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Chris Lattnerd80e9732002-04-28 00:47:11 +00001//===-- GCSE.cpp - SSA based Global Common Subexpr Elimination ------------===//
2//
3// This pass is designed to be a very quick global transformation that
4// eliminates global common subexpressions from a function. It does this by
5// examining the SSA value graph of the function, instead of doing slow, dense,
6// bit-vector computations.
7//
8// This pass works best if it is proceeded with a simple constant propogation
9// pass and an instruction combination pass because this pass does not do any
10// value numbering (in order to be speedy).
11//
12// This pass does not attempt to CSE load instructions, because it does not use
13// pointer analysis to determine when it is safe.
14//
15//===----------------------------------------------------------------------===//
16
Chris Lattner022103b2002-05-07 20:03:00 +000017#include "llvm/Transforms/Scalar.h"
Chris Lattnerd80e9732002-04-28 00:47:11 +000018#include "llvm/InstrTypes.h"
19#include "llvm/iMemory.h"
20#include "llvm/Analysis/Dominators.h"
21#include "llvm/Support/InstVisitor.h"
22#include "llvm/Support/InstIterator.h"
Chris Lattner3dec1f22002-05-10 15:38:35 +000023#include "Support/StatisticReporter.h"
Chris Lattnerd80e9732002-04-28 00:47:11 +000024#include <algorithm>
Chris Lattnerd80e9732002-04-28 00:47:11 +000025
Chris Lattner3dec1f22002-05-10 15:38:35 +000026static Statistic<> NumInstRemoved("gcse\t\t- Number of instructions removed");
27
Chris Lattnerd80e9732002-04-28 00:47:11 +000028namespace {
29 class GCSE : public FunctionPass, public InstVisitor<GCSE, bool> {
30 set<Instruction*> WorkList;
31 DominatorSet *DomSetInfo;
32 ImmediateDominators *ImmDominator;
33 public:
Chris Lattner96c466b2002-04-29 14:57:45 +000034 const char *getPassName() const {
35 return "Global Common Subexpression Elimination";
36 }
37
Chris Lattnerd80e9732002-04-28 00:47:11 +000038 virtual bool runOnFunction(Function *F);
39
40 // Visitation methods, these are invoked depending on the type of
41 // instruction being checked. They should return true if a common
42 // subexpression was folded.
43 //
44 bool visitUnaryOperator(Instruction *I);
45 bool visitBinaryOperator(Instruction *I);
46 bool visitGetElementPtrInst(GetElementPtrInst *I);
47 bool visitCastInst(CastInst *I){return visitUnaryOperator((Instruction*)I);}
48 bool visitShiftInst(ShiftInst *I) {
49 return visitBinaryOperator((Instruction*)I);
50 }
51 bool visitInstruction(Instruction *) { return false; }
52
53 private:
54 void ReplaceInstWithInst(Instruction *First, BasicBlock::iterator SI);
55 void CommonSubExpressionFound(Instruction *I, Instruction *Other);
56
57 // This transformation requires dominator and immediate dominator info
58 virtual void getAnalysisUsage(AnalysisUsage &AU) const {
Chris Lattner97e52e42002-04-28 21:27:06 +000059 AU.preservesCFG();
Chris Lattnerd80e9732002-04-28 00:47:11 +000060 AU.addRequired(DominatorSet::ID);
61 AU.addRequired(ImmediateDominators::ID);
62 }
63 };
64}
65
66// createGCSEPass - The public interface to this file...
67Pass *createGCSEPass() { return new GCSE(); }
68
69
70// GCSE::runOnFunction - This is the main transformation entry point for a
71// function.
72//
73bool GCSE::runOnFunction(Function *F) {
74 bool Changed = false;
75
76 DomSetInfo = &getAnalysis<DominatorSet>();
77 ImmDominator = &getAnalysis<ImmediateDominators>();
78
79 // Step #1: Add all instructions in the function to the worklist for
80 // processing. All of the instructions are considered to be our
81 // subexpressions to eliminate if possible.
82 //
83 WorkList.insert(inst_begin(F), inst_end(F));
84
85 // Step #2: WorkList processing. Iterate through all of the instructions,
86 // checking to see if there are any additionally defined subexpressions in the
87 // program. If so, eliminate them!
