| ; This test makes sure that add instructions are properly eliminated. |
| ; |
| ; This also tests that a subtract with a constant is properly converted |
| ; to a add w/negative constant |
| |
| ; RUN: as < %s | opt -instcombine -die | dis | grep-not add |
| |
| implementation |
| |
| int %test1(int %A) { |
| %B = add int %A, 0 |
| ret int %B |
| } |
| |
| int %test2(int %A) { |
| %B = add int %A, 5 |
| %C = add int %B, -5 |
| ret int %C |
| } |
| |
| int %test3(int %A) { |
| %B = add int %A, 5 |
| %C = sub int %B, 5 ;; This should get converted to an add |
| ret int %C |
| } |
| |
| int %test4(int %A, int %B) { |
| %C = sub int 0, %A |
| %D = add int %B, %C ; D = B + -A = B - A |
| ret int %D |
| } |
| |
| int %test5(int %A, int %B) { |
| %C = sub int 0, %A |
| %D = add int %C, %B ; D = -A + B = B - A |
| ret int %D |
| } |
| |
| int %test6(int %A) { |
| %B = mul int 7, %A |
| %C = add int %B, %A ; C = 7*A+A == 8*A == A << 3 |
| ret int %C |
| } |
| |
| int %test7(int %A) { |
| %B = mul int 7, %A |
| %C = add int %A, %B ; C = A+7*A == 8*A == A << 3 |
| ret int %C |
| } |
| |
| int %test8(int %A, int %B) { ; (A & C1)+(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0 |
| %A1 = and int %A, 7 |
| %B1 = and int %B, 128 |
| %C = add int %A1, %B1 |
| ret int %C |
| } |
| |