argv[2]); |
| exit(1); |
| } |
| |
| printf("%d percent of %u is %u.\n", percent, base, |
| e2p_percent(percent, base)); |
| |
| exit(0); |
| } |
| #endif |