| ## Module statistics.py |
| ## |
| ## Copyright (c) 2013 Steven D'Aprano <steve+python@pearwood.info>. |
| ## |
| ## Licensed under the Apache License, Version 2.0 (the "License"); |
| ## you may not use this file except in compliance with the License. |
| ## You may obtain a copy of the License at |
| ## |
| ## http://www.apache.org/licenses/LICENSE-2.0 |
| ## |
| ## Unless required by applicable law or agreed to in writing, software |
| ## distributed under the License is distributed on an "AS IS" BASIS, |
| ## WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. |
| ## See the License for the specific language governing permissions and |
| ## limitations under the License. |
| |
| |
| """ |
| Basic statistics module. |
| |
| This module provides functions for calculating statistics of data, including |
| averages, variance, and standard deviation. |
| |
| Calculating averages |
| -------------------- |
| |
| ================== ============================================= |
| Function Description |
| ================== ============================================= |
| mean Arithmetic mean (average) of data. |
| median Median (middle value) of data. |
| median_low Low median of data. |
| median_high High median of data. |
| median_grouped Median, or 50th percentile, of grouped data. |
| mode Mode (most common value) of data. |
| ================== ============================================= |
| |
| Calculate the arithmetic mean ("the average") of data: |
| |
| >>> mean([-1.0, 2.5, 3.25, 5.75]) |
| 2.625 |
| |
| |
| Calculate the standard median of discrete data: |
| |
| >>> median([2, 3, 4, 5]) |
| 3.5 |
| |
| |
| Calculate the median, or 50th percentile, of data grouped into class intervals |
| centred on the data values provided. E.g. if your data points are rounded to |
| the nearest whole number: |
| |
| >>> median_grouped([2, 2, 3, 3, 3, 4]) #doctest: +ELLIPSIS |
| 2.8333333333... |
| |
| This should be interpreted in this way: you have two data points in the class |
| interval 1.5-2.5, three data points in the class interval 2.5-3.5, and one in |
| the class interval 3.5-4.5. The median of these data points is 2.8333... |
| |
| |
| Calculating variability or spread |
| --------------------------------- |
| |
| ================== ============================================= |
| Function Description |
| ================== ============================================= |
| pvariance Population variance of data. |
| variance Sample variance of data. |
| pstdev Population standard deviation of data. |
| stdev Sample standard deviation of data. |
| ================== ============================================= |
| |
| Calculate the standard deviation of sample data: |
| |
| >>> stdev([2.5, 3.25, 5.5, 11.25, 11.75]) #doctest: +ELLIPSIS |
| 4.38961843444... |
| |
| If you have previously calculated the mean, you can pass it as the optional |
| second argument to the four "spread" functions to avoid recalculating it: |
| |
| >>> data = [1, 2, 2, 4, 4, 4, 5, 6] |
| >>> mu = mean(data) |
| >>> pvariance(data, mu) |
| 2.5 |
| |
| |
| Exceptions |
| ---------- |
| |
| A single exception is defined: StatisticsError is a subclass of ValueError. |
| |
| """ |
| |
| __all__ = [ 'StatisticsError', |
| 'pstdev', 'pvariance', 'stdev', 'variance', |
| 'median', 'median_low', 'median_high', 'median_grouped', |
| 'mean', 'mode', |
| ] |
| |
| |
| import collections |
| import math |
| |
| from fractions import Fraction |
| from decimal import Decimal |
| from itertools import groupby |
| from bisect import bisect_left, bisect_right |
| |
| |
| |
| # === Exceptions === |
| |
| class StatisticsError(ValueError): |
| pass |
| |
| |
| # === Private utilities === |
| |
| def _sum(data, start=0): |
| """_sum(data [, start]) -> (type, sum, count) |
| |
| Return a high-precision sum of the given numeric data as a fraction, |
| together with the type to be converted to and the count of items. |
