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/*
* Copyright (c) 2000, 2003, Oracle and/or its affiliates. All rights reserved.
* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
*
* This code is free software; you can redistribute it and/or modify it
* under the terms of the GNU General Public License version 2 only, as
* published by the Free Software Foundation. Oracle designates this
* particular file as subject to the "Classpath" exception as provided
* by Oracle in the LICENSE file that accompanied this code.
*
* This code is distributed in the hope that it will be useful, but WITHOUT
* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
* FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
* version 2 for more details (a copy is included in the LICENSE file that
* accompanied this code).
*
* You should have received a copy of the GNU General Public License version
* 2 along with this work; if not, write to the Free Software Foundation,
* Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
*
* Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
* or visit www.oracle.com if you need additional information or have any
* questions.
*/
package javax.imageio.stream;
import java.util.ArrayList;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.IOException;
/**
* Package-visible class consolidating common code for
* {@code MemoryCacheImageInputStream} and
* {@code MemoryCacheImageOutputStream}.
* This class keeps an {@code ArrayList} of 8K blocks,
* loaded sequentially. Blocks may only be disposed of
* from the index 0 forward. As blocks are freed, the
* corresponding entries in the array list are set to
* {@code null}, but no compacting is performed.
* This allows the index for each block to never change,
* and the length of the cache is always the same as the
* total amount of data ever cached. Cached data is
* therefore always contiguous from the point of last
* disposal to the current length.
*
* <p> The total number of blocks resident in the cache must not
* exceed {@code Integer.MAX_VALUE}. In practice, the limit of
* available memory will be exceeded long before this becomes an
* issue, since a full cache would contain 8192*2^31 = 16 terabytes of
* data.
*
* A {@code MemoryCache} may be reused after a call
* to {@code reset()}.
*/
class MemoryCache {
private static final int BUFFER_LENGTH = 8192;
private ArrayList<byte[]> cache = new ArrayList<>();
private long cacheStart = 0L;
/**
* The largest position ever written to the cache.
*/
private long length = 0L;
private byte[] getCacheBlock(long blockNum) throws IOException {
long blockOffset = blockNum - cacheStart;
if (blockOffset > Integer.MAX_VALUE) {
// This can only happen when the cache hits 16 terabytes of
// contiguous data...
throw new IOException("Cache addressing limit exceeded!");
}
return cache.get((int)blockOffset);
}
/**
* Ensures that at least {@code pos} bytes are cached,
* or the end of the source is reached. The return value
* is equal to the smaller of {@code pos} and the
* length of the source.
*
* @throws IOException if there is no more memory for cache
*/
public long loadFromStream(InputStream stream, long pos)
throws IOException {
// We've already got enough data cached
if (pos < length) {
return pos;
}
int offset = (int)(length % BUFFER_LENGTH);
byte [] buf = null;
long len = pos - length;
if (offset != 0) {
buf = getCacheBlock(length/BUFFER_LENGTH);
}
while (len > 0) {
if (buf == null) {
try {
buf = new byte[BUFFER_LENGTH];
} catch (OutOfMemoryError e) {
throw new IOException("No memory left for cache!");
}
offset = 0;
}
int left = BUFFER_LENGTH - offset;
int nbytes = (int)Math.min(len, (long)left);
nbytes = stream.read(buf, offset, nbytes);
if (nbytes == -1) {
return length; // EOF
}
if (offset == 0) {
cache.add(buf);
}
len -= nbytes;
length += nbytes;
offset += nbytes;
if (offset >= BUFFER_LENGTH) {
// we've filled the current buffer, so a new one will be
// allocated next time around (and offset will be reset to 0)
buf = null;
}
}
return pos;
}
/**
* Writes out a portion of the cache to an {@code OutputStream}.
* This method preserves no state about the output stream, and does
* not dispose of any blocks containing bytes written. To dispose
* blocks, use {@link #disposeBefore disposeBefore()}.
*
* @exception IndexOutOfBoundsException if any portion of
* the requested data is not in the cache (including if {@code pos}
* is in a block already disposed), or if either {@code pos} or
* {@code len} is < 0.
* @throws IOException if there is an I/O exception while writing to the
* stream
*/
public void writeToStream(OutputStream stream, long pos, long len)
throws IOException {
if (pos + len > length) {
throw new IndexOutOfBoundsException("Argument out of cache");
}
if ((pos < 0) || (len < 0)) {
throw new IndexOutOfBoundsException("Negative pos or len");
}
if (len == 0) {
return;
}
long bufIndex = pos/BUFFER_LENGTH;
if (bufIndex < cacheStart) {
throw new IndexOutOfBoundsException("pos already disposed");
}
int offset = (int)(pos % BUFFER_LENGTH);
byte[] buf = getCacheBlock(bufIndex++);
while (len > 0) {
if (buf == null) {
buf = getCacheBlock(bufIndex++);
offset = 0;
}
int nbytes = (int)Math.min(len, (long)(BUFFER_LENGTH - offset));
stream.write(buf, offset, nbytes);
buf = null;
len -= nbytes;
}
}
/**
* Ensure that there is space to write a byte at the given position.
