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David Howells108b42b2006-03-31 16:00:29 +01001 ============================
2 LINUX KERNEL MEMORY BARRIERS
3 ============================
4
5By: David Howells <dhowells@redhat.com>
David Howells90fddab2010-03-24 09:43:00 +00006 Paul E. McKenney <paulmck@linux.vnet.ibm.com>
David Howells108b42b2006-03-31 16:00:29 +01007
8Contents:
9
10 (*) Abstract memory access model.
11
12 - Device operations.
13 - Guarantees.
14
15 (*) What are memory barriers?
16
17 - Varieties of memory barrier.
18 - What may not be assumed about memory barriers?
19 - Data dependency barriers.
20 - Control dependencies.
21 - SMP barrier pairing.
22 - Examples of memory barrier sequences.
David Howells670bd952006-06-10 09:54:12 -070023 - Read memory barriers vs load speculation.
Paul E. McKenney241e6662011-02-10 16:54:50 -080024 - Transitivity
David Howells108b42b2006-03-31 16:00:29 +010025
26 (*) Explicit kernel barriers.
27
28 - Compiler barrier.
Jarek Poplawski81fc6322007-05-23 13:58:20 -070029 - CPU memory barriers.
David Howells108b42b2006-03-31 16:00:29 +010030 - MMIO write barrier.
31
32 (*) Implicit kernel memory barriers.
33
34 - Locking functions.
35 - Interrupt disabling functions.
David Howells50fa6102009-04-28 15:01:38 +010036 - Sleep and wake-up functions.
David Howells108b42b2006-03-31 16:00:29 +010037 - Miscellaneous functions.
38
39 (*) Inter-CPU locking barrier effects.
40
41 - Locks vs memory accesses.
42 - Locks vs I/O accesses.
43
44 (*) Where are memory barriers needed?
45
46 - Interprocessor interaction.
47 - Atomic operations.
48 - Accessing devices.
49 - Interrupts.
50
51 (*) Kernel I/O barrier effects.
52
53 (*) Assumed minimum execution ordering model.
54
55 (*) The effects of the cpu cache.
56
57 - Cache coherency.
58 - Cache coherency vs DMA.
59 - Cache coherency vs MMIO.
60
61 (*) The things CPUs get up to.
62
63 - And then there's the Alpha.
64
David Howells90fddab2010-03-24 09:43:00 +000065 (*) Example uses.
66
67 - Circular buffers.
68
David Howells108b42b2006-03-31 16:00:29 +010069 (*) References.
70
71
72============================
73ABSTRACT MEMORY ACCESS MODEL
74============================
75
76Consider the following abstract model of the system:
77
78 : :
79 : :
80 : :
81 +-------+ : +--------+ : +-------+
82 | | : | | : | |
83 | | : | | : | |
84 | CPU 1 |<----->| Memory |<----->| CPU 2 |
85 | | : | | : | |
86 | | : | | : | |
87 +-------+ : +--------+ : +-------+
88 ^ : ^ : ^
89 | : | : |
90 | : | : |
91 | : v : |
92 | : +--------+ : |
93 | : | | : |
94 | : | | : |
95 +---------->| Device |<----------+
96 : | | :
97 : | | :
98 : +--------+ :
99 : :
100
101Each CPU executes a program that generates memory access operations. In the
102abstract CPU, memory operation ordering is very relaxed, and a CPU may actually
103perform the memory operations in any order it likes, provided program causality
104appears to be maintained. Similarly, the compiler may also arrange the
105instructions it emits in any order it likes, provided it doesn't affect the
106apparent operation of the program.
107
108So in the above diagram, the effects of the memory operations performed by a
109CPU are perceived by the rest of the system as the operations cross the
110interface between the CPU and rest of the system (the dotted lines).
111
112
113For example, consider the following sequence of events:
114
115 CPU 1 CPU 2
116 =============== ===============
117 { A == 1; B == 2 }
Alexey Dobriyan615cc2c2014-06-06 14:36:41 -0700118 A = 3; x = B;
119 B = 4; y = A;
David Howells108b42b2006-03-31 16:00:29 +0100120
121The set of accesses as seen by the memory system in the middle can be arranged
122in 24 different combinations:
123
124 STORE A=3, STORE B=4, x=LOAD A->3, y=LOAD B->4
125 STORE A=3, STORE B=4, y=LOAD B->4, x=LOAD A->3
126 STORE A=3, x=LOAD A->3, STORE B=4, y=LOAD B->4
127 STORE A=3, x=LOAD A->3, y=LOAD B->2, STORE B=4
128 STORE A=3, y=LOAD B->2, STORE B=4, x=LOAD A->3
129 STORE A=3, y=LOAD B->2, x=LOAD A->3, STORE B=4
130 STORE B=4, STORE A=3, x=LOAD A->3, y=LOAD B->4
131 STORE B=4, ...
132 ...
133
134and can thus result in four different combinations of values:
135
136 x == 1, y == 2
137 x == 1, y == 4
138 x == 3, y == 2
139 x == 3, y == 4
140
141
142Furthermore, the stores committed by a CPU to the memory system may not be
143perceived by the loads made by another CPU in the same order as the stores were
144committed.
145
146
147As a further example, consider this sequence of events:
148
149 CPU 1 CPU 2
150 =============== ===============
151 { A == 1, B == 2, C = 3, P == &A, Q == &C }
152 B = 4; Q = P;
153 P = &B D = *Q;
154
155There is an obvious data dependency here, as the value loaded into D depends on
156the address retrieved from P by CPU 2. At the end of the sequence, any of the
157following results are possible:
158
159 (Q == &A) and (D == 1)
160 (Q == &B) and (D == 2)
161 (Q == &B) and (D == 4)
162
163Note that CPU 2 will never try and load C into D because the CPU will load P
164into Q before issuing the load of *Q.
165
166
167DEVICE OPERATIONS
168-----------------
169
170Some devices present their control interfaces as collections of memory
171locations, but the order in which the control registers are accessed is very
172important. For instance, imagine an ethernet card with a set of internal
173registers that are accessed through an address port register (A) and a data
174port register (D). To read internal register 5, the following code might then
175be used:
176
177 *A = 5;
178 x = *D;
179
180but this might show up as either of the following two sequences:
181
182 STORE *A = 5, x = LOAD *D
183 x = LOAD *D, STORE *A = 5
184
185the second of which will almost certainly result in a malfunction, since it set
186the address _after_ attempting to read the register.
187
188
189GUARANTEES
190----------
191
192There are some minimal guarantees that may be expected of a CPU:
193
194 (*) On any given CPU, dependent memory accesses will be issued in order, with
195 respect to itself. This means that for:
196
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800197 ACCESS_ONCE(Q) = P; smp_read_barrier_depends(); D = ACCESS_ONCE(*Q);
David Howells108b42b2006-03-31 16:00:29 +0100198
199 the CPU will issue the following memory operations:
200
201 Q = LOAD P, D = LOAD *Q
202
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800203 and always in that order. On most systems, smp_read_barrier_depends()
204 does nothing, but it is required for DEC Alpha. The ACCESS_ONCE()
205 is required to prevent compiler mischief. Please note that you
206 should normally use something like rcu_dereference() instead of
207 open-coding smp_read_barrier_depends().
David Howells108b42b2006-03-31 16:00:29 +0100208
209 (*) Overlapping loads and stores within a particular CPU will appear to be
210 ordered within that CPU. This means that for:
211
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800212 a = ACCESS_ONCE(*X); ACCESS_ONCE(*X) = b;
David Howells108b42b2006-03-31 16:00:29 +0100213
214 the CPU will only issue the following sequence of memory operations:
215
216 a = LOAD *X, STORE *X = b
217
218 And for:
219
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800220 ACCESS_ONCE(*X) = c; d = ACCESS_ONCE(*X);
David Howells108b42b2006-03-31 16:00:29 +0100221
222 the CPU will only issue:
223
224 STORE *X = c, d = LOAD *X
225
Matt LaPlantefa00e7e2006-11-30 04:55:36 +0100226 (Loads and stores overlap if they are targeted at overlapping pieces of
David Howells108b42b2006-03-31 16:00:29 +0100227 memory).
228
229And there are a number of things that _must_ or _must_not_ be assumed:
230
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800231 (*) It _must_not_ be assumed that the compiler will do what you want with
232 memory references that are not protected by ACCESS_ONCE(). Without
233 ACCESS_ONCE(), the compiler is within its rights to do all sorts
Paul E. McKenney692118d2013-12-11 13:59:07 -0800234 of "creative" transformations, which are covered in the Compiler
235 Barrier section.
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800236
David Howells108b42b2006-03-31 16:00:29 +0100237 (*) It _must_not_ be assumed that independent loads and stores will be issued
238 in the order given. This means that for:
239
240 X = *A; Y = *B; *D = Z;
241
242 we may get any of the following sequences:
243
244 X = LOAD *A, Y = LOAD *B, STORE *D = Z
245 X = LOAD *A, STORE *D = Z, Y = LOAD *B
246 Y = LOAD *B, X = LOAD *A, STORE *D = Z
247 Y = LOAD *B, STORE *D = Z, X = LOAD *A
248 STORE *D = Z, X = LOAD *A, Y = LOAD *B
249 STORE *D = Z, Y = LOAD *B, X = LOAD *A
250
251 (*) It _must_ be assumed that overlapping memory accesses may be merged or
252 discarded. This means that for:
253
254 X = *A; Y = *(A + 4);
255
256 we may get any one of the following sequences:
257
258 X = LOAD *A; Y = LOAD *(A + 4);
259 Y = LOAD *(A + 4); X = LOAD *A;
260 {X, Y} = LOAD {*A, *(A + 4) };
261
262 And for:
263
Paul E. McKenneyf191eec2012-10-03 10:28:30 -0700264 *A = X; *(A + 4) = Y;
David Howells108b42b2006-03-31 16:00:29 +0100265
Paul E. McKenneyf191eec2012-10-03 10:28:30 -0700266 we may get any of:
David Howells108b42b2006-03-31 16:00:29 +0100267
Paul E. McKenneyf191eec2012-10-03 10:28:30 -0700268 STORE *A = X; STORE *(A + 4) = Y;
269 STORE *(A + 4) = Y; STORE *A = X;
270 STORE {*A, *(A + 4) } = {X, Y};
David Howells108b42b2006-03-31 16:00:29 +0100271
272
273=========================
274WHAT ARE MEMORY BARRIERS?
275=========================
276
277As can be seen above, independent memory operations are effectively performed
278in random order, but this can be a problem for CPU-CPU interaction and for I/O.
279What is required is some way of intervening to instruct the compiler and the
280CPU to restrict the order.
281
282Memory barriers are such interventions. They impose a perceived partial
David Howells2b948952006-06-25 05:48:49 -0700283ordering over the memory operations on either side of the barrier.
284
285Such enforcement is important because the CPUs and other devices in a system
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700286can use a variety of tricks to improve performance, including reordering,
David Howells2b948952006-06-25 05:48:49 -0700287deferral and combination of memory operations; speculative loads; speculative
288branch prediction and various types of caching. Memory barriers are used to
289override or suppress these tricks, allowing the code to sanely control the
290interaction of multiple CPUs and/or devices.
David Howells108b42b2006-03-31 16:00:29 +0100291
292
293VARIETIES OF MEMORY BARRIER
294---------------------------
295
296Memory barriers come in four basic varieties:
297
298 (1) Write (or store) memory barriers.
299
300 A write memory barrier gives a guarantee that all the STORE operations
301 specified before the barrier will appear to happen before all the STORE
302 operations specified after the barrier with respect to the other
303 components of the system.
304
305 A write barrier is a partial ordering on stores only; it is not required
306 to have any effect on loads.
307
David Howells6bc39272006-06-25 05:49:22 -0700308 A CPU can be viewed as committing a sequence of store operations to the
David Howells108b42b2006-03-31 16:00:29 +0100309 memory system as time progresses. All stores before a write barrier will
310 occur in the sequence _before_ all the stores after the write barrier.
311
312 [!] Note that write barriers should normally be paired with read or data
313 dependency barriers; see the "SMP barrier pairing" subsection.
314
315
316 (2) Data dependency barriers.
317
318 A data dependency barrier is a weaker form of read barrier. In the case
319 where two loads are performed such that the second depends on the result
320 of the first (eg: the first load retrieves the address to which the second
321 load will be directed), a data dependency barrier would be required to
322 make sure that the target of the second load is updated before the address
323 obtained by the first load is accessed.
324
325 A data dependency barrier is a partial ordering on interdependent loads
326 only; it is not required to have any effect on stores, independent loads
327 or overlapping loads.
328
329 As mentioned in (1), the other CPUs in the system can be viewed as
330 committing sequences of stores to the memory system that the CPU being
331 considered can then perceive. A data dependency barrier issued by the CPU
332 under consideration guarantees that for any load preceding it, if that
333 load touches one of a sequence of stores from another CPU, then by the
334 time the barrier completes, the effects of all the stores prior to that
335 touched by the load will be perceptible to any loads issued after the data
336 dependency barrier.
337
338 See the "Examples of memory barrier sequences" subsection for diagrams
339 showing the ordering constraints.
340
341 [!] Note that the first load really has to have a _data_ dependency and
342 not a control dependency. If the address for the second load is dependent
343 on the first load, but the dependency is through a conditional rather than
344 actually loading the address itself, then it's a _control_ dependency and
345 a full read barrier or better is required. See the "Control dependencies"
346 subsection for more information.
347
348 [!] Note that data dependency barriers should normally be paired with
349 write barriers; see the "SMP barrier pairing" subsection.
350
351
352 (3) Read (or load) memory barriers.
353
354 A read barrier is a data dependency barrier plus a guarantee that all the
355 LOAD operations specified before the barrier will appear to happen before
356 all the LOAD operations specified after the barrier with respect to the
357 other components of the system.
358
359 A read barrier is a partial ordering on loads only; it is not required to
360 have any effect on stores.
361
362 Read memory barriers imply data dependency barriers, and so can substitute
363 for them.
364
365 [!] Note that read barriers should normally be paired with write barriers;
366 see the "SMP barrier pairing" subsection.
367
368
369 (4) General memory barriers.
370
David Howells670bd952006-06-10 09:54:12 -0700371 A general memory barrier gives a guarantee that all the LOAD and STORE
372 operations specified before the barrier will appear to happen before all
373 the LOAD and STORE operations specified after the barrier with respect to
374 the other components of the system.
375
376 A general memory barrier is a partial ordering over both loads and stores.
David Howells108b42b2006-03-31 16:00:29 +0100377
378 General memory barriers imply both read and write memory barriers, and so
379 can substitute for either.
380
381
382And a couple of implicit varieties:
383
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100384 (5) ACQUIRE operations.
David Howells108b42b2006-03-31 16:00:29 +0100385
386 This acts as a one-way permeable barrier. It guarantees that all memory
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100387 operations after the ACQUIRE operation will appear to happen after the
388 ACQUIRE operation with respect to the other components of the system.
389 ACQUIRE operations include LOCK operations and smp_load_acquire()
390 operations.
David Howells108b42b2006-03-31 16:00:29 +0100391
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100392 Memory operations that occur before an ACQUIRE operation may appear to
393 happen after it completes.
David Howells108b42b2006-03-31 16:00:29 +0100394
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100395 An ACQUIRE operation should almost always be paired with a RELEASE
396 operation.
David Howells108b42b2006-03-31 16:00:29 +0100397
398
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100399 (6) RELEASE operations.
David Howells108b42b2006-03-31 16:00:29 +0100400
401 This also acts as a one-way permeable barrier. It guarantees that all
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100402 memory operations before the RELEASE operation will appear to happen
403 before the RELEASE operation with respect to the other components of the
404 system. RELEASE operations include UNLOCK operations and
405 smp_store_release() operations.
