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Chris Lattner7bfa8b62002-04-18 17:35:39 +00001; This test makes sure that add instructions are properly eliminated.
Chris Lattner7bfa8b62002-04-18 17:35:39 +00002
Chris Lattnerb66f4242004-02-28 05:26:06 +00003; RUN: llvm-as < %s | opt -instcombine | llvm-dis | grep -v OK | not grep add
Chris Lattner7bfa8b62002-04-18 17:35:39 +00004
5implementation
6
Chris Lattnerde293ee2003-02-18 19:43:53 +00007int %test1(int %A) {
Chris Lattner7bfa8b62002-04-18 17:35:39 +00008 %B = add int %A, 0
9 ret int %B
Chris Lattnerde293ee2003-02-18 19:43:53 +000010}
Chris Lattner7bfa8b62002-04-18 17:35:39 +000011
Chris Lattnerde293ee2003-02-18 19:43:53 +000012int %test2(int %A) {
Chris Lattner7bfa8b62002-04-18 17:35:39 +000013 %B = add int %A, 5
14 %C = add int %B, -5
15 ret int %C
Chris Lattnerde293ee2003-02-18 19:43:53 +000016}
Chris Lattner7bfa8b62002-04-18 17:35:39 +000017
Chris Lattnerde293ee2003-02-18 19:43:53 +000018int %test3(int %A) {
Chris Lattner7bfa8b62002-04-18 17:35:39 +000019 %B = add int %A, 5
20 %C = sub int %B, 5 ;; This should get converted to an add
21 ret int %C
Chris Lattnerde293ee2003-02-18 19:43:53 +000022}
Chris Lattner7bfa8b62002-04-18 17:35:39 +000023
Chris Lattner2ae37b02003-02-18 19:43:21 +000024int %test4(int %A, int %B) {
Chris Lattnere0c3fbb2002-05-06 16:44:53 +000025 %C = sub int 0, %A
26 %D = add int %B, %C ; D = B + -A = B - A
27 ret int %D
28}
29
Chris Lattner2ae37b02003-02-18 19:43:21 +000030int %test5(int %A, int %B) {
Chris Lattnere0c3fbb2002-05-06 16:44:53 +000031 %C = sub int 0, %A
32 %D = add int %C, %B ; D = -A + B = B - A
33 ret int %D
34}
35
Chris Lattner39593402003-02-18 19:55:31 +000036int %test6(int %A) {
37 %B = mul int 7, %A
38 %C = add int %B, %A ; C = 7*A+A == 8*A == A << 3
39 ret int %C
40}
41
42int %test7(int %A) {
43 %B = mul int 7, %A
44 %C = add int %A, %B ; C = A+7*A == 8*A == A << 3
45 ret int %C
46}
47
Chris Lattnerdec13672003-03-10 23:52:54 +000048int %test8(int %A, int %B) { ; (A & C1)+(B & C2) -> (A & C1)|(B & C2) iff C1&C2 == 0
49 %A1 = and int %A, 7
50 %B1 = and int %B, 128
51 %C = add int %A1, %B1
52 ret int %C
53}
Chris Lattnercb269142003-03-11 00:10:59 +000054
Chris Lattnerdaff6442003-07-24 19:44:51 +000055int %test9(int %A) {
56 %B = shl int %A, ubyte 4
57 %C = add int %B, %B ; === shl int %A, 5
58 ret int %C
59}
Chris Lattner9b741f12003-08-13 05:27:57 +000060
61bool %test10(ubyte %A, ubyte %b) {
62 %B = add ubyte %A, %b
63 %c = setne ubyte %B, 0 ; === A != -b
64 ret bool %c
65}
66
67bool %test11(ubyte %A) {
68 %B = add ubyte %A, 255
69 %c = setne ubyte %B, 0 ; === A != 1
70 ret bool %c
71}
Chris Lattner895746a2003-08-13 19:01:09 +000072
73int %test12(int %A, int %B) {
74 %C_OK = add int %B, %A ; Should be transformed into shl A, 1
75 br label %X
76X:
77 %D = add int %C_OK, %A
78 ret int %D
79}
80
81int %test13(int %A, int %B, int %C) {
82 %D_OK = add int %A, %B
83 %E_OK = add int %D_OK, %C
84 %F = add int %E_OK, %A ;; shl A, 1
85 ret int %F
86}
87
88uint %test14(uint %offset, uint %difference) {
89 %tmp.2 = and uint %difference, 3
90 %tmp.3_OK = add uint %tmp.2, %offset
91 %tmp.5.mask = and uint %difference, 4294967292
92 %tmp.8 = add uint %tmp.3_OK, %tmp.5.mask ; == add %offset, %difference
93 ret uint %tmp.8
94}
95
Chris Lattnerdef041c2003-09-19 15:33:46 +000096ubyte %test15(ubyte %A) {
97 %B = add ubyte %A, 192 ; Does not effect result
98 %C = and ubyte %B, 16 ; Only one bit set
99 ret ubyte %C
100}
101
102ubyte %test16(ubyte %A) {
103 %B = add ubyte %A, 16 ; Turn this into a XOR
104 %C = and ubyte %B, 16 ; Only one bit set
105 ret ubyte %C
106}
107
Chris Lattnerd15f2732003-10-02 15:11:09 +0000108int %test17(int %A) {
109 %B = xor int %A, -1
110 %C = add int %B, 1 ; == sub int 0, %A
111 ret int %C
112}
113
114ubyte %test18(ubyte %A) {
115 %B = xor ubyte %A, 255
116 %C = add ubyte %B, 17 ; == sub ubyte 16, %A
117 ret ubyte %C
118}