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Dan Gohmanf17a25c2007-07-18 16:29:46 +00001; This is the test case taken from appel's book that illustrates a hard case
2; that SCCP gets right. BB3 should be completely eliminated.
3;
Tanya Lattnerba93e2d2008-03-19 04:14:49 +00004; RUN: llvm-as < %s | opt -sccp -constprop -dce -simplifycfg | \
Dan Gohmanf17a25c2007-07-18 16:29:46 +00005; RUN: llvm-dis | not grep BB3
6
Tanya Lattnerba93e2d2008-03-19 04:14:49 +00007define i32 @testfunction(i32 %i0, i32 %j0) {
Dan Gohmanf17a25c2007-07-18 16:29:46 +00008BB1:
9 br label %BB2
Tanya Lattnerba93e2d2008-03-19 04:14:49 +000010BB2: ; preds = %BB7, %BB1
11 %j2 = phi i32 [ %j4, %BB7 ], [ 1, %BB1 ] ; <i32> [#uses=2]
12 %k2 = phi i32 [ %k4, %BB7 ], [ 0, %BB1 ] ; <i32> [#uses=4]
13 %kcond = icmp slt i32 %k2, 100 ; <i1> [#uses=1]
14 br i1 %kcond, label %BB3, label %BB4
15BB3: ; preds = %BB2
16 %jcond = icmp slt i32 %j2, 20 ; <i1> [#uses=1]
17 br i1 %jcond, label %BB5, label %BB6
18BB4: ; preds = %BB2
19 ret i32 %j2
20BB5: ; preds = %BB3
21 %k3 = add i32 %k2, 1 ; <i32> [#uses=1]
Dan Gohmanf17a25c2007-07-18 16:29:46 +000022 br label %BB7
Tanya Lattnerba93e2d2008-03-19 04:14:49 +000023BB6: ; preds = %BB3
24 %k5 = add i32 %k2, 1 ; <i32> [#uses=1]
Dan Gohmanf17a25c2007-07-18 16:29:46 +000025 br label %BB7
Tanya Lattnerba93e2d2008-03-19 04:14:49 +000026BB7: ; preds = %BB6, %BB5
27 %j4 = phi i32 [ 1, %BB5 ], [ %k2, %BB6 ] ; <i32> [#uses=1]
28 %k4 = phi i32 [ %k3, %BB5 ], [ %k5, %BB6 ] ; <i32> [#uses=1]
Dan Gohmanf17a25c2007-07-18 16:29:46 +000029 br label %BB2
30}
Tanya Lattnerba93e2d2008-03-19 04:14:49 +000031