David Howells108b42b2006-03-31 16:00:29 +0100406
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100407 Memory operations that occur after a RELEASE operation may appear to
David Howells108b42b2006-03-31 16:00:29 +0100408 happen before it completes.
409
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100410 The use of ACQUIRE and RELEASE operations generally precludes the need
411 for other sorts of memory barrier (but note the exceptions mentioned in
412 the subsection "MMIO write barrier"). In addition, a RELEASE+ACQUIRE
413 pair is -not- guaranteed to act as a full memory barrier. However, after
414 an ACQUIRE on a given variable, all memory accesses preceding any prior
415 RELEASE on that same variable are guaranteed to be visible. In other
416 words, within a given variable's critical section, all accesses of all
417 previous critical sections for that variable are guaranteed to have
418 completed.
Paul E. McKenney17eb88e2013-12-11 13:59:09 -0800419
Peter Zijlstra2e4f5382013-11-06 14:57:36 +0100420 This means that ACQUIRE acts as a minimal "acquire" operation and
421 RELEASE acts as a minimal "release" operation.
David Howells108b42b2006-03-31 16:00:29 +0100422
423
424Memory barriers are only required where there's a possibility of interaction
425between two CPUs or between a CPU and a device. If it can be guaranteed that
426there won't be any such interaction in any particular piece of code, then
427memory barriers are unnecessary in that piece of code.
428
429
430Note that these are the _minimum_ guarantees. Different architectures may give
431more substantial guarantees, but they may _not_ be relied upon outside of arch
432specific code.
433
434
435WHAT MAY NOT BE ASSUMED ABOUT MEMORY BARRIERS?
436----------------------------------------------
437
438There are certain things that the Linux kernel memory barriers do not guarantee:
439
440 (*) There is no guarantee that any of the memory accesses specified before a
441 memory barrier will be _complete_ by the completion of a memory barrier
442 instruction; the barrier can be considered to draw a line in that CPU's
443 access queue that accesses of the appropriate type may not cross.
444
445 (*) There is no guarantee that issuing a memory barrier on one CPU will have
446 any direct effect on another CPU or any other hardware in the system. The
447 indirect effect will be the order in which the second CPU sees the effects
448 of the first CPU's accesses occur, but see the next point:
449
David Howells6bc39272006-06-25 05:49:22 -0700450 (*) There is no guarantee that a CPU will see the correct order of effects
David Howells108b42b2006-03-31 16:00:29 +0100451 from a second CPU's accesses, even _if_ the second CPU uses a memory
452 barrier, unless the first CPU _also_ uses a matching memory barrier (see
453 the subsection on "SMP Barrier Pairing").
454
455 (*) There is no guarantee that some intervening piece of off-the-CPU
456 hardware[*] will not reorder the memory accesses. CPU cache coherency
457 mechanisms should propagate the indirect effects of a memory barrier
458 between CPUs, but might not do so in order.
459
460 [*] For information on bus mastering DMA and coherency please read:
461
Randy Dunlap4b5ff462008-03-10 17:16:32 -0700462 Documentation/PCI/pci.txt
Paul Bolle395cf962011-08-15 02:02:26 +0200463 Documentation/DMA-API-HOWTO.txt
David Howells108b42b2006-03-31 16:00:29 +0100464 Documentation/DMA-API.txt
465
466
467DATA DEPENDENCY BARRIERS
468------------------------
469
470The usage requirements of data dependency barriers are a little subtle, and
471it's not always obvious that they're needed. To illustrate, consider the
472following sequence of events:
473
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800474 CPU 1 CPU 2
475 =============== ===============
David Howells108b42b2006-03-31 16:00:29 +0100476 { A == 1, B == 2, C = 3, P == &A, Q == &C }
477 B = 4;
478 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800479 ACCESS_ONCE(P) = &B
480 Q = ACCESS_ONCE(P);
481 D = *Q;
David Howells108b42b2006-03-31 16:00:29 +0100482
483There's a clear data dependency here, and it would seem that by the end of the
484sequence, Q must be either &A or &B, and that:
485
486 (Q == &A) implies (D == 1)
487 (Q == &B) implies (D == 4)
488
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700489But! CPU 2's perception of P may be updated _before_ its perception of B, thus
David Howells108b42b2006-03-31 16:00:29 +0100490leading to the following situation:
491
492 (Q == &B) and (D == 2) ????
493
494Whilst this may seem like a failure of coherency or causality maintenance, it
495isn't, and this behaviour can be observed on certain real CPUs (such as the DEC
496Alpha).
497
David Howells2b948952006-06-25 05:48:49 -0700498To deal with this, a data dependency barrier or better must be inserted
499between the address load and the data load:
David Howells108b42b2006-03-31 16:00:29 +0100500
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800501 CPU 1 CPU 2
502 =============== ===============
David Howells108b42b2006-03-31 16:00:29 +0100503 { A == 1, B == 2, C = 3, P == &A, Q == &C }
504 B = 4;
505 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800506 ACCESS_ONCE(P) = &B
507 Q = ACCESS_ONCE(P);
508 <data dependency barrier>
509 D = *Q;
David Howells108b42b2006-03-31 16:00:29 +0100510
511This enforces the occurrence of one of the two implications, and prevents the
512third possibility from arising.
513
514[!] Note that this extremely counterintuitive situation arises most easily on
515machines with split caches, so that, for example, one cache bank processes
516even-numbered cache lines and the other bank processes odd-numbered cache
517lines. The pointer P might be stored in an odd-numbered cache line, and the
518variable B might be stored in an even-numbered cache line. Then, if the
519even-numbered bank of the reading CPU's cache is extremely busy while the
520odd-numbered bank is idle, one can see the new value of the pointer P (&B),
David Howells6bc39272006-06-25 05:49:22 -0700521but the old value of the variable B (2).
David Howells108b42b2006-03-31 16:00:29 +0100522
523
Ingo Molnare0edc782013-11-22 11:24:53 +0100524Another example of where data dependency barriers might be required is where a
David Howells108b42b2006-03-31 16:00:29 +0100525number is read from memory and then used to calculate the index for an array
526access:
527
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800528 CPU 1 CPU 2
529 =============== ===============
David Howells108b42b2006-03-31 16:00:29 +0100530 { M[0] == 1, M[1] == 2, M[3] = 3, P == 0, Q == 3 }
531 M[1] = 4;
532 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800533 ACCESS_ONCE(P) = 1
534 Q = ACCESS_ONCE(P);
535 <data dependency barrier>
536 D = M[Q];
David Howells108b42b2006-03-31 16:00:29 +0100537
538
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800539The data dependency barrier is very important to the RCU system,
540for example. See rcu_assign_pointer() and rcu_dereference() in
541include/linux/rcupdate.h. This permits the current target of an RCU'd
542pointer to be replaced with a new modified target, without the replacement
543target appearing to be incompletely initialised.
David Howells108b42b2006-03-31 16:00:29 +0100544
545See also the subsection on "Cache Coherency" for a more thorough example.
546
547
548CONTROL DEPENDENCIES
549--------------------
550
551A control dependency requires a full read memory barrier, not simply a data
552dependency barrier to make it work correctly. Consider the following bit of
553code:
554
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800555 q = ACCESS_ONCE(a);
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800556 if (q) {
557 <data dependency barrier> /* BUG: No data dependency!!! */
558 p = ACCESS_ONCE(b);
Paul E. McKenney45c8a362013-07-02 15:24:09 -0700559 }
David Howells108b42b2006-03-31 16:00:29 +0100560
561This will not have the desired effect because there is no actual data
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800562dependency, but rather a control dependency that the CPU may short-circuit
563by attempting to predict the outcome in advance, so that other CPUs see
564the load from b as having happened before the load from a. In such a
565case what's actually required is:
David Howells108b42b2006-03-31 16:00:29 +0100566
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800567 q = ACCESS_ONCE(a);
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800568 if (q) {
Paul E. McKenney45c8a362013-07-02 15:24:09 -0700569 <read barrier>
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800570 p = ACCESS_ONCE(b);
Paul E. McKenney45c8a362013-07-02 15:24:09 -0700571 }
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800572
573However, stores are not speculated. This means that ordering -is- provided
574in the following example:
575
576 q = ACCESS_ONCE(a);
577 if (ACCESS_ONCE(q)) {
578 ACCESS_ONCE(b) = p;
579 }
580
581Please note that ACCESS_ONCE() is not optional! Without the ACCESS_ONCE(),
582the compiler is within its rights to transform this example:
583
584 q = a;
585 if (q) {
586 b = p; /* BUG: Compiler can reorder!!! */
587 do_something();
588 } else {
589 b = p; /* BUG: Compiler can reorder!!! */
590 do_something_else();
591 }
592
593into this, which of course defeats the ordering:
594
595 b = p;
596 q = a;
597 if (q)
598 do_something();
599 else
600 do_something_else();
601
602Worse yet, if the compiler is able to prove (say) that the value of
603variable 'a' is always non-zero, it would be well within its rights
604to optimize the original example by eliminating the "if" statement
605as follows:
606
607 q = a;
608 b = p; /* BUG: Compiler can reorder!!! */
609 do_something();
610
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800611The solution is again ACCESS_ONCE() and barrier(), which preserves the
612ordering between the load from variable 'a' and the store to variable 'b':
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800613
614 q = ACCESS_ONCE(a);
615 if (q) {
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800616 barrier();
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800617 ACCESS_ONCE(b) = p;
618 do_something();
619 } else {
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800620 barrier();
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800621 ACCESS_ONCE(b) = p;
622 do_something_else();
623 }
624
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800625The initial ACCESS_ONCE() is required to prevent the compiler from
626proving the value of 'a', and the pair of barrier() invocations are
627required to prevent the compiler from pulling the two identical stores
628to 'b' out from the legs of the "if" statement.
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800629
630It is important to note that control dependencies absolutely require a
631a conditional. For example, the following "optimized" version of
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800632the above example breaks ordering, which is why the barrier() invocations
633are absolutely required if you have identical stores in both legs of
634the "if" statement:
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800635
636 q = ACCESS_ONCE(a);
637 ACCESS_ONCE(b) = p; /* BUG: No ordering vs. load from a!!! */
638 if (q) {
639 /* ACCESS_ONCE(b) = p; -- moved up, BUG!!! */
640 do_something();
641 } else {
642 /* ACCESS_ONCE(b) = p; -- moved up, BUG!!! */
643 do_something_else();
644 }
645
646It is of course legal for the prior load to be part of the conditional,
647for example, as follows:
648
649 if (ACCESS_ONCE(a) > 0) {
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800650 barrier();
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800651 ACCESS_ONCE(b) = q / 2;
652 do_something();
653 } else {
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800654 barrier();
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800655 ACCESS_ONCE(b) = q / 3;
656 do_something_else();
657 }
658
659This will again ensure that the load from variable 'a' is ordered before the
660stores to variable 'b'.
661
662In addition, you need to be careful what you do with the local variable 'q',
663otherwise the compiler might be able to guess the value and again remove
664the needed conditional. For example:
665
666 q = ACCESS_ONCE(a);
667 if (q % MAX) {
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800668 barrier();
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800669 ACCESS_ONCE(b) = p;
670 do_something();
671 } else {
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800672 barrier();
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800673 ACCESS_ONCE(b) = p;
674 do_something_else();
675 }
676
677If MAX is defined to be 1, then the compiler knows that (q % MAX) is
678equal to zero, in which case the compiler is within its rights to
679transform the above code into the following:
680
681 q = ACCESS_ONCE(a);
682 ACCESS_ONCE(b) = p;
683 do_something_else();
684
685This transformation loses the ordering between the load from variable 'a'
686and the store to variable 'b'. If you are relying on this ordering, you
687should do something like the following:
688
689 q = ACCESS_ONCE(a);
690 BUILD_BUG_ON(MAX <= 1); /* Order load from a with store to b. */
691 if (q % MAX) {
692 ACCESS_ONCE(b) = p;
693 do_something();
694 } else {
695 ACCESS_ONCE(b) = p;
696 do_something_else();
697 }
698
699Finally, control dependencies do -not- provide transitivity. This is
Paul E. McKenney5646f7a2014-07-25 17:05:24 -0700700demonstrated by two related examples, with the initial values of
701x and y both being zero:
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800702
703 CPU 0 CPU 1
704 ===================== =====================
705 r1 = ACCESS_ONCE(x); r2 = ACCESS_ONCE(y);
Paul E. McKenney5646f7a2014-07-25 17:05:24 -0700706 if (r1 > 0) if (r2 > 0)
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800707 ACCESS_ONCE(y) = 1; ACCESS_ONCE(x) = 1;
708
709 assert(!(r1 == 1 && r2 == 1));
710
711The above two-CPU example will never trigger the assert(). However,
712if control dependencies guaranteed transitivity (which they do not),
Paul E. McKenney5646f7a2014-07-25 17:05:24 -0700713then adding the following CPU would guarantee a related assertion:
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800714
Paul E. McKenney5646f7a2014-07-25 17:05:24 -0700715 CPU 2
716 =====================
717 ACCESS_ONCE(x) = 2;
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800718
Paul E. McKenney5646f7a2014-07-25 17:05:24 -0700719 assert(!(r1 == 2 && r2 == 1 && x == 2)); /* FAILS!!! */
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800720
Paul E. McKenney5646f7a2014-07-25 17:05:24 -0700721But because control dependencies do -not- provide transitivity, the above
722assertion can fail after the combined three-CPU example completes. If you
723need the three-CPU example to provide ordering, you will need smp_mb()
724between the loads and stores in the CPU 0 and CPU 1 code fragments,
725that is, just before or just after the "if" statements.
726
727These two examples are the LB and WWC litmus tests from this paper:
728http://www.cl.cam.ac.uk/users/pes20/ppc-supplemental/test6.pdf and this
729site: https://www.cl.cam.ac.uk/~pes20/ppcmem/index.html.
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800730
731In summary:
732
733 (*) Control dependencies can order prior loads against later stores.
734 However, they do -not- guarantee any other sort of ordering:
735 Not prior loads against later loads, nor prior stores against
736 later anything. If you need these other forms of ordering,
737 use smb_rmb(), smp_wmb(), or, in the case of prior stores and
738 later loads, smp_mb().
739
Paul E. McKenney9b2b3bf2014-02-12 20:19:47 -0800740 (*) If both legs of the "if" statement begin with identical stores
741 to the same variable, a barrier() statement is required at the
742 beginning of each leg of the "if" statement.
743
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800744 (*) Control dependencies require at least one run-time conditional
Paul E. McKenney586dd562014-02-11 12:28:06 -0800745 between the prior load and the subsequent store, and this
746 conditional must involve the prior load. If the compiler
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800747 is able to optimize the conditional away, it will have also
748 optimized away the ordering. Careful use of ACCESS_ONCE() can
749 help to preserve the needed conditional.
750
751 (*) Control dependencies require that the compiler avoid reordering the
752 dependency into nonexistence. Careful use of ACCESS_ONCE() or
Paul E. McKenney692118d2013-12-11 13:59:07 -0800753 barrier() can help to preserve your control dependency. Please
754 see the Compiler Barrier section for more information.
Peter Zijlstra18c03c62013-12-11 13:59:06 -0800755
756 (*) Control dependencies do -not- provide transitivity. If you
757 need transitivity, use smp_mb().
David Howells108b42b2006-03-31 16:00:29 +0100758
759
760SMP BARRIER PAIRING
761-------------------
762
763When dealing with CPU-CPU interactions, certain types of memory barrier should
764always be paired. A lack of appropriate pairing is almost certainly an error.