| |
| If optional argument ``start`` is given, it is added to the total. |
| If ``data`` is empty, ``start`` (defaulting to 0) is returned. |
| |
| |
| Examples |
| -------- |
| |
| >>> _sum([3, 2.25, 4.5, -0.5, 1.0], 0.75) |
| (<class 'float' ...>, Fraction(11, 1), 5) |
| |
| Some sources of round-off error will be avoided: |
| |
| >>> _sum([1e50, 1, -1e50] * 1000) # Built-in sum returns zero. |
| (<class 'float' ...>, Fraction(1000, 1), 3000) |
| |
| Fractions and Decimals are also supported: |
| |
| >>> from fractions import Fraction as F |
| >>> _sum([F(2, 3), F(7, 5), F(1, 4), F(5, 6)]) |
| (<class 'fractions.Fraction' ...>, Fraction(63, 20), 4) |
| |
| >>> from decimal import Decimal as D |
| >>> data = [D("0.1375"), D("0.2108"), D("0.3061"), D("0.0419")] |
| >>> _sum(data) |
| (<class 'decimal.Decimal' ...>, Fraction(6963, 10000), 4) |
| |
| Mixed types are currently treated as an error, except that int is |
| allowed. |
| """ |
| count = 0 |
| n, d = _exact_ratio(start) |
| partials = {d: n} |
| partials_get = partials.get |
| T = _coerce(int, type(start)) |
| for typ, values in groupby(data, type): |
| T = _coerce(T, typ) # or raise TypeError |
| for n,d in map(_exact_ratio, values): |
| count += 1 |
| partials[d] = partials_get(d, 0) + n |
| if None in partials: |
| # The sum will be a NAN or INF. We can ignore all the finite |
| # partials, and just look at this special one. |
| total = partials[None] |
| assert not _isfinite(total) |
| else: |
| # Sum all the partial sums using builtin sum. |
| # FIXME is this faster if we sum them in order of the denominator? |
| total = sum(Fraction(n, d) for d, n in sorted(partials.items())) |
| return (T, total, count) |
| |
| |
| def _isfinite(x): |
| try: |
| return x.is_finite() # Likely a Decimal. |
| except AttributeError: |
| return math.isfinite(x) # Coerces to float first. |
| |
| |
| def _coerce(T, S): |
| """Coerce types T and S to a common type, or raise TypeError. |
| |
| Coercion rules are currently an implementation detail. See the CoerceTest |
| test class in test_statistics for details. |
| """ |
| # See http://bugs.python.org/issue24068. |
| assert T is not bool, "initial type T is bool" |
| # If the types are the same, no need to coerce anything. Put this |
| # first, so that the usual case (no coercion needed) happens as soon |
| # as possible. |
| if T is S: return T |
| # Mixed int & other coerce to the other type. |
| if S is int or S is bool: return T |
| if T is int: return S |
| # If one is a (strict) subclass of the other, coerce to the subclass. |
| if issubclass(S, T): return S |
| if issubclass(T, S): return T |
| # Ints coerce to the other type. |
| if issubclass(T, int): return S |
| if issubclass(S, int): return T |
| # Mixed fraction & float coerces to float (or float subclass). |
| if issubclass(T, Fraction) and issubclass(S, float): |
| return S |
| if issubclass(T, float) and issubclass(S, Fraction): |
| return T |
| # Any other combination is disallowed. |
| msg = "don't know how to coerce %s and %s" |
| raise TypeError(msg % (T.__name__, S.__name__)) |
| |
| |
| def _exact_ratio(x): |
| """Return Real number x to exact (numerator, denominator) pair. |
| |
| >>> _exact_ratio(0.25) |
| (1, 4) |
| |
| x is expected to be an int, Fraction, Decimal or float. |
| """ |
| try: |
| # Optimise the common case of floats. We expect that the most often |
| # used numeric type will be builtin floats, so try to make this as |
| # fast as possible. |
| if type(x) is float or type(x) is Decimal: |
| return x.as_integer_ratio() |
| try: |
| # x may be an int, Fraction, or Integral ABC. |
| return (x.numerator, x.denominator) |
| except AttributeError: |
| try: |
| # x may be a float or Decimal subclass. |
| return x.as_integer_ratio() |
| except AttributeError: |
| # Just give up? |
| pass |
| except (OverflowError, ValueError): |