*
* throws IOException if there is no more memory left for cache
*/
private void pad(long pos) throws IOException {
long currIndex = cacheStart + cache.size() - 1;
long lastIndex = pos/BUFFER_LENGTH;
long numNewBuffers = lastIndex - currIndex;
for (long i = 0; i < numNewBuffers; i++) {
try {
cache.add(new byte[BUFFER_LENGTH]);
} catch (OutOfMemoryError e) {
throw new IOException("No memory left for cache!");
}
}
}
/**
* Overwrites and/or appends the cache from a byte array.
* The length of the cache will be extended as needed to hold
* the incoming data.
*
* @param b an array of bytes containing data to be written.
* @param off the starting offset within the data array.
* @param len the number of bytes to be written.
* @param pos the cache position at which to begin writing.
*
* @exception NullPointerException if {@code b} is {@code null}.
* @exception IndexOutOfBoundsException if {@code off},
* {@code len}, or {@code pos} are negative,
* or if {@code off+len > b.length}.
* @throws IOException if there is an I/O error while writing to the cache
*/
public void write(byte[] b, int off, int len, long pos)
throws IOException {
if (b == null) {
throw new NullPointerException("b == null!");
}
// Fix 4430357 - if off + len < 0, overflow occurred
if ((off < 0) || (len < 0) || (pos < 0) ||
(off + len > b.length) || (off + len < 0)) {
throw new IndexOutOfBoundsException();
}
// Ensure there is space for the incoming data
long lastPos = pos + len - 1;
if (lastPos >= length) {
pad(lastPos);
length = lastPos + 1;
}
// Copy the data into the cache, block by block
int offset = (int)(pos % BUFFER_LENGTH);
while (len > 0) {
byte[] buf = getCacheBlock(pos/BUFFER_LENGTH);
int nbytes = Math.min(len, BUFFER_LENGTH - offset);
System.arraycopy(b, off, buf, offset, nbytes);
pos += nbytes;
off += nbytes;
len -= nbytes;
offset = 0; // Always after the first time
}
}
/**
* Overwrites or appends a single byte to the cache.
* The length of the cache will be extended as needed to hold
* the incoming data.
*
* @param b an {@code int} whose 8 least significant bits
* will be written.
* @param pos the cache position at which to begin writing.
*
* @exception IndexOutOfBoundsException if {@code pos} is negative.
* @throws IOException if there is an I/O error while writing to the cache
*/
public void write(int b, long pos) throws IOException {
if (pos < 0) {
throw new ArrayIndexOutOfBoundsException("pos < 0");
}
// Ensure there is space for the incoming data
if (pos >= length) {
pad(pos);
length = pos + 1;
}
// Insert the data.
byte[] buf = getCacheBlock(pos/BUFFER_LENGTH);
int offset = (int)(pos % BUFFER_LENGTH);
buf[offset] = (byte)b;
}
/**
* Returns the total length of data that has been cached,
* regardless of whether any early blocks have been disposed.
* This value will only ever increase.
*/
public long getLength() {
return length;
}
/**
* Returns the single byte at the given position, as an
* {@code int}. Returns -1 if this position has
* not been cached or has been disposed.
*
* @throws IOException if an I/O error occurs while reading from the byte
* array
*/
public int read(long pos) throws IOException {
if (pos >= length) {
return -1;
}
byte[] buf = getCacheBlock(pos/BUFFER_LENGTH);
if (buf == null) {
return -1;
}
return buf[(int)(pos % BUFFER_LENGTH)] & 0xff;
}
/**
* Copy {@code len} bytes from the cache, starting
* at cache position {@code pos}, into the array
* {@code b} at offset {@code off}.
*
* @exception NullPointerException if b is {@code null}
* @exception IndexOutOfBoundsException if {@code off},
* {@code len} or {@code pos} are negative or if
* {@code off + len > b.length} or if any portion of the
* requested data is not in the cache (including if
* {@code pos} is in a block that has already been disposed).
* @throws IOException if an I/O exception occurs while reading from the
* byte array
*/
public void read(byte[] b, int off, int len, long pos)
throws IOException {
if (b == null) {
throw new NullPointerException("b == null!");
}
// Fix 4430357 - if off + len < 0, overflow occurred
if ((off < 0) || (len < 0) || (pos < 0) ||
(off + len > b.length) || (off + len < 0)) {
throw new IndexOutOfBoundsException();
}
if (pos + len > length) {
throw new IndexOutOfBoundsException();
}
long index = pos/BUFFER_LENGTH;
int offset = (int)pos % BUFFER_LENGTH;
while (len > 0) {
int nbytes = Math.min(len, BUFFER_LENGTH - offset);
byte[] buf = getCacheBlock(index++);
System.arraycopy(buf, offset, b, off, nbytes);
len -= nbytes;
off += nbytes;
offset = 0; // Always after the first time
}
}
/**
* Free the blocks up to the position {@code pos}.
* The byte at {@code pos} remains available.
*
* @exception IndexOutOfBoundsException if {@code pos}
* is in a block that has already been disposed.
*/
public void disposeBefore(long pos) {
long index = pos/BUFFER_LENGTH;
if (index < cacheStart) {
throw new IndexOutOfBoundsException("pos already disposed");
}
long numBlocks = Math.min(index - cacheStart, cache.size());
for (long i = 0; i < numBlocks; i++) {
cache.remove(0);
}
this.cacheStart = index;
}
/**
* Erase the entire cache contents and reset the length to 0.
* The cache object may subsequently be reused as though it had just
* been allocated.
*/
public void reset() {
cache.clear();
cacheStart = 0;
length = 0L;
}
}