765
Paul E. McKenney128ea442014-06-19 10:01:23 -0700766General barriers pair with each other, though they also pair with
767most other types of barriers, albeit without transitivity. An acquire
768barrier pairs with a release barrier, but both may also pair with other
769barriers, including of course general barriers. A write barrier pairs
770with a data dependency barrier, an acquire barrier, a release barrier,
771a read barrier, or a general barrier. Similarly a read barrier or a
772data dependency barrier pairs with a write barrier, an acquire barrier,
773a release barrier, or a general barrier:
David Howells108b42b2006-03-31 16:00:29 +0100774
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800775 CPU 1 CPU 2
776 =============== ===============
777 ACCESS_ONCE(a) = 1;
David Howells108b42b2006-03-31 16:00:29 +0100778 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800779 ACCESS_ONCE(b) = 2; x = ACCESS_ONCE(b);
780 <read barrier>
781 y = ACCESS_ONCE(a);
David Howells108b42b2006-03-31 16:00:29 +0100782
783Or:
784
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800785 CPU 1 CPU 2
786 =============== ===============================
David Howells108b42b2006-03-31 16:00:29 +0100787 a = 1;
788 <write barrier>
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800789 ACCESS_ONCE(b) = &a; x = ACCESS_ONCE(b);
790 <data dependency barrier>
791 y = *x;
David Howells108b42b2006-03-31 16:00:29 +0100792
793Basically, the read barrier always has to be there, even though it can be of
794the "weaker" type.
795
David Howells670bd952006-06-10 09:54:12 -0700796[!] Note that the stores before the write barrier would normally be expected to
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700797match the loads after the read barrier or the data dependency barrier, and vice
David Howells670bd952006-06-10 09:54:12 -0700798versa:
799
Paul E. McKenney2ecf8102013-12-11 13:59:04 -0800800 CPU 1 CPU 2
801 =================== ===================
802 ACCESS_ONCE(a) = 1; }---- --->{ v = ACCESS_ONCE(c);
803 ACCESS_ONCE(b) = 2; } \ / { w = ACCESS_ONCE(d);
804 <write barrier> \ <read barrier>
805 ACCESS_ONCE(c) = 3; } / \ { x = ACCESS_ONCE(a);
806 ACCESS_ONCE(d) = 4; }---- --->{ y = ACCESS_ONCE(b);
David Howells670bd952006-06-10 09:54:12 -0700807
David Howells108b42b2006-03-31 16:00:29 +0100808
809EXAMPLES OF MEMORY BARRIER SEQUENCES
810------------------------------------
811
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700812Firstly, write barriers act as partial orderings on store operations.
David Howells108b42b2006-03-31 16:00:29 +0100813Consider the following sequence of events:
814
815 CPU 1
816 =======================
817 STORE A = 1
818 STORE B = 2
819 STORE C = 3
820 <write barrier>
821 STORE D = 4
822 STORE E = 5
823
824This sequence of events is committed to the memory coherence system in an order
825that the rest of the system might perceive as the unordered set of { STORE A,
Adrian Bunk80f72282006-06-30 18:27:16 +0200826STORE B, STORE C } all occurring before the unordered set of { STORE D, STORE E
David Howells108b42b2006-03-31 16:00:29 +0100827}:
828
829 +-------+ : :
830 | | +------+
831 | |------>| C=3 | } /\
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700832 | | : +------+ }----- \ -----> Events perceptible to
833 | | : | A=1 | } \/ the rest of the system
David Howells108b42b2006-03-31 16:00:29 +0100834 | | : +------+ }
835 | CPU 1 | : | B=2 | }
836 | | +------+ }
837 | | wwwwwwwwwwwwwwww } <--- At this point the write barrier
838 | | +------+ } requires all stores prior to the
839 | | : | E=5 | } barrier to be committed before
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700840 | | : +------+ } further stores may take place
David Howells108b42b2006-03-31 16:00:29 +0100841 | |------>| D=4 | }
842 | | +------+
843 +-------+ : :
844 |
David Howells670bd952006-06-10 09:54:12 -0700845 | Sequence in which stores are committed to the
846 | memory system by CPU 1
David Howells108b42b2006-03-31 16:00:29 +0100847 V
848
849
Jarek Poplawski81fc6322007-05-23 13:58:20 -0700850Secondly, data dependency barriers act as partial orderings on data-dependent
David Howells108b42b2006-03-31 16:00:29 +0100851loads. Consider the following sequence of events:
852
853 CPU 1 CPU 2
854 ======================= =======================
David Howellsc14038c2006-04-10 22:54:24 -0700855 { B = 7; X = 9; Y = 8; C = &Y }
David Howells108b42b2006-03-31 16:00:29 +0100856 STORE A = 1
857 STORE B = 2
858 <write barrier>
859 STORE C = &B LOAD X
860 STORE D = 4 LOAD C (gets &B)
861 LOAD *C (reads B)
862
863Without intervention, CPU 2 may perceive the events on CPU 1 in some
864effectively random order, despite the write barrier issued by CPU 1:
865
866 +-------+ : : : :
867 | | +------+ +-------+ | Sequence of update
868 | |------>| B=2 |----- --->| Y->8 | | of perception on
869 | | : +------+ \ +-------+ | CPU 2
870 | CPU 1 | : | A=1 | \ --->| C->&Y | V
871 | | +------+ | +-------+
872 | | wwwwwwwwwwwwwwww | : :
873 | | +------+ | : :
874 | | : | C=&B |--- | : : +-------+
875 | | : +------+ \ | +-------+ | |
876 | |------>| D=4 | ----------->| C->&B |------>| |
877 | | +------+ | +-------+ | |
878 +-------+ : : | : : | |
879 | : : | |
880 | : : | CPU 2 |
881 | +-------+ | |
882 Apparently incorrect ---> | | B->7 |------>| |
883 perception of B (!) | +-------+ | |
884 | : : | |
885 | +-------+ | |
886 The load of X holds ---> \ | X->9 |------>| |
887 up the maintenance \ +-------+ | |
888 of coherence of B ----->| B->2 | +-------+
889 +-------+
890 : :
891
892
893In the above example, CPU 2 perceives that B is 7, despite the load of *C
Paolo Ornati670e9f32006-10-03 22:57:56 +0200894(which would be B) coming after the LOAD of C.
David Howells108b42b2006-03-31 16:00:29 +0100895
896If, however, a data dependency barrier were to be placed between the load of C
David Howellsc14038c2006-04-10 22:54:24 -0700897and the load of *C (ie: B) on CPU 2:
898
899 CPU 1 CPU 2
900 ======================= =======================
901 { B = 7; X = 9; Y = 8; C = &Y }
902 STORE A = 1
903 STORE B = 2
904 <write barrier>
905 STORE C = &B LOAD X
906 STORE D = 4 LOAD C (gets &B)
907 <data dependency barrier>
908 LOAD *C (reads B)
909
910then the following will occur:
David Howells108b42b2006-03-31 16:00:29 +0100911
912 +-------+ : : : :
913 | | +------+ +-------+
914 | |------>| B=2 |----- --->| Y->8 |
915 | | : +------+ \ +-------+
916 | CPU 1 | : | A=1 | \ --->| C->&Y |
917 | | +------+ | +-------+
918 | | wwwwwwwwwwwwwwww | : :
919 | | +------+ | : :
920 | | : | C=&B |--- | : : +-------+
921 | | : +------+ \ | +-------+ | |
922 | |------>| D=4 | ----------->| C->&B |------>| |
923 | | +------+ | +-------+ | |
924 +-------+ : : | : : | |
925 | : : | |
926 | : : | CPU 2 |
927 | +-------+ | |
David Howells670bd952006-06-10 09:54:12 -0700928 | | X->9 |------>| |
929 | +-------+ | |
930 Makes sure all effects ---> \ ddddddddddddddddd | |
931 prior to the store of C \ +-------+ | |
932 are perceptible to ----->| B->2 |------>| |
933 subsequent loads +-------+ | |
David Howells108b42b2006-03-31 16:00:29 +0100934 : : +-------+
935
936
937And thirdly, a read barrier acts as a partial order on loads. Consider the
938following sequence of events:
939
940 CPU 1 CPU 2
941 ======================= =======================
David Howells670bd952006-06-10 09:54:12 -0700942 { A = 0, B = 9 }
David Howells108b42b2006-03-31 16:00:29 +0100943 STORE A=1
David Howells108b42b2006-03-31 16:00:29 +0100944 <write barrier>
David Howells670bd952006-06-10 09:54:12 -0700945 STORE B=2
David Howells108b42b2006-03-31 16:00:29 +0100946 LOAD B
David Howells670bd952006-06-10 09:54:12 -0700947 LOAD A
David Howells108b42b2006-03-31 16:00:29 +0100948
949Without intervention, CPU 2 may then choose to perceive the events on CPU 1 in
950some effectively random order, despite the write barrier issued by CPU 1:
951
David Howells670bd952006-06-10 09:54:12 -0700952 +-------+ : : : :
953 | | +------+ +-------+
954 | |------>| A=1 |------ --->| A->0 |
955 | | +------+ \ +-------+
956 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 |
957 | | +------+ | +-------+
958 | |------>| B=2 |--- | : :
959 | | +------+ \ | : : +-------+
960 +-------+ : : \ | +-------+ | |
961 ---------->| B->2 |------>| |
962 | +-------+ | CPU 2 |
963 | | A->0 |------>| |
964 | +-------+ | |
965 | : : +-------+
966 \ : :
967 \ +-------+
968 ---->| A->1 |
969 +-------+
970 : :
David Howells108b42b2006-03-31 16:00:29 +0100971
972
David Howells6bc39272006-06-25 05:49:22 -0700973If, however, a read barrier were to be placed between the load of B and the
David Howells670bd952006-06-10 09:54:12 -0700974load of A on CPU 2:
David Howells108b42b2006-03-31 16:00:29 +0100975
David Howells670bd952006-06-10 09:54:12 -0700976 CPU 1 CPU 2
977 ======================= =======================
978 { A = 0, B = 9 }
979 STORE A=1
980 <write barrier>
981 STORE B=2
982 LOAD B
983 <read barrier>
984 LOAD A
985
986then the partial ordering imposed by CPU 1 will be perceived correctly by CPU
9872:
988
989 +-------+ : : : :
990 | | +------+ +-------+
991 | |------>| A=1 |------ --->| A->0 |
992 | | +------+ \ +-------+
993 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 |
994 | | +------+ | +-------+
995 | |------>| B=2 |--- | : :
996 | | +------+ \ | : : +-------+
997 +-------+ : : \ | +-------+ | |
998 ---------->| B->2 |------>| |
999 | +-------+ | CPU 2 |
1000 | : : | |
1001 | : : | |
1002 At this point the read ----> \ rrrrrrrrrrrrrrrrr | |
1003 barrier causes all effects \ +-------+ | |
1004 prior to the storage of B ---->| A->1 |------>| |
1005 to be perceptible to CPU 2 +-------+ | |
1006 : : +-------+
1007
1008
1009To illustrate this more completely, consider what could happen if the code
1010contained a load of A either side of the read barrier:
1011
1012 CPU 1 CPU 2
1013 ======================= =======================
1014 { A = 0, B = 9 }
1015 STORE A=1
1016 <write barrier>
1017 STORE B=2
1018 LOAD B
1019 LOAD A [first load of A]
1020 <read barrier>
1021 LOAD A [second load of A]
1022
1023Even though the two loads of A both occur after the load of B, they may both
1024come up with different values:
1025
1026 +-------+ : : : :
1027 | | +------+ +-------+
1028 | |------>| A=1 |------ --->| A->0 |
1029 | | +------+ \ +-------+
1030 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 |
1031 | | +------+ | +-------+
1032 | |------>| B=2 |--- | : :
1033 | | +------+ \ | : : +-------+
1034 +-------+ : : \ | +-------+ | |
1035 ---------->| B->2 |------>| |
1036 | +-------+ | CPU 2 |
1037 | : : | |
1038 | : : | |
1039 | +-------+ | |
1040 | | A->0 |------>| 1st |
1041 | +-------+ | |
1042 At this point the read ----> \ rrrrrrrrrrrrrrrrr | |
1043 barrier causes all effects \ +-------+ | |
1044 prior to the storage of B ---->| A->1 |------>| 2nd |
1045 to be perceptible to CPU 2 +-------+ | |
1046 : : +-------+
1047
1048
1049But it may be that the update to A from CPU 1 becomes perceptible to CPU 2
1050before the read barrier completes anyway:
1051
1052 +-------+ : : : :
1053 | | +------+ +-------+
1054 | |------>| A=1 |------ --->| A->0 |
1055 | | +------+ \ +-------+
1056 | CPU 1 | wwwwwwwwwwwwwwww \ --->| B->9 |
1057 | | +------+ | +-------+
1058 | |------>| B=2 |--- | : :
1059 | | +------+ \ | : : +-------+
1060 +-------+ : : \ | +-------+ | |
1061 ---------->| B->2 |------>| |
1062 | +-------+ | CPU 2 |
1063 | : : | |
1064 \ : : | |
1065 \ +-------+ | |
1066 ---->| A->1 |------>| 1st |
1067 +-------+ | |
1068 rrrrrrrrrrrrrrrrr | |
1069 +-------+ | |
1070 | A->1 |------>| 2nd |
1071 +-------+ | |
1072 : : +-------+
1073
1074
1075The guarantee is that the second load will always come up with A == 1 if the
1076load of B came up with B == 2. No such guarantee exists for the first load of
1077A; that may come up with either A == 0 or A == 1.
1078
1079
1080READ MEMORY BARRIERS VS LOAD SPECULATION
1081----------------------------------------
1082
1083Many CPUs speculate with loads: that is they see that they will need to load an
1084item from memory, and they find a time where they're not using the bus for any
1085other loads, and so do the load in advance - even though they haven't actually
1086got to that point in the instruction execution flow yet. This permits the
1087actual load instruction to potentially complete immediately because the CPU
1088already has the value to hand.
1089
1090It may turn out that the CPU didn't actually need the value - perhaps because a
1091branch circumvented the load - in which case it can discard the value or just
1092cache it for later use.
