blob: 822de22093c85ea1c950a4e8afb35b127e5a15a3 [file] [log] [blame]
Krzysztof Parzyszek046090d2018-03-12 14:01:28 +00001; RUN: llc -march=hexagon -enable-aa-sched-mi < %s | FileCheck %s
2
3; The two memory addresses in the load and the memop below are trivially
4; non-aliasing. However, there are some cases where the scheduler cannot
5; determine this - in this case, it is because of the use of memops, that on the
6; surface. do not have only one mem operand. However, the backend knows MIs and
7; can step in and help some cases. In our case, if the base registers are the
8; same and the offsets different and the memory access size is such that
9; the two accesses won't overlap, we can tell the scheduler that there is no
10; dependence due to aliasing between the two instructions.
11; In the example below, this allows the load to be packetized with the memop.
12; CHECK: {
13; CHECK: r{{[0-9]*}} = memw(r{{[0-9]*}}+#4)
14; CHECK-NEXT: memw(r{{[0-9]*}}+#0) += #3
15; CHECK: }
16
17@g0 = common global [10 x i32] zeroinitializer, align 8
18
19; Function Attrs: nounwind
20define void @f0(i32* nocapture %a0) #0 {
21b0:
22 %v0 = load i32, i32* %a0, align 4, !tbaa !0
23 %v1 = add nsw i32 %v0, 3
24 store i32 %v1, i32* %a0, align 4, !tbaa !0
25 %v2 = getelementptr inbounds i32, i32* %a0, i32 1
26 %v3 = load i32, i32* %v2, align 4, !tbaa !0
27 store i32 %v3, i32* getelementptr inbounds ([10 x i32], [10 x i32]* @g0, i32 0, i32 0), align 8, !tbaa !0
28 ret void
29}
30
31attributes #0 = { nounwind "target-cpu"="hexagonv60" }
32
33!0 = !{!1, !1, i64 0}
34!1 = !{!"int", !2}
35!2 = !{!"omnipotent char", !3}
36!3 = !{!"Simple C/C++ TBAA"}