| # float NAN or INF. |
| assert not _isfinite(x) |
| return (x, None) |
| msg = "can't convert type '{}' to numerator/denominator" |
| raise TypeError(msg.format(type(x).__name__)) |
| |
| |
| def _convert(value, T): |
| """Convert value to given numeric type T.""" |
| if type(value) is T: |
| # This covers the cases where T is Fraction, or where value is |
| # a NAN or INF (Decimal or float). |
| return value |
| if issubclass(T, int) and value.denominator != 1: |
| T = float |
| try: |
| # FIXME: what do we do if this overflows? |
| return T(value) |
| except TypeError: |
| if issubclass(T, Decimal): |
| return T(value.numerator)/T(value.denominator) |
| else: |
| raise |
| |
| |
| def _counts(data): |
| # Generate a table of sorted (value, frequency) pairs. |
| table = collections.Counter(iter(data)).most_common() |
| if not table: |
| return table |
| # Extract the values with the highest frequency. |
| maxfreq = table[0][1] |
| for i in range(1, len(table)): |
| if table[i][1] != maxfreq: |
| table = table[:i] |
| break |
| return table |
| |
| |
| def _find_lteq(a, x): |
| 'Locate the leftmost value exactly equal to x' |
| i = bisect_left(a, x) |
| if i != len(a) and a[i] == x: |
| return i |
| raise ValueError |
| |
| |
| def _find_rteq(a, l, x): |
| 'Locate the rightmost value exactly equal to x' |
| i = bisect_right(a, x, lo=l) |
| if i != (len(a)+1) and a[i-1] == x: |
| return i-1 |
| raise ValueError |
| |
| # === Measures of central tendency (averages) === |
| |
| def mean(data): |
| """Return the sample arithmetic mean of data. |
| |
| >>> mean([1, 2, 3, 4, 4]) |
| 2.8 |
| |
| >>> from fractions import Fraction as F |
| >>> mean([F(3, 7), F(1, 21), F(5, 3), F(1, 3)]) |
| Fraction(13, 21) |
| |
| >>> from decimal import Decimal as D |
| >>> mean([D("0.5"), D("0.75"), D("0.625"), D("0.375")]) |
| Decimal('0.5625') |
| |
| If ``data`` is empty, StatisticsError will be raised. |
| """ |
| if iter(data) is data: |
| data = list(data) |
| n = len(data) |
| if n < 1: |
| raise StatisticsError('mean requires at least one data point') |
| T, total, count = _sum(data) |
| assert count == n |
| return _convert(total/n, T) |
| |
| |
| # FIXME: investigate ways to calculate medians without sorting? Quickselect? |
| def median(data): |
| """Return the median (middle value) of numeric data. |
| |
| When the number of data points is odd, return the middle data point. |
| When the number of data points is even, the median is interpolated by |
| taking the average of the two middle values: |
| |
| >>> median([1, 3, 5]) |
| 3 |
| >>> median([1, 3, 5, 7]) |
| 4.0 |
| |
| """ |
| data = sorted(data) |
| n = len(data) |
| if n == 0: |
| raise StatisticsError("no median for empty data") |
| if n%2 == 1: |
| return data[n//2] |
| else: |
| i = n//2 |
| return (data[i - 1] + data[i])/2 |
| |
| |
| def median_low(data): |
| """Return the low median of numeric data. |
| |
| When the number of data points is odd, the middle value is returned. |
| When it is even, the smaller of the two middle values is returned. |
| |
| >>> median_low([1, 3, 5]) |
| 3 |
| >>> median_low([1, 3, 5, 7]) |
| 3 |
| |
| """ |
| data = sorted(data) |
| n = len(data) |
| if n == 0: |
| raise StatisticsError("no median for empty data") |
| if n%2 == 1: |
| return data[n//2] |
| else: |
| return data[n//2 - 1] |
| |
| |
| def median_high(data): |
| """Return the high median of data. |
| |
| When the number of data points is odd, the middle value is returned. |
| When it is even, the larger of the two middle values is returned. |
| |
| >>> median_high([1, 3, 5]) |
| 3 |
| >>> median_high([1, 3, 5, 7]) |
| 5 |
| |
| """ |
| data = sorted(data) |
| n = len(data) |
| if n == 0: |
| raise StatisticsError("no median for empty data") |
| return data[n//2] |
| |
| |
| def median_grouped(data, interval=1): |
| """Return the 50th percentile (median) of grouped continuous data. |
| |