1093
1094Consider:
1095
Ingo Molnare0edc782013-11-22 11:24:53 +01001096 CPU 1 CPU 2
David Howells670bd952006-06-10 09:54:12 -07001097 ======================= =======================
Ingo Molnare0edc782013-11-22 11:24:53 +01001098 LOAD B
1099 DIVIDE } Divide instructions generally
1100 DIVIDE } take a long time to perform
1101 LOAD A
David Howells670bd952006-06-10 09:54:12 -07001102
1103Which might appear as this:
1104
1105 : : +-------+
1106 +-------+ | |
1107 --->| B->2 |------>| |
1108 +-------+ | CPU 2 |
1109 : :DIVIDE | |
1110 +-------+ | |
1111 The CPU being busy doing a ---> --->| A->0 |~~~~ | |
1112 division speculates on the +-------+ ~ | |
1113 LOAD of A : : ~ | |
1114 : :DIVIDE | |
1115 : : ~ | |
1116 Once the divisions are complete --> : : ~-->| |
1117 the CPU can then perform the : : | |
1118 LOAD with immediate effect : : +-------+
1119
1120
1121Placing a read barrier or a data dependency barrier just before the second
1122load:
1123
Ingo Molnare0edc782013-11-22 11:24:53 +01001124 CPU 1 CPU 2
David Howells670bd952006-06-10 09:54:12 -07001125 ======================= =======================
Ingo Molnare0edc782013-11-22 11:24:53 +01001126 LOAD B
1127 DIVIDE
1128 DIVIDE
David Howells670bd952006-06-10 09:54:12 -07001129 <read barrier>
Ingo Molnare0edc782013-11-22 11:24:53 +01001130 LOAD A
David Howells670bd952006-06-10 09:54:12 -07001131
1132will force any value speculatively obtained to be reconsidered to an extent
1133dependent on the type of barrier used. If there was no change made to the
1134speculated memory location, then the speculated value will just be used:
1135
1136 : : +-------+
1137 +-------+ | |
1138 --->| B->2 |------>| |
1139 +-------+ | CPU 2 |
1140 : :DIVIDE | |
1141 +-------+ | |
1142 The CPU being busy doing a ---> --->| A->0 |~~~~ | |
1143 division speculates on the +-------+ ~ | |
1144 LOAD of A : : ~ | |
1145 : :DIVIDE | |
1146 : : ~ | |
1147 : : ~ | |
1148 rrrrrrrrrrrrrrrr~ | |
1149 : : ~ | |
1150 : : ~-->| |
1151 : : | |
1152 : : +-------+
1153
1154
1155but if there was an update or an invalidation from another CPU pending, then
1156the speculation will be cancelled and the value reloaded:
1157
1158 : : +-------+
1159 +-------+ | |
1160 --->| B->2 |------>| |
1161 +-------+ | CPU 2 |
1162 : :DIVIDE | |
1163 +-------+ | |
1164 The CPU being busy doing a ---> --->| A->0 |~~~~ | |
1165 division speculates on the +-------+ ~ | |
1166 LOAD of A : : ~ | |
1167 : :DIVIDE | |
1168 : : ~ | |
1169 : : ~ | |
1170 rrrrrrrrrrrrrrrrr | |
1171 +-------+ | |
1172 The speculation is discarded ---> --->| A->1 |------>| |
1173 and an updated value is +-------+ | |
1174 retrieved : : +-------+
David Howells108b42b2006-03-31 16:00:29 +01001175
1176
Paul E. McKenney241e6662011-02-10 16:54:50 -08001177TRANSITIVITY
1178------------
1179
1180Transitivity is a deeply intuitive notion about ordering that is not
1181always provided by real computer systems. The following example
1182demonstrates transitivity (also called "cumulativity"):
1183
1184 CPU 1 CPU 2 CPU 3
1185 ======================= ======================= =======================
1186 { X = 0, Y = 0 }
1187 STORE X=1 LOAD X STORE Y=1
1188 <general barrier> <general barrier>
1189 LOAD Y LOAD X
1190
1191Suppose that CPU 2's load from X returns 1 and its load from Y returns 0.
1192This indicates that CPU 2's load from X in some sense follows CPU 1's
1193store to X and that CPU 2's load from Y in some sense preceded CPU 3's
1194store to Y. The question is then "Can CPU 3's load from X return 0?"
1195
1196Because CPU 2's load from X in some sense came after CPU 1's store, it
1197is natural to expect that CPU 3's load from X must therefore return 1.
1198This expectation is an example of transitivity: if a load executing on
1199CPU A follows a load from the same variable executing on CPU B, then
1200CPU A's load must either return the same value that CPU B's load did,
1201or must return some later value.
1202
1203In the Linux kernel, use of general memory barriers guarantees
1204transitivity. Therefore, in the above example, if CPU 2's load from X
1205returns 1 and its load from Y returns 0, then CPU 3's load from X must
1206also return 1.
1207
1208However, transitivity is -not- guaranteed for read or write barriers.
1209For example, suppose that CPU 2's general barrier in the above example
1210is changed to a read barrier as shown below:
1211
1212 CPU 1 CPU 2 CPU 3
1213 ======================= ======================= =======================
1214 { X = 0, Y = 0 }
1215 STORE X=1 LOAD X STORE Y=1
1216 <read barrier> <general barrier>
1217 LOAD Y LOAD X
1218
1219This substitution destroys transitivity: in this example, it is perfectly
1220legal for CPU 2's load from X to return 1, its load from Y to return 0,
1221and CPU 3's load from X to return 0.
1222
1223The key point is that although CPU 2's read barrier orders its pair
1224of loads, it does not guarantee to order CPU 1's store. Therefore, if
1225this example runs on a system where CPUs 1 and 2 share a store buffer
1226or a level of cache, CPU 2 might have early access to CPU 1's writes.
1227General barriers are therefore required to ensure that all CPUs agree
1228on the combined order of CPU 1's and CPU 2's accesses.
1229
1230To reiterate, if your code requires transitivity, use general barriers
1231throughout.
1232
1233
David Howells108b42b2006-03-31 16:00:29 +01001234========================
1235EXPLICIT KERNEL BARRIERS
1236========================
1237
1238The Linux kernel has a variety of different barriers that act at different
1239levels:
1240
1241 (*) Compiler barrier.
1242
1243 (*) CPU memory barriers.
1244
1245 (*) MMIO write barrier.
1246
1247
1248COMPILER BARRIER
1249----------------
1250
1251The Linux kernel has an explicit compiler barrier function that prevents the
1252compiler from moving the memory accesses either side of it to the other side:
1253
1254 barrier();
1255
Peter Zijlstra18c03c62013-12-11 13:59:06 -08001256This is a general barrier -- there are no read-read or write-write variants
Paul E. McKenney692118d2013-12-11 13:59:07 -08001257of barrier(). However, ACCESS_ONCE() can be thought of as a weak form
Peter Zijlstra18c03c62013-12-11 13:59:06 -08001258for barrier() that affects only the specific accesses flagged by the
1259ACCESS_ONCE().
David Howells108b42b2006-03-31 16:00:29 +01001260
Paul E. McKenney692118d2013-12-11 13:59:07 -08001261The barrier() function has the following effects:
1262
1263 (*) Prevents the compiler from reordering accesses following the
1264 barrier() to precede any accesses preceding the barrier().
1265 One example use for this property is to ease communication between
1266 interrupt-handler code and the code that was interrupted.
1267
1268 (*) Within a loop, forces the compiler to load the variables used
1269 in that loop's conditional on each pass through that loop.
1270
1271The ACCESS_ONCE() function can prevent any number of optimizations that,
1272while perfectly safe in single-threaded code, can be fatal in concurrent
1273code. Here are some examples of these sorts of optimizations:
1274
Paul E. McKenney449f7412014-01-02 15:03:50 -08001275 (*) The compiler is within its rights to reorder loads and stores
1276 to the same variable, and in some cases, the CPU is within its
1277 rights to reorder loads to the same variable. This means that
1278 the following code:
1279
1280 a[0] = x;
1281 a[1] = x;
1282
1283 Might result in an older value of x stored in a[1] than in a[0].
1284 Prevent both the compiler and the CPU from doing this as follows:
1285
1286 a[0] = ACCESS_ONCE(x);
1287 a[1] = ACCESS_ONCE(x);
1288
1289 In short, ACCESS_ONCE() provides cache coherence for accesses from
1290 multiple CPUs to a single variable.
1291
Paul E. McKenney692118d2013-12-11 13:59:07 -08001292 (*) The compiler is within its rights to merge successive loads from
1293 the same variable. Such merging can cause the compiler to "optimize"
1294 the following code:
1295
1296 while (tmp = a)
1297 do_something_with(tmp);
1298
1299 into the following code, which, although in some sense legitimate
1300 for single-threaded code, is almost certainly not what the developer
1301 intended:
1302
1303 if (tmp = a)
1304 for (;;)
1305 do_something_with(tmp);
1306
1307 Use ACCESS_ONCE() to prevent the compiler from doing this to you:
1308
1309 while (tmp = ACCESS_ONCE(a))
1310 do_something_with(tmp);
1311
1312 (*) The compiler is within its rights to reload a variable, for example,
1313 in cases where high register pressure prevents the compiler from
1314 keeping all data of interest in registers. The compiler might
1315 therefore optimize the variable 'tmp' out of our previous example:
1316
1317 while (tmp = a)
1318 do_something_with(tmp);
1319
1320 This could result in the following code, which is perfectly safe in
1321 single-threaded code, but can be fatal in concurrent code:
1322
1323 while (a)
1324 do_something_with(a);
1325
1326 For example, the optimized version of this code could result in
1327 passing a zero to do_something_with() in the case where the variable
1328 a was modified by some other CPU between the "while" statement and
1329 the call to do_something_with().
1330
1331 Again, use ACCESS_ONCE() to prevent the compiler from doing this:
1332
1333 while (tmp = ACCESS_ONCE(a))
1334 do_something_with(tmp);
1335
1336 Note that if the compiler runs short of registers, it might save
1337 tmp onto the stack. The overhead of this saving and later restoring
1338 is why compilers reload variables. Doing so is perfectly safe for
1339 single-threaded code, so you need to tell the compiler about cases
1340 where it is not safe.
1341
1342 (*) The compiler is within its rights to omit a load entirely if it knows
1343 what the value will be. For example, if the compiler can prove that
1344 the value of variable 'a' is always zero, it can optimize this code:
1345
1346 while (tmp = a)
1347 do_something_with(tmp);
1348
1349 Into this:
1350
1351 do { } while (0);
1352
1353 This transformation is a win for single-threaded code because it gets
1354 rid of a load and a branch. The problem is that the compiler will
1355 carry out its proof assuming that the current CPU is the only one
1356 updating variable 'a'. If variable 'a' is shared, then the compiler's
1357 proof will be erroneous. Use ACCESS_ONCE() to tell the compiler
1358 that it doesn't know as much as it thinks it does:
1359
1360 while (tmp = ACCESS_ONCE(a))
1361 do_something_with(tmp);
1362
1363 But please note that the compiler is also closely watching what you
1364 do with the value after the ACCESS_ONCE(). For example, suppose you
1365 do the following and MAX is a preprocessor macro with the value 1:
1366
1367 while ((tmp = ACCESS_ONCE(a)) % MAX)
1368 do_something_with(tmp);
1369
1370 Then the compiler knows that the result of the "%" operator applied
1371 to MAX will always be zero, again allowing the compiler to optimize
1372 the code into near-nonexistence. (It will still load from the
1373 variable 'a'.)
1374
1375 (*) Similarly, the compiler is within its rights to omit a store entirely
1376 if it knows that the variable already has the value being stored.
1377 Again, the compiler assumes that the current CPU is the only one
1378 storing into the variable, which can cause the compiler to do the
1379 wrong thing for shared variables. For example, suppose you have
1380 the following:
1381
1382 a = 0;
1383 /* Code that does not store to variable a. */
1384 a = 0;
1385
1386 The compiler sees that the value of variable 'a' is already zero, so
1387 it might well omit the second store. This would come as a fatal
1388 surprise if some other CPU might have stored to variable 'a' in the
1389 meantime.
1390
1391 Use ACCESS_ONCE() to prevent the compiler from making this sort of
1392 wrong guess:
1393
1394 ACCESS_ONCE(a) = 0;
1395 /* Code that does not store to variable a. */
1396 ACCESS_ONCE(a) = 0;
1397
1398 (*) The compiler is within its rights to reorder memory accesses unless
1399 you tell it not to. For example, consider the following interaction
1400 between process-level code and an interrupt handler:
1401
1402 void process_level(void)
1403 {
1404 msg = get_message();
1405 flag = true;
1406 }
1407
1408 void interrupt_handler(void)
1409 {
1410 if (flag)
1411 process_message(msg);
1412 }
1413
Masanari Iidadf5cbb22014-03-21 10:04:30 +09001414 There is nothing to prevent the compiler from transforming
Paul E. McKenney692118d2013-12-11 13:59:07 -08001415 process_level() to the following, in fact, this might well be a
1416 win for single-threaded code:
1417
1418 void process_level(void)
1419 {
1420 flag = true;
1421 msg = get_message();
1422 }
1423
1424 If the interrupt occurs between these two statement, then
1425 interrupt_handler() might be passed a garbled msg. Use ACCESS_ONCE()
1426 to prevent this as follows:
1427
1428 void process_level(void)
1429 {
1430 ACCESS_ONCE(msg) = get_message();
1431 ACCESS_ONCE(flag) = true;
1432 }
1433
1434 void interrupt_handler(void)
1435 {
1436 if (ACCESS_ONCE(flag))
1437 process_message(ACCESS_ONCE(msg));
1438 }
1439
1440 Note that the ACCESS_ONCE() wrappers in interrupt_handler()
1441 are needed if this interrupt handler can itself be interrupted
1442 by something that also accesses 'flag' and 'msg', for example,
1443 a nested interrupt or an NMI. Otherwise, ACCESS_ONCE() is not
1444 needed in interrupt_handler() other than for documentation purposes.
1445 (Note also that nested interrupts do not typically occur in modern
1446 Linux kernels, in fact, if an interrupt handler returns with
1447 interrupts enabled, you will get a WARN_ONCE() splat.)
1448
1449 You should assume that the compiler can move ACCESS_ONCE() past
1450 code not containing ACCESS_ONCE(), barrier(), or similar primitives.
1451
1452 This effect could also be achieved using barrier(), but ACCESS_ONCE()
1453 is more selective: With ACCESS_ONCE(), the compiler need only forget
1454 the contents of the indicated memory locations, while with barrier()
1455 the compiler must discard the value of all memory locations that
1456 it has currented cached in any machine registers. Of course,
1457 the compiler must also respect the order in which the ACCESS_ONCE()s
1458 occur, though the CPU of course need not do so.
1459
1460 (*) The compiler is within its rights to invent stores to a variable,
1461 as in the following example:
1462
1463 if (a)
1464 b = a;
1465 else
1466 b = 42;
1467
1468 The compiler might save a branch by optimizing this as follows:
1469
1470 b = 42;
1471 if (a)
1472 b = a;
1473
1474 In single-threaded code, this is not only safe, but also saves
1475 a branch. Unfortunately, in concurrent code, this optimization
1476 could cause some other CPU to see a spurious value of 42 -- even
1477 if variable 'a' was never zero -- when loading variable 'b'.
1478 Use ACCESS_ONCE() to prevent this as follows:
1479
1480 if (a)
1481 ACCESS_ONCE(b) = a;
1482 else
1483 ACCESS_ONCE(b) = 42;
1484
1485 The compiler can also invent loads. These are usually less
1486 damaging, but they can result in cache-line bouncing and thus in
1487 poor performance and scalability. Use ACCESS_ONCE() to prevent
1488 invented loads.
1489
1490 (*) For aligned memory locations whose size allows them to be accessed
1491 with a single memory-reference instruction, prevents "load tearing"
1492 and "store tearing," in which a single large access is replaced by
1493 multiple smaller accesses. For example, given an architecture having
1494 16-bit store instructions with 7-bit immediate fields, the compiler
1495 might be tempted to use two 16-bit store-immediate instructions to
1496 implement the following 32-bit store:
1497
1498 p = 0x00010002;
1499
1500 Please note that GCC really does use this sort of optimization,
1501 which is not surprising given that it would likely take more
1502 than two instructions to build the constant and then store it.
1503 This optimization can therefore be a win in single-threaded code.
1504 In fact, a recent bug (since fixed) caused GCC to incorrectly use
1505 this optimization in a volatile store. In the absence of such bugs,
1506 use of ACCESS_ONCE() prevents store tearing in the following example:
1507
1508 ACCESS_ONCE(p) = 0x00010002;
1509
1510 Use of packed structures can also result in load and store tearing,
1511 as in this example:
1512
1513 struct __attribute__((__packed__)) foo {
1514 short a;
1515 int b;
1516 short c;
1517 };
1518 struct foo foo1, foo2;
1519 ...