88 //
89 while (!WorkList.empty()) {
90 Instruction *I = *WorkList.begin(); // Get an instruction from the worklist
91 WorkList.erase(WorkList.begin());
92
93 // Visit the instruction, dispatching to the correct visit function based on
94 // the instruction type. This does the checking.
95 //
96 Changed |= visit(I);
97 }
98
99 // When the worklist is empty, return whether or not we changed anything...
100 return Changed;
101}
102
103
104// ReplaceInstWithInst - Destroy the instruction pointed to by SI, making all
105// uses of the instruction use First now instead.
106//
107void GCSE::ReplaceInstWithInst(Instruction *First, BasicBlock::iterator SI) {
108 Instruction *Second = *SI;
Chris Lattner8b054c02002-04-29 16:20:25 +0000109
110 //cerr << "DEL " << (void*)Second << Second;
Chris Lattnerd80e9732002-04-28 00:47:11 +0000111
112 // Add the first instruction back to the worklist
113 WorkList.insert(First);
114
115 // Add all uses of the second instruction to the worklist
116 for (Value::use_iterator UI = Second->use_begin(), UE = Second->use_end();
117 UI != UE; ++UI)
118 WorkList.insert(cast<Instruction>(*UI));
119
120 // Make all users of 'Second' now use 'First'
121 Second->replaceAllUsesWith(First);
122
123 // Erase the second instruction from the program
124 delete Second->getParent()->getInstList().remove(SI);
125}
126
127// CommonSubExpressionFound - The two instruction I & Other have been found to
128// be common subexpressions. This function is responsible for eliminating one
129// of them, and for fixing the worklist to be correct.
130//
131void GCSE::CommonSubExpressionFound(Instruction *I, Instruction *Other) {
132 // I has already been removed from the worklist, Other needs to be.
Chris Lattner8b054c02002-04-29 16:20:25 +0000133 assert(I != Other && WorkList.count(I) == 0 && "I shouldn't be on worklist!");
134
135 WorkList.erase(Other); // Other may not actually be on the worklist anymore...
Chris Lattnerd80e9732002-04-28 00:47:11 +0000136
Chris Lattner3dec1f22002-05-10 15:38:35 +0000137 ++NumInstRemoved; // Keep track of number of instructions eliminated
138
Chris Lattnerd80e9732002-04-28 00:47:11 +0000139 // Handle the easy case, where both instructions are in the same basic block
140 BasicBlock *BB1 = I->getParent(), *BB2 = Other->getParent();
141 if (BB1 == BB2) {
142 // Eliminate the second occuring instruction. Add all uses of the second
143 // instruction to the worklist.
144 //
145 // Scan the basic block looking for the "first" instruction
146 BasicBlock::iterator BI = BB1->begin();
147 while (*BI != I && *BI != Other) {
148 ++BI;
149 assert(BI != BB1->end() && "Instructions not found in parent BB!");
150 }
151
152 // Keep track of which instructions occurred first & second
153 Instruction *First = *BI;
154 Instruction *Second = I != First ? I : Other; // Get iterator to second inst
155 BI = find(BI, BB1->end(), Second);
156 assert(BI != BB1->end() && "Second instruction not found in parent block!");
157
158 // Destroy Second, using First instead.
159 ReplaceInstWithInst(First, BI);
160
161 // Otherwise, the two instructions are in different basic blocks. If one
162 // dominates the other instruction, we can simply use it
163 //
164 } else if (DomSetInfo->dominates(BB1, BB2)) { // I dom Other?
165 BasicBlock::iterator BI = find(BB2->begin(), BB2->end(), Other);
166 assert(BI != BB2->end() && "Other not in parent basic block!");
167 ReplaceInstWithInst(I, BI);
168 } else if (DomSetInfo->dominates(BB2, BB1)) { // Other dom I?
169 BasicBlock::iterator BI = find(BB1->begin(), BB1->end(), I);
170 assert(BI != BB1->end() && "I not in parent basic block!");
171 ReplaceInstWithInst(Other, BI);
172 } else {
173 // Handle the most general case now. In this case, neither I dom Other nor
174 // Other dom I. Because we are in SSA form, we are guaranteed that the
175 // operands of the two instructions both dominate the uses, so we _know_
176 // that there must exist a block that dominates both instructions (if the
177 // operands of the instructions are globals or constants, worst case we
178 // would get the entry node of the function). Search for this block now.