| >>> median_grouped([1, 2, 2, 3, 4, 4, 4, 4, 4, 5]) |
| 3.7 |
| >>> median_grouped([52, 52, 53, 54]) |
| 52.5 |
| |
| This calculates the median as the 50th percentile, and should be |
| used when your data is continuous and grouped. In the above example, |
| the values 1, 2, 3, etc. actually represent the midpoint of classes |
| 0.5-1.5, 1.5-2.5, 2.5-3.5, etc. The middle value falls somewhere in |
| class 3.5-4.5, and interpolation is used to estimate it. |
| |
| Optional argument ``interval`` represents the class interval, and |
| defaults to 1. Changing the class interval naturally will change the |
| interpolated 50th percentile value: |
| |
| >>> median_grouped([1, 3, 3, 5, 7], interval=1) |
| 3.25 |
| >>> median_grouped([1, 3, 3, 5, 7], interval=2) |
| 3.5 |
| |
| This function does not check whether the data points are at least |
| ``interval`` apart. |
| """ |
| data = sorted(data) |
| n = len(data) |
| if n == 0: |
| raise StatisticsError("no median for empty data") |
| elif n == 1: |
| return data[0] |
| # Find the value at the midpoint. Remember this corresponds to the |
| # centre of the class interval. |
| x = data[n//2] |
| for obj in (x, interval): |
| if isinstance(obj, (str, bytes)): |
| raise TypeError('expected number but got %r' % obj) |
| try: |
| L = x - interval/2 # The lower limit of the median interval. |
| except TypeError: |
| # Mixed type. For now we just coerce to float. |
| L = float(x) - float(interval)/2 |
| |
| # Uses bisection search to search for x in data with log(n) time complexity |
| # Find the position of leftmost occurrence of x in data |
| l1 = _find_lteq(data, x) |
| # Find the position of rightmost occurrence of x in data[l1...len(data)] |
| # Assuming always l1 <= l2 |
| l2 = _find_rteq(data, l1, x) |
| cf = l1 |
| f = l2 - l1 + 1 |
| return L + interval*(n/2 - cf)/f |
| |
| |
| def mode(data): |
| """Return the most common data point from discrete or nominal data. |
| |
| ``mode`` assumes discrete data, and returns a single value. This is the |
| standard treatment of the mode as commonly taught in schools: |
| |
| >>> mode([1, 1, 2, 3, 3, 3, 3, 4]) |
| 3 |
| |
| This also works with nominal (non-numeric) data: |
| |
| >>> mode(["red", "blue", "blue", "red", "green", "red", "red"]) |
| 'red' |
| |
| If there is not exactly one most common value, ``mode`` will raise |
| StatisticsError. |
| """ |
| # Generate a table of sorted (value, frequency) pairs. |
| table = _counts(data) |
| if len(table) == 1: |
| return table[0][0] |
| elif table: |
| raise StatisticsError( |
| 'no unique mode; found %d equally common values' % len(table) |
| ) |
| else: |
| raise StatisticsError('no mode for empty data') |
| |
| |
| # === Measures of spread === |
| |
| # See http://mathworld.wolfram.com/Variance.html |
| # http://mathworld.wolfram.com/SampleVariance.html |
| # http://en.wikipedia.org/wiki/Algorithms_for_calculating_variance |
| # |
| # Under no circumstances use the so-called "computational formula for |
| # variance", as that is only suitable for hand calculations with a small |
| # amount of low-precision data. It has terrible numeric properties. |
| # |
| # See a comparison of three computational methods here: |
| # http://www.johndcook.com/blog/2008/09/26/comparing-three-methods-of-computing-standard-deviation/ |
| |
| def _ss(data, c=None): |
| """Return sum of square deviations of sequence data. |
| |
| If ``c`` is None, the mean is calculated in one pass, and the deviations |
| from the mean are calculated in a second pass. Otherwise, deviations are |
| calculated from ``c`` as given. Use the second case with care, as it can |
| lead to garbage results. |
| """ |
| if c is None: |
| c = mean(data) |
| T, total, count = _sum((x-c)**2 for x in data) |
| # The following sum should mathematically equal zero, but due to rounding |
| # error may not. |
| U, total2, count2 = _sum((x-c) for x in data) |
| assert T == U and count == count2 |