1520
1521 foo2.a = foo1.a;
1522 foo2.b = foo1.b;
1523 foo2.c = foo1.c;
1524
1525 Because there are no ACCESS_ONCE() wrappers and no volatile markings,
1526 the compiler would be well within its rights to implement these three
1527 assignment statements as a pair of 32-bit loads followed by a pair
1528 of 32-bit stores. This would result in load tearing on 'foo1.b'
1529 and store tearing on 'foo2.b'. ACCESS_ONCE() again prevents tearing
1530 in this example:
1531
1532 foo2.a = foo1.a;
1533 ACCESS_ONCE(foo2.b) = ACCESS_ONCE(foo1.b);
1534 foo2.c = foo1.c;
1535
1536All that aside, it is never necessary to use ACCESS_ONCE() on a variable
1537that has been marked volatile. For example, because 'jiffies' is marked
1538volatile, it is never necessary to say ACCESS_ONCE(jiffies). The reason
1539for this is that ACCESS_ONCE() is implemented as a volatile cast, which
1540has no effect when its argument is already marked volatile.
1541
1542Please note that these compiler barriers have no direct effect on the CPU,
1543which may then reorder things however it wishes.
David Howells108b42b2006-03-31 16:00:29 +01001544
1545
1546CPU MEMORY BARRIERS
1547-------------------
1548
1549The Linux kernel has eight basic CPU memory barriers:
1550
1551 TYPE MANDATORY SMP CONDITIONAL
1552 =============== ======================= ===========================
1553 GENERAL mb() smp_mb()
1554 WRITE wmb() smp_wmb()
1555 READ rmb() smp_rmb()
1556 DATA DEPENDENCY read_barrier_depends() smp_read_barrier_depends()
1557
1558
Nick Piggin73f10282008-05-14 06:35:11 +02001559All memory barriers except the data dependency barriers imply a compiler
1560barrier. Data dependencies do not impose any additional compiler ordering.
1561
1562Aside: In the case of data dependencies, the compiler would be expected to
1563issue the loads in the correct order (eg. `a[b]` would have to load the value
1564of b before loading a[b]), however there is no guarantee in the C specification
1565that the compiler may not speculate the value of b (eg. is equal to 1) and load
1566a before b (eg. tmp = a[1]; if (b != 1) tmp = a[b]; ). There is also the
1567problem of a compiler reloading b after having loaded a[b], thus having a newer
1568copy of b than a[b]. A consensus has not yet been reached about these problems,
1569however the ACCESS_ONCE macro is a good place to start looking.
David Howells108b42b2006-03-31 16:00:29 +01001570
1571SMP memory barriers are reduced to compiler barriers on uniprocessor compiled
Jarek Poplawski81fc6322007-05-23 13:58:20 -07001572systems because it is assumed that a CPU will appear to be self-consistent,
David Howells108b42b2006-03-31 16:00:29 +01001573and will order overlapping accesses correctly with respect to itself.
1574
1575[!] Note that SMP memory barriers _must_ be used to control the ordering of
1576references to shared memory on SMP systems, though the use of locking instead
1577is sufficient.
1578
1579Mandatory barriers should not be used to control SMP effects, since mandatory
1580barriers unnecessarily impose overhead on UP systems. They may, however, be
1581used to control MMIO effects on accesses through relaxed memory I/O windows.
1582These are required even on non-SMP systems as they affect the order in which
1583memory operations appear to a device by prohibiting both the compiler and the
1584CPU from reordering them.
1585
1586
1587There are some more advanced barrier functions:
1588
1589 (*) set_mb(var, value)
David Howells108b42b2006-03-31 16:00:29 +01001590
Oleg Nesterov75b2bd52006-11-08 17:44:38 -08001591 This assigns the value to the variable and then inserts a full memory
Steven Rostedtf92213b2006-07-14 16:05:01 -04001592 barrier after it, depending on the function. It isn't guaranteed to
David Howells108b42b2006-03-31 16:00:29 +01001593 insert anything more than a compiler barrier in a UP compilation.
1594
1595
Peter Zijlstra1b156112014-03-13 19:00:35 +01001596 (*) smp_mb__before_atomic();
1597 (*) smp_mb__after_atomic();
David Howells108b42b2006-03-31 16:00:29 +01001598
Peter Zijlstra1b156112014-03-13 19:00:35 +01001599 These are for use with atomic (such as add, subtract, increment and
1600 decrement) functions that don't return a value, especially when used for
1601 reference counting. These functions do not imply memory barriers.
1602
1603 These are also used for atomic bitop functions that do not return a
1604 value (such as set_bit and clear_bit).
David Howells108b42b2006-03-31 16:00:29 +01001605
1606 As an example, consider a piece of code that marks an object as being dead
1607 and then decrements the object's reference count:
1608
1609 obj->dead = 1;
Peter Zijlstra1b156112014-03-13 19:00:35 +01001610 smp_mb__before_atomic();
David Howells108b42b2006-03-31 16:00:29 +01001611 atomic_dec(&obj->ref_count);
1612
1613 This makes sure that the death mark on the object is perceived to be set
1614 *before* the reference counter is decremented.
1615
1616 See Documentation/atomic_ops.txt for more information. See the "Atomic
1617 operations" subsection for information on where to use these.
1618
1619
David Howells108b42b2006-03-31 16:00:29 +01001620MMIO WRITE BARRIER
1621------------------
1622
1623The Linux kernel also has a special barrier for use with memory-mapped I/O
1624writes:
1625
1626 mmiowb();
1627
1628This is a variation on the mandatory write barrier that causes writes to weakly
1629ordered I/O regions to be partially ordered. Its effects may go beyond the
1630CPU->Hardware interface and actually affect the hardware at some level.
1631
1632See the subsection "Locks vs I/O accesses" for more information.
1633
1634
1635===============================
1636IMPLICIT KERNEL MEMORY BARRIERS
1637===============================
1638
1639Some of the other functions in the linux kernel imply memory barriers, amongst
David Howells670bd952006-06-10 09:54:12 -07001640which are locking and scheduling functions.
David Howells108b42b2006-03-31 16:00:29 +01001641
1642This specification is a _minimum_ guarantee; any particular architecture may
1643provide more substantial guarantees, but these may not be relied upon outside
1644of arch specific code.
1645
1646
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001647ACQUIRING FUNCTIONS
1648-------------------
David Howells108b42b2006-03-31 16:00:29 +01001649
1650The Linux kernel has a number of locking constructs:
1651
1652 (*) spin locks
1653 (*) R/W spin locks
1654 (*) mutexes
1655 (*) semaphores
1656 (*) R/W semaphores
1657 (*) RCU
1658
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001659In all cases there are variants on "ACQUIRE" operations and "RELEASE" operations
David Howells108b42b2006-03-31 16:00:29 +01001660for each construct. These operations all imply certain barriers:
1661
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001662 (1) ACQUIRE operation implication:
David Howells108b42b2006-03-31 16:00:29 +01001663
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001664 Memory operations issued after the ACQUIRE will be completed after the
1665 ACQUIRE operation has completed.
David Howells108b42b2006-03-31 16:00:29 +01001666
Paul E. McKenney8dd853d2014-02-23 08:34:24 -08001667 Memory operations issued before the ACQUIRE may be completed after
1668 the ACQUIRE operation has completed. An smp_mb__before_spinlock(),
1669 combined with a following ACQUIRE, orders prior loads against
1670 subsequent loads and stores and also orders prior stores against
1671 subsequent stores. Note that this is weaker than smp_mb()! The
1672 smp_mb__before_spinlock() primitive is free on many architectures.
David Howells108b42b2006-03-31 16:00:29 +01001673
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001674 (2) RELEASE operation implication:
David Howells108b42b2006-03-31 16:00:29 +01001675
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001676 Memory operations issued before the RELEASE will be completed before the
1677 RELEASE operation has completed.
David Howells108b42b2006-03-31 16:00:29 +01001678
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001679 Memory operations issued after the RELEASE may be completed before the
1680 RELEASE operation has completed.
David Howells108b42b2006-03-31 16:00:29 +01001681
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001682 (3) ACQUIRE vs ACQUIRE implication:
David Howells108b42b2006-03-31 16:00:29 +01001683
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001684 All ACQUIRE operations issued before another ACQUIRE operation will be
1685 completed before that ACQUIRE operation.
David Howells108b42b2006-03-31 16:00:29 +01001686
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001687 (4) ACQUIRE vs RELEASE implication:
David Howells108b42b2006-03-31 16:00:29 +01001688
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001689 All ACQUIRE operations issued before a RELEASE operation will be
1690 completed before the RELEASE operation.
David Howells108b42b2006-03-31 16:00:29 +01001691
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001692 (5) Failed conditional ACQUIRE implication:
David Howells108b42b2006-03-31 16:00:29 +01001693
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001694 Certain locking variants of the ACQUIRE operation may fail, either due to
1695 being unable to get the lock immediately, or due to receiving an unblocked
David Howells108b42b2006-03-31 16:00:29 +01001696 signal whilst asleep waiting for the lock to become available. Failed
1697 locks do not imply any sort of barrier.
1698
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001699[!] Note: one of the consequences of lock ACQUIREs and RELEASEs being only
1700one-way barriers is that the effects of instructions outside of a critical
1701section may seep into the inside of the critical section.
David Howells108b42b2006-03-31 16:00:29 +01001702
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001703An ACQUIRE followed by a RELEASE may not be assumed to be full memory barrier
1704because it is possible for an access preceding the ACQUIRE to happen after the
1705ACQUIRE, and an access following the RELEASE to happen before the RELEASE, and
1706the two accesses can themselves then cross:
David Howells670bd952006-06-10 09:54:12 -07001707
1708 *A = a;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001709 ACQUIRE M
1710 RELEASE M
David Howells670bd952006-06-10 09:54:12 -07001711 *B = b;
1712
1713may occur as:
1714
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001715 ACQUIRE M, STORE *B, STORE *A, RELEASE M
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001716
Paul E. McKenney8dd853d2014-02-23 08:34:24 -08001717When the ACQUIRE and RELEASE are a lock acquisition and release,
1718respectively, this same reordering can occur if the lock's ACQUIRE and
1719RELEASE are to the same lock variable, but only from the perspective of
1720another CPU not holding that lock. In short, a ACQUIRE followed by an
1721RELEASE may -not- be assumed to be a full memory barrier.
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001722
Paul E. McKenney8dd853d2014-02-23 08:34:24 -08001723Similarly, the reverse case of a RELEASE followed by an ACQUIRE does not
1724imply a full memory barrier. If it is necessary for a RELEASE-ACQUIRE
1725pair to produce a full barrier, the ACQUIRE can be followed by an
1726smp_mb__after_unlock_lock() invocation. This will produce a full barrier
1727if either (a) the RELEASE and the ACQUIRE are executed by the same
1728CPU or task, or (b) the RELEASE and ACQUIRE act on the same variable.
1729The smp_mb__after_unlock_lock() primitive is free on many architectures.
1730Without smp_mb__after_unlock_lock(), the CPU's execution of the critical
1731sections corresponding to the RELEASE and the ACQUIRE can cross, so that:
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001732
1733 *A = a;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001734 RELEASE M
1735 ACQUIRE N
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001736 *B = b;
1737
1738could occur as:
1739
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001740 ACQUIRE N, STORE *B, STORE *A, RELEASE M
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001741
Paul E. McKenney8dd853d2014-02-23 08:34:24 -08001742It might appear that this reordering could introduce a deadlock.
1743However, this cannot happen because if such a deadlock threatened,
1744the RELEASE would simply complete, thereby avoiding the deadlock.
1745
1746 Why does this work?
1747
1748 One key point is that we are only talking about the CPU doing
1749 the reordering, not the compiler. If the compiler (or, for
1750 that matter, the developer) switched the operations, deadlock
1751 -could- occur.
1752
1753 But suppose the CPU reordered the operations. In this case,
1754 the unlock precedes the lock in the assembly code. The CPU
1755 simply elected to try executing the later lock operation first.
1756 If there is a deadlock, this lock operation will simply spin (or
1757 try to sleep, but more on that later). The CPU will eventually
1758 execute the unlock operation (which preceded the lock operation
1759 in the assembly code), which will unravel the potential deadlock,
1760 allowing the lock operation to succeed.
1761
1762 But what if the lock is a sleeplock? In that case, the code will
1763 try to enter the scheduler, where it will eventually encounter
1764 a memory barrier, which will force the earlier unlock operation
1765 to complete, again unraveling the deadlock. There might be
1766 a sleep-unlock race, but the locking primitive needs to resolve
1767 such races properly in any case.
1768
1769With smp_mb__after_unlock_lock(), the two critical sections cannot overlap.
1770For example, with the following code, the store to *A will always be
1771seen by other CPUs before the store to *B:
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001772
1773 *A = a;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001774 RELEASE M
1775 ACQUIRE N
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001776 smp_mb__after_unlock_lock();
1777 *B = b;
1778
Paul E. McKenney8dd853d2014-02-23 08:34:24 -08001779The operations will always occur in one of the following orders:
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001780
Paul E. McKenney8dd853d2014-02-23 08:34:24 -08001781 STORE *A, RELEASE, ACQUIRE, smp_mb__after_unlock_lock(), STORE *B
1782 STORE *A, ACQUIRE, RELEASE, smp_mb__after_unlock_lock(), STORE *B
1783 ACQUIRE, STORE *A, RELEASE, smp_mb__after_unlock_lock(), STORE *B
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08001784
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001785If the RELEASE and ACQUIRE were instead both operating on the same lock
Paul E. McKenney8dd853d2014-02-23 08:34:24 -08001786variable, only the first of these alternatives can occur. In addition,
1787the more strongly ordered systems may rule out some of the above orders.
1788But in any case, as noted earlier, the smp_mb__after_unlock_lock()
1789ensures that the store to *A will always be seen as happening before
1790the store to *B.
David Howells670bd952006-06-10 09:54:12 -07001791
David Howells108b42b2006-03-31 16:00:29 +01001792Locks and semaphores may not provide any guarantee of ordering on UP compiled
1793systems, and so cannot be counted on in such a situation to actually achieve
1794anything at all - especially with respect to I/O accesses - unless combined
1795with interrupt disabling operations.
1796
1797See also the section on "Inter-CPU locking barrier effects".
1798
1799
1800As an example, consider the following:
1801
1802 *A = a;
1803 *B = b;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001804 ACQUIRE
David Howells108b42b2006-03-31 16:00:29 +01001805 *C = c;
1806 *D = d;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001807 RELEASE
David Howells108b42b2006-03-31 16:00:29 +01001808 *E = e;
1809 *F = f;
1810
1811The following sequence of events is acceptable:
1812
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001813 ACQUIRE, {*F,*A}, *E, {*C,*D}, *B, RELEASE
David Howells108b42b2006-03-31 16:00:29 +01001814
1815 [+] Note that {*F,*A} indicates a combined access.
1816
1817But none of the following are:
1818
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001819 {*F,*A}, *B, ACQUIRE, *C, *D, RELEASE, *E
1820 *A, *B, *C, ACQUIRE, *D, RELEASE, *E, *F
1821 *A, *B, ACQUIRE, *C, RELEASE, *D, *E, *F
1822 *B, ACQUIRE, *C, *D, RELEASE, {*F,*A}, *E
David Howells108b42b2006-03-31 16:00:29 +01001823
1824
1825
1826INTERRUPT DISABLING FUNCTIONS
1827-----------------------------
1828
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001829Functions that disable interrupts (ACQUIRE equivalent) and enable interrupts
1830(RELEASE equivalent) will act as compiler barriers only. So if memory or I/O
David Howells108b42b2006-03-31 16:00:29 +01001831barriers are required in such a situation, they must be provided from some
1832other means.
1833
1834
David Howells50fa6102009-04-28 15:01:38 +01001835SLEEP AND WAKE-UP FUNCTIONS
1836---------------------------
1837
1838Sleeping and waking on an event flagged in global data can be viewed as an
1839interaction between two pieces of data: the task state of the task waiting for
1840the event and the global data used to indicate the event. To make sure that
1841these appear to happen in the right order, the primitives to begin the process
1842of going to sleep, and the primitives to initiate a wake up imply certain
1843barriers.