179 //
180
181 // Search up the immediate dominator chain of BB1 for the shared dominator
182 BasicBlock *SharedDom = (*ImmDominator)[BB1];
183 while (!DomSetInfo->dominates(SharedDom, BB2))
184 SharedDom = (*ImmDominator)[SharedDom];
185
186 // At this point, shared dom must dominate BOTH BB1 and BB2...
187 assert(SharedDom && DomSetInfo->dominates(SharedDom, BB1) &&
188 DomSetInfo->dominates(SharedDom, BB2) && "Dominators broken!");
189
190 // Rip 'I' out of BB1, and move it to the end of SharedDom.
191 BB1->getInstList().remove(I);
192 SharedDom->getInstList().insert(SharedDom->end()-1, I);
193
194 // Eliminate 'Other' now.
195 BasicBlock::iterator BI = find(BB2->begin(), BB2->end(), Other);
196 assert(BI != BB2->end() && "I not in parent basic block!");
197 ReplaceInstWithInst(I, BI);
198 }
199}
200
201//===----------------------------------------------------------------------===//
202//
203// Visitation methods, these are invoked depending on the type of instruction
204// being checked. They should return true if a common subexpression was folded.
205//
206//===----------------------------------------------------------------------===//
207
208bool GCSE::visitUnaryOperator(Instruction *I) {
209 Value *Op = I->getOperand(0);
210 Function *F = I->getParent()->getParent();
211
212 for (Value::use_iterator UI = Op->use_begin(), UE = Op->use_end();
213 UI != UE; ++UI)
214 if (Instruction *Other = dyn_cast<Instruction>(*UI))
215 // Check to see if this new binary operator is not I, but same operand...
216 if (Other != I && Other->getOpcode() == I->getOpcode() &&
217 Other->getOperand(0) == Op && // Is the operand the same?
218 // Is it embeded in the same function? (This could be false if LHS
219 // is a constant or global!)
220 Other->getParent()->getParent() == F &&
221
222 // Check that the types are the same, since this code handles casts...
223 Other->getType() == I->getType()) {
224
225 // These instructions are identical. Handle the situation.
226 CommonSubExpressionFound(I, Other);
227 return true; // One instruction eliminated!
228 }
229
230 return false;
231}
232
233bool GCSE::visitBinaryOperator(Instruction *I) {
234 Value *LHS = I->getOperand(0), *RHS = I->getOperand(1);
235 Function *F = I->getParent()->getParent();
236
237 for (Value::use_iterator UI = LHS->use_begin(), UE = LHS->use_end();
238 UI != UE; ++UI)
239 if (Instruction *Other = dyn_cast<Instruction>(*UI))
240 // Check to see if this new binary operator is not I, but same operand...
241 if (Other != I && Other->getOpcode() == I->getOpcode() &&
242 // Are the LHS and RHS the same?
243 Other->getOperand(0) == LHS && Other->getOperand(1) == RHS &&
244 // Is it embeded in the same function? (This could be false if LHS
245 // is a constant or global!)
246 Other->getParent()->getParent() == F) {
247
248 // These instructions are identical. Handle the situation.
249 CommonSubExpressionFound(I, Other);
250 return true; // One instruction eliminated!
251 }
252
253 return false;
254}
255
256bool GCSE::visitGetElementPtrInst(GetElementPtrInst *I) {
257 Value *Op = I->getOperand(0);
258 Function *F = I->getParent()->getParent();
259
260 for (Value::use_iterator UI = Op->use_begin(), UE = Op->use_end();
261 UI != UE; ++UI)
262 if (GetElementPtrInst *Other = dyn_cast<GetElementPtrInst>(*UI))
263 // Check to see if this new binary operator is not I, but same operand...
264 if (Other != I && Other->getParent()->getParent() == F &&
265 Other->getType() == I->getType()) {
266
267 // Check to see that all operators past the 0th are the same...
268 unsigned i = 1, e = I->getNumOperands();
269 for (; i != e; ++i)
270 if (I->getOperand(i) != Other->getOperand(i)) break;
271
272 if (i == e) {
273 // These instructions are identical. Handle the situation.
274 CommonSubExpressionFound(I, Other);
275 return true; // One instruction eliminated!
276 }
277 }
278
279 return false;
280}