| total -= total2**2/len(data) |
| assert not total < 0, 'negative sum of square deviations: %f' % total |
| return (T, total) |
| |
| |
| def variance(data, xbar=None): |
| """Return the sample variance of data. |
| |
| data should be an iterable of Real-valued numbers, with at least two |
| values. The optional argument xbar, if given, should be the mean of |
| the data. If it is missing or None, the mean is automatically calculated. |
| |
| Use this function when your data is a sample from a population. To |
| calculate the variance from the entire population, see ``pvariance``. |
| |
| Examples: |
| |
| >>> data = [2.75, 1.75, 1.25, 0.25, 0.5, 1.25, 3.5] |
| >>> variance(data) |
| 1.3720238095238095 |
| |
| If you have already calculated the mean of your data, you can pass it as |
| the optional second argument ``xbar`` to avoid recalculating it: |
| |
| >>> m = mean(data) |
| >>> variance(data, m) |
| 1.3720238095238095 |
| |
| This function does not check that ``xbar`` is actually the mean of |
| ``data``. Giving arbitrary values for ``xbar`` may lead to invalid or |
| impossible results. |
| |
| Decimals and Fractions are supported: |
| |
| >>> from decimal import Decimal as D |
| >>> variance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")]) |
| Decimal('31.01875') |
| |
| >>> from fractions import Fraction as F |
| >>> variance([F(1, 6), F(1, 2), F(5, 3)]) |
| Fraction(67, 108) |
| |
| """ |
| if iter(data) is data: |
| data = list(data) |
| n = len(data) |
| if n < 2: |
| raise StatisticsError('variance requires at least two data points') |
| T, ss = _ss(data, xbar) |
| return _convert(ss/(n-1), T) |
| |
| |
| def pvariance(data, mu=None): |
| """Return the population variance of ``data``. |
| |
| data should be an iterable of Real-valued numbers, with at least one |
| value. The optional argument mu, if given, should be the mean of |
| the data. If it is missing or None, the mean is automatically calculated. |
| |
| Use this function to calculate the variance from the entire population. |
| To estimate the variance from a sample, the ``variance`` function is |
| usually a better choice. |
| |
| Examples: |
| |
| >>> data = [0.0, 0.25, 0.25, 1.25, 1.5, 1.75, 2.75, 3.25] |
| >>> pvariance(data) |
| 1.25 |
| |
| If you have already calculated the mean of the data, you can pass it as |
| the optional second argument to avoid recalculating it: |
| |
| >>> mu = mean(data) |
| >>> pvariance(data, mu) |
| 1.25 |
| |
| This function does not check that ``mu`` is actually the mean of ``data``. |
| Giving arbitrary values for ``mu`` may lead to invalid or impossible |
| results. |
| |
| Decimals and Fractions are supported: |
| |
| >>> from decimal import Decimal as D |
| >>> pvariance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")]) |
| Decimal('24.815') |
| |
| >>> from fractions import Fraction as F |
| >>> pvariance([F(1, 4), F(5, 4), F(1, 2)]) |
| Fraction(13, 72) |
| |
| """ |
| if iter(data) is data: |
| data = list(data) |
| n = len(data) |
| if n < 1: |
| raise StatisticsError('pvariance requires at least one data point') |
| T, ss = _ss(data, mu) |
| return _convert(ss/n, T) |
| |
| |
| def stdev(data, xbar=None): |
| """Return the square root of the sample variance. |
| |
| See ``variance`` for arguments and other details. |
| |
| >>> stdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75]) |
| 1.0810874155219827 |
| |
| """ |
| var = variance(data, xbar) |
| try: |
| return var.sqrt() |
| except AttributeError: |
| return math.sqrt(var) |
| |
| |
| def pstdev(data, mu=None): |
| """Return the square root of the population variance. |
| |
| See ``pvariance`` for arguments and other details. |
| |
| >>> pstdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75]) |
| 0.986893273527251 |
| |
| """ |
| var = pvariance(data, mu) |
| try: |
| return var.sqrt() |
| except AttributeError: |
| return math.sqrt(var) |