1844
1845Firstly, the sleeper normally follows something like this sequence of events:
1846
1847 for (;;) {
1848 set_current_state(TASK_UNINTERRUPTIBLE);
1849 if (event_indicated)
1850 break;
1851 schedule();
1852 }
1853
1854A general memory barrier is interpolated automatically by set_current_state()
1855after it has altered the task state:
1856
1857 CPU 1
1858 ===============================
1859 set_current_state();
1860 set_mb();
1861 STORE current->state
1862 <general barrier>
1863 LOAD event_indicated
1864
1865set_current_state() may be wrapped by:
1866
1867 prepare_to_wait();
1868 prepare_to_wait_exclusive();
1869
1870which therefore also imply a general memory barrier after setting the state.
1871The whole sequence above is available in various canned forms, all of which
1872interpolate the memory barrier in the right place:
1873
1874 wait_event();
1875 wait_event_interruptible();
1876 wait_event_interruptible_exclusive();
1877 wait_event_interruptible_timeout();
1878 wait_event_killable();
1879 wait_event_timeout();
1880 wait_on_bit();
1881 wait_on_bit_lock();
1882
1883
1884Secondly, code that performs a wake up normally follows something like this:
1885
1886 event_indicated = 1;
1887 wake_up(&event_wait_queue);
1888
1889or:
1890
1891 event_indicated = 1;
1892 wake_up_process(event_daemon);
1893
1894A write memory barrier is implied by wake_up() and co. if and only if they wake
1895something up. The barrier occurs before the task state is cleared, and so sits
1896between the STORE to indicate the event and the STORE to set TASK_RUNNING:
1897
1898 CPU 1 CPU 2
1899 =============================== ===============================
1900 set_current_state(); STORE event_indicated
1901 set_mb(); wake_up();
1902 STORE current->state <write barrier>
1903 <general barrier> STORE current->state
1904 LOAD event_indicated
1905
Paul E. McKenney5726ce02014-05-13 10:14:51 -07001906To repeat, this write memory barrier is present if and only if something
1907is actually awakened. To see this, consider the following sequence of
1908events, where X and Y are both initially zero:
1909
1910 CPU 1 CPU 2
1911 =============================== ===============================
1912 X = 1; STORE event_indicated
1913 smp_mb(); wake_up();
1914 Y = 1; wait_event(wq, Y == 1);
1915 wake_up(); load from Y sees 1, no memory barrier
1916 load from X might see 0
1917
1918In contrast, if a wakeup does occur, CPU 2's load from X would be guaranteed
1919to see 1.
1920
David Howells50fa6102009-04-28 15:01:38 +01001921The available waker functions include:
1922
1923 complete();
1924 wake_up();
1925 wake_up_all();
1926 wake_up_bit();
1927 wake_up_interruptible();
1928 wake_up_interruptible_all();
1929 wake_up_interruptible_nr();
1930 wake_up_interruptible_poll();
1931 wake_up_interruptible_sync();
1932 wake_up_interruptible_sync_poll();
1933 wake_up_locked();
1934 wake_up_locked_poll();
1935 wake_up_nr();
1936 wake_up_poll();
1937 wake_up_process();
1938
1939
1940[!] Note that the memory barriers implied by the sleeper and the waker do _not_
1941order multiple stores before the wake-up with respect to loads of those stored
1942values after the sleeper has called set_current_state(). For instance, if the
1943sleeper does:
1944
1945 set_current_state(TASK_INTERRUPTIBLE);
1946 if (event_indicated)
1947 break;
1948 __set_current_state(TASK_RUNNING);
1949 do_something(my_data);
1950
1951and the waker does:
1952
1953 my_data = value;
1954 event_indicated = 1;
1955 wake_up(&event_wait_queue);
1956
1957there's no guarantee that the change to event_indicated will be perceived by
1958the sleeper as coming after the change to my_data. In such a circumstance, the
1959code on both sides must interpolate its own memory barriers between the
1960separate data accesses. Thus the above sleeper ought to do:
1961
1962 set_current_state(TASK_INTERRUPTIBLE);
1963 if (event_indicated) {
1964 smp_rmb();
1965 do_something(my_data);
1966 }
1967
1968and the waker should do:
1969
1970 my_data = value;
1971 smp_wmb();
1972 event_indicated = 1;
1973 wake_up(&event_wait_queue);
1974
1975
David Howells108b42b2006-03-31 16:00:29 +01001976MISCELLANEOUS FUNCTIONS
1977-----------------------
1978
1979Other functions that imply barriers:
1980
1981 (*) schedule() and similar imply full memory barriers.
1982
David Howells108b42b2006-03-31 16:00:29 +01001983
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001984===================================
1985INTER-CPU ACQUIRING BARRIER EFFECTS
1986===================================
David Howells108b42b2006-03-31 16:00:29 +01001987
1988On SMP systems locking primitives give a more substantial form of barrier: one
1989that does affect memory access ordering on other CPUs, within the context of
1990conflict on any particular lock.
1991
1992
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01001993ACQUIRES VS MEMORY ACCESSES
1994---------------------------
David Howells108b42b2006-03-31 16:00:29 +01001995
Aneesh Kumar79afecf2006-05-15 09:44:36 -07001996Consider the following: the system has a pair of spinlocks (M) and (Q), and
David Howells108b42b2006-03-31 16:00:29 +01001997three CPUs; then should the following sequence of events occur:
1998
1999 CPU 1 CPU 2
2000 =============================== ===============================
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002001 ACCESS_ONCE(*A) = a; ACCESS_ONCE(*E) = e;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002002 ACQUIRE M ACQUIRE Q
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002003 ACCESS_ONCE(*B) = b; ACCESS_ONCE(*F) = f;
2004 ACCESS_ONCE(*C) = c; ACCESS_ONCE(*G) = g;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002005 RELEASE M RELEASE Q
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002006 ACCESS_ONCE(*D) = d; ACCESS_ONCE(*H) = h;
David Howells108b42b2006-03-31 16:00:29 +01002007
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002008Then there is no guarantee as to what order CPU 3 will see the accesses to *A
David Howells108b42b2006-03-31 16:00:29 +01002009through *H occur in, other than the constraints imposed by the separate locks
2010on the separate CPUs. It might, for example, see:
2011
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002012 *E, ACQUIRE M, ACQUIRE Q, *G, *C, *F, *A, *B, RELEASE Q, *D, *H, RELEASE M
David Howells108b42b2006-03-31 16:00:29 +01002013
2014But it won't see any of:
2015
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002016 *B, *C or *D preceding ACQUIRE M
2017 *A, *B or *C following RELEASE M
2018 *F, *G or *H preceding ACQUIRE Q
2019 *E, *F or *G following RELEASE Q
David Howells108b42b2006-03-31 16:00:29 +01002020
2021
2022However, if the following occurs:
2023
2024 CPU 1 CPU 2
2025 =============================== ===============================
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002026 ACCESS_ONCE(*A) = a;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002027 ACQUIRE M [1]
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002028 ACCESS_ONCE(*B) = b;
2029 ACCESS_ONCE(*C) = c;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002030 RELEASE M [1]
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002031 ACCESS_ONCE(*D) = d; ACCESS_ONCE(*E) = e;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002032 ACQUIRE M [2]
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08002033 smp_mb__after_unlock_lock();
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002034 ACCESS_ONCE(*F) = f;
2035 ACCESS_ONCE(*G) = g;
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002036 RELEASE M [2]
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002037 ACCESS_ONCE(*H) = h;
David Howells108b42b2006-03-31 16:00:29 +01002038
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002039CPU 3 might see:
David Howells108b42b2006-03-31 16:00:29 +01002040
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002041 *E, ACQUIRE M [1], *C, *B, *A, RELEASE M [1],
2042 ACQUIRE M [2], *H, *F, *G, RELEASE M [2], *D
David Howells108b42b2006-03-31 16:00:29 +01002043
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002044But assuming CPU 1 gets the lock first, CPU 3 won't see any of:
David Howells108b42b2006-03-31 16:00:29 +01002045
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002046 *B, *C, *D, *F, *G or *H preceding ACQUIRE M [1]
2047 *A, *B or *C following RELEASE M [1]
2048 *F, *G or *H preceding ACQUIRE M [2]
2049 *A, *B, *C, *E, *F or *G following RELEASE M [2]
David Howells108b42b2006-03-31 16:00:29 +01002050
Paul E. McKenney17eb88e2013-12-11 13:59:09 -08002051Note that the smp_mb__after_unlock_lock() is critically important
2052here: Without it CPU 3 might see some of the above orderings.
2053Without smp_mb__after_unlock_lock(), the accesses are not guaranteed
2054to be seen in order unless CPU 3 holds lock M.
2055
David Howells108b42b2006-03-31 16:00:29 +01002056
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002057ACQUIRES VS I/O ACCESSES
2058------------------------
David Howells108b42b2006-03-31 16:00:29 +01002059
2060Under certain circumstances (especially involving NUMA), I/O accesses within
2061two spinlocked sections on two different CPUs may be seen as interleaved by the
2062PCI bridge, because the PCI bridge does not necessarily participate in the
2063cache-coherence protocol, and is therefore incapable of issuing the required
2064read memory barriers.
2065
2066For example:
2067
2068 CPU 1 CPU 2
2069 =============================== ===============================
2070 spin_lock(Q)
2071 writel(0, ADDR)
2072 writel(1, DATA);
2073 spin_unlock(Q);
2074 spin_lock(Q);
2075 writel(4, ADDR);
2076 writel(5, DATA);
2077 spin_unlock(Q);
2078
2079may be seen by the PCI bridge as follows:
2080
2081 STORE *ADDR = 0, STORE *ADDR = 4, STORE *DATA = 1, STORE *DATA = 5
2082
2083which would probably cause the hardware to malfunction.
2084
2085
2086What is necessary here is to intervene with an mmiowb() before dropping the
2087spinlock, for example:
2088
2089 CPU 1 CPU 2
2090 =============================== ===============================
2091 spin_lock(Q)
2092 writel(0, ADDR)
2093 writel(1, DATA);
2094 mmiowb();
2095 spin_unlock(Q);
2096 spin_lock(Q);
2097 writel(4, ADDR);
2098 writel(5, DATA);
2099 mmiowb();
2100 spin_unlock(Q);
2101
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002102this will ensure that the two stores issued on CPU 1 appear at the PCI bridge
2103before either of the stores issued on CPU 2.
David Howells108b42b2006-03-31 16:00:29 +01002104
2105
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002106Furthermore, following a store by a load from the same device obviates the need
2107for the mmiowb(), because the load forces the store to complete before the load
David Howells108b42b2006-03-31 16:00:29 +01002108is performed:
2109
2110 CPU 1 CPU 2
2111 =============================== ===============================
2112 spin_lock(Q)
2113 writel(0, ADDR)
2114 a = readl(DATA);
2115 spin_unlock(Q);
2116 spin_lock(Q);
2117 writel(4, ADDR);
2118 b = readl(DATA);
2119 spin_unlock(Q);
2120
2121
2122See Documentation/DocBook/deviceiobook.tmpl for more information.
2123
2124
2125=================================
2126WHERE ARE MEMORY BARRIERS NEEDED?
2127=================================
2128
2129Under normal operation, memory operation reordering is generally not going to
2130be a problem as a single-threaded linear piece of code will still appear to
David Howells50fa6102009-04-28 15:01:38 +01002131work correctly, even if it's in an SMP kernel. There are, however, four
David Howells108b42b2006-03-31 16:00:29 +01002132circumstances in which reordering definitely _could_ be a problem:
2133
2134 (*) Interprocessor interaction.
2135
2136 (*) Atomic operations.
2137
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002138 (*) Accessing devices.
David Howells108b42b2006-03-31 16:00:29 +01002139
2140 (*) Interrupts.
2141
2142
2143INTERPROCESSOR INTERACTION
2144--------------------------
2145
2146When there's a system with more than one processor, more than one CPU in the
2147system may be working on the same data set at the same time. This can cause
2148synchronisation problems, and the usual way of dealing with them is to use
2149locks. Locks, however, are quite expensive, and so it may be preferable to
2150operate without the use of a lock if at all possible. In such a case
2151operations that affect both CPUs may have to be carefully ordered to prevent
2152a malfunction.
2153
2154Consider, for example, the R/W semaphore slow path. Here a waiting process is
2155queued on the semaphore, by virtue of it having a piece of its stack linked to
2156the semaphore's list of waiting processes:
2157
2158 struct rw_semaphore {
2159 ...
2160 spinlock_t lock;
2161 struct list_head waiters;
2162 };
2163
2164 struct rwsem_waiter {
2165 struct list_head list;
2166 struct task_struct *task;
2167 };
2168
2169To wake up a particular waiter, the up_read() or up_write() functions have to:
2170
2171 (1) read the next pointer from this waiter's record to know as to where the
2172 next waiter record is;
2173
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002174 (2) read the pointer to the waiter's task structure;
David Howells108b42b2006-03-31 16:00:29 +01002175
2176 (3) clear the task pointer to tell the waiter it has been given the semaphore;
2177
2178 (4) call wake_up_process() on the task; and
2179
2180 (5) release the reference held on the waiter's task struct.
2181
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002182In other words, it has to perform this sequence of events:
David Howells108b42b2006-03-31 16:00:29 +01002183
2184 LOAD waiter->list.next;
2185 LOAD waiter->task;
2186 STORE waiter->task;
2187 CALL wakeup
2188 RELEASE task
2189
2190and if any of these steps occur out of order, then the whole thing may
2191malfunction.
2192
2193Once it has queued itself and dropped the semaphore lock, the waiter does not
2194get the lock again; it instead just waits for its task pointer to be cleared
2195before proceeding. Since the record is on the waiter's stack, this means that
2196if the task pointer is cleared _before_ the next pointer in the list is read,
2197another CPU might start processing the waiter and might clobber the waiter's
2198stack before the up*() function has a chance to read the next pointer.
2199
2200Consider then what might happen to the above sequence of events:
2201
2202 CPU 1 CPU 2
2203 =============================== ===============================
2204 down_xxx()
2205 Queue waiter
2206 Sleep
2207 up_yyy()
2208 LOAD waiter->task;
2209 STORE waiter->task;
2210 Woken up by other event
2211 <preempt>
2212 Resume processing
2213 down_xxx() returns
2214 call foo()
2215 foo() clobbers *waiter
2216 </preempt>
2217 LOAD waiter->list.next;
2218 --- OOPS ---
2219
2220This could be dealt with using the semaphore lock, but then the down_xxx()
2221function has to needlessly get the spinlock again after being woken up.
2222
2223The way to deal with this is to insert a general SMP memory barrier:
2224
2225 LOAD waiter->list.next;
2226 LOAD waiter->task;
2227 smp_mb();
2228 STORE waiter->task;
2229 CALL wakeup
2230 RELEASE task
2231
2232In this case, the barrier makes a guarantee that all memory accesses before the
2233barrier will appear to happen before all the memory accesses after the barrier
2234with respect to the other CPUs on the system. It does _not_ guarantee that all
2235the memory accesses before the barrier will be complete by the time the barrier
2236instruction itself is complete.
2237
2238On a UP system - where this wouldn't be a problem - the smp_mb() is just a
2239compiler barrier, thus making sure the compiler emits the instructions in the
David Howells6bc39272006-06-25 05:49:22 -07002240right order without actually intervening in the CPU. Since there's only one
2241CPU, that CPU's dependency ordering logic will take care of everything else.
