blob: b6489ef918de04a2018c089617c5a36cbbbe7ca7 [file] [log] [blame]
Brian Paul9abbeda2009-09-16 19:33:01 -06001/*
2 * Copyright (C) 2009 VMware, Inc. All Rights Reserved.
3 *
4 * Permission is hereby granted, free of charge, to any person obtaining a
5 * copy of this software and associated documentation files (the "Software"),
6 * to deal in the Software without restriction, including without limitation
7 * the rights to use, copy, modify, merge, publish, distribute, sublicense,
8 * and/or sell copies of the Software, and to permit persons to whom the
9 * Software is furnished to do so, subject to the following conditions:
10 *
11 * The above copyright notice and this permission notice shall be included
12 * in all copies or substantial portions of the Software.
13 *
14 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS
15 * OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
16 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL
17 * VMWARE BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN
18 * AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN
19 * CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
20 */
21
22/**
23 * Common perf code. This should be re-usable with other APIs.
24 */
25
26#include "common.h"
27#include "glmain.h"
28
Keith Whitwelle95a3a22009-09-17 12:08:04 +010029#include <stdio.h>
30#include <stdlib.h>
31#include <stdarg.h>
32
Vinson Lee017fae02009-10-05 18:42:58 -070033#if defined(_MSC_VER)
34#define snprintf _snprintf
35#endif
36
Keith Whitwelle95a3a22009-09-17 12:08:04 +010037
38/* Need to add a fflush windows console with mingw, otherwise nothing
39 * shows up until program exit. May want to add logging here.
40 */
41void
42perf_printf(const char *format, ...)
43{
44 va_list ap;
45 va_start(ap, format);
46
47 fflush(stdout);
48 vfprintf(stdout, format, ap);
49 fflush(stdout);
50
51 va_end(ap);
52}
53
54
Brian Paul9abbeda2009-09-16 19:33:01 -060055
56/**
57 * Run function 'f' for enough iterations to reach a steady state.
58 * Return the rate (iterations/second).
59 */
60double
61PerfMeasureRate(PerfRateFunc f)
62{
63 const double minDuration = 1.0;
64 double rate = 0.0, prevRate = 0.0;
65 unsigned subiters;
66
67 /* Compute initial number of iterations to try.
68 * If the test function is pretty slow this helps to avoid
69 * extraordarily long run times.
70 */
71 subiters = 2;
72 {
73 const double t0 = PerfGetTime();
74 double t1;
75 do {
76 f(subiters); /* call the rendering function */
77 t1 = PerfGetTime();
78 subiters *= 2;
79 } while (t1 - t0 < 0.1 * minDuration);
80 }
Keith Whitwelle95a3a22009-09-17 12:08:04 +010081 /*perf_printf("initial subIters = %u\n", subiters);*/
Brian Paul9abbeda2009-09-16 19:33:01 -060082
83 while (1) {
84 const double t0 = PerfGetTime();
85 unsigned iters = 0;
86 double t1;
87
88 do {
89 f(subiters); /* call the rendering function */
90 t1 = PerfGetTime();
91 iters += subiters;
92 } while (t1 - t0 < minDuration);
93
94 rate = iters / (t1 - t0);
95
96 if (0)
Keith Whitwelle95a3a22009-09-17 12:08:04 +010097 perf_printf("prevRate %f rate %f ratio %f iters %u\n",
Brian Paul9abbeda2009-09-16 19:33:01 -060098 prevRate, rate, rate/prevRate, iters);
99
100 /* Try and speed the search up by skipping a few steps:
101 */
102 if (rate > prevRate * 1.6)
103 subiters *= 8;
104 else if (rate > prevRate * 1.2)
105 subiters *= 4;
106 else if (rate > prevRate * 1.05)
107 subiters *= 2;
108 else
109 break;
110
111 prevRate = rate;
112 }
113
114 if (0)
Keith Whitwelle95a3a22009-09-17 12:08:04 +0100115 perf_printf("%s returning iters %u rate %f\n", __FUNCTION__, subiters, rate);
Brian Paul9abbeda2009-09-16 19:33:01 -0600116 return rate;
117}
118
119
Keith Whitwelled63bd62009-09-21 15:51:26 +0100120/* Note static buffer, can only use once per printf.
121 */
122const char *
123PerfHumanFloat( double d )
124{
125 static char buf[80];
126
127 if (d > 1000000000.0)
128 snprintf(buf, sizeof(buf), "%.1f billion", d / 1000000000.0);
129 else if (d > 1000000.0)
130 snprintf(buf, sizeof(buf), "%.1f million", d / 1000000.0);
131 else if (d > 1000.0)
132 snprintf(buf, sizeof(buf), "%.1f thousand", d / 1000.0);
133 else
134 snprintf(buf, sizeof(buf), "%.1f", d);
135
136 return buf;
137}