David Howells108b42b2006-03-31 16:00:29 +01002242
2243
2244ATOMIC OPERATIONS
2245-----------------
2246
David Howellsdbc87002006-04-10 22:54:23 -07002247Whilst they are technically interprocessor interaction considerations, atomic
2248operations are noted specially as some of them imply full memory barriers and
2249some don't, but they're very heavily relied on as a group throughout the
2250kernel.
2251
2252Any atomic operation that modifies some state in memory and returns information
2253about the state (old or new) implies an SMP-conditional general memory barrier
Nick Piggin26333572007-10-18 03:06:39 -07002254(smp_mb()) on each side of the actual operation (with the exception of
2255explicit lock operations, described later). These include:
David Howells108b42b2006-03-31 16:00:29 +01002256
2257 xchg();
2258 cmpxchg();
Paul E. McKenneyfb2b5812013-12-11 13:59:05 -08002259 atomic_xchg(); atomic_long_xchg();
2260 atomic_cmpxchg(); atomic_long_cmpxchg();
2261 atomic_inc_return(); atomic_long_inc_return();
2262 atomic_dec_return(); atomic_long_dec_return();
2263 atomic_add_return(); atomic_long_add_return();
2264 atomic_sub_return(); atomic_long_sub_return();
2265 atomic_inc_and_test(); atomic_long_inc_and_test();
2266 atomic_dec_and_test(); atomic_long_dec_and_test();
2267 atomic_sub_and_test(); atomic_long_sub_and_test();
2268 atomic_add_negative(); atomic_long_add_negative();
David Howellsdbc87002006-04-10 22:54:23 -07002269 test_and_set_bit();
2270 test_and_clear_bit();
2271 test_and_change_bit();
David Howells108b42b2006-03-31 16:00:29 +01002272
Paul E. McKenneyfb2b5812013-12-11 13:59:05 -08002273 /* when succeeds (returns 1) */
2274 atomic_add_unless(); atomic_long_add_unless();
2275
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002276These are used for such things as implementing ACQUIRE-class and RELEASE-class
David Howellsdbc87002006-04-10 22:54:23 -07002277operations and adjusting reference counters towards object destruction, and as
2278such the implicit memory barrier effects are necessary.
David Howells108b42b2006-03-31 16:00:29 +01002279
David Howells108b42b2006-03-31 16:00:29 +01002280
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002281The following operations are potential problems as they do _not_ imply memory
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002282barriers, but might be used for implementing such things as RELEASE-class
David Howellsdbc87002006-04-10 22:54:23 -07002283operations:
2284
2285 atomic_set();
David Howells108b42b2006-03-31 16:00:29 +01002286 set_bit();
2287 clear_bit();
2288 change_bit();
David Howellsdbc87002006-04-10 22:54:23 -07002289
2290With these the appropriate explicit memory barrier should be used if necessary
Peter Zijlstra1b156112014-03-13 19:00:35 +01002291(smp_mb__before_atomic() for instance).
David Howells108b42b2006-03-31 16:00:29 +01002292
2293
David Howellsdbc87002006-04-10 22:54:23 -07002294The following also do _not_ imply memory barriers, and so may require explicit
Peter Zijlstra1b156112014-03-13 19:00:35 +01002295memory barriers under some circumstances (smp_mb__before_atomic() for
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002296instance):
David Howells108b42b2006-03-31 16:00:29 +01002297
2298 atomic_add();
2299 atomic_sub();
2300 atomic_inc();
2301 atomic_dec();
2302
2303If they're used for statistics generation, then they probably don't need memory
2304barriers, unless there's a coupling between statistical data.
2305
2306If they're used for reference counting on an object to control its lifetime,
2307they probably don't need memory barriers because either the reference count
2308will be adjusted inside a locked section, or the caller will already hold
2309sufficient references to make the lock, and thus a memory barrier unnecessary.
2310
2311If they're used for constructing a lock of some description, then they probably
2312do need memory barriers as a lock primitive generally has to do things in a
2313specific order.
2314
David Howells108b42b2006-03-31 16:00:29 +01002315Basically, each usage case has to be carefully considered as to whether memory
David Howellsdbc87002006-04-10 22:54:23 -07002316barriers are needed or not.
2317
Nick Piggin26333572007-10-18 03:06:39 -07002318The following operations are special locking primitives:
2319
2320 test_and_set_bit_lock();
2321 clear_bit_unlock();
2322 __clear_bit_unlock();
2323
Peter Zijlstra2e4f5382013-11-06 14:57:36 +01002324These implement ACQUIRE-class and RELEASE-class operations. These should be used in
Nick Piggin26333572007-10-18 03:06:39 -07002325preference to other operations when implementing locking primitives, because
2326their implementations can be optimised on many architectures.
2327
David Howellsdbc87002006-04-10 22:54:23 -07002328[!] Note that special memory barrier primitives are available for these
2329situations because on some CPUs the atomic instructions used imply full memory
2330barriers, and so barrier instructions are superfluous in conjunction with them,
2331and in such cases the special barrier primitives will be no-ops.
David Howells108b42b2006-03-31 16:00:29 +01002332
2333See Documentation/atomic_ops.txt for more information.
2334
2335
2336ACCESSING DEVICES
2337-----------------
2338
2339Many devices can be memory mapped, and so appear to the CPU as if they're just
2340a set of memory locations. To control such a device, the driver usually has to
2341make the right memory accesses in exactly the right order.
2342
2343However, having a clever CPU or a clever compiler creates a potential problem
2344in that the carefully sequenced accesses in the driver code won't reach the
2345device in the requisite order if the CPU or the compiler thinks it is more
2346efficient to reorder, combine or merge accesses - something that would cause
2347the device to malfunction.
2348
2349Inside of the Linux kernel, I/O should be done through the appropriate accessor
2350routines - such as inb() or writel() - which know how to make such accesses
2351appropriately sequential. Whilst this, for the most part, renders the explicit
2352use of memory barriers unnecessary, there are a couple of situations where they
2353might be needed:
2354
2355 (1) On some systems, I/O stores are not strongly ordered across all CPUs, and
2356 so for _all_ general drivers locks should be used and mmiowb() must be
2357 issued prior to unlocking the critical section.
2358
2359 (2) If the accessor functions are used to refer to an I/O memory window with
2360 relaxed memory access properties, then _mandatory_ memory barriers are
2361 required to enforce ordering.
2362
2363See Documentation/DocBook/deviceiobook.tmpl for more information.
2364
2365
2366INTERRUPTS
2367----------
2368
2369A driver may be interrupted by its own interrupt service routine, and thus the
2370two parts of the driver may interfere with each other's attempts to control or
2371access the device.
2372
2373This may be alleviated - at least in part - by disabling local interrupts (a
2374form of locking), such that the critical operations are all contained within
2375the interrupt-disabled section in the driver. Whilst the driver's interrupt
2376routine is executing, the driver's core may not run on the same CPU, and its
2377interrupt is not permitted to happen again until the current interrupt has been
2378handled, thus the interrupt handler does not need to lock against that.
2379
2380However, consider a driver that was talking to an ethernet card that sports an
2381address register and a data register. If that driver's core talks to the card
2382under interrupt-disablement and then the driver's interrupt handler is invoked:
2383
2384 LOCAL IRQ DISABLE
2385 writew(ADDR, 3);
2386 writew(DATA, y);
2387 LOCAL IRQ ENABLE
2388 <interrupt>
2389 writew(ADDR, 4);
2390 q = readw(DATA);
2391 </interrupt>
2392
2393The store to the data register might happen after the second store to the
2394address register if ordering rules are sufficiently relaxed:
2395
2396 STORE *ADDR = 3, STORE *ADDR = 4, STORE *DATA = y, q = LOAD *DATA
2397
2398
2399If ordering rules are relaxed, it must be assumed that accesses done inside an
2400interrupt disabled section may leak outside of it and may interleave with
2401accesses performed in an interrupt - and vice versa - unless implicit or
2402explicit barriers are used.
2403
2404Normally this won't be a problem because the I/O accesses done inside such
2405sections will include synchronous load operations on strictly ordered I/O
2406registers that form implicit I/O barriers. If this isn't sufficient then an
2407mmiowb() may need to be used explicitly.
2408
2409
2410A similar situation may occur between an interrupt routine and two routines
2411running on separate CPUs that communicate with each other. If such a case is
2412likely, then interrupt-disabling locks should be used to guarantee ordering.
2413
2414
2415==========================
2416KERNEL I/O BARRIER EFFECTS
2417==========================
2418
2419When accessing I/O memory, drivers should use the appropriate accessor
2420functions:
2421
2422 (*) inX(), outX():
2423
2424 These are intended to talk to I/O space rather than memory space, but
2425 that's primarily a CPU-specific concept. The i386 and x86_64 processors do
2426 indeed have special I/O space access cycles and instructions, but many
2427 CPUs don't have such a concept.
2428
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002429 The PCI bus, amongst others, defines an I/O space concept which - on such
2430 CPUs as i386 and x86_64 - readily maps to the CPU's concept of I/O
David Howells6bc39272006-06-25 05:49:22 -07002431 space. However, it may also be mapped as a virtual I/O space in the CPU's
2432 memory map, particularly on those CPUs that don't support alternate I/O
2433 spaces.
David Howells108b42b2006-03-31 16:00:29 +01002434
2435 Accesses to this space may be fully synchronous (as on i386), but
2436 intermediary bridges (such as the PCI host bridge) may not fully honour
2437 that.
2438
2439 They are guaranteed to be fully ordered with respect to each other.
2440
2441 They are not guaranteed to be fully ordered with respect to other types of
2442 memory and I/O operation.
2443
2444 (*) readX(), writeX():
2445
2446 Whether these are guaranteed to be fully ordered and uncombined with
2447 respect to each other on the issuing CPU depends on the characteristics
2448 defined for the memory window through which they're accessing. On later
2449 i386 architecture machines, for example, this is controlled by way of the
2450 MTRR registers.
2451
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002452 Ordinarily, these will be guaranteed to be fully ordered and uncombined,
David Howells108b42b2006-03-31 16:00:29 +01002453 provided they're not accessing a prefetchable device.
2454
2455 However, intermediary hardware (such as a PCI bridge) may indulge in
2456 deferral if it so wishes; to flush a store, a load from the same location
2457 is preferred[*], but a load from the same device or from configuration
2458 space should suffice for PCI.
2459
2460 [*] NOTE! attempting to load from the same location as was written to may
Ingo Molnare0edc782013-11-22 11:24:53 +01002461 cause a malfunction - consider the 16550 Rx/Tx serial registers for
2462 example.
David Howells108b42b2006-03-31 16:00:29 +01002463
2464 Used with prefetchable I/O memory, an mmiowb() barrier may be required to
2465 force stores to be ordered.
2466
2467 Please refer to the PCI specification for more information on interactions
2468 between PCI transactions.
2469
2470 (*) readX_relaxed()
2471
2472 These are similar to readX(), but are not guaranteed to be ordered in any
2473 way. Be aware that there is no I/O read barrier available.
2474
2475 (*) ioreadX(), iowriteX()
2476
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002477 These will perform appropriately for the type of access they're actually
David Howells108b42b2006-03-31 16:00:29 +01002478 doing, be it inX()/outX() or readX()/writeX().
2479
2480
2481========================================
2482ASSUMED MINIMUM EXECUTION ORDERING MODEL
2483========================================
2484
2485It has to be assumed that the conceptual CPU is weakly-ordered but that it will
2486maintain the appearance of program causality with respect to itself. Some CPUs
2487(such as i386 or x86_64) are more constrained than others (such as powerpc or
2488frv), and so the most relaxed case (namely DEC Alpha) must be assumed outside
2489of arch-specific code.
2490
2491This means that it must be considered that the CPU will execute its instruction
2492stream in any order it feels like - or even in parallel - provided that if an
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002493instruction in the stream depends on an earlier instruction, then that
David Howells108b42b2006-03-31 16:00:29 +01002494earlier instruction must be sufficiently complete[*] before the later
2495instruction may proceed; in other words: provided that the appearance of
2496causality is maintained.
2497
2498 [*] Some instructions have more than one effect - such as changing the
2499 condition codes, changing registers or changing memory - and different
2500 instructions may depend on different effects.
2501
2502A CPU may also discard any instruction sequence that winds up having no
2503ultimate effect. For example, if two adjacent instructions both load an
2504immediate value into the same register, the first may be discarded.
2505
2506
2507Similarly, it has to be assumed that compiler might reorder the instruction
2508stream in any way it sees fit, again provided the appearance of causality is
2509maintained.
2510
2511
2512============================
2513THE EFFECTS OF THE CPU CACHE
2514============================
2515
2516The way cached memory operations are perceived across the system is affected to
2517a certain extent by the caches that lie between CPUs and memory, and by the
2518memory coherence system that maintains the consistency of state in the system.
2519
2520As far as the way a CPU interacts with another part of the system through the
2521caches goes, the memory system has to include the CPU's caches, and memory
2522barriers for the most part act at the interface between the CPU and its cache
2523(memory barriers logically act on the dotted line in the following diagram):
2524
2525 <--- CPU ---> : <----------- Memory ----------->
2526 :
2527 +--------+ +--------+ : +--------+ +-----------+
2528 | | | | : | | | | +--------+
Ingo Molnare0edc782013-11-22 11:24:53 +01002529 | CPU | | Memory | : | CPU | | | | |
2530 | Core |--->| Access |----->| Cache |<-->| | | |
David Howells108b42b2006-03-31 16:00:29 +01002531 | | | Queue | : | | | |--->| Memory |
Ingo Molnare0edc782013-11-22 11:24:53 +01002532 | | | | : | | | | | |
2533 +--------+ +--------+ : +--------+ | | | |
David Howells108b42b2006-03-31 16:00:29 +01002534 : | Cache | +--------+
2535 : | Coherency |
2536 : | Mechanism | +--------+
2537 +--------+ +--------+ : +--------+ | | | |
2538 | | | | : | | | | | |
2539 | CPU | | Memory | : | CPU | | |--->| Device |
Ingo Molnare0edc782013-11-22 11:24:53 +01002540 | Core |--->| Access |----->| Cache |<-->| | | |
2541 | | | Queue | : | | | | | |
David Howells108b42b2006-03-31 16:00:29 +01002542 | | | | : | | | | +--------+
2543 +--------+ +--------+ : +--------+ +-----------+
2544 :
2545 :
2546
2547Although any particular load or store may not actually appear outside of the
2548CPU that issued it since it may have been satisfied within the CPU's own cache,
2549it will still appear as if the full memory access had taken place as far as the
2550other CPUs are concerned since the cache coherency mechanisms will migrate the
2551cacheline over to the accessing CPU and propagate the effects upon conflict.
2552
2553The CPU core may execute instructions in any order it deems fit, provided the
2554expected program causality appears to be maintained. Some of the instructions
2555generate load and store operations which then go into the queue of memory
2556accesses to be performed. The core may place these in the queue in any order
2557it wishes, and continue execution until it is forced to wait for an instruction
2558to complete.
2559
2560What memory barriers are concerned with is controlling the order in which
2561accesses cross from the CPU side of things to the memory side of things, and
2562the order in which the effects are perceived to happen by the other observers
2563in the system.
2564
2565[!] Memory barriers are _not_ needed within a given CPU, as CPUs always see
2566their own loads and stores as if they had happened in program order.
2567
2568[!] MMIO or other device accesses may bypass the cache system. This depends on
2569the properties of the memory window through which devices are accessed and/or
2570the use of any special device communication instructions the CPU may have.
2571
2572
2573CACHE COHERENCY
2574---------------
2575
2576Life isn't quite as simple as it may appear above, however: for while the
2577caches are expected to be coherent, there's no guarantee that that coherency
2578will be ordered. This means that whilst changes made on one CPU will
2579eventually become visible on all CPUs, there's no guarantee that they will
2580become apparent in the same order on those other CPUs.
2581
2582
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002583Consider dealing with a system that has a pair of CPUs (1 & 2), each of which
2584has a pair of parallel data caches (CPU 1 has A/B, and CPU 2 has C/D):
David Howells108b42b2006-03-31 16:00:29 +01002585
2586 :
2587 : +--------+
2588 : +---------+ | |
2589 +--------+ : +--->| Cache A |<------->| |
2590 | | : | +---------+ | |
2591 | CPU 1 |<---+ | |
2592 | | : | +---------+ | |
2593 +--------+ : +--->| Cache B |<------->| |
2594 : +---------+ | |
2595 : | Memory |
2596 : +---------+ | System |
2597 +--------+ : +--->| Cache C |<------->| |
2598 | | : | +---------+ | |
2599 | CPU 2 |<---+ | |
2600 | | : | +---------+ | |
2601 +--------+ : +--->| Cache D |<------->| |
2602 : +---------+ | |
2603 : +--------+
2604 :
2605
2606Imagine the system has the following properties:
2607
2608 (*) an odd-numbered cache line may be in cache A, cache C or it may still be
2609 resident in memory;
2610
2611 (*) an even-numbered cache line may be in cache B, cache D or it may still be
2612 resident in memory;
2613
2614 (*) whilst the CPU core is interrogating one cache, the other cache may be
2615 making use of the bus to access the rest of the system - perhaps to
2616 displace a dirty cacheline or to do a speculative load;
2617
2618 (*) each cache has a queue of operations that need to be applied to that cache
2619 to maintain coherency with the rest of the system;
2620
2621 (*) the coherency queue is not flushed by normal loads to lines already
2622 present in the cache, even though the contents of the queue may
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002623 potentially affect those loads.
David Howells108b42b2006-03-31 16:00:29 +01002624
2625Imagine, then, that two writes are made on the first CPU, with a write barrier
2626between them to guarantee that they will appear to reach that CPU's caches in
2627the requisite order:
2628
2629 CPU 1 CPU 2 COMMENT
2630 =============== =============== =======================================
2631 u == 0, v == 1 and p == &u, q == &u
2632 v = 2;
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002633 smp_wmb(); Make sure change to v is visible before
David Howells108b42b2006-03-31 16:00:29 +01002634 change to p
2635 <A:modify v=2> v is now in cache A exclusively
2636 p = &v;
2637 <B:modify p=&v> p is now in cache B exclusively
2638
2639The write memory barrier forces the other CPUs in the system to perceive that
2640the local CPU's caches have apparently been updated in the correct order. But
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002641now imagine that the second CPU wants to read those values:
David Howells108b42b2006-03-31 16:00:29 +01002642
2643 CPU 1 CPU 2 COMMENT
2644 =============== =============== =======================================
2645 ...
2646 q = p;
2647 x = *q;
2648
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002649The above pair of reads may then fail to happen in the expected order, as the
David Howells108b42b2006-03-31 16:00:29 +01002650cacheline holding p may get updated in one of the second CPU's caches whilst
2651the update to the cacheline holding v is delayed in the other of the second
2652CPU's caches by some other cache event:
2653
2654 CPU 1 CPU 2 COMMENT
2655 =============== =============== =======================================
2656 u == 0, v == 1 and p == &u, q == &u
2657 v = 2;
2658 smp_wmb();
2659 <A:modify v=2> <C:busy>
2660 <C:queue v=2>
Aneesh Kumar79afecf2006-05-15 09:44:36 -07002661 p = &v; q = p;
David Howells108b42b2006-03-31 16:00:29 +01002662 <D:request p>
2663 <B:modify p=&v> <D:commit p=&v>
Ingo Molnare0edc782013-11-22 11:24:53 +01002664 <D:read p>
David Howells108b42b2006-03-31 16:00:29 +01002665 x = *q;
2666 <C:read *q> Reads from v before v updated in cache
2667 <C:unbusy>
2668 <C:commit v=2>
2669
2670Basically, whilst both cachelines will be updated on CPU 2 eventually, there's
2671no guarantee that, without intervention, the order of update will be the same
2672as that committed on CPU 1.
2673
2674
2675To intervene, we need to interpolate a data dependency barrier or a read
2676barrier between the loads. This will force the cache to commit its coherency
2677queue before processing any further requests:
2678
2679 CPU 1 CPU 2 COMMENT
2680 =============== =============== =======================================
2681 u == 0, v == 1 and p == &u, q == &u
2682 v = 2;
2683 smp_wmb();
2684 <A:modify v=2> <C:busy>
2685 <C:queue v=2>
Paolo 'Blaisorblade' Giarrusso3fda9822006-10-19 23:28:19 -07002686 p = &v; q = p;
David Howells108b42b2006-03-31 16:00:29 +01002687 <D:request p>
2688 <B:modify p=&v> <D:commit p=&v>
Ingo Molnare0edc782013-11-22 11:24:53 +01002689 <D:read p>
David Howells108b42b2006-03-31 16:00:29 +01002690 smp_read_barrier_depends()
2691 <C:unbusy>
2692 <C:commit v=2>
2693 x = *q;
2694 <C:read *q> Reads from v after v updated in cache
2695
2696
2697This sort of problem can be encountered on DEC Alpha processors as they have a
2698split cache that improves performance by making better use of the data bus.
2699Whilst most CPUs do imply a data dependency barrier on the read when a memory
2700access depends on a read, not all do, so it may not be relied on.
2701
2702Other CPUs may also have split caches, but must coordinate between the various
Matt LaPlante3f6dee92006-10-03 22:45:33 +02002703cachelets for normal memory accesses. The semantics of the Alpha removes the
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002704need for coordination in the absence of memory barriers.
David Howells108b42b2006-03-31 16:00:29 +01002705
2706
2707CACHE COHERENCY VS DMA
2708----------------------
2709
2710Not all systems maintain cache coherency with respect to devices doing DMA. In
2711such cases, a device attempting DMA may obtain stale data from RAM because
2712dirty cache lines may be resident in the caches of various CPUs, and may not
2713have been written back to RAM yet. To deal with this, the appropriate part of
2714the kernel must flush the overlapping bits of cache on each CPU (and maybe
2715invalidate them as well).
2716
2717In addition, the data DMA'd to RAM by a device may be overwritten by dirty
2718cache lines being written back to RAM from a CPU's cache after the device has
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002719installed its own data, or cache lines present in the CPU's cache may simply
2720obscure the fact that RAM has been updated, until at such time as the cacheline
2721is discarded from the CPU's cache and reloaded. To deal with this, the
2722appropriate part of the kernel must invalidate the overlapping bits of the
David Howells108b42b2006-03-31 16:00:29 +01002723cache on each CPU.
2724
2725See Documentation/cachetlb.txt for more information on cache management.
2726
2727
2728CACHE COHERENCY VS MMIO
2729-----------------------
2730
2731Memory mapped I/O usually takes place through memory locations that are part of
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002732a window in the CPU's memory space that has different properties assigned than
David Howells108b42b2006-03-31 16:00:29 +01002733the usual RAM directed window.
2734
2735Amongst these properties is usually the fact that such accesses bypass the
2736caching entirely and go directly to the device buses. This means MMIO accesses
2737may, in effect, overtake accesses to cached memory that were emitted earlier.
2738A memory barrier isn't sufficient in such a case, but rather the cache must be
2739flushed between the cached memory write and the MMIO access if the two are in
2740any way dependent.
2741
2742
2743=========================
2744THE THINGS CPUS GET UP TO
2745=========================
2746
2747A programmer might take it for granted that the CPU will perform memory
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002748operations in exactly the order specified, so that if the CPU is, for example,
David Howells108b42b2006-03-31 16:00:29 +01002749given the following piece of code to execute:
2750
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002751 a = ACCESS_ONCE(*A);
2752 ACCESS_ONCE(*B) = b;
2753 c = ACCESS_ONCE(*C);
2754 d = ACCESS_ONCE(*D);
2755 ACCESS_ONCE(*E) = e;
David Howells108b42b2006-03-31 16:00:29 +01002756
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002757they would then expect that the CPU will complete the memory operation for each
David Howells108b42b2006-03-31 16:00:29 +01002758instruction before moving on to the next one, leading to a definite sequence of
2759operations as seen by external observers in the system:
2760
2761 LOAD *A, STORE *B, LOAD *C, LOAD *D, STORE *E.
2762
2763
2764Reality is, of course, much messier. With many CPUs and compilers, the above
2765assumption doesn't hold because:
2766
2767 (*) loads are more likely to need to be completed immediately to permit
2768 execution progress, whereas stores can often be deferred without a
2769 problem;
2770
2771 (*) loads may be done speculatively, and the result discarded should it prove
2772 to have been unnecessary;
2773
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002774 (*) loads may be done speculatively, leading to the result having been fetched
2775 at the wrong time in the expected sequence of events;
David Howells108b42b2006-03-31 16:00:29 +01002776
2777 (*) the order of the memory accesses may be rearranged to promote better use
2778 of the CPU buses and caches;
2779
2780 (*) loads and stores may be combined to improve performance when talking to
2781 memory or I/O hardware that can do batched accesses of adjacent locations,
2782 thus cutting down on transaction setup costs (memory and PCI devices may
2783 both be able to do this); and
2784
2785 (*) the CPU's data cache may affect the ordering, and whilst cache-coherency
2786 mechanisms may alleviate this - once the store has actually hit the cache
2787 - there's no guarantee that the coherency management will be propagated in
2788 order to other CPUs.
2789
2790So what another CPU, say, might actually observe from the above piece of code
2791is:
2792
2793 LOAD *A, ..., LOAD {*C,*D}, STORE *E, STORE *B
2794
2795 (Where "LOAD {*C,*D}" is a combined load)
2796
2797
2798However, it is guaranteed that a CPU will be self-consistent: it will see its
2799_own_ accesses appear to be correctly ordered, without the need for a memory
2800barrier. For instance with the following code:
2801
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002802 U = ACCESS_ONCE(*A);
2803 ACCESS_ONCE(*A) = V;
2804 ACCESS_ONCE(*A) = W;
2805 X = ACCESS_ONCE(*A);
2806 ACCESS_ONCE(*A) = Y;
2807 Z = ACCESS_ONCE(*A);
David Howells108b42b2006-03-31 16:00:29 +01002808
2809and assuming no intervention by an external influence, it can be assumed that
2810the final result will appear to be:
2811
2812 U == the original value of *A
2813 X == W
2814 Z == Y
2815 *A == Y
2816
2817The code above may cause the CPU to generate the full sequence of memory
2818accesses:
2819
2820 U=LOAD *A, STORE *A=V, STORE *A=W, X=LOAD *A, STORE *A=Y, Z=LOAD *A
2821
2822in that order, but, without intervention, the sequence may have almost any
2823combination of elements combined or discarded, provided the program's view of
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002824the world remains consistent. Note that ACCESS_ONCE() is -not- optional
2825in the above example, as there are architectures where a given CPU might
Paul E. McKenney8dd853d2014-02-23 08:34:24 -08002826reorder successive loads to the same location. On such architectures,
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002827ACCESS_ONCE() does whatever is necessary to prevent this, for example, on
2828Itanium the volatile casts used by ACCESS_ONCE() cause GCC to emit the
2829special ld.acq and st.rel instructions that prevent such reordering.
David Howells108b42b2006-03-31 16:00:29 +01002830
2831The compiler may also combine, discard or defer elements of the sequence before
2832the CPU even sees them.
2833
2834For instance:
2835
2836 *A = V;
2837 *A = W;
2838
2839may be reduced to:
2840
2841 *A = W;
2842
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002843since, without either a write barrier or an ACCESS_ONCE(), it can be
2844assumed that the effect of the storage of V to *A is lost. Similarly:
David Howells108b42b2006-03-31 16:00:29 +01002845
2846 *A = Y;
2847 Z = *A;
2848
Paul E. McKenney2ecf8102013-12-11 13:59:04 -08002849may, without a memory barrier or an ACCESS_ONCE(), be reduced to:
David Howells108b42b2006-03-31 16:00:29 +01002850
2851 *A = Y;
2852 Z = Y;
2853
2854and the LOAD operation never appear outside of the CPU.
2855
2856
2857AND THEN THERE'S THE ALPHA
2858--------------------------
2859
2860The DEC Alpha CPU is one of the most relaxed CPUs there is. Not only that,
2861some versions of the Alpha CPU have a split data cache, permitting them to have
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002862two semantically-related cache lines updated at separate times. This is where
David Howells108b42b2006-03-31 16:00:29 +01002863the data dependency barrier really becomes necessary as this synchronises both
2864caches with the memory coherence system, thus making it seem like pointer
2865changes vs new data occur in the right order.
2866
Jarek Poplawski81fc6322007-05-23 13:58:20 -07002867The Alpha defines the Linux kernel's memory barrier model.
David Howells108b42b2006-03-31 16:00:29 +01002868
2869See the subsection on "Cache Coherency" above.
2870
2871
David Howells90fddab2010-03-24 09:43:00 +00002872============
2873EXAMPLE USES
2874============
2875
2876CIRCULAR BUFFERS
2877----------------
2878
2879Memory barriers can be used to implement circular buffering without the need
2880of a lock to serialise the producer with the consumer. See:
2881
2882 Documentation/circular-buffers.txt
2883
2884for details.
2885
2886
David Howells108b42b2006-03-31 16:00:29 +01002887==========
2888REFERENCES
2889==========
2890
2891Alpha AXP Architecture Reference Manual, Second Edition (Sites & Witek,
2892Digital Press)
2893 Chapter 5.2: Physical Address Space Characteristics
2894 Chapter 5.4: Caches and Write Buffers
2895 Chapter 5.5: Data Sharing
2896 Chapter 5.6: Read/Write Ordering
2897
2898AMD64 Architecture Programmer's Manual Volume 2: System Programming
2899 Chapter 7.1: Memory-Access Ordering
2900 Chapter 7.4: Buffering and Combining Memory Writes
2901
2902IA-32 Intel Architecture Software Developer's Manual, Volume 3:
2903System Programming Guide
2904 Chapter 7.1: Locked Atomic Operations
2905 Chapter 7.2: Memory Ordering
2906 Chapter 7.4: Serializing Instructions
2907
2908The SPARC Architecture Manual, Version 9
2909 Chapter 8: Memory Models
2910 Appendix D: Formal Specification of the Memory Models
2911 Appendix J: Programming with the Memory Models
2912
2913UltraSPARC Programmer Reference Manual
2914 Chapter 5: Memory Accesses and Cacheability
2915 Chapter 15: Sparc-V9 Memory Models
2916
2917UltraSPARC III Cu User's Manual
2918 Chapter 9: Memory Models
2919
2920UltraSPARC IIIi Processor User's Manual
2921 Chapter 8: Memory Models
2922
2923UltraSPARC Architecture 2005
2924 Chapter 9: Memory
2925 Appendix D: Formal Specifications of the Memory Models
2926
2927UltraSPARC T1 Supplement to the UltraSPARC Architecture 2005
2928 Chapter 8: Memory Models
2929 Appendix F: Caches and Cache Coherency
2930
2931Solaris Internals, Core Kernel Architecture, p63-68:
2932 Chapter 3.3: Hardware Considerations for Locks and
2933 Synchronization
2934
2935Unix Systems for Modern Architectures, Symmetric Multiprocessing and Caching
2936for Kernel Programmers:
2937 Chapter 13: Other Memory Models
2938
2939Intel Itanium Architecture Software Developer's Manual: Volume 1:
2940 Section 2.6: Speculation
2941 Section 4.4: Memory Access